regex: match repeated (arbitrary times) pattern, but sort in separate groups

up vote
2
down vote

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I'm trying to match (if possible, only) the values of coordinates contained in lines like:

function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01  1.0000     0.290000      2.0000      1.56000      3.0000      5.47000      4.0000      17.3000      4.50000      31.2000      5.0000      52.6000

The first couple is matched as wished, that is to say in two different groups, by

(?<=bcouples:s)(S+)s+(S+)s+

Then,

    (?<=bcouples:s)((S+)s+(S+)s+)+

matches the whole line, but only splits the last two coordinates in separate groups.

Precision: the number of couples of coordinates is not known, so just adding several times

(S+)s+(S+)s+

in the end of the regex is not an option.

Thanks for your input!

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

What environment are you using this in?
– CertainPerformance
Nov 12 at 9:13

I'm using Python, adding this in tags
– Dionysis
Nov 12 at 10:50

add a comment |

up vote
2
down vote

favorite

I'm trying to match (if possible, only) the values of coordinates contained in lines like:

function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01  1.0000     0.290000      2.0000      1.56000      3.0000      5.47000      4.0000      17.3000      4.50000      31.2000      5.0000      52.6000

The first couple is matched as wished, that is to say in two different groups, by

(?<=bcouples:s)(S+)s+(S+)s+

Then,

    (?<=bcouples:s)((S+)s+(S+)s+)+

matches the whole line, but only splits the last two coordinates in separate groups.

Precision: the number of couples of coordinates is not known, so just adding several times

(S+)s+(S+)s+

in the end of the regex is not an option.

Thanks for your input!

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

What environment are you using this in?
– CertainPerformance
Nov 12 at 9:13

I'm using Python, adding this in tags
– Dionysis
Nov 12 at 10:50

add a comment |

up vote
2
down vote

favorite

I'm trying to match (if possible, only) the values of coordinates contained in lines like:

function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01  1.0000     0.290000      2.0000      1.56000      3.0000      5.47000      4.0000      17.3000      4.50000      31.2000      5.0000      52.6000

The first couple is matched as wished, that is to say in two different groups, by

(?<=bcouples:s)(S+)s+(S+)s+

Then,

    (?<=bcouples:s)((S+)s+(S+)s+)+

matches the whole line, but only splits the last two coordinates in separate groups.

Precision: the number of couples of coordinates is not known, so just adding several times

(S+)s+(S+)s+

in the end of the regex is not an option.

Thanks for your input!

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

I'm trying to match (if possible, only) the values of coordinates contained in lines like:

function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01  1.0000     0.290000      2.0000      1.56000      3.0000      5.47000      4.0000      17.3000      4.50000      31.2000      5.0000      52.6000

The first couple is matched as wished, that is to say in two different groups, by

(?<=bcouples:s)(S+)s+(S+)s+

Then,

    (?<=bcouples:s)((S+)s+(S+)s+)+

matches the whole line, but only splits the last two coordinates in separate groups.

Precision: the number of couples of coordinates is not known, so just adding several times

(S+)s+(S+)s+

in the end of the regex is not an option.

Thanks for your input!

python regex regex-group

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

edited Nov 12 at 10:50

asked Nov 12 at 9:13

Dionysis

164

asked Nov 12 at 9:13

Dionysis

164

asked Nov 12 at 9:13

Dionysis

164

What environment are you using this in?
– CertainPerformance
Nov 12 at 9:13

I'm using Python, adding this in tags
– Dionysis
Nov 12 at 10:50

add a comment |

What environment are you using this in?
– CertainPerformance
Nov 12 at 9:13

I'm using Python, adding this in tags
– Dionysis
Nov 12 at 10:50

What environment are you using this in?
– CertainPerformance
Nov 12 at 9:13

I'm using Python, adding this in tags
– Dionysis
Nov 12 at 10:50

add a comment |

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

Use findall():

re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",s)



([d.Ee+-]+)s+([d.Ee+-]+) --> two float numbers,

                                  () each of grouped;

 (?:s+ ... )+? -->  +? there can be more couples, ? means non-greedy matching,

                     (?: the outer group is not interesting;

Edit:
You can select the appropriate line:

 if "couples:" in s:

     coords= re.findall(...)

If your text contains more "couples", you can split it. In the following example, we can apply the regex for the 2nd or 3rd, or both part of the splitted string:

s="function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) couples: 0.1E+00 0.2E+00  9.00000     0.900000E-01"



ls=s.split("couples")

print(ls)

['function f is described by the (x,y) ',

 ': 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) ',

 ': 0.1E+00 0.2E+00  9.00000     0.900000E-01']



 re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",ls[1])

 [('0.000000E+00', '0.000000E+00'), ('5.00000', '0.500000E-01')]

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

Use findall():

re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",s)



([d.Ee+-]+)s+([d.Ee+-]+) --> two float numbers,

                                  () each of grouped;

 (?:s+ ... )+? -->  +? there can be more couples, ? means non-greedy matching,

                     (?: the outer group is not interesting;

Edit:
You can select the appropriate line:

 if "couples:" in s:

     coords= re.findall(...)

