pandas loc function refers to different row when writing vs. reading -> ValueError











up vote
2
down vote

favorite












When running the example code below I get a



ValueError: cannot set using a multi-index selection indexer with a different
length than the value


The error is raised upon execution of



df.loc[(9, 0), ("clouds", "type")] = np.array([None, None])


here:



~Anaconda3libsite-packagespandascoreindexing.py in _setitem_with_indexer(self, indexer, value)
492
493 if len(obj[idx]) != len(value):
--> 494 raise ValueError


The problem seems to be connected to writing a numpy array to a "cell" of the dataframe. It seems that obj[idx] refers to index (20,) in the dataframe, while it should refer to (9,0). A few iterations before the one that raises the error, when executing



df.loc[(6, 0), ("clouds", "type")] = np.array([None, None])


no error is raised as by coincidence obj[idx] refers to index (17,) in the dataframe which has 2 sub-indices, so that by chance len(obj[idx])==len(value)==2.



Remark:



When I read



df.loc[(9, 0), ("clouds", "type")].values


it correctly returns [104].



Question:



Am I using the .loc function incorrectly? Am I doing something else wrong? Or is this a problem within pandas? How could I avoid it?



I greatly appreciate any help as the problem got me stuck for a few days now :/



Code:



import pandas as pd
import numpy as np

mi = pd.MultiIndex(levels=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]],
labels=[[0, 0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 7, 8, 9, 10, 10, 11, 12, 12, 13, 14, 14,
14, 15, 16, 17, 17, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 21, 21, 21, 22, 22, 22],
[0, 1, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 3, 4, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 2, 0, 0,
0, 1, 0, 1, 2, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 0, 1, 2]])


mc = pd.MultiIndex(levels=[['clouds', 'group', 'header', 'vertical_visibility', 'visibility', 'weather', 'wind', 'windshear'],
['', 'BR', 'DS', 'DU', 'DZ', 'FC', 'FG', 'FU', 'GR', 'GS', 'HZ', 'IC', 'PL', 'PO', 'PY', 'RA', 'SA', 'SG', 'SN', 'SQ', 'SS', 'UP', 'VA', 'altitude', 'ceiling', 'direction', 'form', 'from_date', 'from_hours', 'from_minutes', 'gust', 'icao_code', 'layer', 'more', 'origin_date', 'origin_hours', 'origin_minutes', 'probability', 'range', 'speed', 'till_date', 'till_hours', 'till_minutes', 'type', 'unit', 'valid_from_date', 'valid_from_hours', 'valid_till_date', 'valid_till_hours'],
['bool', 'intensity', 'modifier']],
labels=[[0, 0, 0, 1, 1, 1],
[24, 32, 43, 27, 28, 29],
[-1, -1, -1, -1, -1, -1]])

arr = np.array(range(0,len(mi)*len(mc))).reshape(len(mi),len(mc))

df = pd.DataFrame(arr, index=mi, columns=mc)


values = {0: {0: [None]}, 1: {0: [None], 1: [None], 2: [None], 3: [None]}, 2: {0: [None], 2: [None]}, 3: {0: [None], 1: [None], 2: [None], 3: [None], 4: [None], 5: [None]}, 4: {0: [None]}, 6: {0: [None, None]}, 9: {0: [None, None]}}


for i, val in values.items():
for j, v in val.items():
df.loc[(i,j),("clouds", "type")] = np.array(v)









share|improve this question




















  • 4




    Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
    – John Zwinck
    Nov 12 at 12:51










  • Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
    – MaxMike
    Nov 12 at 16:19















up vote
2
down vote

favorite












When running the example code below I get a



ValueError: cannot set using a multi-index selection indexer with a different
length than the value


The error is raised upon execution of



df.loc[(9, 0), ("clouds", "type")] = np.array([None, None])


here:



~Anaconda3libsite-packagespandascoreindexing.py in _setitem_with_indexer(self, indexer, value)
492
493 if len(obj[idx]) != len(value):
--> 494 raise ValueError


The problem seems to be connected to writing a numpy array to a "cell" of the dataframe. It seems that obj[idx] refers to index (20,) in the dataframe, while it should refer to (9,0). A few iterations before the one that raises the error, when executing



df.loc[(6, 0), ("clouds", "type")] = np.array([None, None])


no error is raised as by coincidence obj[idx] refers to index (17,) in the dataframe which has 2 sub-indices, so that by chance len(obj[idx])==len(value)==2.



Remark:



When I read



df.loc[(9, 0), ("clouds", "type")].values


it correctly returns [104].



