pandas issue with pandas.NaT when changing from pandas._libs.tslib.NaTType
Since pandas 0.23.4, pandas._libs.tslib.NaTType is completely deprecated, so I have to use pandas.NaT as indicated in 0.23.2 changelog,
The type import pandas.tslib.NaTType is deprecated and can be replaced by using type(pandas.NaT)
But when I tried the following code,
from pandas import NaT
val_type = type(val)
if issubclass(val_type, NaT):
return 'NaT'
I got an error,
TypeError: issubclass() arg 2 must be a class or tuple of classes
If I try,
if isinstance(val_type, NaT):
return 'NaT'
I got the following error,
TypeError: isinstance() arg 2 must be a type or tuple of types
python python-3.x pandas
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
add a comment |
Since pandas 0.23.4, pandas._libs.tslib.NaTType is completely deprecated, so I have to use pandas.NaT as indicated in 0.23.2 changelog,
The type import pandas.tslib.NaTType is deprecated and can be replaced by using type(pandas.NaT)
But when I tried the following code,
from pandas import NaT
val_type = type(val)
if issubclass(val_type, NaT):
return 'NaT'
I got an error,
TypeError: issubclass() arg 2 must be a class or tuple of classes
If I try,
if isinstance(val_type, NaT):
return 'NaT'
I got the following error,
TypeError: isinstance() arg 2 must be a type or tuple of types
python python-3.x pandas
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
add a comment |
Since pandas 0.23.4, pandas._libs.tslib.NaTType is completely deprecated, so I have to use pandas.NaT as indicated in 0.23.2 changelog,
The type import pandas.tslib.NaTType is deprecated and can be replaced by using type(pandas.NaT)
But when I tried the following code,
from pandas import NaT
val_type = type(val)
if issubclass(val_type, NaT):
return 'NaT'
I got an error,
TypeError: issubclass() arg 2 must be a class or tuple of classes
If I try,
if isinstance(val_type, NaT):
return 'NaT'
I got the following error,
TypeError: isinstance() arg 2 must be a type or tuple of types
python python-3.x pandas
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
Since pandas 0.23.4, pandas._libs.tslib.NaTType is completely deprecated, so I have to use pandas.NaT as indicated in 0.23.2 changelog,
The type import pandas.tslib.NaTType is deprecated and can be replaced by using type(pandas.NaT)
But when I tried the following code,
from pandas import NaT
val_type = type(val)
if issubclass(val_type, NaT):
return 'NaT'
I got an error,
TypeError: issubclass() arg 2 must be a class or tuple of classes
If I try,
if isinstance(val_type, NaT):
return 'NaT'
I got the following error,
TypeError: isinstance() arg 2 must be a type or tuple of types
python python-3.x pandas
python python-3.x pandas
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
asked Nov 20 '18 at 18:17
daiyuedaiyue
2,472103967
2,472103967
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Well, as the deprecation message suggested, you should use type(pandas.NaT), not NaT directly. So if you imported the name, you can do issubclass(val_type, type(pandas.NaT)).
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
add a comment |
To expound a bit on other answers:
pandas._libs.tslibs.nattype.NaTType is a class, defined here.
class NaTType(_NaT):
"""(N)ot-(A)-(T)ime, the time equivalent of NaN"""
pandas.NaT (brought into the top-level namespace) is an instance of the class above, defined here:
NaT = NaTType()
With the reason being
This is a pseudo-native sentinel value that can be represented by NumPy in a singular dtype (datetime64[ns]).
issubclass() requires you to pass an actual class, not the class instance, and using type(pd.NaT) will do that for you without directly accessing any "nonpublic" API.
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
add a comment |
You need to give isinstance() the actual type you are looking for. In this case, I would do type(df.loc[knownnatdata) and use that as input for the method. For example, I filled a dataframe column with pd.NaT
df = pd.DataFrame([[1,1],[3,4],[3,4]], columns=["a", 'b'])
df['c'],df['d']=np.nan, pd.NaT
a b c d
0 1 1 NaN NaT
1 3 4 NaN NaT
2 3 4 NaN NaT
Then type(df['d'].iloc[0]) gives me pandas._libs.tslibs.nattype.NaTType (which is still the type in my version, but note that it is still not JUST NaT)
to which I compare
isinstance(df['d'].iloc[0],pd._libs.tslibs.nattype.NaTType)
True
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53399137%2fpandas-issue-with-pandas-nat-when-changing-from-pandas-libs-tslib-nattype%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Well, as the deprecation message suggested, you should use type(pandas.NaT), not NaT directly. So if you imported the name, you can do issubclass(val_type, type(pandas.NaT)).
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
add a comment |
Well, as the deprecation message suggested, you should use type(pandas.NaT), not NaT directly. So if you imported the name, you can do issubclass(val_type, type(pandas.NaT)).
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
add a comment |
Well, as the deprecation message suggested, you should use type(pandas.NaT), not NaT directly. So if you imported the name, you can do issubclass(val_type, type(pandas.NaT)).
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
Well, as the deprecation message suggested, you should use type(pandas.NaT), not NaT directly. So if you imported the name, you can do issubclass(val_type, type(pandas.NaT)).
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
answered Nov 20 '18 at 18:26
zsomkozsomko
4966
4966
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
add a comment |
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
This is much more elegant than mine
– G. Anderson
Nov 20 '18 at 18:30
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
@BradSolomon - please check this. You can see how to use it, so you will have to input types, not their instances.