If your text contains more "couples", you can split it. In the following example, we can apply the regex for the 2nd or 3rd, or both part of the splitted string:

s="function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) couples: 0.1E+00 0.2E+00  9.00000     0.900000E-01"



ls=s.split("couples")

print(ls)

['function f is described by the (x,y) ',

 ': 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) ',

 ': 0.1E+00 0.2E+00  9.00000     0.900000E-01']



 re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",ls[1])

 [('0.000000E+00', '0.000000E+00'), ('5.00000', '0.500000E-01')]

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

add a comment |

up vote
1
down vote

accepted

Use findall():

re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",s)



([d.Ee+-]+)s+([d.Ee+-]+) --> two float numbers,

                                  () each of grouped;

 (?:s+ ... )+? -->  +? there can be more couples, ? means non-greedy matching,

                     (?: the outer group is not interesting;

Edit:
You can select the appropriate line:

 if "couples:" in s:

     coords= re.findall(...)

If your text contains more "couples", you can split it. In the following example, we can apply the regex for the 2nd or 3rd, or both part of the splitted string:

s="function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) couples: 0.1E+00 0.2E+00  9.00000     0.900000E-01"



ls=s.split("couples")

print(ls)

['function f is described by the (x,y) ',

 ': 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) ',

 ': 0.1E+00 0.2E+00  9.00000     0.900000E-01']



 re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",ls[1])

 [('0.000000E+00', '0.000000E+00'), ('5.00000', '0.500000E-01')]

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

add a comment |

up vote
1
down vote

accepted

Use findall():

re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",s)



([d.Ee+-]+)s+([d.Ee+-]+) --> two float numbers,

                                  () each of grouped;

 (?:s+ ... )+? -->  +? there can be more couples, ? means non-greedy matching,

                     (?: the outer group is not interesting;

Edit:
You can select the appropriate line:

 if "couples:" in s:

     coords= re.findall(...)

If your text contains more "couples", you can split it. In the following example, we can apply the regex for the 2nd or 3rd, or both part of the splitted string:

s="function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) couples: 0.1E+00 0.2E+00  9.00000     0.900000E-01"



ls=s.split("couples")

print(ls)

['function f is described by the (x,y) ',

 ': 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) ',

 ': 0.1E+00 0.2E+00  9.00000     0.900000E-01']



 re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",ls[1])

 [('0.000000E+00', '0.000000E+00'), ('5.00000', '0.500000E-01')]

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

Use findall():

re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",s)



([d.Ee+-]+)s+([d.Ee+-]+) --> two float numbers,

                                  () each of grouped;

 (?:s+ ... )+? -->  +? there can be more couples, ? means non-greedy matching,

                     (?: the outer group is not interesting;

Edit:
You can select the appropriate line:

 if "couples:" in s:

     coords= re.findall(...)

If your text contains more "couples", you can split it. In the following example, we can apply the regex for the 2nd or 3rd, or both part of the splitted string:

s="function f is described by the (x,y) couples: 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) couples: 0.1E+00 0.2E+00  9.00000     0.900000E-01"



ls=s.split("couples")

print(ls)

['function f is described by the (x,y) ',

 ': 0.000000E+00 0.000000E+00  5.00000     0.500000E-01 function g is described by the (x,y) ',

 ': 0.1E+00 0.2E+00  9.00000     0.900000E-01']



 re.findall(r"(?:s+([d.Ee+-]+)s+([d.Ee+-]+))+?",ls[1])

 [('0.000000E+00', '0.000000E+00'), ('5.00000', '0.500000E-01')]

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

edited Nov 13 at 15:14

answered Nov 12 at 15:53

kantal

60717

answered Nov 12 at 15:53

kantal

60717

answered Nov 12 at 15:53

kantal

60717

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

add a comment |

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

Thanks, this answers the question perfectly, but I have two more questions: 1/ What if I would like to end the search at a specific word occurence? For example, imagine that after the f function, there is a g function described exactly by the same way. How do I get the couples of coordinates separately and why adding 's*function' at the end of your regex doesn't work? 2/ Do we really need the 're.findall()'? It looks like 're.search()' would be enough...
– Dionysis
Nov 13 at 13:38

1/ I have edited the code above. 2/ re.search() stops at the first matching, findall() iterates further.
– kantal
Nov 13 at 15:17

add a comment |

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