Elasticsearch - Convert Json Strin to XcontentBuilder












0















I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.



XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
builder.copyCurrentStructure(parser);


I worked well until I updated elasticsearch 6.3+.
There is error on ES 6.3+ with same code.




Description Resource Path Location Type The method
createParser(NamedXContentRegistry, DeprecationHandler, String) in the
type JsonXContent is not applicable for the arguments
(NamedXContentRegistry, String) test.java











share|improve this question



























    0















    I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.



    XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
    XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
    builder.copyCurrentStructure(parser);


    I worked well until I updated elasticsearch 6.3+.
    There is error on ES 6.3+ with same code.




    Description Resource Path Location Type The method
    createParser(NamedXContentRegistry, DeprecationHandler, String) in the
    type JsonXContent is not applicable for the arguments
    (NamedXContentRegistry, String) test.java











    share|improve this question

























      0












      0








      0








      I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.



      XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
      XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
      builder.copyCurrentStructure(parser);


      I worked well until I updated elasticsearch 6.3+.
      There is error on ES 6.3+ with same code.




      Description Resource Path Location Type The method
      createParser(NamedXContentRegistry, DeprecationHandler, String) in the
      type JsonXContent is not applicable for the arguments
      (NamedXContentRegistry, String) test.java











      share|improve this question














      I was using elasticsearch 6.2.2. and this is how I convert json string to Xcontentbuilder.



      XContentBuilder builder = JsonXContent.contentBuilder().prettyPrint();
      XContentParser parser = JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY, jsonObj.toString());
      builder.copyCurrentStructure(parser);


      I worked well until I updated elasticsearch 6.3+.
      There is error on ES 6.3+ with same code.




      Description Resource Path Location Type The method
      createParser(NamedXContentRegistry, DeprecationHandler, String) in the
      type JsonXContent is not applicable for the arguments
      (NamedXContentRegistry, String) test.java








      elasticsearch






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      share|improve this question










      asked Nov 20 '18 at 4:25









      DK2DK2

      185316




      185316
























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          The Compile Error has called out: your createParser miss a DeprecationHandler parameter.



          So you should set the DeprecationHandler, for example:



          JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
          LoggingDeprecationHandler.INSTANCE,
          jsonObj.toString());





          share|improve this answer























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            1 Answer
            1






            active

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            active

            oldest

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            active

            oldest

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            1














            The Compile Error has called out: your createParser miss a DeprecationHandler parameter.



            So you should set the DeprecationHandler, for example:



            JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
            LoggingDeprecationHandler.INSTANCE,
            jsonObj.toString());





            share|improve this answer




























              1














              The Compile Error has called out: your createParser miss a DeprecationHandler parameter.



              So you should set the DeprecationHandler, for example:



              JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
              LoggingDeprecationHandler.INSTANCE,
              jsonObj.toString());





              share|improve this answer


























                1












                1








                1







                The Compile Error has called out: your createParser miss a DeprecationHandler parameter.



                So you should set the DeprecationHandler, for example:



                JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
                LoggingDeprecationHandler.INSTANCE,
                jsonObj.toString());





                share|improve this answer













                The Compile Error has called out: your createParser miss a DeprecationHandler parameter.



                So you should set the DeprecationHandler, for example:



                JsonXContent.jsonXContent.createParser(NamedXContentRegistry.EMPTY,
                LoggingDeprecationHandler.INSTANCE,
                jsonObj.toString());






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 20 '18 at 5:59









                chengpohichengpohi

                11.8k1329




                11.8k1329
































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