How to effectively transfer a price value between forms from one page to another












0















Basically what I have is 4 pages in this order




  1. form1.php

  2. form2.php

  3. form3.php

  4. form4.php


Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form



What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page



And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue



The html of the first page with the jquery calculating the price






var basePrice = 0;

$(".calculate").change(function() {
newPrice = basePrice;

$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});

$('#item-price').html(newPrice);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >

<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>

</div>

<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>

</select>

</div>

<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>

<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>

</form>





the consecutive pages have similar forms



so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text



What is the best method to implement this with, and how can i properly do it?










share|improve this question



























    0















    Basically what I have is 4 pages in this order




    1. form1.php

    2. form2.php

    3. form3.php

    4. form4.php


    Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form



    What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page



    And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue



    The html of the first page with the jquery calculating the price






    var basePrice = 0;

    $(".calculate").change(function() {
    newPrice = basePrice;

    $('.calculate option:selected').each(function() {
    newPrice += $(this).data('price')
    });

    $('#item-price').html(newPrice);
    });

    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <form id="myForm" role="form" method="POST" action="form2.php" >

    <div class="form-group col-md-12">
    <select class="calculate diff " id="service" name="serv" required>
    <option data-price="0" value="0">Choose A Service </option>
    <option data-price="0" value="1">Airport Shuttle</option>
    </select>

    </div>

    <div class="form-group col-md-12">
    <select class="calculate diff" id="airport" name="arpt" required>
    <option data-price="0" value="0">Pick an Airport </option>
    <option data-price="6000" value="1">MM1</option>
    <option data-price="5900" value="2">MM2</option>

    </select>

    </div>

    <div class="col-md-12 row" style="margin-top:-20px">
    <h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
    </div>

    <div class="col-md-6" >
    <a href="form2.php">
    <button style="float:right;" type="submit" class="button2">
    <span><span>NEXT</span></span></button></a>
    </div>

    </form>





    the consecutive pages have similar forms



    so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text



    What is the best method to implement this with, and how can i properly do it?










    share|improve this question

























      0












      0








      0








      Basically what I have is 4 pages in this order




      1. form1.php

      2. form2.php

      3. form3.php

      4. form4.php


      Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form



      What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page



      And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue



      The html of the first page with the jquery calculating the price






      var basePrice = 0;

      $(".calculate").change(function() {
      newPrice = basePrice;

      $('.calculate option:selected').each(function() {
      newPrice += $(this).data('price')
      });

      $('#item-price').html(newPrice);
      });

      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
      <form id="myForm" role="form" method="POST" action="form2.php" >

      <div class="form-group col-md-12">
      <select class="calculate diff " id="service" name="serv" required>
      <option data-price="0" value="0">Choose A Service </option>
      <option data-price="0" value="1">Airport Shuttle</option>
      </select>

      </div>

      <div class="form-group col-md-12">
      <select class="calculate diff" id="airport" name="arpt" required>
      <option data-price="0" value="0">Pick an Airport </option>
      <option data-price="6000" value="1">MM1</option>
      <option data-price="5900" value="2">MM2</option>

      </select>

      </div>

      <div class="col-md-12 row" style="margin-top:-20px">
      <h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
      </div>

      <div class="col-md-6" >
      <a href="form2.php">
      <button style="float:right;" type="submit" class="button2">
      <span><span>NEXT</span></span></button></a>
      </div>

      </form>





      the consecutive pages have similar forms



      so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text



      What is the best method to implement this with, and how can i properly do it?










      share|improve this question














      Basically what I have is 4 pages in this order




      1. form1.php

      2. form2.php

      3. form3.php

      4. form4.php


      Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form



      What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page



      And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue



      The html of the first page with the jquery calculating the price






      var basePrice = 0;

      $(".calculate").change(function() {
      newPrice = basePrice;

      $('.calculate option:selected').each(function() {
      newPrice += $(this).data('price')
      });

      $('#item-price').html(newPrice);
      });

      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
      <form id="myForm" role="form" method="POST" action="form2.php" >

      <div class="form-group col-md-12">
      <select class="calculate diff " id="service" name="serv" required>
      <option data-price="0" value="0">Choose A Service </option>
      <option data-price="0" value="1">Airport Shuttle</option>
      </select>

