Display items in ComboBox where item's bool property equals other bool property
I have a List< SerialPort> where items have IsOpen property equals true or false. I want to display only items where IsOpen equals CheckBox.IsChecked property.
ViewModel code:
private ObservableCollection<SerialPort> _PortsCollection;
public ObservableCollection<SerialPort> PortsCollection
{
get { return _PortsCollection; }
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
private SerialPort _SelectedPort;
public SerialPort SelectedPort
{
get { return _SelectedPort; }
set { _SelectedPort = value; OnPropertyChanged("SelectedPort"); }
}
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value; OnPropertyChanged("CheckBoxChecked"); }
}
XAML:
<ComboBox
Width="100"
Height="23"
DisplayMemberPath="PortName"
ItemsSource="{Binding PortsCollection}"
SelectedItem="{Binding SelectedPort}"/>
<CheckBox
Content="Show ports where IsOpen == CheckBoxChecked"
IsChecked="{Binding CheckBoxChecked}"/>
I've tried to do that with converter but converter allows only one parameter. I don't want to separate parameters in the converter because it's ugly. Any idea how to do this without separation parameters in converter?
c# wpf combobox
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
add a comment |
I have a List< SerialPort> where items have IsOpen property equals true or false. I want to display only items where IsOpen equals CheckBox.IsChecked property.
ViewModel code:
private ObservableCollection<SerialPort> _PortsCollection;
public ObservableCollection<SerialPort> PortsCollection
{
get { return _PortsCollection; }
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
private SerialPort _SelectedPort;
public SerialPort SelectedPort
{
get { return _SelectedPort; }
set { _SelectedPort = value; OnPropertyChanged("SelectedPort"); }
}
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value; OnPropertyChanged("CheckBoxChecked"); }
}
XAML:
<ComboBox
Width="100"
Height="23"
DisplayMemberPath="PortName"
ItemsSource="{Binding PortsCollection}"
SelectedItem="{Binding SelectedPort}"/>
<CheckBox
Content="Show ports where IsOpen == CheckBoxChecked"
IsChecked="{Binding CheckBoxChecked}"/>
I've tried to do that with converter but converter allows only one parameter. I don't want to separate parameters in the converter because it's ugly. Any idea how to do this without separation parameters in converter?
c# wpf combobox
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
add a comment |
I have a List< SerialPort> where items have IsOpen property equals true or false. I want to display only items where IsOpen equals CheckBox.IsChecked property.
ViewModel code:
private ObservableCollection<SerialPort> _PortsCollection;
public ObservableCollection<SerialPort> PortsCollection
{
get { return _PortsCollection; }
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
private SerialPort _SelectedPort;
public SerialPort SelectedPort
{
get { return _SelectedPort; }
set { _SelectedPort = value; OnPropertyChanged("SelectedPort"); }
}
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value; OnPropertyChanged("CheckBoxChecked"); }
}
XAML:
<ComboBox
Width="100"
Height="23"
DisplayMemberPath="PortName"
ItemsSource="{Binding PortsCollection}"
SelectedItem="{Binding SelectedPort}"/>
<CheckBox
Content="Show ports where IsOpen == CheckBoxChecked"
IsChecked="{Binding CheckBoxChecked}"/>
I've tried to do that with converter but converter allows only one parameter. I don't want to separate parameters in the converter because it's ugly. Any idea how to do this without separation parameters in converter?
c# wpf combobox
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
I have a List< SerialPort> where items have IsOpen property equals true or false. I want to display only items where IsOpen equals CheckBox.IsChecked property.