Question:



Am I using the .loc function incorrectly? Am I doing something else wrong? Or is this a problem within pandas? How could I avoid it?



I greatly appreciate any help as the problem got me stuck for a few days now :/



Code:



import pandas as pd
import numpy as np

mi = pd.MultiIndex(levels=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]],
labels=[[0, 0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 7, 8, 9, 10, 10, 11, 12, 12, 13, 14, 14,
14, 15, 16, 17, 17, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 21, 21, 21, 22, 22, 22],
[0, 1, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 3, 4, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 2, 0, 0,
0, 1, 0, 1, 2, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 0, 1, 2]])


mc = pd.MultiIndex(levels=[['clouds', 'group', 'header', 'vertical_visibility', 'visibility', 'weather', 'wind', 'windshear'],
['', 'BR', 'DS', 'DU', 'DZ', 'FC', 'FG', 'FU', 'GR', 'GS', 'HZ', 'IC', 'PL', 'PO', 'PY', 'RA', 'SA', 'SG', 'SN', 'SQ', 'SS', 'UP', 'VA', 'altitude', 'ceiling', 'direction', 'form', 'from_date', 'from_hours', 'from_minutes', 'gust', 'icao_code', 'layer', 'more', 'origin_date', 'origin_hours', 'origin_minutes', 'probability', 'range', 'speed', 'till_date', 'till_hours', 'till_minutes', 'type', 'unit', 'valid_from_date', 'valid_from_hours', 'valid_till_date', 'valid_till_hours'],
['bool', 'intensity', 'modifier']],
labels=[[0, 0, 0, 1, 1, 1],
[24, 32, 43, 27, 28, 29],
[-1, -1, -1, -1, -1, -1]])

arr = np.array(range(0,len(mi)*len(mc))).reshape(len(mi),len(mc))

df = pd.DataFrame(arr, index=mi, columns=mc)


values = {0: {0: [None]}, 1: {0: [None], 1: [None], 2: [None], 3: [None]}, 2: {0: [None], 2: [None]}, 3: {0: [None], 1: [None], 2: [None], 3: [None], 4: [None], 5: [None]}, 4: {0: [None]}, 6: {0: [None, None]}, 9: {0: [None, None]}}


for i, val in values.items():
for j, v in val.items():
df.loc[(i,j),("clouds", "type")] = np.array(v)









share|improve this question




















  • 4




    Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
    – John Zwinck
    Nov 12 at 12:51










  • Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
    – MaxMike
    Nov 12 at 16:19













up vote
2
down vote

favorite









up vote
2
down vote

favorite











When running the example code below I get a



ValueError: cannot set using a multi-index selection indexer with a different
length than the value


The error is raised upon execution of



df.loc[(9, 0), ("clouds", "type")] = np.array([None, None])


here:



~Anaconda3libsite-packagespandascoreindexing.py in _setitem_with_indexer(self, indexer, value)
492
493 if len(obj[idx]) != len(value):
--> 494 raise ValueError


The problem seems to be connected to writing a numpy array to a "cell" of the dataframe. It seems that obj[idx] refers to index (20,) in the dataframe, while it should refer to (9,0). A few iterations before the one that raises the error, when executing



df.loc[(6, 0), ("clouds", "type")] = np.array([None, None])


no error is raised as by coincidence obj[idx] refers to index (17,) in the dataframe which has 2 sub-indices, so that by chance len(obj[idx])==len(value)==2.



Remark:



When I read



df.loc[(9, 0), ("clouds", "type")].values


it correctly returns [104].



Question:



Am I using the .loc function incorrectly? Am I doing something else wrong? Or is this a problem within pandas? How could I avoid it?



I greatly appreciate any help as the problem got me stuck for a few days now :/



Code:



import pandas as pd
import numpy as np

mi = pd.MultiIndex(levels=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]],
labels=[[0, 0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 7, 8, 9, 10, 10, 11, 12, 12, 13, 14, 14,
14, 15, 16, 17, 17, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 21, 21, 21, 22, 22, 22],
[0, 1, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 3, 4, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 2, 0, 0,
0, 1, 0, 1, 2, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 0, 1, 2]])


