Transform Rows data to column from a grouped data in LINQ












1















I am reading a csv file.



The data is not sorted in any order. I have read the file using the below code



List<LatencyData> latencys = new List<LatencyData>();
using (var reader = new StreamReader(filePath))
{

LatencyData latencyData = null;
while (!reader.EndOfStream)
{
var line = reader.ReadLine();
var values = line.Split(';');
var row = values[0].Split(',');


latencyData = new LatencyData
{
TimeStamp = (row[0] + "000"),
Prefix = row[1],
Uplink = row[2],
Latency = row[3]
};

latencys.Add(latencyData);
}
}


The Next step was to group on the basis of Time stamp.



var grouped = latencys.GroupBy(item => item.TimeStamp);


which looks like this after grouping.



enter image description here



Now I want to transform the data into this format



timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
1541030400 198 267.67 263 null 198


for that i used this part.



var transformed = grouped.Select(g => new
{
Hubs = g.Select(hub => new
{
stamp = g.Key,
Latency0 = g.Where(item => item.Uplink == "0").Select(data => data.Latency),
Latency1 = g.Where(item => item.Uplink == "1").Select(data => data.Latency),
Latency2 = g.Where(item => item.Uplink == "2").Select(data => data.Latency),
Latency3 = g.Where(item => item.Uplink == "3").Select(data => data.Latency),
Latency4 = g.Where(item => item.Uplink == "4").Select(data => data.Latency),
})
});


The Result is not correct and there is many rows for the same values are returned. It should have only one row per key



timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
1541030400 198 267.67 263 null 198


What am I doing wrong here?










share|improve this question





























    1















    I am reading a csv file.



    The data is not sorted in any order. I have read the file using the below code



    List<LatencyData> latencys = new List<LatencyData>();
    using (var reader = new StreamReader(filePath))
    {

    LatencyData latencyData = null;
    while (!reader.EndOfStream)
    {
    var line = reader.ReadLine();
    var values = line.Split(';');
    var row = values[0].Split(',');


    latencyData = new LatencyData
    {
    TimeStamp = (row[0] + "000"),
    Prefix = row[1],
    Uplink = row[2],
    Latency = row[3]
    };

    latencys.Add(latencyData);
    }
    }


    The Next step was to group on the basis of Time stamp.



    var grouped = latencys.GroupBy(item => item.TimeStamp);


    which looks like this after grouping.



    enter image description here



    Now I want to transform the data into this format



    timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
    1541030400 198 267.67 263 null 198


    for that i used this part.



    var transformed = grouped.Select(g => new
    {
    Hubs = g.Select(hub => new
    {
    stamp = g.Key,
    Latency0 = g.Where(item => item.Uplink == "0").Select(data => data.Latency),
    Latency1 = g.Where(item => item.Uplink == "1").Select(data => data.Latency),
    Latency2 = g.Where(item => item.Uplink == "2").Select(data => data.Latency),
    Latency3 = g.Where(item => item.Uplink == "3").Select(data => data.Latency),
    Latency4 = g.Where(item => item.Uplink == "4").Select(data => data.Latency),
    })
    });


    The Result is not correct and there is many rows for the same values are returned. It should have only one row per key



    timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
    1541030400 198 267.67 263 null 198


    What am I doing wrong here?










    share|improve this question



























      1












      1








      1








      I am reading a csv file.



      The data is not sorted in any order. I have read the file using the below code



      List<LatencyData> latencys = new List<LatencyData>();
      using (var reader = new StreamReader(filePath))
      {

      LatencyData latencyData = null;
      while (!reader.EndOfStream)
      {
      var line = reader.ReadLine();
      var values = line.Split(';');
      var row = values[0].Split(',');


      latencyData = new LatencyData
      {
      TimeStamp = (row[0] + "000"),
      Prefix = row[1],
      Uplink = row[2],
      Latency = row[3]
      };

      latencys.Add(latencyData);
      }
      }


      The Next step was to group on the basis of Time stamp.



      var grouped = latencys.GroupBy(item => item.TimeStamp);


      which looks like this after grouping.



      enter image description here



      Now I want to transform the data into this format



      timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
      1541030400 198 267.67 263 null 198


      for that i used this part.



      var transformed = grouped.Select(g => new
      {
      Hubs = g.Select(hub => new
      {
      stamp = g.Key,
      Latency0 = g.Where(item => item.Uplink == "0").Select(data => data.Latency),
      Latency1 = g.Where(item => item.Uplink == "1").Select(data => data.Latency),
      Latency2 = g.Where(item => item.Uplink == "2").Select(data => data.Latency),
      Latency3 = g.Where(item => item.Uplink == "3").Select(data => data.Latency),
      Latency4 = g.Where(item => item.Uplink == "4").Select(data => data.Latency),
      })
      });


      The Result is not correct and there is many rows for the same values are returned. It should have only one row per key



      timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
      1541030400 198 267.67 263 null 198


      What am I doing wrong here?










      share|improve this question
















      I am reading a csv file.



