Ruby Iterating over an array and find match in an hash and replace the element in array











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I would like someone to clarify how can I possibly iterating over an array, find an exact match in an hash[value], and replace the element in the array with the hash[key].



As example, if I have a morse directory morse_dict = {
"a" => ".-","b" => "-...","c" => "-.-.","d" => "-..","e" => ".","f" => "..-.","g" => "--.","h" => "....","i" => "..","j" => ".---","k" => "-.-","l" => ".-..","m" => "--","n" => "-.","o" => "---","p" => ".--.","q" => "--.-","r" => ".-.","s" => "...","t" => "-","u" => "..-","v" => "...-","w" => ".--","x" => "-..-","y" => "-.--","z" => "--.."," " => " ","1" => ".----","2" => "..---","3" => "...--","4" => "....-","5" => ".....","6" => "-....","7" => "--...","8" => "---..","9" => "----.","0" => "-----"
}



and I want a method that for a given string in morse code returns a string in regular alphabet.
This is the codewars kata.



I am not interested in the solution to the challenge itself, I would like to understand the principle of this.



So far I have thought of proceeding this way:



def morse_code(arr)
arr.split(" ").each {|element|
element.each_char {|char|
(morse_dict.include?(char)) ? (print "true") : (print "false")}
}
end


I only print false, which means that I am not actually looking for match into the hash.










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    up vote
    1
    down vote

    favorite












    I would like someone to clarify how can I possibly iterating over an array, find an exact match in an hash[value], and replace the element in the array with the hash[key].



    As example, if I have a morse directory morse_dict = {
    "a" => ".-","b" => "-...","c" => "-.-.","d" => "-..","e" => ".","f" => "..-.","g" => "--.","h" => "....","i" => "..","j" => ".---","k" => "-.-","l" => ".-..","m" => "--","n" => "-.","o" => "---","p" => ".--.","q" => "--.-","r" => ".-.","s" => "...","t" => "-","u" => "..-","v" => "...-","w" => ".--","x" => "-..-","y" => "-.--","z" => "--.."," " => " ","1" => ".----","2" => "..---","3" => "...--","4" => "....-","5" => ".....","6" => "-....","7" => "--...","8" => "---..","9" => "----.","0" => "-----"
    }



    and I want a method that for a given string in morse code returns a string in regular alphabet.
    This is the codewars kata.



    I am not interested in the solution to the challenge itself, I would like to understand the principle of this.



    So far I have thought of proceeding this way:



    def morse_code(arr)
    arr.split(" ").each {|element|
    element.each_char {|char|
    (morse_dict.include?(char)) ? (print "true") : (print "false")}
    }
    end


    I only print false, which means that I am not actually looking for match into the hash.










    share|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I would like someone to clarify how can I possibly iterating over an array, find an exact match in an hash[value], and replace the element in the array with the hash[key].



      As example, if I have a morse directory morse_dict = {
      "a" => ".-","b" => "-...","c" => "-.-.","d" => "-..","e" => ".","f" => "..-.","g" => "--.","h" => "....","i" => "..","j" => ".---","k" => "-.-","l" => ".-..","m" => "--","n" => "-.","o" => "---","p" => ".--.","q" => "--.-","r" => ".-.","s" => "...","t" => "-","u" => "..-","v" => "...-","w" => ".--","x" => "-..-","y" => "-.--","z" => "--.."," " => " ","1" => ".----","2" => "..---","3" => "...--","4" => "....-","5" => ".....","6" => "-....","7" => "--...","8" => "---..","9" => "----.","0" => "-----"
      }



      and I want a method that for a given string in morse code returns a string in regular alphabet.
      This is the codewars kata.



      I am not interested in the solution to the challenge itself, I would like to understand the principle of this.



      So far I have thought of proceeding this way:



      def morse_code(arr)
      arr.split(" ").each {|element|
      element.each_char {|char|
      (morse_dict.include?(char)) ? (print "true") : (print "false")}
      }
      end


      I only print false, which means that I am not actually looking for match into the hash.










      share|improve this question















      I would like someone to clarify how can I possibly iterating over an array, find an exact match in an hash[value], and replace the element in the array with the hash[key].



