Elasticsearch - Convert Json Strin to XcontentBuilder
I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.
XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
builder.copyCurrentStructure(parser);
I worked well until I updated elasticsearch 6.3+.
There is error on ES 6.3+ with same code.
Description Resource Path Location Type The method
createParser(NamedXContentRegistry, DeprecationHandler, String) in the
type JsonXContent is not applicable for the arguments
(NamedXContentRegistry, String) test.java
elasticsearch
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I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.
XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
builder.copyCurrentStructure(parser);
I worked well until I updated elasticsearch 6.3+.
There is error on ES 6.3+ with same code.
Description Resource Path Location Type The method
createParser(NamedXContentRegistry, DeprecationHandler, String) in the
type JsonXContent is not applicable for the arguments
(NamedXContentRegistry, String) test.java
elasticsearch
add a comment |
I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.
XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
builder.copyCurrentStructure(parser);
I worked well until I updated elasticsearch 6.3+.
There is error on ES 6.3+ with same code.
Description Resource Path Location Type The method
createParser(NamedXContentRegistry, DeprecationHandler, String) in the
type JsonXContent is not applicable for the arguments
(NamedXContentRegistry, String) test.java
elasticsearch
I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.
XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
builder.copyCurrentStructure(parser);
I worked well until I updated elasticsearch 6.3+.
There is error on ES 6.3+ with same code.
Description Resource Path Location Type The method
createParser(NamedXContentRegistry, DeprecationHandler, String) in the
type JsonXContent is not applicable for the arguments
(NamedXContentRegistry, String) test.java
elasticsearch
elasticsearch
asked Nov 20 '18 at 4:25
DK2DK2
185316
185316
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add a comment |
1 Answer
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The Compile Error has called out: your createParser miss a DeprecationHandler parameter.
So you should set the DeprecationHandler, for example:
JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
LoggingDeprecationHandler.INSTANCE,
jsonObj.toString());
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The Compile Error has called out: your createParser miss a DeprecationHandler parameter.
So you should set the DeprecationHandler, for example:
JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
LoggingDeprecationHandler.INSTANCE,
jsonObj.toString());
add a comment |
The Compile Error has called out: your createParser miss a DeprecationHandler parameter.
So you should set the DeprecationHandler, for example:
JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
LoggingDeprecationHandler.INSTANCE,
jsonObj.toString());
add a comment |
The Compile Error has called out: your createParser miss a DeprecationHandler parameter.
So you should set the DeprecationHandler, for example:
JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
LoggingDeprecationHandler.INSTANCE,
jsonObj.toString());
The Compile Error has called out: your createParser miss a DeprecationHandler parameter.
So you should set the DeprecationHandler, for example:
JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
LoggingDeprecationHandler.INSTANCE,
jsonObj.toString());
answered Nov 20 '18 at 5:59
chengpohichengpohi
11.8k1329
11.8k1329
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