Why I can't access NSMutable Array in my method?





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I try to add object to my NSMutable array in my method, but keep getting error. It works, if I add the object in init. It doesn't say that anything is wrong until I try to execute the code.



This is below the #import stuff where I declare two arrays:



NSMutableArray *actions1, *actions2;


This is in init:



actions1 = [NSMutableArray array];


Here I try to add 1 to the array:



- (void) storeAction:(int) action {
[actions1 addObject:@"1"];
}


The same code works in int as I said earlier.



I also would like it to store the int value declared "action", but this didn't seem to work either.



[addObject:@"%d", action];









share|improve this question























  • Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

    – Guys
    Feb 29 '12 at 22:26




















2















I try to add object to my NSMutable array in my method, but keep getting error. It works, if I add the object in init. It doesn't say that anything is wrong until I try to execute the code.



This is below the #import stuff where I declare two arrays:



NSMutableArray *actions1, *actions2;


This is in init:



actions1 = [NSMutableArray array];


Here I try to add 1 to the array:



- (void) storeAction:(int) action {
[actions1 addObject:@"1"];
}


The same code works in int as I said earlier.



I also would like it to store the int value declared "action", but this didn't seem to work either.



[addObject:@"%d", action];









share|improve this question























  • Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

    – Guys
    Feb 29 '12 at 22:26
















2












2








2








I try to add object to my NSMutable array in my method, but keep getting error. It works, if I add the object in init. It doesn't say that anything is wrong until I try to execute the code.



This is below the #import stuff where I declare two arrays:



NSMutableArray *actions1, *actions2;


This is in init:



actions1 = [NSMutableArray array];


Here I try to add 1 to the array:



- (void) storeAction:(int) action {
[actions1 addObject:@"1"];
}


The same code works in int as I said earlier.



I also would like it to store the int value declared "action", but this didn't seem to work either.



[addObject:@"%d", action];









share|improve this question














I try to add object to my NSMutable array in my method, but keep getting error. It works, if I add the object in init. It doesn't say that anything is wrong until I try to execute the code.



This is below the #import stuff where I declare two arrays:



NSMutableArray *actions1, *actions2;


This is in init:



actions1 = [NSMutableArray array];


Here I try to add 1 to the array:



- (void) storeAction:(int) action {
[actions1 addObject:@"1"];
}


The same code works in int as I said earlier.



I also would like it to store the int value declared "action", but this didn't seem to work either.



[addObject:@"%d", action];






iphone objective-c methods






share|improve this question













share|improve this question











share|improve this question




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asked Feb 29 '12 at 20:49









LiuhuLiuhu

4118




4118













  • Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

    – Guys
    Feb 29 '12 at 22:26





















  • Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

    – Guys
    Feb 29 '12 at 22:26



















Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

– Guys
Feb 29 '12 at 22:26







Regarding the [addObject:@"%d", action]; - please elaborate what does it mean "didn't seem to work either".. what's happening ? and BTW - why aren't you storing the int as a NSNumber object ? ([NSNumber numberWithInt:1])

– Guys
Feb 29 '12 at 22:26














3 Answers
3






active

oldest

votes


















5














[NSMutableArray array]; is returning an autoreleased object, by the time you try to access it, it is most likely deallocated already. Try [[NSMutableArray alloc] init]; instead. And than you should urgently check the memory management rules.






share|improve this answer


























  • I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

    – Daniel G. Wilson
    Feb 29 '12 at 20:55











  • Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

    – Liuhu
    Feb 29 '12 at 22:06








  • 1





    addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

    – gregheo
    Feb 29 '12 at 23:00











  • Thank you. Love peple who are willing to help.

    – Liuhu
    Mar 1 '12 at 14:40



















2














Try out this code



actions1 = [[NSMutableArray alloc] init];


Hope this helps.






share|improve this answer

































    0














    Alternatively, in your header file:



    @property(nonatomic, strong)NSMutableArray *actions1;


    Then in the implantation file:



    @synthesize actions1 = _actions1;


    Then you can access your array as self.actions1.






    share|improve this answer


























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      5














      [NSMutableArray array]; is returning an autoreleased object, by the time you try to access it, it is most likely deallocated already. Try [[NSMutableArray alloc] init]; instead. And than you should urgently check the memory management rules.






      share|improve this answer


























      • I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

        – Daniel G. Wilson
        Feb 29 '12 at 20:55











      • Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

        – Liuhu
        Feb 29 '12 at 22:06








      • 1





        addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

        – gregheo
        Feb 29 '12 at 23:00











      • Thank you. Love peple who are willing to help.