      As example, if I have a morse directory morse_dict = {
      "a" => ".-","b" => "-...","c" => "-.-.","d" => "-..","e" => ".","f" => "..-.","g" => "--.","h" => "....","i" => "..","j" => ".---","k" => "-.-","l" => ".-..","m" => "--","n" => "-.","o" => "---","p" => ".--.","q" => "--.-","r" => ".-.","s" => "...","t" => "-","u" => "..-","v" => "...-","w" => ".--","x" => "-..-","y" => "-.--","z" => "--.."," " => " ","1" => ".----","2" => "..---","3" => "...--","4" => "....-","5" => ".....","6" => "-....","7" => "--...","8" => "---..","9" => "----.","0" => "-----"
      }



      and I want a method that for a given string in morse code returns a string in regular alphabet.
      This is the codewars kata.



      I am not interested in the solution to the challenge itself, I would like to understand the principle of this.



      So far I have thought of proceeding this way:



      def morse_code(arr)
      arr.split(" ").each {|element|
      element.each_char {|char|
      (morse_dict.include?(char)) ? (print "true") : (print "false")}
      }
      end


      I only print false, which means that I am not actually looking for match into the hash.







      arrays ruby hash iteration






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      edited Nov 14 at 23:10









      Cary Swoveland

      66.8k53865




      66.8k53865










      asked Nov 11 at 19:12









      Floroz

      85




      85
























          3 Answers
          3






          active

          oldest

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          up vote
          0
          down vote



          accepted










          I understand from the kata that letters are to be separated by one space and words by three spaces.



          As a first step I will two changes to the hash morse_dict: remove the key ' '; and add key-value pairs for some punctuation characters. The space character key is not needed; the need for punctuation codes is discussed in the kata.



          PUNCTUATION = { "."=>".-.-.-", ","=>"--..--", "?"=>"..--..", "!"=>"-.-.--" }

          ALPHA_TO_MORSE = dict.reject { |k,_| k == " " }.merge(PUNCTUATION)
          #=> {"a"=>".-", "b"=>"-...", "c"=>"-.-.", "d"=>"-..", "e"=>".", "f"=>"..-.",
          # "g"=>"--.", "h"=>"....", "i"=>"..", "j"=>".---", "k"=>"-.-", "l"=>".-..",
          # "m"=>"--", "n"=>"-.", "o"=>"---", "p"=>".--.", "q"=>"--.-", "r"=>".-.",
          # "s"=>"...", "t"=>"-", "u"=>"..-", "v"=>"...-", "w"=>".--", "x"=>"-..-",
          # "y"=>"-.--", "z"=>"--..", "1"=>".----", "2"=>"..---", "3"=>"...--",
          # "4"=>"....-", "5"=>".....", "6"=>"-....", "7"=>"--...", "8"=>"---..",
          # "9"=>"----.", "0"=>"-----", "."=>".-.-.-", ","=>"--..--", "?"=>"..--..",
          # "!"=>"-.-.--"}


          I obtained the Morse codes for the punctuation characters from the Morse Code Wiki. Additional punctuation characters could be added if desired.



          The hash ALPHA_TO_MORSE is used in encoding text. The inverse of this hash is needed for decoding messages in Morse code. Also needed for decoding is the key value pair "...---..."=>"sos".



          MORSE_TO_ALPHA = ALPHA_TO_MORSE.invert.merge("...---..."=>"sos")
          #=> {".-"=>"a", "-..."=>"b", "-.-."=>"c", "-.."=>"d", "."=>"e", "..-."=>"f",
          # "--."=>"g", "...."=>"h", ".."=>"i", ".---"=>"j", "-.-"=>"k", ".-.."=>"l",
          # "--"=>"m", "-."=>"n", "---"=>"o", ".--."=>"p", "--.-"=>"q", ".-."=>"r",
          # "..."=>"s", "-"=>"t", "..-"=>"u", "...-"=>"v", ".--"=>"w", "-..-"=>"x",
          # "-.--"=>"y", "--.."=>"z", ".----"=>"1", "..---"=>"2", "...--"=>"3",
          # "....-"=>"4", "....."=>"5", "-...."=>"6", "--..."=>"7", "---.."=>"8",
          # "----."=>"9", "-----"=>"0", ".-.-.-"=>".", "--..--"=>",",
          # "..--.."=>"?", "-.-.--"=>"!""...---..."=>"sos"}


          One more hash is needed to deal with cases where the message "sos" (or "SOS"--Morse code is case insensitive), or "sos" followed by a punctuation character (e.g., "sos!") is to be encoded.1 See the Wiki.