– zsomko
Nov 20 '18 at 18:35
add a comment |
To expound a bit on other answers:
pandas._libs.tslibs.nattype.NaTType is a class, defined here.
class NaTType(_NaT):
"""(N)ot-(A)-(T)ime, the time equivalent of NaN"""
pandas.NaT (brought into the top-level namespace) is an instance of the class above, defined here:
NaT = NaTType()
With the reason being
This is a pseudo-native sentinel value that can be represented by NumPy in a singular dtype (datetime64[ns]).
issubclass() requires you to pass an actual class, not the class instance, and using type(pd.NaT) will do that for you without directly accessing any "nonpublic" API.
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
add a comment |
To expound a bit on other answers:
pandas._libs.tslibs.nattype.NaTType is a class, defined here.
class NaTType(_NaT):
"""(N)ot-(A)-(T)ime, the time equivalent of NaN"""
pandas.NaT (brought into the top-level namespace) is an instance of the class above, defined here:
NaT = NaTType()
With the reason being
This is a pseudo-native sentinel value that can be represented by NumPy in a singular dtype (datetime64[ns]).
issubclass() requires you to pass an actual class, not the class instance, and using type(pd.NaT) will do that for you without directly accessing any "nonpublic" API.
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
add a comment |
To expound a bit on other answers:
pandas._libs.tslibs.nattype.NaTType is a class, defined here.
class NaTType(_NaT):
"""(N)ot-(A)-(T)ime, the time equivalent of NaN"""
pandas.NaT (brought into the top-level namespace) is an instance of the class above, defined here:
NaT = NaTType()
With the reason being
This is a pseudo-native sentinel value that can be represented by NumPy in a singular dtype (datetime64[ns]).
issubclass() requires you to pass an actual class, not the class instance, and using type(pd.NaT) will do that for you without directly accessing any "nonpublic" API.
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
To expound a bit on other answers:
pandas._libs.tslibs.nattype.NaTType is a class, defined here.
class NaTType(_NaT):
"""(N)ot-(A)-(T)ime, the time equivalent of NaN"""
pandas.NaT (brought into the top-level namespace) is an instance of the class above, defined here:
NaT = NaTType()
With the reason being
This is a pseudo-native sentinel value that can be represented by NumPy in a singular dtype (datetime64[ns]).
issubclass() requires you to pass an actual class, not the class instance, and using type(pd.NaT) will do that for you without directly accessing any "nonpublic" API.
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
answered Nov 20 '18 at 18:33
Brad SolomonBrad Solomon
13.9k83689
13.9k83689
add a comment |
add a comment |
You need to give isinstance() the actual type you are looking for. In this case, I would do type(df.loc[knownnatdata) and use that as input for the method. For example, I filled a dataframe column with pd.NaT
df = pd.DataFrame([[1,1],[3,4],[3,4]], columns=["a", 'b'])
df['c'],df['d']=np.nan, pd.NaT
a b c d
0 1 1 NaN NaT
1 3 4 NaN NaT
2 3 4 NaN NaT
Then type(df['d'].iloc[0]) gives me pandas._libs.tslibs.nattype.NaTType (which is still the type in my version, but note that it is still not JUST NaT)
to which I compare
isinstance(df['d'].iloc[0],pd._libs.tslibs.nattype.NaTType)
True
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
add a comment |
You need to give isinstance() the actual type you are looking for. In this case, I would do type(df.loc[knownnatdata) and use that as input for the method. For example, I filled a dataframe column with pd.NaT
df = pd.DataFrame([[1,1],[3,4],[3,4]], columns=["a", 'b'])
df['c'],df['d']=np.nan, pd.NaT
a b c d
0 1 1 NaN NaT
1 3 4 NaN NaT
2 3 4 NaN NaT
Then type(df['d'].iloc[0]) gives me pandas._libs.tslibs.nattype.NaTType (which is still the type in my version, but note that it is still not JUST NaT)
to which I compare
isinstance(df['d'].iloc[0],pd._libs.tslibs.nattype.NaTType)
True
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
add a comment |
You need to give isinstance() the actual type you are looking for. In this case, I would do type(df.loc[knownnatdata) and use that as input for the method. For example, I filled a dataframe column with pd.NaT
df = pd.DataFrame([[1,1],[3,4],[3,4]], columns=["a", 'b'])
df['c'],df['d']=np.nan, pd.NaT
a b c d
0 1 1 NaN NaT
1 3 4 NaN NaT
2 3 4 NaN NaT
Then type(df['d'].iloc[0]) gives me pandas._libs.tslibs.nattype.NaTType (which is still the type in my version, but note that it is still not JUST NaT)
to which I compare
isinstance(df['d'].iloc[0],pd._libs.tslibs.nattype.NaTType)
True
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
You need to give isinstance() the actual type you are looking for. In this case, I would do type(df.loc[knownnatdata) and use that as input for the method. For example, I filled a dataframe column with pd.NaT
df = pd.DataFrame([[1,1],[3,4],[3,4]], columns=["a", 'b'])
df['c'],df['d']=np.nan, pd.NaT
a b c d
0 1 1 NaN NaT
1 3 4 NaN NaT
2 3 4 NaN NaT
Then type(df['d'].iloc[0]) gives me pandas._libs.tslibs.nattype.NaTType (which is still the type in my version, but note that it is still not JUST NaT)
to which I compare
isinstance(df['d'].iloc[0],pd._libs.tslibs.nattype.NaTType)
True
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
answered Nov 20 '18 at 18:29
G. AndersonG. Anderson
1,631210
1,631210
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53399137%2fpandas-issue-with-pandas-nat-when-changing-from-pandas-libs-tslib-nattype%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