mc = pd.MultiIndex(levels=[['clouds', 'group', 'header', 'vertical_visibility', 'visibility', 'weather', 'wind', 'windshear'],
['', 'BR', 'DS', 'DU', 'DZ', 'FC', 'FG', 'FU', 'GR', 'GS', 'HZ', 'IC', 'PL', 'PO', 'PY', 'RA', 'SA', 'SG', 'SN', 'SQ', 'SS', 'UP', 'VA', 'altitude', 'ceiling', 'direction', 'form', 'from_date', 'from_hours', 'from_minutes', 'gust', 'icao_code', 'layer', 'more', 'origin_date', 'origin_hours', 'origin_minutes', 'probability', 'range', 'speed', 'till_date', 'till_hours', 'till_minutes', 'type', 'unit', 'valid_from_date', 'valid_from_hours', 'valid_till_date', 'valid_till_hours'],
['bool', 'intensity', 'modifier']],
labels=[[0, 0, 0, 1, 1, 1],
[24, 32, 43, 27, 28, 29],
[-1, -1, -1, -1, -1, -1]])

arr = np.array(range(0,len(mi)*len(mc))).reshape(len(mi),len(mc))

df = pd.DataFrame(arr, index=mi, columns=mc)


values = {0: {0: [None]}, 1: {0: [None], 1: [None], 2: [None], 3: [None]}, 2: {0: [None], 2: [None]}, 3: {0: [None], 1: [None], 2: [None], 3: [None], 4: [None], 5: [None]}, 4: {0: [None]}, 6: {0: [None, None]}, 9: {0: [None, None]}}


for i, val in values.items():
for j, v in val.items():
df.loc[(i,j),("clouds", "type")] = np.array(v)









share|improve this question















When running the example code below I get a



ValueError: cannot set using a multi-index selection indexer with a different
length than the value


The error is raised upon execution of



df.loc[(9, 0), ("clouds", "type")] = np.array([None, None])


here:



~Anaconda3libsite-packagespandascoreindexing.py in _setitem_with_indexer(self, indexer, value)
492
493 if len(obj[idx]) != len(value):
--> 494 raise ValueError


The problem seems to be connected to writing a numpy array to a "cell" of the dataframe. It seems that obj[idx] refers to index (20,) in the dataframe, while it should refer to (9,0). A few iterations before the one that raises the error, when executing



df.loc[(6, 0), ("clouds", "type")] = np.array([None, None])


no error is raised as by coincidence obj[idx] refers to index (17,) in the dataframe which has 2 sub-indices, so that by chance len(obj[idx])==len(value)==2.



Remark:



When I read



df.loc[(9, 0), ("clouds", "type")].values


it correctly returns [104].



Question:



Am I using the .loc function incorrectly? Am I doing something else wrong? Or is this a problem within pandas? How could I avoid it?



I greatly appreciate any help as the problem got me stuck for a few days now :/



Code:



import pandas as pd
import numpy as np

mi = pd.MultiIndex(levels=[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22],
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]],
labels=[[0, 0, 1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 7, 8, 9, 10, 10, 11, 12, 12, 13, 14, 14,
14, 15, 16, 17, 17, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 21, 21, 21, 22, 22, 22],
[0, 1, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 3, 4, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 2, 0, 0,
0, 1, 0, 1, 2, 0, 1, 2, 3, 0, 1, 2, 0, 1, 2, 0, 1, 2]])


mc = pd.MultiIndex(levels=[['clouds', 'group', 'header', 'vertical_visibility', 'visibility', 'weather', 'wind', 'windshear'],
['', 'BR', 'DS', 'DU', 'DZ', 'FC', 'FG', 'FU', 'GR', 'GS', 'HZ', 'IC', 'PL', 'PO', 'PY', 'RA', 'SA', 'SG', 'SN', 'SQ', 'SS', 'UP', 'VA', 'altitude', 'ceiling', 'direction', 'form', 'from_date', 'from_hours', 'from_minutes', 'gust', 'icao_code', 'layer', 'more', 'origin_date', 'origin_hours', 'origin_minutes', 'probability', 'range', 'speed', 'till_date', 'till_hours', 'till_minutes', 'type', 'unit', 'valid_from_date', 'valid_from_hours', 'valid_till_date', 'valid_till_hours'],
['bool', 'intensity', 'modifier']],
labels=[[0, 0, 0, 1, 1, 1],
[24, 32, 43, 27, 28, 29],
[-1, -1, -1, -1, -1, -1]])

arr = np.array(range(0,len(mi)*len(mc))).reshape(len(mi),len(mc))

df = pd.DataFrame(arr, index=mi, columns=mc)


values = {0: {0: [None]}, 1: {0: [None], 1: [None], 2: [None], 3: [None]}, 2: {0: [None], 2: [None]}, 3: {0: [None], 1: [None], 2: [None], 3: [None], 4: [None], 5: [None]}, 4: {0: [None]}, 6: {0: [None, None]}, 9: {0: [None, None]}}


for i, val in values.items():
for j, v in val.items():
df.loc[(i,j),("clouds", "type")] = np.array(v)






python python-3.x pandas numpy






share|improve this question















share|improve this question













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share|improve this question








edited Nov 12 at 13:10









unutbu

539k9911541222




539k9911541222










asked Nov 12 at 12:43









MaxMike

162




162








  • 4




    Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
    – John Zwinck
    Nov 12 at 12:51










  • Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
    – MaxMike
    Nov 12 at 16:19














  • 4




    Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
    – John Zwinck
    Nov 12 at 12:51










  • Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
    – MaxMike
    Nov 12 at 16:19








4




4




Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
– John Zwinck
Nov 12 at 12:51




Is it really your intention to use this loop-of-loops to insert a bunch of NumPy arrays containing [None, None] or similar into a DataFrame? This is very unusual and suggests a design problem.
– John Zwinck
Nov 12 at 12:51












Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
– MaxMike
Nov 12 at 16:19




Thanks for your remark! What I am trying to do is to fit weather forecast objects (~100 million of them) as efficiently as possible into a dataframe. To save memory I wanted to conver e. g. the "cloud type" element of each forecast into a column of categorical data. The "cloud elements" can take various alphanumerical values, NaN (no cloud element in forecast) and None (cloud element given but no type). As each forecast may contain several cloud layers I wanted to store lists/arrays instead of a scalar value.
– MaxMike
Nov 12 at 16:19












2 Answers
2






active

oldest

votes

















up vote
1
down vote













The ("clouds", "type", None) column has integer dtype:



In [28]: df[("clouds", "type", None)].dtype
Out[28]: dtype('int64')


So if you want to assign NumPy arrays to this column, first change the dtype to object:



df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')





  • Use df.at or df.iat to select or assign values to particular cells of a DataFrame.

  • Use df.loc or df.iloc to select or assign values to columns, rows or sub-DataFrames.




Therefore, use df.at here:



df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
for i, val in values.items():
for j, v in val.items():
df.at[(i, j), ("clouds", "type", None)] = np.array(v)


which yields a df that looks like



      clouds                         group                        
ceiling layer type from_date from_hours from_minutes
NaN NaN NaN NaN NaN NaN
0 0 0 1 [None] 3 4 5
1 6 7 8 9 10 11
1 0 12 13 [None] 15 16 17
1 18 19 [None] 21 22 23
2 24 25 [None] 27 28 29
3 30 31 [None] 33 34 35
2 0 36 37 [None] 39 40 41
1 42 43 44 45 46 47
2 48 49 [None] 51 52 53
3 0 54 55 [None] 57 58 59
1 60 61 [None] 63 64 65
2 66 67 [None] 69 70 71
3 72 73 [None] 75 76 77
4 78 79 [None] 81 82 83
5 84 85 [None] 87 88 89
4 0 90 91 [None] 93 94 95
5 0 96 97 98 99 100 101
6 0 102 103 [None, None] 105 106 107
7 0 108 109 110 111 112 113
8 0 114 115 116 117 118 119
9 0 120 121 [None, None] 123 124 125
...




Regarding the comment that you wish to use the cloud/type column for categorical data:



Columns with categorical data must contain hashable values. Generally, it does not make sense to make mutable objects hashable. So, for instance, Python mutable builtins (such as lists), or NumPy arrays are not hashable. But Python immutable builtins (such as tuples) are hashable. Therefore, if you use



df.at[(i, j), ("clouds", "type", None)] = tuple(v)


then you can make the ("clouds", "type", None) column of category dtype:



df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
for i, val in values.items():
for j, v in val.items():
df.at[(i, j), ("clouds", "type", None)] = tuple(v)

df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('category')


Notice that it is necessary to first make the column of object dtype so that it may contain Python objects such as tuples, and then convert to category dtype only after all the possible values have been assigned.





Depending on what you want to do with the data, it might also make more sense to "tidy" the data by assigning only strings to the clouds/type column and using multiple rows instead of tuples:



For example,



6  0     102   103  'foo'       105        106          107
6 0 102 103 'bar' 105 106 107


instead of



6  0     102   103  ('foo', 'bar')       105        106          107


One advantage of using multiple rows is that selecting all rows with cloud/type
'foo' is now easy:



df.loc[df[("clouds", "type", None)] == 'foo']


or to select all rows with foo or bar cloud/type:



df.loc[df[("clouds", "type", None)].isin(['foo', 'bar'])]


If you use tuples, you would have to use something like



df.loc[[any(kind in item for kind in ('foo', 'bar')) 
for item in df[("clouds", "type", None)]]]


Note only is this longer and harder to read, it is also slower.