          SOS_WITH_PUNCTUATION = PUNCTUATION.each_with_object({}) { |(k,v),h|
          h["sos#{k}"] = "...---... #{v}" }.merge('sos'=>"...---...")
          #=> {"sos."=>"...---... .-.-.-", "sos,"=>"...---... --..--",
          # "sos?"=>"...---... ..--..", "sos!"=>"...---... -.-.--", "sos"=>"...---..."}


          The encoding and decoding methods follow. encode checks to see if each word in the string is a key in the hash SOS_WITH_PUNCTUATION. If it is, the value of key is the Morse code for the word; else, the word is divided into letters and each letter is translated into Morse code.



          def encode(str)
          str.strip.downcase.split.map do |word|
          if SOS_WITH_PUNCTUATION.key?(word)
          SOS_WITH_PUNCTUATION[word]
          else
          word.each_char.map { |c| ALPHA_TO_MORSE[c] }.join(' ')
          end
          end.join (' ')
          end

          def decode(morse)
          morse.strip.split(/ {3}/).map do |word|
          word.split.map { |c| MORSE_TO_ALPHA[c] }.join
          end.join(' ')
          end


          We can now try out these two methods.



          str = "  Is now the time for   you, and 007, to send an SOS?"




          morse = encode str
          #=> ".. ... -. --- .-- - .... . - .. -- . ..-. --- .-. -.-- --- ..- --..-- .- -. -.. ----- ----- --... --..-- - --- ... . -. -.. .- -. ...---... ..--.."




          decode morse
          #=> "is now the time for you, and 007, to send an sos?"


          1 It would be simpler to have a pre-processing step that would convert, say, "sos." to "sos .", but when the resulting Morse code were decoded there would be a space between "sos" and ".". I suppose that cryptographers could deal with that, but I've chosen to avoid the insertion of the space.






          share|improve this answer























          • Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
            – Floroz
            Nov 12 at 11:36












          • What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
            – Floroz
            Nov 12 at 11:43












          • Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
            – Cary Swoveland
            Nov 13 at 9:19










          • Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
            – Floroz
            Nov 13 at 14:12












          • Floroz, I've edited my answer.
            – Cary Swoveland
            Nov 15 at 4:34


















          up vote
          1
          down vote













          Using Hash#key without replacing the array, rather creating a new one (use map! for replacement):



          array = [1,2,3,4,5]    
          hash = {a: 4, b: 7, c: 3}

          array.map { |el| hash.key(el) }
          # => [nil, nil, :c, :a, nil]


          You may want to think about using Hash#invert and simply referencing the elements by keys for performance reasons as Hash#key is O(n) while Hash# is O(1).



          array = [1,2,3,4,5]
          hash = {a: 4, b: 7, c: 3}
          inverted_hash = hash.invert

          array.map { |el| inverted_hash[el] }
          # => [nil, nil, :c, :a, nil]





          share|improve this answer






























            up vote
            0
            down vote













            assuming: arr = 'a b c d', which is not an arr, so please make that morse_string



            def morse_code(morse_string)
            new_elements =

            # iterate over each character in the string,
            morse_string.split(" ").each do |element|
            if morse_dict[element]
            # https://apidock.com/ruby/Array/push
            new_elements.push( morse_dict[element] )
            else
            # whatever you want to do when there is no match
            end
            end
            # re-create the string again, but with braille
            # https://apidock.com/ruby/Array/join
            new_elements.join(' ')
            end

            morse_string = 'a b c d'
            morse_code(morse_string)





            share|improve this answer





















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              3 Answers
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              3 Answers
              3






              active

              oldest

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              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              0
              down vote



              accepted










              I understand from the kata that letters are to be separated by one space and words by three spaces.



              As a first step I will two changes to the hash morse_dict: remove the key ' '; and add key-value pairs for some punctuation characters. The space character key is not needed; the need for punctuation codes is discussed in the kata.



