Put Excel row cells under each other in one column with its serial number repeating
Is there any possibility of formula, to put cells of one row below each other in a column with its serial number repeating in first column of that particular row
For example:
Check this image:
This need to change into below image
Required End Result:
excel excel-formula
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
add a comment |
Is there any possibility of formula, to put cells of one row below each other in a column with its serial number repeating in first column of that particular row
For example:
Check this image:
This need to change into below image
Required End Result:
excel excel-formula
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04
add a comment |
Is there any possibility of formula, to put cells of one row below each other in a column with its serial number repeating in first column of that particular row
For example:
Check this image:
This need to change into below image
Required End Result:
excel excel-formula
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
Is there any possibility of formula, to put cells of one row below each other in a column with its serial number repeating in first column of that particular row
For example:
Check this image:
This need to change into below image
Required End Result:
excel excel-formula
excel excel-formula
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
edited Nov 20 '18 at 22:19
K.Dᴀᴠɪs
7,270112439
7,270112439
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
asked Nov 20 '18 at 16:46
codecheckcodecheck
81
81
Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04
add a comment |
Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04
Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04
Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04
add a comment |
1 Answer
1
active
oldest
votes
With your table in A1 through D4 (or below), in E1 enter:
=INDEX($A$2:$A$9999,ROUNDUP(ROW()/3,0))
and copy downwards and in F1 enter:
=INDEX($B$2:$D$9999,ROUNDUP(ROWS($1:1)/3,0),MOD(ROWS($1:1)-1,3)+1)
and copy downward:
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
With your table in A1 through D4 (or below), in E1 enter:
=INDEX($A$2:$A$9999,ROUNDUP(ROW()/3,0))
and copy downwards and in F1 enter:
=INDEX($B$2:$D$9999,ROUNDUP(ROWS($1:1)/3,0),MOD(ROWS($1:1)-1,3)+1)
and copy downward:
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
add a comment |
With your table in A1 through D4 (or below), in E1 enter:
=INDEX($A$2:$A$9999,ROUNDUP(ROW()/3,0))
and copy downwards and in F1 enter:
=INDEX($B$2:$D$9999,ROUNDUP(ROWS($1:1)/3,0),MOD(ROWS($1:1)-1,3)+1)
and copy downward:
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
add a comment |
With your table in A1 through D4 (or below), in E1 enter:
=INDEX($A$2:$A$9999,ROUNDUP(ROW()/3,0))
and copy downwards and in F1 enter:
=INDEX($B$2:$D$9999,ROUNDUP(ROWS($1:1)/3,0),MOD(ROWS($1:1)-1,3)+1)
and copy downward:
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
With your table in A1 through D4 (or below), in E1 enter:
=INDEX($A$2:$A$9999,ROUNDUP(ROW()/3,0))
and copy downwards and in F1 enter:
=INDEX($B$2:$D$9999,ROUNDUP(ROWS($1:1)/3,0),MOD(ROWS($1:1)-1,3)+1)
and copy downward:
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
answered Nov 20 '18 at 17:11
Gary's StudentGary's Student
73.8k94064
73.8k94064
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
add a comment |
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
Thank You Gary both formulas working perfectly fine.
– codecheck
Nov 20 '18 at 19:09
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
@codecheck Thanks for the feedback!
– Gary's Student
Nov 20 '18 at 19:11
add a comment |
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Hi, Welcome to stack overflow. Please tell us what approaches you have already tried. Also, you might find this helpful: stackoverflow.com/help/how-to-ask
– Gravitate
Nov 20 '18 at 17:04