      </div>

      <div class="form-group col-md-12">
      <select class="calculate diff" id="airport" name="arpt" required>
      <option data-price="0" value="0">Pick an Airport </option>
      <option data-price="6000" value="1">MM1</option>
      <option data-price="5900" value="2">MM2</option>

      </select>

      </div>

      <div class="col-md-12 row" style="margin-top:-20px">
      <h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
      </div>

      <div class="col-md-6" >
      <a href="form2.php">
      <button style="float:right;" type="submit" class="button2">
      <span><span>NEXT</span></span></button></a>
      </div>

      </form>





      the consecutive pages have similar forms



      so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text



      What is the best method to implement this with, and how can i properly do it?






      var basePrice = 0;

      $(".calculate").change(function() {
      newPrice = basePrice;

      $('.calculate option:selected').each(function() {
      newPrice += $(this).data('price')
      });

      $('#item-price').html(newPrice);
      });

      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
      <form id="myForm" role="form" method="POST" action="form2.php" >

      <div class="form-group col-md-12">
      <select class="calculate diff " id="service" name="serv" required>
      <option data-price="0" value="0">Choose A Service </option>
      <option data-price="0" value="1">Airport Shuttle</option>
      </select>

      </div>

      <div class="form-group col-md-12">
      <select class="calculate diff" id="airport" name="arpt" required>
      <option data-price="0" value="0">Pick an Airport </option>
      <option data-price="6000" value="1">MM1</option>
      <option data-price="5900" value="2">MM2</option>

      </select>

      </div>

      <div class="col-md-12 row" style="margin-top:-20px">
      <h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
      </div>

      <div class="col-md-6" >
      <a href="form2.php">
      <button style="float:right;" type="submit" class="button2">
      <span><span>NEXT</span></span></button></a>
      </div>

      </form>





      var basePrice = 0;

      $(".calculate").change(function() {
      newPrice = basePrice;

      $('.calculate option:selected').each(function() {
      newPrice += $(this).data('price')
      });

      $('#item-price').html(newPrice);
      });

      <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
      <form id="myForm" role="form" method="POST" action="form2.php" >

      <div class="form-group col-md-12">
      <select class="calculate diff " id="service" name="serv" required>
      <option data-price="0" value="0">Choose A Service </option>
      <option data-price="0" value="1">Airport Shuttle</option>
      </select>

      </div>

      <div class="form-group col-md-12">
      <select class="calculate diff" id="airport" name="arpt" required>
      <option data-price="0" value="0">Pick an Airport </option>
      <option data-price="6000" value="1">MM1</option>
      <option data-price="5900" value="2">MM2</option>

      </select>

      </div>

      <div class="col-md-12 row" style="margin-top:-20px">
      <h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
      </div>

      <div class="col-md-6" >
      <a href="form2.php">
      <button style="float:right;" type="submit" class="button2">
      <span><span>NEXT</span></span></button></a>
      </div>

      </form>






      php html forms






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 19 '18 at 19:03









      Dr whoDr who

      326




      326
























          1 Answer
          1






          active

          oldest

          votes


















          2














          You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.



          This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.



          JavaScript



          (function ($) {
          $('form').submit(function() {
          $.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
          return true;
          });
          });
          })(jQuery);


          PHP Controller



          session_start();
          $_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+

          # Pointed out by @FunkFortyNiner
          $_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+


          Form 2/3/4



          <?php session_start(); ?>
          <h1>£<?= $_SESSION['price']; ?></h1>


          If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.






          share|improve this answer


























          • Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

            – Funk Forty Niner
            Nov 19 '18 at 19:43






          • 1





            @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

            – Jaquarh
            Nov 19 '18 at 19:45











          • @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

            – Dr who
            Nov 19 '18 at 23:42











          • var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

            – Jaquarh
            Nov 20 '18 at 9:43













          • no its not getting the correct value @Jaquarh

            – Dr who
            Nov 20 '18 at 17:14











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381059%2fhow-to-effectively-transfer-a-price-value-between-forms-from-one-page-to-another%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.



          This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.