              PUNCTUATION = { "."=>".-.-.-", ","=>"--..--", "?"=>"..--..", "!"=>"-.-.--" }

              ALPHA_TO_MORSE = dict.reject { |k,_| k == " " }.merge(PUNCTUATION)
              #=> {"a"=>".-", "b"=>"-...", "c"=>"-.-.", "d"=>"-..", "e"=>".", "f"=>"..-.",
              # "g"=>"--.", "h"=>"....", "i"=>"..", "j"=>".---", "k"=>"-.-", "l"=>".-..",
              # "m"=>"--", "n"=>"-.", "o"=>"---", "p"=>".--.", "q"=>"--.-", "r"=>".-.",
              # "s"=>"...", "t"=>"-", "u"=>"..-", "v"=>"...-", "w"=>".--", "x"=>"-..-",
              # "y"=>"-.--", "z"=>"--..", "1"=>".----", "2"=>"..---", "3"=>"...--",
              # "4"=>"....-", "5"=>".....", "6"=>"-....", "7"=>"--...", "8"=>"---..",
              # "9"=>"----.", "0"=>"-----", "."=>".-.-.-", ","=>"--..--", "?"=>"..--..",
              # "!"=>"-.-.--"}


              I obtained the Morse codes for the punctuation characters from the Morse Code Wiki. Additional punctuation characters could be added if desired.



              The hash ALPHA_TO_MORSE is used in encoding text. The inverse of this hash is needed for decoding messages in Morse code. Also needed for decoding is the key value pair "...---..."=>"sos".



              MORSE_TO_ALPHA = ALPHA_TO_MORSE.invert.merge("...---..."=>"sos")
              #=> {".-"=>"a", "-..."=>"b", "-.-."=>"c", "-.."=>"d", "."=>"e", "..-."=>"f",
              # "--."=>"g", "...."=>"h", ".."=>"i", ".---"=>"j", "-.-"=>"k", ".-.."=>"l",
              # "--"=>"m", "-."=>"n", "---"=>"o", ".--."=>"p", "--.-"=>"q", ".-."=>"r",
              # "..."=>"s", "-"=>"t", "..-"=>"u", "...-"=>"v", ".--"=>"w", "-..-"=>"x",
              # "-.--"=>"y", "--.."=>"z", ".----"=>"1", "..---"=>"2", "...--"=>"3",
              # "....-"=>"4", "....."=>"5", "-...."=>"6", "--..."=>"7", "---.."=>"8",
              # "----."=>"9", "-----"=>"0", ".-.-.-"=>".", "--..--"=>",",
              # "..--.."=>"?", "-.-.--"=>"!""...---..."=>"sos"}


              One more hash is needed to deal with cases where the message "sos" (or "SOS"--Morse code is case insensitive), or "sos" followed by a punctuation character (e.g., "sos!") is to be encoded.1 See the Wiki.



              SOS_WITH_PUNCTUATION = PUNCTUATION.each_with_object({}) { |(k,v),h|
              h["sos#{k}"] = "...---... #{v}" }.merge('sos'=>"...---...")
              #=> {"sos."=>"...---... .-.-.-", "sos,"=>"...---... --..--",
              # "sos?"=>"...---... ..--..", "sos!"=>"...---... -.-.--", "sos"=>"...---..."}


              The encoding and decoding methods follow. encode checks to see if each word in the string is a key in the hash SOS_WITH_PUNCTUATION. If it is, the value of key is the Morse code for the word; else, the word is divided into letters and each letter is translated into Morse code.



              def encode(str)
              str.strip.downcase.split.map do |word|
              if SOS_WITH_PUNCTUATION.key?(word)
              SOS_WITH_PUNCTUATION[word]
              else
              word.each_char.map { |c| ALPHA_TO_MORSE[c] }.join(' ')
              end
              end.join (' ')
              end

              def decode(morse)
              morse.strip.split(/ {3}/).map do |word|
              word.split.map { |c| MORSE_TO_ALPHA[c] }.join
              end.join(' ')
              end


              We can now try out these two methods.



              str = "  Is now the time for   you, and 007, to send an SOS?"




              morse = encode str
              #=> ".. ... -. --- .-- - .... . - .. -- . ..-. --- .-. -.-- --- ..- --..-- .- -. -.. ----- ----- --... --..-- - --- ... . -. -.. .- -. ...---... ..--.."




              decode morse
              #=> "is now the time for you, and 007, to send an sos?"


