How to ignore part of input and output in Keras?
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I'm trying to train a model that takes n values as input and output n values. The problem is that n can be from 1 to 700. So I build a network with 700 as input and 700 as output. The extra inputs and outputs are set to zero.
When training the model, I don't care about if the extra outputs are accurate or not. So I tried to define my own loss function as follows:
def mse_truncate(y_true, y_pred):
def fn(x):
return tf.cond(x < 0.01,lambda: 0.0,lambda: 1.0)
#Ignore the square error if y_true[i] is near zero
sgn = tf.map_fn(fn,y_true)
return K.mean(sgn * K.square(y_true-y_pred),axis=-1)
This function works on console.
But when I compile the model, I get an error:
model.compile(optimizer='sgd',loss=mse_truncate, metrics=['accuracy'])
ValueError: Shape must be rank 0 but is rank 1 for 'loss_5/dense_2_loss/map/while/cond/Switch' (op: 'Switch') with input shapes: [?], [?].
Can someone tell me what's wrong here?
Or are there better ways to handle the variable length input and output?
Note:
More on the problem, the input is a sequence(length <= 700) and the output is the distance between the first element and each element in the sequence.
python machine-learning keras conv-neural-network loss-function
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up vote
0
down vote
favorite
I'm trying to train a model that takes n values as input and output n values. The problem is that n can be from 1 to 700. So I build a network with 700 as input and 700 as output. The extra inputs and outputs are set to zero.
When training the model, I don't care about if the extra outputs are accurate or not. So I tried to define my own loss function as follows:
def mse_truncate(y_true, y_pred):
def fn(x):
return tf.cond(x < 0.01,lambda: 0.0,lambda: 1.0)
#Ignore the square error if y_true[i] is near zero
sgn = tf.map_fn(fn,y_true)
return K.mean(sgn * K.square(y_true-y_pred),axis=-1)
This function works on console.
But when I compile the model, I get an error:
model.compile(optimizer='sgd',loss=mse_truncate, metrics=['accuracy'])
ValueError: Shape must be rank 0 but is rank 1 for 'loss_5/dense_2_loss/map/while/cond/Switch' (op: 'Switch') with input shapes: [?], [?].
Can someone tell me what's wrong here?
Or are there better ways to handle the variable length input and output?
Note:
More on the problem, the input is a sequence(length <= 700) and the output is the distance between the first element and each element in the sequence.
python machine-learning keras conv-neural-network loss-function
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm trying to train a model that takes n values as input and output n values. The problem is that n can be from 1 to 700. So I build a network with 700 as input and 700 as output. The extra inputs and outputs are set to zero.
When training the model, I don't care about if the extra outputs are accurate or not. So I tried to define my own loss function as follows:
def mse_truncate(y_true, y_pred):
def fn(x):
return tf.cond(x < 0.01,lambda: 0.0,lambda: 1.0)
#Ignore the square error if y_true[i] is near zero
sgn = tf.map_fn(fn,y_true)
return K.mean(sgn * K.square(y_true-y_pred),axis=-1)
This function works on console.
But when I compile the model, I get an error:
model.compile(optimizer='sgd',loss=mse_truncate, metrics=['accuracy'])
ValueError: Shape must be rank 0 but is rank 1 for 'loss_5/dense_2_loss/map/while/cond/Switch' (op: 'Switch') with input shapes: [?], [?].
Can someone tell me what's wrong here?
Or are there better ways to handle the variable length input and output?
Note:
More on the problem, the input is a sequence(length <= 700) and the output is the distance between the first element and each element in the sequence.
python machine-learning keras conv-neural-network loss-function
I'm trying to train a model that takes n values as input and output n values. The problem is that n can be from 1 to 700. So I build a network with 700 as input and 700 as output. The extra inputs and outputs are set to zero.
When training the model, I don't care about if the extra outputs are accurate or not. So I tried to define my own loss function as follows:
def mse_truncate(y_true, y_pred):
def fn(x):
return tf.cond(x < 0.01,lambda: 0.0,lambda: 1.0)
#Ignore the square error if y_true[i] is near zero
sgn = tf.map_fn(fn,y_true)
return K.mean(sgn * K.square(y_true-y_pred),axis=-1)
This function works on console.
But when I compile the model, I get an error:
model.compile(optimizer='sgd',loss=mse_truncate, metrics=['accuracy'])
ValueError: Shape must be rank 0 but is rank 1 for 'loss_5/dense_2_loss/map/while/cond/Switch' (op: 'Switch') with input shapes: [?], [?].
Can someone tell me what's wrong here?
Or are there better ways to handle the variable length input and output?
Note:
More on the problem, the input is a sequence(length <= 700) and the output is the distance between the first element and each element in the sequence.
python machine-learning keras conv-neural-network loss-function
python machine-learning keras conv-neural-network loss-function
asked Nov 8 at 21:41
Varelse
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