String Sorter Returing Exit Code 0 instead of the Strings
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-1
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I am trying to make a string sorter that takes user input and puts it into alphabetical order. My code looks like this:
public class StringSorter {
public static void main(String argv) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
int comparison = (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]));
if (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]) < 0) {
System.out.println("Alphabetical Order: " + Integer.toString(comparison));
}
}
}
How do I make it print the strings instead of "Exit Code 0"?
I forgot to add that I cannot use java.util.Arrays or java.util.Vector for this assignment
java string user-input
add a comment |
up vote
-1
down vote
favorite
I am trying to make a string sorter that takes user input and puts it into alphabetical order. My code looks like this:
public class StringSorter {
public static void main(String argv) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
int comparison = (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]));
if (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]) < 0) {
System.out.println("Alphabetical Order: " + Integer.toString(comparison));
}
}
}
How do I make it print the strings instead of "Exit Code 0"?
I forgot to add that I cannot use java.util.Arrays or java.util.Vector for this assignment
java string user-input
It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am trying to make a string sorter that takes user input and puts it into alphabetical order. My code looks like this:
public class StringSorter {
public static void main(String argv) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
int comparison = (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]));
if (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]) < 0) {
System.out.println("Alphabetical Order: " + Integer.toString(comparison));
}
}
}
How do I make it print the strings instead of "Exit Code 0"?
I forgot to add that I cannot use java.util.Arrays or java.util.Vector for this assignment
java string user-input
I am trying to make a string sorter that takes user input and puts it into alphabetical order. My code looks like this:
public class StringSorter {
public static void main(String argv) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
int comparison = (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]));
if (stringsToSort[0].compareToIgnoreCase(stringsToSort[1]) < 0) {
System.out.println("Alphabetical Order: " + Integer.toString(comparison));
}
}
}
How do I make it print the strings instead of "Exit Code 0"?
I forgot to add that I cannot use java.util.Arrays or java.util.Vector for this assignment
java string user-input
java string user-input
edited Nov 10 at 21:36
asked Nov 10 at 19:01
Matt Cheifetz
11
11
It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10
add a comment |
It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10
It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10
It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10
add a comment |
3 Answers
3
active
oldest
votes
up vote
0
down vote
Right now you are printing the result of a comparison and not the string and you're only sorting the two first strings.
You call Array.sort()
first and then you print the array. Replace your comparison and print with
Arrays.sort(stringsToSort);
for (String string : stringsToSort) {
System.out.println(string);
}
add a comment |
up vote
0
down vote
The code is going to print 1, if the first String is alphabetically smaller than the second String otherwise it will do nothing and return 0 exit code.
If you intend to do is print the array, you should iterate using a for loop on the elements of the array and print the element.
For sorting the array, you could use any of the sorting algos. Selection sort is the simplest to understand. Following is a link for sorting a String array.
http://web.cs.iastate.edu/~smkautz/cs227f12/examples/week11/SelectionSortExamples.java
add a comment |
up vote
0
down vote
You can use a custom sorting like this for your one,
public class A {
public static void main(String args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
Arrays.sort(stringsToSort, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return s1.compareToIgnoreCase(s2);
}
});
for (int i = 0; i < stringsToSort.length; i++) {
System.out.println(stringsToSort[i]);
}
}
}
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Right now you are printing the result of a comparison and not the string and you're only sorting the two first strings.
You call Array.sort()
first and then you print the array. Replace your comparison and print with
Arrays.sort(stringsToSort);
for (String string : stringsToSort) {
System.out.println(string);
}
add a comment |
up vote
0
down vote
Right now you are printing the result of a comparison and not the string and you're only sorting the two first strings.
You call Array.sort()
first and then you print the array. Replace your comparison and print with
Arrays.sort(stringsToSort);
for (String string : stringsToSort) {
System.out.println(string);
}
add a comment |
up vote
0
down vote
up vote
0
down vote
Right now you are printing the result of a comparison and not the string and you're only sorting the two first strings.
You call Array.sort()
first and then you print the array. Replace your comparison and print with
Arrays.sort(stringsToSort);
for (String string : stringsToSort) {
System.out.println(string);
}
Right now you are printing the result of a comparison and not the string and you're only sorting the two first strings.