              1 It would be simpler to have a pre-processing step that would convert, say, "sos." to "sos .", but when the resulting Morse code were decoded there would be a space between "sos" and ".". I suppose that cryptographers could deal with that, but I've chosen to avoid the insertion of the space.






              share|improve this answer























              • Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
                – Floroz
                Nov 12 at 11:36












              • What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
                – Floroz
                Nov 12 at 11:43












              • Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
                – Cary Swoveland
                Nov 13 at 9:19










              • Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
                – Floroz
                Nov 13 at 14:12












              • Floroz, I've edited my answer.
                – Cary Swoveland
                Nov 15 at 4:34















              up vote
              0
              down vote



              accepted










              I understand from the kata that letters are to be separated by one space and words by three spaces.



              As a first step I will two changes to the hash morse_dict: remove the key ' '; and add key-value pairs for some punctuation characters. The space character key is not needed; the need for punctuation codes is discussed in the kata.



              PUNCTUATION = { "."=>".-.-.-", ","=>"--..--", "?"=>"..--..", "!"=>"-.-.--" }

              ALPHA_TO_MORSE = dict.reject { |k,_| k == " " }.merge(PUNCTUATION)
              #=> {"a"=>".-", "b"=>"-...", "c"=>"-.-.", "d"=>"-..", "e"=>".", "f"=>"..-.",
              # "g"=>"--.", "h"=>"....", "i"=>"..", "j"=>".---", "k"=>"-.-", "l"=>".-..",
              # "m"=>"--", "n"=>"-.", "o"=>"---", "p"=>".--.", "q"=>"--.-", "r"=>".-.",
              # "s"=>"...", "t"=>"-", "u"=>"..-", "v"=>"...-", "w"=>".--", "x"=>"-..-",
              # "y"=>"-.--", "z"=>"--..", "1"=>".----", "2"=>"..---", "3"=>"...--",
              # "4"=>"....-", "5"=>".....", "6"=>"-....", "7"=>"--...", "8"=>"---..",
              # "9"=>"----.", "0"=>"-----", "."=>".-.-.-", ","=>"--..--", "?"=>"..--..",
              # "!"=>"-.-.--"}


              I obtained the Morse codes for the punctuation characters from the Morse Code Wiki. Additional punctuation characters could be added if desired.



              The hash ALPHA_TO_MORSE is used in encoding text. The inverse of this hash is needed for decoding messages in Morse code. Also needed for decoding is the key value pair "...---..."=>"sos".



              MORSE_TO_ALPHA = ALPHA_TO_MORSE.invert.merge("...---..."=>"sos")
              #=> {".-"=>"a", "-..."=>"b", "-.-."=>"c", "-.."=>"d", "."=>"e", "..-."=>"f",
              # "--."=>"g", "...."=>"h", ".."=>"i", ".---"=>"j", "-.-"=>"k", ".-.."=>"l",
              # "--"=>"m", "-."=>"n", "---"=>"o", ".--."=>"p", "--.-"=>"q", ".-."=>"r",
              # "..."=>"s", "-"=>"t", "..-"=>"u", "...-"=>"v", ".--"=>"w", "-..-"=>"x",
              # "-.--"=>"y", "--.."=>"z", ".----"=>"1", "..---"=>"2", "...--"=>"3",
              # "....-"=>"4", "....."=>"5", "-...."=>"6", "--..."=>"7", "---.."=>"8",
              # "----."=>"9", "-----"=>"0", ".-.-.-"=>".", "--..--"=>",",
              # "..--.."=>"?", "-.-.--"=>"!""...---..."=>"sos"}


              One more hash is needed to deal with cases where the message "sos" (or "SOS"--Morse code is case insensitive), or "sos" followed by a punctuation character (e.g., "sos!") is to be encoded.1 See the Wiki.