ViewModel code:
private ObservableCollection<SerialPort> _PortsCollection;
public ObservableCollection<SerialPort> PortsCollection
{
get { return _PortsCollection; }
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
private SerialPort _SelectedPort;
public SerialPort SelectedPort
{
get { return _SelectedPort; }
set { _SelectedPort = value; OnPropertyChanged("SelectedPort"); }
}
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value; OnPropertyChanged("CheckBoxChecked"); }
}
XAML:
<ComboBox
Width="100"
Height="23"
DisplayMemberPath="PortName"
ItemsSource="{Binding PortsCollection}"
SelectedItem="{Binding SelectedPort}"/>
<CheckBox
Content="Show ports where IsOpen == CheckBoxChecked"
IsChecked="{Binding CheckBoxChecked}"/>
I've tried to do that with converter but converter allows only one parameter. I don't want to separate parameters in the converter because it's ugly. Any idea how to do this without separation parameters in converter?
c# wpf combobox
c# wpf combobox
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
asked Nov 16 '18 at 12:11
Aleksey PavlovAleksey Pavlov
468
468
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Here's how I'd do it. I'd change what the PortsCollection returns depending on the value of CheckBoxChecked,
private List<SerialPort> _AllPorts;
public ObservableCollection<SerialPort> PortsCollection
{
get
{
return new ObservableCollection<SerialPort>(_AllPorts.Where(x => x.IsOpen == CheckBoxChecked));
}
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
and tell the GUI that the PortsCollection has changed when the checkbox changes.
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value;
OnPropertyChanged("CheckBoxChecked");
OnPropertyChanged("PortsCollection");
}
}
I don't think there's a way to apply a filter in XAML
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here's how I'd do it. I'd change what the PortsCollection returns depending on the value of CheckBoxChecked,
private List<SerialPort> _AllPorts;
public ObservableCollection<SerialPort> PortsCollection
{
get
{
return new ObservableCollection<SerialPort>(_AllPorts.Where(x => x.IsOpen == CheckBoxChecked));
}
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
and tell the GUI that the PortsCollection has changed when the checkbox changes.
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value;
OnPropertyChanged("CheckBoxChecked");
OnPropertyChanged("PortsCollection");
}
}
I don't think there's a way to apply a filter in XAML
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
add a comment |
Here's how I'd do it. I'd change what the PortsCollection returns depending on the value of CheckBoxChecked,
private List<SerialPort> _AllPorts;
public ObservableCollection<SerialPort> PortsCollection
{
get
{
return new ObservableCollection<SerialPort>(_AllPorts.Where(x => x.IsOpen == CheckBoxChecked));
}
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
and tell the GUI that the PortsCollection has changed when the checkbox changes.
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value;
OnPropertyChanged("CheckBoxChecked");
OnPropertyChanged("PortsCollection");
}
}
I don't think there's a way to apply a filter in XAML
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
add a comment |
Here's how I'd do it. I'd change what the PortsCollection returns depending on the value of CheckBoxChecked,
private List<SerialPort> _AllPorts;
public ObservableCollection<SerialPort> PortsCollection
{
get
{
return new ObservableCollection<SerialPort>(_AllPorts.Where(x => x.IsOpen == CheckBoxChecked));
}
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
and tell the GUI that the PortsCollection has changed when the checkbox changes.
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value;
OnPropertyChanged("CheckBoxChecked");
OnPropertyChanged("PortsCollection");
}
}
I don't think there's a way to apply a filter in XAML
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
Here's how I'd do it. I'd change what the PortsCollection returns depending on the value of CheckBoxChecked,
private List<SerialPort> _AllPorts;
public ObservableCollection<SerialPort> PortsCollection
{
get
{
return new ObservableCollection<SerialPort>(_AllPorts.Where(x => x.IsOpen == CheckBoxChecked));
}
set { _PortsCollection = value; OnPropertyChanged("PortsCollection"); }
}
and tell the GUI that the PortsCollection has changed when the checkbox changes.
private bool _CheckBoxChecked;
public bool CheckBoxChecked
{
get { return _CheckBoxChecked; }
set { _CheckBoxChecked = value;
OnPropertyChanged("CheckBoxChecked");
OnPropertyChanged("PortsCollection");
}
}
I don't think there's a way to apply a filter in XAML
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
edited Nov 16 '18 at 12:39
Aleksey Pavlov
468
468
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
answered Nov 16 '18 at 12:28
Robin BennettRobin Bennett
1,472112
1,472112
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
add a comment |
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
1
1
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
Wow, the solution was so simple. Thanks!
– Aleksey Pavlov
Nov 16 '18 at 12:31
add a comment |
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