How to count all RecyclerView items in UiAutomator for not different items












0















I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?










share|improve this question



























    0















    I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?










    share|improve this question

























      0












      0








      0








      I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?










      share|improve this question














      I have to swipe to the end of the list and to count the elements, but these elements are not all different. How can I count them?







      uiautomator android-uiautomator






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 19 '18 at 21:09









      Ani DanielAni Daniel

      11




      11
























          1 Answer
          1






          active

          oldest

          votes


















          0














          You can add those elements in a list and scroll down after adding them.
          You can add all those list elements in HashSet which will ensure that no elements are counted twice.
          You can swipe down the recycler view using UiDevice object.
          I can give more detail and code about this once I get to know about your scenario in more detail.






          share|improve this answer
























          • The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

            – Ani Daniel
            Nov 29 '18 at 16:55













          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53382663%2fhow-to-count-all-recyclerview-items-in-uiautomator-for-not-different-items%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You can add those elements in a list and scroll down after adding them.
          You can add all those list elements in HashSet which will ensure that no elements are counted twice.
          You can swipe down the recycler view using UiDevice object.
          I can give more detail and code about this once I get to know about your scenario in more detail.






          share|improve this answer
























          • The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

            – Ani Daniel
            Nov 29 '18 at 16:55


















          0














          You can add those elements in a list and scroll down after adding them.
          You can add all those list elements in HashSet which will ensure that no elements are counted twice.
          You can swipe down the recycler view using UiDevice object.
          I can give more detail and code about this once I get to know about your scenario in more detail.






          share|improve this answer
























          • The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

            – Ani Daniel
            Nov 29 '18 at 16:55
















          0












          0








          0







          You can add those elements in a list and scroll down after adding them.
          You can add all those list elements in HashSet which will ensure that no elements are counted twice.
          You can swipe down the recycler view using UiDevice object.
          I can give more detail and code about this once I get to know about your scenario in more detail.






          share|improve this answer













          You can add those elements in a list and scroll down after adding them.
          You can add all those list elements in HashSet which will ensure that no elements are counted twice.
          You can swipe down the recycler view using UiDevice object.
          I can give more detail and code about this once I get to know about your scenario in more detail.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 28 '18 at 8:27









          Sushant SomaniSushant Somani

          4271218




          4271218













          • The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

            – Ani Daniel
            Nov 29 '18 at 16:55





















          • The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

            – Ani Daniel
            Nov 29 '18 at 16:55



















          The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

          – Ani Daniel
          Nov 29 '18 at 16:55







          The problem is that some elements are duplicate, so at the bottom of the list, I will definitely not have all the objects using HashSet. If I try to put them into an Array, after I scroll down, the last item from the list before scrolling will appear again in the new list after scrolling so it will be count again. One option which I have think about, is to get name & location for the last item in the list and after I swipe down, to check what's the index of that element, take the list size and subtract this index ... it's indeed a complex action

          – Ani Daniel
          Nov 29 '18 at 16:55






















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53382663%2fhow-to-count-all-recyclerview-items-in-uiautomator-for-not-different-items%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Guess what letter conforming each word

          Port of Spain

          Run scheduled task as local user group (not BUILTIN)