              SOS_WITH_PUNCTUATION = PUNCTUATION.each_with_object({}) { |(k,v),h|
              h["sos#{k}"] = "...---... #{v}" }.merge('sos'=>"...---...")
              #=> {"sos."=>"...---... .-.-.-", "sos,"=>"...---... --..--",
              # "sos?"=>"...---... ..--..", "sos!"=>"...---... -.-.--", "sos"=>"...---..."}


              The encoding and decoding methods follow. encode checks to see if each word in the string is a key in the hash SOS_WITH_PUNCTUATION. If it is, the value of key is the Morse code for the word; else, the word is divided into letters and each letter is translated into Morse code.



              def encode(str)
              str.strip.downcase.split.map do |word|
              if SOS_WITH_PUNCTUATION.key?(word)
              SOS_WITH_PUNCTUATION[word]
              else
              word.each_char.map { |c| ALPHA_TO_MORSE[c] }.join(' ')
              end
              end.join (' ')
              end

              def decode(morse)
              morse.strip.split(/ {3}/).map do |word|
              word.split.map { |c| MORSE_TO_ALPHA[c] }.join
              end.join(' ')
              end


              We can now try out these two methods.



              str = "  Is now the time for   you, and 007, to send an SOS?"




              morse = encode str
              #=> ".. ... -. --- .-- - .... . - .. -- . ..-. --- .-. -.-- --- ..- --..-- .- -. -.. ----- ----- --... --..-- - --- ... . -. -.. .- -. ...---... ..--.."




              decode morse
              #=> "is now the time for you, and 007, to send an sos?"


              1 It would be simpler to have a pre-processing step that would convert, say, "sos." to "sos .", but when the resulting Morse code were decoded there would be a space between "sos" and ".". I suppose that cryptographers could deal with that, but I've chosen to avoid the insertion of the space.






              share|improve this answer























              • Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
                – Floroz
                Nov 12 at 11:36












              • What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
                – Floroz
                Nov 12 at 11:43












              • Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
                – Cary Swoveland
                Nov 13 at 9:19










              • Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
                – Floroz
                Nov 13 at 14:12












              • Floroz, I've edited my answer.
                – Cary Swoveland
                Nov 15 at 4:34













              up vote
              0
              down vote



              accepted







              up vote
              0
              down vote



              accepted






              I understand from the kata that letters are to be separated by one space and words by three spaces.



              As a first step I will two changes to the hash morse_dict: remove the key ' '; and add key-value pairs for some punctuation characters. The space character key is not needed; the need for punctuation codes is discussed in the kata.



              PUNCTUATION = { "."=>".-.-.-", ","=>"--..--", "?"=>"..--..", "!"=>"-.-.--" }

              ALPHA_TO_MORSE = dict.reject { |k,_| k == " " }.merge(PUNCTUATION)
              #=> {"a"=>".-", "b"=>"-...", "c"=>"-.-.", "d"=>"-..", "e"=>".", "f"=>"..-.",
              # "g"=>"--.", "h"=>"....", "i"=>"..", "j"=>".---", "k"=>"-.-", "l"=>".-..",
              # "m"=>"--", "n"=>"-.", "o"=>"---", "p"=>".--.", "q"=>"--.-", "r"=>".-.",
              # "s"=>"...", "t"=>"-", "u"=>"..-", "v"=>"...-", "w"=>".--", "x"=>"-..-",
              # "y"=>"-.--", "z"=>"--..", "1"=>".----", "2"=>"..---", "3"=>"...--",
              # "4"=>"....-", "5"=>".....", "6"=>"-....", "7"=>"--...", "8"=>"---..",
              # "9"=>"----.", "0"=>"-----", "."=>".-.-.-", ","=>"--..--", "?"=>"..--..",
              # "!"=>"-.-.--"}


              I obtained the Morse codes for the punctuation characters from the Morse Code Wiki. Additional punctuation characters could be added if desired.



              The hash ALPHA_TO_MORSE is used in encoding text. The inverse of this hash is needed for decoding messages in Morse code. Also needed for decoding is the key value pair "...---..."=>"sos".



              MORSE_TO_ALPHA = ALPHA_TO_MORSE.invert.merge("...---..."=>"sos")
              #=> {".-"=>"a", "-..."=>"b", "-.-."=>"c", "-.."=>"d", "."=>"e", "..-."=>"f",
              # "--."=>"g", "...."=>"h", ".."=>"i", ".---"=>"j", "-.-"=>"k", ".-.."=>"l",
              # "--"=>"m", "-."=>"n", "---"=>"o", ".--."=>"p", "--.-"=>"q", ".-."=>"r",
              # "..."=>"s", "-"=>"t", "..-"=>"u", "...-"=>"v", ".--"=>"w", "-..-"=>"x",
              # "-.--"=>"y", "--.."=>"z", ".----"=>"1", "..---"=>"2", "...--"=>"3",
              # "....-"=>"4", "....."=>"5", "-...."=>"6", "--..."=>"7", "---.."=>"8",
              # "----."=>"9", "-----"=>"0", ".-.-.-"=>".", "--..--"=>",",
              # "..--.."=>"?", "-.-.--"=>"!""...---..."=>"sos"}


              One more hash is needed to deal with cases where the message "sos" (or "SOS"--Morse code is case insensitive), or "sos" followed by a punctuation character (e.g., "sos!") is to be encoded.1 See the Wiki.