          JavaScript



          (function ($) {
          $('form').submit(function() {
          $.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
          return true;
          });
          });
          })(jQuery);


          PHP Controller



          session_start();
          $_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+

          # Pointed out by @FunkFortyNiner
          $_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+


          Form 2/3/4



          <?php session_start(); ?>
          <h1>£<?= $_SESSION['price']; ?></h1>


          If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.






          share|improve this answer


























          • Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

            – Funk Forty Niner
            Nov 19 '18 at 19:43






          • 1





            @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

            – Jaquarh
            Nov 19 '18 at 19:45











          • @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

            – Dr who
            Nov 19 '18 at 23:42











          • var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

            – Jaquarh
            Nov 20 '18 at 9:43













          • no its not getting the correct value @Jaquarh

            – Dr who
            Nov 20 '18 at 17:14
















          2














          You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.



          This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.



          JavaScript



          (function ($) {
          $('form').submit(function() {
          $.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
          return true;
          });
          });
          })(jQuery);


          PHP Controller



          session_start();
          $_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+

          # Pointed out by @FunkFortyNiner
          $_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+


          Form 2/3/4



          <?php session_start(); ?>
          <h1>£<?= $_SESSION['price']; ?></h1>


          If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.






          share|improve this answer


























          • Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

            – Funk Forty Niner
            Nov 19 '18 at 19:43






          • 1





            @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

            – Jaquarh
            Nov 19 '18 at 19:45











          • @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

            – Dr who
            Nov 19 '18 at 23:42











          • var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

            – Jaquarh
            Nov 20 '18 at 9:43













          • no its not getting the correct value @Jaquarh

            – Dr who
            Nov 20 '18 at 17:14














          2












          2








          2







          You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.



          This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.



          JavaScript



          (function ($) {
          $('form').submit(function() {
          $.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
          return true;
          });
          });
          })(jQuery);


          PHP Controller



          session_start();
          $_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+

          # Pointed out by @FunkFortyNiner
          $_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+


          Form 2/3/4



          <?php session_start(); ?>
          <h1>£<?= $_SESSION['price']; ?></h1>


          If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.






          share|improve this answer















          You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.



          This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.



          JavaScript



          (function ($) {
          $('form').submit(function() {
          $.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
          return true;
          });
          });
          })(jQuery);


          PHP Controller



          session_start();
          $_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+

          # Pointed out by @FunkFortyNiner
          $_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+


          Form 2/3/4



          <?php session_start(); ?>
          <h1>£<?= $_SESSION['price']; ?></h1>


          If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 19 '18 at 19:48

























          answered Nov 19 '18 at 19:35









          JaquarhJaquarh

          3,4191135




          3,4191135













          • Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

            – Funk Forty Niner
            Nov 19 '18 at 19:43






          • 1





            @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

            – Jaquarh
            Nov 19 '18 at 19:45











          • @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

            – Dr who
            Nov 19 '18 at 23:42











          • var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

            – Jaquarh
            Nov 20 '18 at 9:43













          • no its not getting the correct value @Jaquarh

            – Dr who
            Nov 20 '18 at 17:14



















          • Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

            – Funk Forty Niner
            Nov 19 '18 at 19:43






          • 1





            @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

            – Jaquarh
            Nov 19 '18 at 19:45











          • @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

            – Dr who
            Nov 19 '18 at 23:42











          • var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

            – Jaquarh
            Nov 20 '18 at 9:43













          • no its not getting the correct value @Jaquarh

            – Dr who
            Nov 20 '18 at 17:14

















          Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

          – Funk Forty Niner
          Nov 19 '18 at 19:43





          Note that the ?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php

          – Funk Forty Niner
          Nov 19 '18 at 19:43




          1




          1





          @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

          – Jaquarh
          Nov 19 '18 at 19:45





          @FunkFortyNiner well noted, isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.

          – Jaquarh
          Nov 19 '18 at 19:45













          @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

          – Dr who
          Nov 19 '18 at 23:42





          @Jaquarh @FunkFortyNiner <h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1

          – Dr who
          Nov 19 '18 at 23:42













          var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

          – Jaquarh
          Nov 20 '18 at 9:43







          var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho

          – Jaquarh
          Nov 20 '18 at 9:43















          no its not getting the correct value @Jaquarh

          – Dr who
          Nov 20 '18 at 17:14





          no its not getting the correct value @Jaquarh

          – Dr who
          Nov 20 '18 at 17:14




















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381059%2fhow-to-effectively-transfer-a-price-value-between-forms-from-one-page-to-another%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          How to pass form data using jquery Ajax to insert data in database?

          National Museum of Racing and Hall of Fame

          Guess what letter conforming each word