One disadvantage of using multiple rows is that it create repeated data which may require greater memory usage. There may be ways around this, such as using multiple tables (and only joining them when required), but a discussion of this would be going way beyond the scope of this question.



So in summary, in general, use tidy data, use multiple rows, and keep your DataFrame dtypes simple -- use integers, floats whenever possible, 'strings' if necessary. Try to avoid using tuples, lists or NumPy arrays as DataFrame values.






share|improve this answer























  • Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
    – MaxMike
    Nov 12 at 16:47






  • 1




    There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
    – unutbu
    Nov 12 at 18:49


















up vote
0
down vote













I think you should either:




  1. create one column per possible cloud layer (if order is important), or

  2. use a bitmask, e.g. a column dtype of 'u8' which has 64 bits, and you can set as many cloud types as are applicable to that row (if order doesn't matter).






share|improve this answer





















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    up vote
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    down vote













    The ("clouds", "type", None) column has integer dtype:



    In [28]: df[("clouds", "type", None)].dtype
    Out[28]: dtype('int64')


    So if you want to assign NumPy arrays to this column, first change the dtype to object:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')





    • Use df.at or df.iat to select or assign values to particular cells of a DataFrame.

    • Use df.loc or df.iloc to select or assign values to columns, rows or sub-DataFrames.




    Therefore, use df.at here:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = np.array(v)


    which yields a df that looks like



          clouds                         group                        
    ceiling layer type from_date from_hours from_minutes
    NaN NaN NaN NaN NaN NaN
    0 0 0 1 [None] 3 4 5
    1 6 7 8 9 10 11
    1 0 12 13 [None] 15 16 17
    1 18 19 [None] 21 22 23
    2 24 25 [None] 27 28 29
    3 30 31 [None] 33 34 35
    2 0 36 37 [None] 39 40 41
    1 42 43 44 45 46 47
    2 48 49 [None] 51 52 53
    3 0 54 55 [None] 57 58 59
    1 60 61 [None] 63 64 65
    2 66 67 [None] 69 70 71
    3 72 73 [None] 75 76 77
    4 78 79 [None] 81 82 83
    5 84 85 [None] 87 88 89
    4 0 90 91 [None] 93 94 95
    5 0 96 97 98 99 100 101
    6 0 102 103 [None, None] 105 106 107
    7 0 108 109 110 111 112 113
    8 0 114 115 116 117 118 119
    9 0 120 121 [None, None] 123 124 125
    ...




    Regarding the comment that you wish to use the cloud/type column for categorical data:



    Columns with categorical data must contain hashable values. Generally, it does not make sense to make mutable objects hashable. So, for instance, Python mutable builtins (such as lists), or NumPy arrays are not hashable. But Python immutable builtins (such as tuples) are hashable. Therefore, if you use



    df.at[(i, j), ("clouds", "type", None)] = tuple(v)


    then you can make the ("clouds", "type", None) column of category dtype:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = tuple(v)

    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('category')


    Notice that it is necessary to first make the column of object dtype so that it may contain Python objects such as tuples, and then convert to category dtype only after all the possible values have been assigned.





    Depending on what you want to do with the data, it might also make more sense to "tidy" the data by assigning only strings to the clouds/type column and using multiple rows instead of tuples:



    For example,



    6  0     102   103  'foo'       105        106          107
    6 0 102 103 'bar' 105 106 107


    instead of



    6  0     102   103  ('foo', 'bar')       105        106          107


    One advantage of using multiple rows is that selecting all rows with cloud/type
    'foo' is now easy:



    df.loc[df[("clouds", "type", None)] == 'foo']


    or to select all rows with foo or bar cloud/type:



    df.loc[df[("clouds", "type", None)].isin(['foo', 'bar'])]


    If you use tuples, you would have to use something like



    df.loc[[any(kind in item for kind in ('foo', 'bar')) 
    for item in df[("clouds", "type", None)]]]


    Note only is this longer and harder to read, it is also slower.



    One disadvantage of using multiple rows is that it create repeated data which may require greater memory usage. There may be ways around this, such as using multiple tables (and only joining them when required), but a discussion of this would be going way beyond the scope of this question.