              SOS_WITH_PUNCTUATION = PUNCTUATION.each_with_object({}) { |(k,v),h|
              h["sos#{k}"] = "...---... #{v}" }.merge('sos'=>"...---...")
              #=> {"sos."=>"...---... .-.-.-", "sos,"=>"...---... --..--",
              # "sos?"=>"...---... ..--..", "sos!"=>"...---... -.-.--", "sos"=>"...---..."}


              The encoding and decoding methods follow. encode checks to see if each word in the string is a key in the hash SOS_WITH_PUNCTUATION. If it is, the value of key is the Morse code for the word; else, the word is divided into letters and each letter is translated into Morse code.



              def encode(str)
              str.strip.downcase.split.map do |word|
              if SOS_WITH_PUNCTUATION.key?(word)
              SOS_WITH_PUNCTUATION[word]
              else
              word.each_char.map { |c| ALPHA_TO_MORSE[c] }.join(' ')
              end
              end.join (' ')
              end

              def decode(morse)
              morse.strip.split(/ {3}/).map do |word|
              word.split.map { |c| MORSE_TO_ALPHA[c] }.join
              end.join(' ')
              end


              We can now try out these two methods.



              str = "  Is now the time for   you, and 007, to send an SOS?"




              morse = encode str
              #=> ".. ... -. --- .-- - .... . - .. -- . ..-. --- .-. -.-- --- ..- --..-- .- -. -.. ----- ----- --... --..-- - --- ... . -. -.. .- -. ...---... ..--.."




              decode morse
              #=> "is now the time for you, and 007, to send an sos?"


              1 It would be simpler to have a pre-processing step that would convert, say, "sos." to "sos .", but when the resulting Morse code were decoded there would be a space between "sos" and ".". I suppose that cryptographers could deal with that, but I've chosen to avoid the insertion of the space.






              share|improve this answer














              I understand from the kata that letters are to be separated by one space and words by three spaces.



              As a first step I will two changes to the hash morse_dict: remove the key ' '; and add key-value pairs for some punctuation characters. The space character key is not needed; the need for punctuation codes is discussed in the kata.



              PUNCTUATION = { "."=>".-.-.-", ","=>"--..--", "?"=>"..--..", "!"=>"-.-.--" }

              ALPHA_TO_MORSE = dict.reject { |k,_| k == " " }.merge(PUNCTUATION)
              #=> {"a"=>".-", "b"=>"-...", "c"=>"-.-.", "d"=>"-..", "e"=>".", "f"=>"..-.",
              # "g"=>"--.", "h"=>"....", "i"=>"..", "j"=>".---", "k"=>"-.-", "l"=>".-..",
              # "m"=>"--", "n"=>"-.", "o"=>"---", "p"=>".--.", "q"=>"--.-", "r"=>".-.",
              # "s"=>"...", "t"=>"-", "u"=>"..-", "v"=>"...-", "w"=>".--", "x"=>"-..-",
              # "y"=>"-.--", "z"=>"--..", "1"=>".----", "2"=>"..---", "3"=>"...--",
              # "4"=>"....-", "5"=>".....", "6"=>"-....", "7"=>"--...", "8"=>"---..",
              # "9"=>"----.", "0"=>"-----", "."=>".-.-.-", ","=>"--..--", "?"=>"..--..",
              # "!"=>"-.-.--"}


              I obtained the Morse codes for the punctuation characters from the Morse Code Wiki. Additional punctuation characters could be added if desired.



              The hash ALPHA_TO_MORSE is used in encoding text. The inverse of this hash is needed for decoding messages in Morse code. Also needed for decoding is the key value pair "...---..."=>"sos".