        – Liuhu
        Mar 1 '12 at 14:40
















      5














      [NSMutableArray array]; is returning an autoreleased object, by the time you try to access it, it is most likely deallocated already. Try [[NSMutableArray alloc] init]; instead. And than you should urgently check the memory management rules.






      share|improve this answer


























      • I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

        – Daniel G. Wilson
        Feb 29 '12 at 20:55











      • Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

        – Liuhu
        Feb 29 '12 at 22:06








      • 1





        addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

        – gregheo
        Feb 29 '12 at 23:00











      • Thank you. Love peple who are willing to help.

        – Liuhu
        Mar 1 '12 at 14:40














      5












      5








      5







      [NSMutableArray array]; is returning an autoreleased object, by the time you try to access it, it is most likely deallocated already. Try [[NSMutableArray alloc] init]; instead. And than you should urgently check the memory management rules.






      share|improve this answer















      [NSMutableArray array]; is returning an autoreleased object, by the time you try to access it, it is most likely deallocated already. Try [[NSMutableArray alloc] init]; instead. And than you should urgently check the memory management rules.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Feb 29 '12 at 20:59

























      answered Feb 29 '12 at 20:52









      vikingosegundovikingosegundo

      48.8k14117163




      48.8k14117163













      • I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

        – Daniel G. Wilson
        Feb 29 '12 at 20:55











      • Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

        – Liuhu
        Feb 29 '12 at 22:06








      • 1





        addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

        – gregheo
        Feb 29 '12 at 23:00











      • Thank you. Love peple who are willing to help.

        – Liuhu
        Mar 1 '12 at 14:40



















      • I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

        – Daniel G. Wilson
        Feb 29 '12 at 20:55











      • Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

        – Liuhu
        Feb 29 '12 at 22:06








      • 1





        addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

        – gregheo
        Feb 29 '12 at 23:00











      • Thank you. Love peple who are willing to help.

        – Liuhu
        Mar 1 '12 at 14:40

















      I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

      – Daniel G. Wilson
      Feb 29 '12 at 20:55





      I prefer this to [[NSMutableArray array] retain], plus you explained why your solution works. +1

      – Daniel G. Wilson
      Feb 29 '12 at 20:55













      Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

      – Liuhu
      Feb 29 '12 at 22:06







      Thanks! Will read that tomorrow. Any idea why this won't work? [addObject:@"%d", action];

      – Liuhu
      Feb 29 '12 at 22:06






      1




      1





      addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

      – gregheo
      Feb 29 '12 at 23:00





      addObject takes a string and doesn't do formatting. You want: [array addObject:[NSString stringWithFormat:@"%d", action]];

      – gregheo
      Feb 29 '12 at 23:00













      Thank you. Love peple who are willing to help.

      – Liuhu
      Mar 1 '12 at 14:40





      Thank you. Love peple who are willing to help.

      – Liuhu
      Mar 1 '12 at 14:40













      2














      Try out this code



      actions1 = [[NSMutableArray alloc] init];


      Hope this helps.






      share|improve this answer






























        2














        Try out this code



        actions1 = [[NSMutableArray alloc] init];


        Hope this helps.






        share|improve this answer




























          2












          2








          2







          Try out this code



          actions1 = [[NSMutableArray alloc] init];


          Hope this helps.






          share|improve this answer















          Try out this code



          actions1 = [[NSMutableArray alloc] init];


          Hope this helps.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 24 '12 at 19:50









          Parth Bhatt

          14.2k25121212




          14.2k25121212










          answered Feb 29 '12 at 20:53









          VinnieVinnie

          1,3771013




          1,3771013























              0














              Alternatively, in your header file:



              @property(nonatomic, strong)NSMutableArray *actions1;


              Then in the implantation file:



              @synthesize actions1 = _actions1;


              Then you can access your array as self.actions1.






              share|improve this answer






























                0














                Alternatively, in your header file:



                @property(nonatomic, strong)NSMutableArray *actions1;


                Then in the implantation file:



                @synthesize actions1 = _actions1;


                Then you can access your array as self.actions1.






                share|improve this answer




























                  0












                  0








                  0







                  Alternatively, in your header file:



                  @property(nonatomic, strong)NSMutableArray *actions1;


                  Then in the implantation file:



                  @synthesize actions1 = _actions1;


                  Then you can access your array as self.actions1.






                  share|improve this answer















                  Alternatively, in your header file:



                  @property(nonatomic, strong)NSMutableArray *actions1;


                  Then in the implantation file:



                  @synthesize actions1 = _actions1;


                  Then you can access your array as self.actions1.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 22 '18 at 1:49









                  Pang

                  7,0131666105




                  7,0131666105










                  answered Feb 29 '12 at 22:06









                  dbrajkovicdbrajkovic

                  3,42511314




                  3,42511314






























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