    So in summary, in general, use tidy data, use multiple rows, and keep your DataFrame dtypes simple -- use integers, floats whenever possible, 'strings' if necessary. Try to avoid using tuples, lists or NumPy arrays as DataFrame values.






    share|improve this answer























    • Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
      – MaxMike
      Nov 12 at 16:47






    • 1




      There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
      – unutbu
      Nov 12 at 18:49















    up vote
    1
    down vote













    The ("clouds", "type", None) column has integer dtype:



    In [28]: df[("clouds", "type", None)].dtype
    Out[28]: dtype('int64')


    So if you want to assign NumPy arrays to this column, first change the dtype to object:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')





    • Use df.at or df.iat to select or assign values to particular cells of a DataFrame.

    • Use df.loc or df.iloc to select or assign values to columns, rows or sub-DataFrames.




    Therefore, use df.at here:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = np.array(v)


    which yields a df that looks like



          clouds                         group                        
    ceiling layer type from_date from_hours from_minutes
    NaN NaN NaN NaN NaN NaN
    0 0 0 1 [None] 3 4 5
    1 6 7 8 9 10 11
    1 0 12 13 [None] 15 16 17
    1 18 19 [None] 21 22 23
    2 24 25 [None] 27 28 29
    3 30 31 [None] 33 34 35
    2 0 36 37 [None] 39 40 41
    1 42 43 44 45 46 47
    2 48 49 [None] 51 52 53
    3 0 54 55 [None] 57 58 59
    1 60 61 [None] 63 64 65
    2 66 67 [None] 69 70 71
    3 72 73 [None] 75 76 77
    4 78 79 [None] 81 82 83
    5 84 85 [None] 87 88 89
    4 0 90 91 [None] 93 94 95
    5 0 96 97 98 99 100 101
    6 0 102 103 [None, None] 105 106 107
    7 0 108 109 110 111 112 113
    8 0 114 115 116 117 118 119
    9 0 120 121 [None, None] 123 124 125
    ...




    Regarding the comment that you wish to use the cloud/type column for categorical data:



    Columns with categorical data must contain hashable values. Generally, it does not make sense to make mutable objects hashable. So, for instance, Python mutable builtins (such as lists), or NumPy arrays are not hashable. But Python immutable builtins (such as tuples) are hashable. Therefore, if you use



    df.at[(i, j), ("clouds", "type", None)] = tuple(v)


    then you can make the ("clouds", "type", None) column of category dtype:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = tuple(v)

    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('category')


    Notice that it is necessary to first make the column of object dtype so that it may contain Python objects such as tuples, and then convert to category dtype only after all the possible values have been assigned.





    Depending on what you want to do with the data, it might also make more sense to "tidy" the data by assigning only strings to the clouds/type column and using multiple rows instead of tuples:



    For example,



    6  0     102   103  'foo'       105        106          107
    6 0 102 103 'bar' 105 106 107


    instead of



    6  0     102   103  ('foo', 'bar')       105        106          107


    One advantage of using multiple rows is that selecting all rows with cloud/type
    'foo' is now easy:



    df.loc[df[("clouds", "type", None)] == 'foo']


    or to select all rows with foo or bar cloud/type:



    df.loc[df[("clouds", "type", None)].isin(['foo', 'bar'])]


    If you use tuples, you would have to use something like



    df.loc[[any(kind in item for kind in ('foo', 'bar')) 
    for item in df[("clouds", "type", None)]]]


    Note only is this longer and harder to read, it is also slower.



    One disadvantage of using multiple rows is that it create repeated data which may require greater memory usage. There may be ways around this, such as using multiple tables (and only joining them when required), but a discussion of this would be going way beyond the scope of this question.



    So in summary, in general, use tidy data, use multiple rows, and keep your DataFrame dtypes simple -- use integers, floats whenever possible, 'strings' if necessary. Try to avoid using tuples, lists or NumPy arrays as DataFrame values.






    share|improve this answer























    • Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
      – MaxMike
      Nov 12 at 16:47






    • 1




      There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
      – unutbu
      Nov 12 at 18:49













    up vote
    1
    down vote










    up vote
    1
    down vote









    The ("clouds", "type", None) column has integer dtype:



    In [28]: df[("clouds", "type", None)].dtype
    Out[28]: dtype('int64')


    So if you want to assign NumPy arrays to this column, first change the dtype to object:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')





    • Use df.at or df.iat to select or assign values to particular cells of a DataFrame.

    • Use df.loc or df.iloc to select or assign values to columns, rows or sub-DataFrames.




