How to define and use a custom force using d3-force?
0
I want to define and use a custom force like centering, radial forces, for which I already have a vector field.
This is the force function I want to use:
function force(alpha) {
viewNode= nodes[0];
//console.log("hey!!!");
var thetaArray= ;
for (var i = 1, n = nodes.length, node; i < n; ++i) {
node = nodes[i];
var theta=Math.atan(node.y/node.x);
if(node.x<0)
{
theta+=Math.PI;
}
thetaArray.push({theta:theta,index:i});
}
thetaArray.sort(function(a,b){return a.theta-b.theta});
for (var i = 1, n = nodes.length, node1, node2, k = alpha * 1; i < n; ++i) {
node1 = nodes[(thetaArray[i].index)%n];
node2 = nodes[(thetaArray[i].index+1)%n];
node1.vx -= (node1.y) * k;
node1.vy += (node1.x) * k;
node2.vx += (node2.y) * k;
node2.vy -= (node2.x) * k;
}
}
javascript d3.js force-layout d3-force-directed
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
add a comment |
0
I want to define and use a custom force like centering, radial forces, for which I already have a vector field.
This is the force function I want to use:
function force(alpha) {
viewNode= nodes[0];
//console.log("hey!!!");
var thetaArray= ;
for (var i = 1, n = nodes.length, node; i < n; ++i) {
node = nodes[i];
var theta=Math.atan(node.y/node.x);
if(node.x<0)
{
theta+=Math.PI;
}
thetaArray.push({theta:theta,index:i});
}
thetaArray.sort(function(a,b){return a.theta-b.theta});
for (var i = 1, n = nodes.length, node1, node2, k = alpha * 1; i < n; ++i) {
node1 = nodes[(thetaArray[i].index)%n];
node2 = nodes[(thetaArray[i].index+1)%n];
node1.vx -= (node1.y) * k;
node1.vy += (node1.x) * k;
node2.vx += (node2.y) * k;
node2.vy -= (node2.x) * k;
}
}
javascript d3.js force-layout d3-force-directed
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
this code will crash. Have you ever looked atMath.atan2
– rioV8
Nov 15 '18 at 21:48
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
You need to make sure you have access to thenodesin your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.
– altocumulus
Nov 15 '18 at 22:22
add a comment |
0
0
0
I want to define and use a custom force like centering, radial forces, for which I already have a vector field.
This is the force function I want to use:
function force(alpha) {
viewNode= nodes[0];
//console.log("hey!!!");
var thetaArray= ;
for (var i = 1, n = nodes.length, node; i < n; ++i) {
node = nodes[i];
var theta=Math.atan(node.y/node.x);
if(node.x<0)
{
theta+=Math.PI;
}
thetaArray.push({theta:theta,index:i});
}
thetaArray.sort(function(a,b){return a.theta-b.theta});
for (var i = 1, n = nodes.length, node1, node2, k = alpha * 1; i < n; ++i) {
node1 = nodes[(thetaArray[i].index)%n];
node2 = nodes[(thetaArray[i].index+1)%n];
node1.vx -= (node1.y) * k;
node1.vy += (node1.x) * k;
node2.vx += (node2.y) * k;
node2.vy -= (node2.x) * k;
}
}
javascript d3.js force-layout d3-force-directed
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
I want to define and use a custom force like centering, radial forces, for which I already have a vector field.
This is the force function I want to use:
function force(alpha) {
viewNode= nodes[0];
//console.log("hey!!!");
var thetaArray= ;
for (var i = 1, n = nodes.length, node; i < n; ++i) {
node = nodes[i];
var theta=Math.atan(node.y/node.x);
if(node.x<0)
{
theta+=Math.PI;
}
thetaArray.push({theta:theta,index:i});
}
thetaArray.sort(function(a,b){return a.theta-b.theta});
for (var i = 1, n = nodes.length, node1, node2, k = alpha * 1; i < n; ++i) {
node1 = nodes[(thetaArray[i].index)%n];
node2 = nodes[(thetaArray[i].index+1)%n];
node1.vx -= (node1.y) * k;
node1.vy += (node1.x) * k;
node2.vx += (node2.y) * k;
node2.vy -= (node2.x) * k;
}
}
javascript d3.js force-layout d3-force-directed
javascript d3.js force-layout d3-force-directed
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
asked Nov 15 '18 at 21:37
Aaditya VazeAaditya Vaze
63
63
this code will crash. Have you ever looked atMath.atan2
– rioV8
Nov 15 '18 at 21:48
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
You need to make sure you have access to thenodesin your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.
– altocumulus
Nov 15 '18 at 22:22
add a comment |
this code will crash. Have you ever looked atMath.atan2
– rioV8
Nov 15 '18 at 21:48
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
You need to make sure you have access to thenodesin your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.
– altocumulus
Nov 15 '18 at 22:22
this code will crash. Have you ever looked at
Math.atan2– rioV8
Nov 15 '18 at 21:48
this code will crash. Have you ever looked at
Math.atan2– rioV8
Nov 15 '18 at 21:48
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
You need to make sure you have access to the
nodes in your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.– altocumulus
Nov 15 '18 at 22:22
You need to make sure you have access to the
nodes in your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.– altocumulus
Nov 15 '18 at 22:22
add a comment |
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this code will crash. Have you ever looked at
Math.atan2– rioV8
Nov 15 '18 at 21:48
You have defined a function, so what is your actual question? Are you seeing errors?
– altocumulus
Nov 15 '18 at 21:49
@rioV8 thanks for your help. I didn't know about that function.
– Aaditya Vaze
Nov 15 '18 at 21:53
@altocumulus I don't know how to use it in a simulation, and not sure if this is the correct way to define it
– Aaditya Vaze
Nov 15 '18 at 21:54
You need to make sure you have access to the
nodesin your function's scope. This can best be done by implementing force.initialize() which will get passed the array of nodes upon initialization. Have a look at a simple implementation, e.g. forceX, to see how to use a closure to save the reference to the nodes. More details are covered by the article Forcing Functions: Inside D3.v4 forces and layout transitions.– altocumulus
Nov 15 '18 at 22:22