How to print multiple plots for each for loop iteration in R?
I have the following code,
for (i in 1:length(split_fill_data)) {
new_frame <- split_fill_data[i]
new_frame_2 <- do.call(rbind.data.frame, new_frame)
if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"])))
{
print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)
#print('hello')
plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))
#x11()
}
}
The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).
How do I make this happen in RStudio?
r plot
edited Nov 19 '18 at 21:29
M-M
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
add a comment |
I have the following code,
for (i in 1:length(split_fill_data)) {
new_frame <- split_fill_data[i]
new_frame_2 <- do.call(rbind.data.frame, new_frame)
if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"])))
{
print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)
#print('hello')
plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))
#x11()
}
}
The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).
How do I make this happen in RStudio?
r plot
edited Nov 19 '18 at 21:29
M-M
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
1
par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 '18 at 21:32
@Gregor problem with usingparis that you have to know the number of plots (not exactly, but in a sense) beforehand.
– M-M
Nov 19 '18 at 21:58
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make itmfrow = c(6, 6)for a little cushion. Otherwise useggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 '18 at 22:12
1
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so usingparwould not be very sufficient. Cheers
– M-M
Nov 19 '18 at 22:16
add a comment |
I have the following code,
for (i in 1:length(split_fill_data)) {
new_frame <- split_fill_data[i]
new_frame_2 <- do.call(rbind.data.frame, new_frame)
if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"])))
{
print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)
#print('hello')
plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))
#x11()
}
}
The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).
How do I make this happen in RStudio?
r plot
edited Nov 19 '18 at 21:29
M-M
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
I have the following code,
for (i in 1:length(split_fill_data)) {
new_frame <- split_fill_data[i]
new_frame_2 <- do.call(rbind.data.frame, new_frame)
if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"])))
{
print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)
#print('hello')
plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))
#x11()
}
}
The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).
How do I make this happen in RStudio?
r plot
r plot
edited Nov 19 '18 at 21:29
M-M
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
edited Nov 19 '18 at 21:29
M-M
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
edited Nov 19 '18 at 21:29
M-M
6,77661944
edited Nov 19 '18 at 21:29
M-M
6,77661944
edited Nov 19 '18 at 21:29
M-M
6,77661944
6,77661944
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
asked Nov 19 '18 at 21:03
SampyKIshanSampyKIshan
24
24
1
par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 '18 at 21:32
@Gregor problem with usingparis that you have to know the number of plots (not exactly, but in a sense) beforehand.
– M-M
Nov 19 '18 at 21:58
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make itmfrow = c(6, 6)for a little cushion. Otherwise useggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 '18 at 22:12
1
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so usingparwould not be very sufficient. Cheers
– M-M
Nov 19 '18 at 22:16
add a comment |
1
par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 '18 at 21:32
@Gregor problem with usingparis that you have to know the number of plots (not exactly, but in a sense) beforehand.
– M-M
Nov 19 '18 at 21:58
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make itmfrow = c(6, 6)for a little cushion. Otherwise useggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 '18 at 22:12
1
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so usingparwould not be very sufficient. Cheers
– M-M
Nov 19 '18 at 22:16
1
1
par(mfrow = c(5, 6))? Or any other way of doing multiple plots...– Gregor
Nov 19 '18 at 21:32
par(mfrow = c(5, 6))? Or any other way of doing multiple plots...– Gregor
Nov 19 '18 at 21:32
@Gregor problem with using
par is that you have to know the number of plots (not exactly, but in a sense) beforehand.– M-M
Nov 19 '18 at 21:58
@Gregor problem with using
par is that you have to know the number of plots (not exactly, but in a sense) beforehand.– M-M
Nov 19 '18 at 21:58
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it
mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).– Gregor
Nov 19 '18 at 22:12
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it
mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).– Gregor
Nov 19 '18 at 22:12
1
1
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using
par would not be very sufficient. Cheers– M-M
Nov 19 '18 at 22:16
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using
par would not be very sufficient. Cheers– M-M
Nov 19 '18 at 22:16
add a comment |
1 Answer
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oldest
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A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
add a comment |
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A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
add a comment |
A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
add a comment |
A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
answered Nov 19 '18 at 22:13
André.BAndré.B
1519
1519
add a comment |
add a comment |
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par(mfrow = c(5, 6))? Or any other way of doing multiple plots...– Gregor
Nov 19 '18 at 21:32
@Gregor problem with using
paris that you have to know the number of plots (not exactly, but in a sense) beforehand.– M-M
Nov 19 '18 at 21:58
stackoverflow.com/questions/10706753/…
– M-M
Nov 19 '18 at 22:11
@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it
mfrow = c(6, 6)for a little cushion. Otherwise useggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).– Gregor
Nov 19 '18 at 22:12
1
@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using
parwould not be very sufficient. Cheers– M-M
Nov 19 '18 at 22:16