python 3 regex string matching ignore whitespace and string.punctuation











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I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.



phrase = "some phrase" #the phrase I'm searching for


Possible matches:



text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"


These are not matches:



text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"


I have tried using something like:



re.search(r'b'+phrase+'b', text)


I would very much appreciate an explanation of why the regex works if you provide a valid solution.










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  • Please edit your question because its not clear what do you want.
    – Juan Ignacio Sánchez
    Nov 10 at 14:24















up vote
1
down vote

favorite












I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.



phrase = "some phrase" #the phrase I'm searching for


Possible matches:



text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"


These are not matches:



text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"


I have tried using something like:



re.search(r'b'+phrase+'b', text)


I would very much appreciate an explanation of why the regex works if you provide a valid solution.










share|improve this question
























  • Please edit your question because its not clear what do you want.
    – Juan Ignacio Sánchez
    Nov 10 at 14:24













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.



phrase = "some phrase" #the phrase I'm searching for


Possible matches:



text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"


These are not matches:



text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"


I have tried using something like:



re.search(r'b'+phrase+'b', text)


I would very much appreciate an explanation of why the regex works if you provide a valid solution.










share|improve this question















I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.



phrase = "some phrase" #the phrase I'm searching for


Possible matches:



text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"


These are not matches:



text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"


I have tried using something like:



re.search(r'b'+phrase+'b', text)


I would very much appreciate an explanation of why the regex works if you provide a valid solution.







regex string python-3.x pattern-matching non-alphanumeric






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edited Nov 10 at 14:30

























asked Nov 10 at 14:17









quixote

154




154












  • Please edit your question because its not clear what do you want.
    – Juan Ignacio Sánchez
    Nov 10 at 14:24


















  • Please edit your question because its not clear what do you want.
    – Juan Ignacio Sánchez
    Nov 10 at 14:24
















Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24




Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










You should use something like this:



re.search(r'bsomeW+phraseb', text)



  • 'W' means non-word character


  • '+' means one or more times



In case you have a given phrase in a variable, you could try this before:



some_phrase = some_phrase.replace(r' ', r'W+')





share|improve this answer























  • some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
    – quixote
    Nov 10 at 15:10










  • finally you put b at the begining and the end.
    – Juan Ignacio Sánchez
    Nov 10 at 15:16










  • does not this solve your problem? please explain to me on what you are stuck
    – Juan Ignacio Sánchez
    Nov 10 at 15:20










  • Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
    – quixote
    Nov 10 at 15:42













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










You should use something like this:



re.search(r'bsomeW+phraseb', text)



  • 'W' means non-word character


  • '+' means one or more times



In case you have a given phrase in a variable, you could try this before:



some_phrase = some_phrase.replace(r' ', r'W+')





share|improve this answer























  • some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
    – quixote
    Nov 10 at 15:10










  • finally you put b at the begining and the end.
    – Juan Ignacio Sánchez
    Nov 10 at 15:16










  • does not this solve your problem? please explain to me on what you are stuck
    – Juan Ignacio Sánchez
    Nov 10 at 15:20










  • Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
    – quixote
    Nov 10 at 15:42

















up vote
1
down vote



accepted










You should use something like this:



re.search(r'bsomeW+phraseb', text)



  • 'W' means non-word character


  • '+' means one or more times



In case you have a given phrase in a variable, you could try this before:



some_phrase = some_phrase.replace(r' ', r'W+')





share|improve this answer























  • some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
    – quixote
    Nov 10 at 15:10










  • finally you put b at the begining and the end.
    – Juan Ignacio Sánchez
    Nov 10 at 15:16










  • does not this solve your problem? please explain to me on what you are stuck
    – Juan Ignacio Sánchez
    Nov 10 at 15:20










  • Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
    – quixote
    Nov 10 at 15:42















up vote
1
down vote



accepted







up vote
1
down vote



accepted






You should use something like this:



re.search(r'bsomeW+phraseb', text)



  • 'W' means non-word character


  • '+' means one or more times



In case you have a given phrase in a variable, you could try this before:



some_phrase = some_phrase.replace(r' ', r'W+')





share|improve this answer














You should use something like this:



re.search(r'bsomeW+phraseb', text)



  • 'W' means non-word character


  • '+' means one or more times



In case you have a given phrase in a variable, you could try this before:



some_phrase = some_phrase.replace(r' ', r'W+')






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 10 at 14:46

























answered Nov 10 at 14:39









Juan Ignacio Sánchez

317111




317111












  • some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
    – quixote
    Nov 10 at 15:10










  • finally you put b at the begining and the end.
    – Juan Ignacio Sánchez
    Nov 10 at 15:16










  • does not this solve your problem? please explain to me on what you are stuck
    – Juan Ignacio Sánchez
    Nov 10 at 15:20










  • Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
    – quixote
    Nov 10 at 15:42




















  • some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
    – quixote
    Nov 10 at 15:10










  • finally you put b at the begining and the end.
    – Juan Ignacio Sánchez
    Nov 10 at 15:16










  • does not this solve your problem? please explain to me on what you are stuck
    – Juan Ignacio Sánchez
    Nov 10 at 15:20










  • Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
    – quixote
    Nov 10 at 15:42


















some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10




some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10












finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16




finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16












does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20




does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20












Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42






Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42




















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