How to effectively transfer a price value between forms from one page to another
Basically what I have is 4 pages in this order
- form1.php
- form2.php
- form3.php
- form4.php
Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form
What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page
And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue
The html of the first page with the jquery calculating the price
var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>the consecutive pages have similar forms
so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text
What is the best method to implement this with, and how can i properly do it?
php html forms
add a comment |
Basically what I have is 4 pages in this order
- form1.php
- form2.php
- form3.php
- form4.php
Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form
What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page
And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue
The html of the first page with the jquery calculating the price
var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>the consecutive pages have similar forms
so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text
What is the best method to implement this with, and how can i properly do it?
php html forms
add a comment |
Basically what I have is 4 pages in this order
- form1.php
- form2.php
- form3.php
- form4.php
Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form
What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page
And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue
The html of the first page with the jquery calculating the price
var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>the consecutive pages have similar forms
so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text
What is the best method to implement this with, and how can i properly do it?
php html forms
Basically what I have is 4 pages in this order
- form1.php
- form2.php
- form3.php
- form4.php
Each page contains a form with an Html select option, and at the bottom of every form, is a text view which displays a price, the price changes based on what options you select, then a Next Button that takes you to the next page is also located at the bottom of the form
What I am trying to achieve here is once i click the next button, the current price being displayed in the text field gets transferred to the next form as the base price, until the user gets to the final Page
And yes i have read about cookies and sessions, as well as POST and GET Methods, but i can't figure out how to implement it and also don't know which method would be better to handle such issue
The html of the first page with the jquery calculating the price
var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>the consecutive pages have similar forms
so if MM1 was selected in page one and next button was clicked, 6000 should automatically be in the page 2 price text
What is the best method to implement this with, and how can i properly do it?
var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>var basePrice = 0;
$(".calculate").change(function() {
newPrice = basePrice;
$('.calculate option:selected').each(function() {
newPrice += $(this).data('price')
});
$('#item-price').html(newPrice);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm" role="form" method="POST" action="form2.php" >
<div class="form-group col-md-12">
<select class="calculate diff " id="service" name="serv" required>
<option data-price="0" value="0">Choose A Service </option>
<option data-price="0" value="1">Airport Shuttle</option>
</select>
</div>
<div class="form-group col-md-12">
<select class="calculate diff" id="airport" name="arpt" required>
<option data-price="0" value="0">Pick an Airport </option>
<option data-price="6000" value="1">MM1</option>
<option data-price="5900" value="2">MM2</option>
</select>
</div>
<div class="col-md-12 row" style="margin-top:-20px">
<h4 class="price">Price Estimate: ₦<span id="item-price" name="price" >0</span></h4>
</div>
<div class="col-md-6" >
<a href="form2.php">
<button style="float:right;" type="submit" class="button2">
<span><span>NEXT</span></span></button></a>
</div>
</form>php html forms
php html forms
asked Nov 19 '18 at 19:03
Dr whoDr who
326
326
add a comment |
add a comment |
1 Answer
1
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oldest
votes
You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.
This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.
JavaScript
(function ($) {
$('form').submit(function() {
$.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
return true;
});
});
})(jQuery);
PHP Controller
session_start();
$_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+
# Pointed out by @FunkFortyNiner
$_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+
Form 2/3/4
<?php session_start(); ?>
<h1>£<?= $_SESSION['price']; ?></h1>
If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.
Note that the??null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php
– Funk Forty Niner
Nov 19 '18 at 19:43
1
@FunkFortyNiner well noted,isset($_POST['price']) ? $_POST['price'] : 0can be used instead.
– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner<h1>£<?= $_SESSION['price']; ?></h1>passes '0' in form2 instead of the price value from form1
– Dr who
Nov 19 '18 at 23:42
var_dump($_POST)and see if it contains the correct value, if not,console.log($('#item-price').html())and see if it is getting the correct value @Drwho
– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
|
show 9 more comments
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.
This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.
JavaScript
(function ($) {
$('form').submit(function() {
$.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
return true;
});
});
})(jQuery);
PHP Controller
session_start();
$_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+
# Pointed out by @FunkFortyNiner
$_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+
Form 2/3/4
<?php session_start(); ?>
<h1>£<?= $_SESSION['price']; ?></h1>
If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.
Note that the??null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php
– Funk Forty Niner
Nov 19 '18 at 19:43
1
@FunkFortyNiner well noted,isset($_POST['price']) ? $_POST['price'] : 0can be used instead.
– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner<h1>£<?= $_SESSION['price']; ?></h1>passes '0' in form2 instead of the price value from form1
– Dr who
Nov 19 '18 at 23:42
var_dump($_POST)and see if it contains the correct value, if not,console.log($('#item-price').html())and see if it is getting the correct value @Drwho
– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
|
show 9 more comments
You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.