    Therefore, use df.at here:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = np.array(v)


    which yields a df that looks like



          clouds                         group                        
    ceiling layer type from_date from_hours from_minutes
    NaN NaN NaN NaN NaN NaN
    0 0 0 1 [None] 3 4 5
    1 6 7 8 9 10 11
    1 0 12 13 [None] 15 16 17
    1 18 19 [None] 21 22 23
    2 24 25 [None] 27 28 29
    3 30 31 [None] 33 34 35
    2 0 36 37 [None] 39 40 41
    1 42 43 44 45 46 47
    2 48 49 [None] 51 52 53
    3 0 54 55 [None] 57 58 59
    1 60 61 [None] 63 64 65
    2 66 67 [None] 69 70 71
    3 72 73 [None] 75 76 77
    4 78 79 [None] 81 82 83
    5 84 85 [None] 87 88 89
    4 0 90 91 [None] 93 94 95
    5 0 96 97 98 99 100 101
    6 0 102 103 [None, None] 105 106 107
    7 0 108 109 110 111 112 113
    8 0 114 115 116 117 118 119
    9 0 120 121 [None, None] 123 124 125
    ...




    Regarding the comment that you wish to use the cloud/type column for categorical data:



    Columns with categorical data must contain hashable values. Generally, it does not make sense to make mutable objects hashable. So, for instance, Python mutable builtins (such as lists), or NumPy arrays are not hashable. But Python immutable builtins (such as tuples) are hashable. Therefore, if you use



    df.at[(i, j), ("clouds", "type", None)] = tuple(v)


    then you can make the ("clouds", "type", None) column of category dtype:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = tuple(v)

    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('category')


    Notice that it is necessary to first make the column of object dtype so that it may contain Python objects such as tuples, and then convert to category dtype only after all the possible values have been assigned.





    Depending on what you want to do with the data, it might also make more sense to "tidy" the data by assigning only strings to the clouds/type column and using multiple rows instead of tuples:



    For example,



    6  0     102   103  'foo'       105        106          107
    6 0 102 103 'bar' 105 106 107


    instead of



    6  0     102   103  ('foo', 'bar')       105        106          107


    One advantage of using multiple rows is that selecting all rows with cloud/type
    'foo' is now easy:



    df.loc[df[("clouds", "type", None)] == 'foo']


    or to select all rows with foo or bar cloud/type:



    df.loc[df[("clouds", "type", None)].isin(['foo', 'bar'])]


    If you use tuples, you would have to use something like



    df.loc[[any(kind in item for kind in ('foo', 'bar')) 
    for item in df[("clouds", "type", None)]]]


    Note only is this longer and harder to read, it is also slower.



    One disadvantage of using multiple rows is that it create repeated data which may require greater memory usage. There may be ways around this, such as using multiple tables (and only joining them when required), but a discussion of this would be going way beyond the scope of this question.



    So in summary, in general, use tidy data, use multiple rows, and keep your DataFrame dtypes simple -- use integers, floats whenever possible, 'strings' if necessary. Try to avoid using tuples, lists or NumPy arrays as DataFrame values.






    share|improve this answer














    The ("clouds", "type", None) column has integer dtype:



    In [28]: df[("clouds", "type", None)].dtype
    Out[28]: dtype('int64')


    So if you want to assign NumPy arrays to this column, first change the dtype to object:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')





    • Use df.at or df.iat to select or assign values to particular cells of a DataFrame.

    • Use df.loc or df.iloc to select or assign values to columns, rows or sub-DataFrames.




    Therefore, use df.at here:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = np.array(v)


    which yields a df that looks like



          clouds                         group                        
    ceiling layer type from_date from_hours from_minutes
    NaN NaN NaN NaN NaN NaN
    0 0 0 1 [None] 3 4 5
    1 6 7 8 9 10 11
    1 0 12 13 [None] 15 16 17
    1 18 19 [None] 21 22 23
    2 24 25 [None] 27 28 29
    3 30 31 [None] 33 34 35
    2 0 36 37 [None] 39 40 41
    1 42 43 44 45 46 47
    2 48 49 [None] 51 52 53
    3 0 54 55 [None] 57 58 59
    1 60 61 [None] 63 64 65
    2 66 67 [None] 69 70 71
    3 72 73 [None] 75 76 77
    4 78 79 [None] 81 82 83
    5 84 85 [None] 87 88 89
    4 0 90 91 [None] 93 94 95
    5 0 96 97 98 99 100 101
    6 0 102 103 [None, None] 105 106 107
    7 0 108 109 110 111 112 113
    8 0 114 115 116 117 118 119
    9 0 120 121 [None, None] 123 124 125
    ...




