Observing container elements using pubsub
This seems like it should be brain-dead simple but I'm not finding anything.
With pubsub I can do something like
class foo():
def __init__(self):
self.blorb = 5
def __setattr__(self, name, value):
pub.sendMessage("foo." + name)
and then anyone can do
pub.subscribe(myFunction, "foo.blorb")
to be notified whenever blorb is modified. And this single __setattr__ definition lets me subscribe to any possible member of the class just by setting a listener to the appropriate topic string.
But if blorb is a list and I want to be notified when any element is modified, or even to subscribe to an individual element of the list, is there an equivalently simple way to do that? Or do I need to do something like wrap the list with methods to access/modify elements?
python containers publish-subscribe
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
add a comment |
This seems like it should be brain-dead simple but I'm not finding anything.
With pubsub I can do something like
class foo():
def __init__(self):
self.blorb = 5
def __setattr__(self, name, value):
pub.sendMessage("foo." + name)
and then anyone can do
pub.subscribe(myFunction, "foo.blorb")
to be notified whenever blorb is modified. And this single __setattr__ definition lets me subscribe to any possible member of the class just by setting a listener to the appropriate topic string.
But if blorb is a list and I want to be notified when any element is modified, or even to subscribe to an individual element of the list, is there an equivalently simple way to do that? Or do I need to do something like wrap the list with methods to access/modify elements?
python containers publish-subscribe
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
add a comment |
This seems like it should be brain-dead simple but I'm not finding anything.
With pubsub I can do something like
class foo():
def __init__(self):
self.blorb = 5
def __setattr__(self, name, value):
pub.sendMessage("foo." + name)
and then anyone can do
pub.subscribe(myFunction, "foo.blorb")
to be notified whenever blorb is modified. And this single __setattr__ definition lets me subscribe to any possible member of the class just by setting a listener to the appropriate topic string.
But if blorb is a list and I want to be notified when any element is modified, or even to subscribe to an individual element of the list, is there an equivalently simple way to do that? Or do I need to do something like wrap the list with methods to access/modify elements?
python containers publish-subscribe
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
This seems like it should be brain-dead simple but I'm not finding anything.
With pubsub I can do something like
class foo():
def __init__(self):
self.blorb = 5
def __setattr__(self, name, value):
pub.sendMessage("foo." + name)
and then anyone can do
pub.subscribe(myFunction, "foo.blorb")
to be notified whenever blorb is modified. And this single __setattr__ definition lets me subscribe to any possible member of the class just by setting a listener to the appropriate topic string.
But if blorb is a list and I want to be notified when any element is modified, or even to subscribe to an individual element of the list, is there an equivalently simple way to do that? Or do I need to do something like wrap the list with methods to access/modify elements?
python containers publish-subscribe
python containers publish-subscribe
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
edited Nov 14 '18 at 16:39
Mark Rotteveel
59.4k1476119
59.4k1476119
asked Nov 14 '18 at 16:36
Jochen
162
asked Nov 14 '18 at 16:36
Jochen
162
asked Nov 14 '18 at 16:36
Jochen
162
162
add a comment |
add a comment |
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