This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.
JavaScript
(function ($) {
$('form').submit(function() {
$.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
return true;
});
});
})(jQuery);
PHP Controller
session_start();
$_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+
# Pointed out by @FunkFortyNiner
$_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+
Form 2/3/4
<?php session_start(); ?>
<h1>£<?= $_SESSION['price']; ?></h1>
If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.
Note that the??null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php
– Funk Forty Niner
Nov 19 '18 at 19:43
1
@FunkFortyNiner well noted,isset($_POST['price']) ? $_POST['price'] : 0can be used instead.
– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner<h1>£<?= $_SESSION['price']; ?></h1>passes '0' in form2 instead of the price value from form1
– Dr who
Nov 19 '18 at 23:42
var_dump($_POST)and see if it contains the correct value, if not,console.log($('#item-price').html())and see if it is getting the correct value @Drwho
– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
|
show 9 more comments
You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.
This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.
JavaScript
(function ($) {
$('form').submit(function() {
$.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
return true;
});
});
})(jQuery);
PHP Controller
session_start();
$_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+
# Pointed out by @FunkFortyNiner
$_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+
Form 2/3/4
<?php session_start(); ?>
<h1>£<?= $_SESSION['price']; ?></h1>
If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.
You could store the data in a local session by sending it to a controller before loading the second form, this would mean using a submit listener on your form and then firing up an AJAX request to some sort of controller. You could then access the data on form 2.
This would only work if the next button was of type submit, other-wise, perhaps use .click(function() {}); instead.
JavaScript
(function ($) {
$('form').submit(function() {
$.post('/some/form/controller', { price: $('#item-price').html() }, function(response) {
return true;
});
});
})(jQuery);
PHP Controller
session_start();
$_SESSION['price'] = $_POST['price'] ?? 0; # PHP 7+
# Pointed out by @FunkFortyNiner
$_SESSION['price'] = isset($_POST['price']) ? $_POST['price'] : 0; #PHP 5.6+
Form 2/3/4
<?php session_start(); ?>
<h1>£<?= $_SESSION['price']; ?></h1>
If this method is too prolonging, perhaps consider making the price a disabled input field when calculating or a hidden input field and just POST all the data to the next form which can be accessed via $_POST and the input name=".." as the index.
edited Nov 19 '18 at 19:48
answered Nov 19 '18 at 19:35
JaquarhJaquarh
3,4191135
3,4191135
Note that the??null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php
– Funk Forty Niner
Nov 19 '18 at 19:43
1
@FunkFortyNiner well noted,isset($_POST['price']) ? $_POST['price'] : 0can be used instead.
– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner<h1>£<?= $_SESSION['price']; ?></h1>passes '0' in form2 instead of the price value from form1
– Dr who
Nov 19 '18 at 23:42
var_dump($_POST)and see if it contains the correct value, if not,console.log($('#item-price').html())and see if it is getting the correct value @Drwho
– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
|
show 9 more comments
Note that the??null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php
– Funk Forty Niner
Nov 19 '18 at 19:43
1
@FunkFortyNiner well noted,isset($_POST['price']) ? $_POST['price'] : 0can be used instead.
– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner<h1>£<?= $_SESSION['price']; ?></h1>passes '0' in form2 instead of the price value from form1
– Dr who
Nov 19 '18 at 23:42
var_dump($_POST)and see if it contains the correct value, if not,console.log($('#item-price').html())and see if it is getting the correct value @Drwho
– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
Note that the
?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php– Funk Forty Niner
Nov 19 '18 at 19:43
Note that the
?? null coalescing operator is only available in PHP 7+ php.net/manual/en/language.operators.comparison.php– Funk Forty Niner
Nov 19 '18 at 19:43
1
1
@FunkFortyNiner well noted,
isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.– Jaquarh
Nov 19 '18 at 19:45
@FunkFortyNiner well noted,
isset($_POST['price']) ? $_POST['price'] : 0 can be used instead.– Jaquarh
Nov 19 '18 at 19:45
@Jaquarh @FunkFortyNiner
<h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1– Dr who
Nov 19 '18 at 23:42
@Jaquarh @FunkFortyNiner
<h1>£<?= $_SESSION['price']; ?></h1> passes '0' in form2 instead of the price value from form1– Dr who
Nov 19 '18 at 23:42
var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho– Jaquarh
Nov 20 '18 at 9:43
var_dump($_POST) and see if it contains the correct value, if not, console.log($('#item-price').html()) and see if it is getting the correct value @Drwho– Jaquarh
Nov 20 '18 at 9:43
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
no its not getting the correct value @Jaquarh
– Dr who
Nov 20 '18 at 17:14
|
show 9 more comments
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