      The data is not sorted in any order. I have read the file using the below code



      List<LatencyData> latencys = new List<LatencyData>();
      using (var reader = new StreamReader(filePath))
      {

      LatencyData latencyData = null;
      while (!reader.EndOfStream)
      {
      var line = reader.ReadLine();
      var values = line.Split(';');
      var row = values[0].Split(',');


      latencyData = new LatencyData
      {
      TimeStamp = (row[0] + "000"),
      Prefix = row[1],
      Uplink = row[2],
      Latency = row[3]
      };

      latencys.Add(latencyData);
      }
      }


      The Next step was to group on the basis of Time stamp.



      var grouped = latencys.GroupBy(item => item.TimeStamp);


      which looks like this after grouping.



      enter image description here



      Now I want to transform the data into this format



      timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
      1541030400 198 267.67 263 null 198


      for that i used this part.



      var transformed = grouped.Select(g => new
      {
      Hubs = g.Select(hub => new
      {
      stamp = g.Key,
      Latency0 = g.Where(item => item.Uplink == "0").Select(data => data.Latency),
      Latency1 = g.Where(item => item.Uplink == "1").Select(data => data.Latency),
      Latency2 = g.Where(item => item.Uplink == "2").Select(data => data.Latency),
      Latency3 = g.Where(item => item.Uplink == "3").Select(data => data.Latency),
      Latency4 = g.Where(item => item.Uplink == "4").Select(data => data.Latency),
      })
      });


      The Result is not correct and there is many rows for the same values are returned. It should have only one row per key



      timeStamp  Latency0 Latency1 Latency2 Latency3 Latency4
      1541030400 198 267.67 263 null 198


      What am I doing wrong here?







      c# linq






      share|improve this question















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      share|improve this question




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      edited Nov 20 '18 at 16:51









      CRAGIN

      9,54623270




      9,54623270










      asked Nov 20 '18 at 16:46









      ankurankur

      2,015124576




      2,015124576
























          1 Answer
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          1














          You're almost there. However you might want to return a value for each latency instead of list of objects:



          var transformed = grouped.Select(g => new
          {
          Hubs = g.Select(hub => new
          {
          stamp = g.Key,
          Latency0 = g.FirstOrDefault(item => item.Uplink == "0")?.Latency,
          Latency1 = g.FirstOrDefault(item => item.Uplink == "1")?.Latency,
          Latency2 = g.FirstOrDefault(item => item.Uplink == "2")?.Latency,
          Latency3 = g.FirstOrDefault(item => item.Uplink == "3")?.Latency,
          Latency4 = g.FirstOrDefault(item => item.Uplink == "4")?.Latency,
          })
          });





          share|improve this answer

























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            1 Answer
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            1 Answer
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            active

            oldest

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            active

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            active

            oldest

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            1














            You're almost there. However you might want to return a value for each latency instead of list of objects:



            var transformed = grouped.Select(g => new
            {
            Hubs = g.Select(hub => new
            {
            stamp = g.Key,
            Latency0 = g.FirstOrDefault(item => item.Uplink == "0")?.Latency,
            Latency1 = g.FirstOrDefault(item => item.Uplink == "1")?.Latency,
            Latency2 = g.FirstOrDefault(item => item.Uplink == "2")?.Latency,
            Latency3 = g.FirstOrDefault(item => item.Uplink == "3")?.Latency,
            Latency4 = g.FirstOrDefault(item => item.Uplink == "4")?.Latency,
            })
            });





            share|improve this answer






























              1














              You're almost there. However you might want to return a value for each latency instead of list of objects:



              var transformed = grouped.Select(g => new
              {
              Hubs = g.Select(hub => new
              {
              stamp = g.Key,
              Latency0 = g.FirstOrDefault(item => item.Uplink == "0")?.Latency,
              Latency1 = g.FirstOrDefault(item => item.Uplink == "1")?.Latency,
              Latency2 = g.FirstOrDefault(item => item.Uplink == "2")?.Latency,
              Latency3 = g.FirstOrDefault(item => item.Uplink == "3")?.Latency,
              Latency4 = g.FirstOrDefault(item => item.Uplink == "4")?.Latency,
              })
              });





              share|improve this answer




























                1












                1








                1







                You're almost there. However you might want to return a value for each latency instead of list of objects:



                var transformed = grouped.Select(g => new
                {
                Hubs = g.Select(hub => new
                {
                stamp = g.Key,
                Latency0 = g.FirstOrDefault(item => item.Uplink == "0")?.Latency,
                Latency1 = g.FirstOrDefault(item => item.Uplink == "1")?.Latency,
                Latency2 = g.FirstOrDefault(item => item.Uplink == "2")?.Latency,
                Latency3 = g.FirstOrDefault(item => item.Uplink == "3")?.Latency,
                Latency4 = g.FirstOrDefault(item => item.Uplink == "4")?.Latency,
                })
                });





                share|improve this answer















                You're almost there. However you might want to return a value for each latency instead of list of objects:



                var transformed = grouped.Select(g => new
                {
                Hubs = g.Select(hub => new
                {
                stamp = g.Key,
                Latency0 = g.FirstOrDefault(item => item.Uplink == "0")?.Latency,
                Latency1 = g.FirstOrDefault(item => item.Uplink == "1")?.Latency,
                Latency2 = g.FirstOrDefault(item => item.Uplink == "2")?.Latency,
                Latency3 = g.FirstOrDefault(item => item.Uplink == "3")?.Latency,
                Latency4 = g.FirstOrDefault(item => item.Uplink == "4")?.Latency,
                })
                });






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 20 '18 at 17:20

























                answered Nov 20 '18 at 17:14









                FabjanFabjan

                10.5k31639




                10.5k31639
































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