You call Array.sort()
first and then you print the array. Replace your comparison and print with
Arrays.sort(stringsToSort);
for (String string : stringsToSort) {
System.out.println(string);
}
answered Nov 10 at 19:22
Joakim Danielson
5,7133521
5,7133521
add a comment |
add a comment |
up vote
0
down vote
The code is going to print 1, if the first String is alphabetically smaller than the second String otherwise it will do nothing and return 0 exit code.
If you intend to do is print the array, you should iterate using a for loop on the elements of the array and print the element.
For sorting the array, you could use any of the sorting algos. Selection sort is the simplest to understand. Following is a link for sorting a String array.
http://web.cs.iastate.edu/~smkautz/cs227f12/examples/week11/SelectionSortExamples.java
add a comment |
up vote
0
down vote
The code is going to print 1, if the first String is alphabetically smaller than the second String otherwise it will do nothing and return 0 exit code.
If you intend to do is print the array, you should iterate using a for loop on the elements of the array and print the element.
For sorting the array, you could use any of the sorting algos. Selection sort is the simplest to understand. Following is a link for sorting a String array.
http://web.cs.iastate.edu/~smkautz/cs227f12/examples/week11/SelectionSortExamples.java
add a comment |
up vote
0
down vote
up vote
0
down vote
The code is going to print 1, if the first String is alphabetically smaller than the second String otherwise it will do nothing and return 0 exit code.
If you intend to do is print the array, you should iterate using a for loop on the elements of the array and print the element.
For sorting the array, you could use any of the sorting algos. Selection sort is the simplest to understand. Following is a link for sorting a String array.
http://web.cs.iastate.edu/~smkautz/cs227f12/examples/week11/SelectionSortExamples.java
The code is going to print 1, if the first String is alphabetically smaller than the second String otherwise it will do nothing and return 0 exit code.
If you intend to do is print the array, you should iterate using a for loop on the elements of the array and print the element.
For sorting the array, you could use any of the sorting algos. Selection sort is the simplest to understand. Following is a link for sorting a String array.
http://web.cs.iastate.edu/~smkautz/cs227f12/examples/week11/SelectionSortExamples.java
answered Nov 10 at 19:29
Bay Max
1158
1158
add a comment |
add a comment |
up vote
0
down vote
You can use a custom sorting like this for your one,
public class A {
public static void main(String args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
Arrays.sort(stringsToSort, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return s1.compareToIgnoreCase(s2);
}
});
for (int i = 0; i < stringsToSort.length; i++) {
System.out.println(stringsToSort[i]);
}
}
}
add a comment |
up vote
0
down vote
You can use a custom sorting like this for your one,
public class A {
public static void main(String args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
Arrays.sort(stringsToSort, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return s1.compareToIgnoreCase(s2);
}
});
for (int i = 0; i < stringsToSort.length; i++) {
System.out.println(stringsToSort[i]);
}
}
}
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use a custom sorting like this for your one,
public class A {
public static void main(String args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
Arrays.sort(stringsToSort, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return s1.compareToIgnoreCase(s2);
}
});
for (int i = 0; i < stringsToSort.length; i++) {
System.out.println(stringsToSort[i]);
}
}
}
You can use a custom sorting like this for your one,
public class A {
public static void main(String args) throws IOException {
BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in), 1);
System.out.println("How many strings do you want to sort?");
int numStrings = Integer.parseInt(stdin.readLine());
System.out.println("Input Strings Here:");
String stringsToSort = new String[numStrings];
for (int i = 0; i < numStrings; i++) {
String s = stdin.readLine();
stringsToSort[i] = s;
}
Arrays.sort(stringsToSort, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
return s1.compareToIgnoreCase(s2);
}
});
for (int i = 0; i < stringsToSort.length; i++) {
System.out.println(stringsToSort[i]);
}
}
}
answered Nov 10 at 19:35
Sand
6759
6759
add a comment |
add a comment |
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It works for me, how are you executing this code?
– Mark
Nov 10 at 19:10