    Regarding the comment that you wish to use the cloud/type column for categorical data:



    Columns with categorical data must contain hashable values. Generally, it does not make sense to make mutable objects hashable. So, for instance, Python mutable builtins (such as lists), or NumPy arrays are not hashable. But Python immutable builtins (such as tuples) are hashable. Therefore, if you use



    df.at[(i, j), ("clouds", "type", None)] = tuple(v)


    then you can make the ("clouds", "type", None) column of category dtype:



    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('object')
    for i, val in values.items():
    for j, v in val.items():
    df.at[(i, j), ("clouds", "type", None)] = tuple(v)

    df[("clouds", "type", None)] = df[("clouds", "type", None)].astype('category')


    Notice that it is necessary to first make the column of object dtype so that it may contain Python objects such as tuples, and then convert to category dtype only after all the possible values have been assigned.





    Depending on what you want to do with the data, it might also make more sense to "tidy" the data by assigning only strings to the clouds/type column and using multiple rows instead of tuples:



    For example,



    6  0     102   103  'foo'       105        106          107
    6 0 102 103 'bar' 105 106 107


    instead of



    6  0     102   103  ('foo', 'bar')       105        106          107


    One advantage of using multiple rows is that selecting all rows with cloud/type
    'foo' is now easy:



    df.loc[df[("clouds", "type", None)] == 'foo']


    or to select all rows with foo or bar cloud/type:



    df.loc[df[("clouds", "type", None)].isin(['foo', 'bar'])]


    If you use tuples, you would have to use something like



    df.loc[[any(kind in item for kind in ('foo', 'bar')) 
    for item in df[("clouds", "type", None)]]]


    Note only is this longer and harder to read, it is also slower.



    One disadvantage of using multiple rows is that it create repeated data which may require greater memory usage. There may be ways around this, such as using multiple tables (and only joining them when required), but a discussion of this would be going way beyond the scope of this question.



    So in summary, in general, use tidy data, use multiple rows, and keep your DataFrame dtypes simple -- use integers, floats whenever possible, 'strings' if necessary. Try to avoid using tuples, lists or NumPy arrays as DataFrame values.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 12 at 22:59

























    answered Nov 12 at 13:38









    unutbu

    539k9911541222




    539k9911541222












    • Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
      – MaxMike
      Nov 12 at 16:47






    • 1




      There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
      – unutbu
      Nov 12 at 18:49


















    • Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
      – MaxMike
      Nov 12 at 16:47






    • 1




      There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
      – unutbu
      Nov 12 at 18:49
















    Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
    – MaxMike
    Nov 12 at 16:47




    Thanks a lot. That works. The ultimate goal however (see my comment below original question) is to convert this into categorical data. The integer values were just filled in to help me finding the error. The usual defaul value is NaN. I assume I may have to find a different approach as it seems that it's not possible to use lists in columns of dtype "category".
    – MaxMike
    Nov 12 at 16:47




    1




    1




    There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
    – unutbu
    Nov 12 at 18:49




    There is a workaround which would require minimal change to your present code: Use tuples instead of NumPy arrays as values. Then you could convert the column to dtype category. (I've edited the post above with code to show how). But from a broader perspective, beware that -- depending on what you want to do with the DataFrame -- holding tuples or arrays as values inside a DataFrame is usually not a good idea. Using tidy data and multiple rows or multiple (joinable) DataFrames is often a better choice.
    – unutbu
    Nov 12 at 18:49












    up vote
    0
    down vote













    I think you should either:




    1. create one column per possible cloud layer (if order is important), or

    2. use a bitmask, e.g. a column dtype of 'u8' which has 64 bits, and you can set as many cloud types as are applicable to that row (if order doesn't matter).






    share|improve this answer

























      up vote
      0
      down vote













      I think you should either:




      1. create one column per possible cloud layer (if order is important), or

      2. use a bitmask, e.g. a column dtype of 'u8' which has 64 bits, and you can set as many cloud types as are applicable to that row (if order doesn't matter).






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        I think you should either:




        1. create one column per possible cloud layer (if order is important), or

        2. use a bitmask, e.g. a column dtype of 'u8' which has 64 bits, and you can set as many cloud types as are applicable to that row (if order doesn't matter).






        share|improve this answer












        I think you should either:




        1. create one column per possible cloud layer (if order is important), or

        2. use a bitmask, e.g. a column dtype of 'u8' which has 64 bits, and you can set as many cloud types as are applicable to that row (if order doesn't matter).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 at 7:38









        John Zwinck

        150k16175286




        150k16175286






























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            Guess what letter conforming each word