              MORSE_TO_ALPHA = ALPHA_TO_MORSE.invert.merge("...---..."=>"sos")
              #=> {".-"=>"a", "-..."=>"b", "-.-."=>"c", "-.."=>"d", "."=>"e", "..-."=>"f",
              # "--."=>"g", "...."=>"h", ".."=>"i", ".---"=>"j", "-.-"=>"k", ".-.."=>"l",
              # "--"=>"m", "-."=>"n", "---"=>"o", ".--."=>"p", "--.-"=>"q", ".-."=>"r",
              # "..."=>"s", "-"=>"t", "..-"=>"u", "...-"=>"v", ".--"=>"w", "-..-"=>"x",
              # "-.--"=>"y", "--.."=>"z", ".----"=>"1", "..---"=>"2", "...--"=>"3",
              # "....-"=>"4", "....."=>"5", "-...."=>"6", "--..."=>"7", "---.."=>"8",
              # "----."=>"9", "-----"=>"0", ".-.-.-"=>".", "--..--"=>",",
              # "..--.."=>"?", "-.-.--"=>"!""...---..."=>"sos"}


              One more hash is needed to deal with cases where the message "sos" (or "SOS"--Morse code is case insensitive), or "sos" followed by a punctuation character (e.g., "sos!") is to be encoded.1 See the Wiki.



              SOS_WITH_PUNCTUATION = PUNCTUATION.each_with_object({}) { |(k,v),h|
              h["sos#{k}"] = "...---... #{v}" }.merge('sos'=>"...---...")
              #=> {"sos."=>"...---... .-.-.-", "sos,"=>"...---... --..--",
              # "sos?"=>"...---... ..--..", "sos!"=>"...---... -.-.--", "sos"=>"...---..."}


              The encoding and decoding methods follow. encode checks to see if each word in the string is a key in the hash SOS_WITH_PUNCTUATION. If it is, the value of key is the Morse code for the word; else, the word is divided into letters and each letter is translated into Morse code.



              def encode(str)
              str.strip.downcase.split.map do |word|
              if SOS_WITH_PUNCTUATION.key?(word)
              SOS_WITH_PUNCTUATION[word]
              else
              word.each_char.map { |c| ALPHA_TO_MORSE[c] }.join(' ')
              end
              end.join (' ')
              end

              def decode(morse)
              morse.strip.split(/ {3}/).map do |word|
              word.split.map { |c| MORSE_TO_ALPHA[c] }.join
              end.join(' ')
              end


              We can now try out these two methods.



              str = "  Is now the time for   you, and 007, to send an SOS?"




              morse = encode str
              #=> ".. ... -. --- .-- - .... . - .. -- . ..-. --- .-. -.-- --- ..- --..-- .- -. -.. ----- ----- --... --..-- - --- ... . -. -.. .- -. ...---... ..--.."




              decode morse
              #=> "is now the time for you, and 007, to send an sos?"


              1 It would be simpler to have a pre-processing step that would convert, say, "sos." to "sos .", but when the resulting Morse code were decoded there would be a space between "sos" and ".". I suppose that cryptographers could deal with that, but I've chosen to avoid the insertion of the space.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 15 at 4:39

























              answered Nov 11 at 22:16









              Cary Swoveland

              66.8k53865




              66.8k53865












              • Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
                – Floroz
                Nov 12 at 11:36












              • What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
                – Floroz
                Nov 12 at 11:43












              • Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
                – Cary Swoveland
                Nov 13 at 9:19










              • Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
                – Floroz
                Nov 13 at 14:12












              • Floroz, I've edited my answer.
                – Cary Swoveland
                Nov 15 at 4:34


















              • Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
                – Floroz
                Nov 12 at 11:36












              • What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
                – Floroz
                Nov 12 at 11:43












              • Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
                – Cary Swoveland
                Nov 13 at 9:19










              • Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
                – Floroz
                Nov 13 at 14:12












              • Floroz, I've edited my answer.
                – Cary Swoveland
                Nov 15 at 4:34
















              Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
              – Floroz
              Nov 12 at 11:36






              Manipulate the string directly works, however I receive this error rb:60:in block in describe: Expected: "SOS", instead got: nil (Test::Error) I have added SOS to the dictionary and paired with '...---..." but it still returns nil
              – Floroz
              Nov 12 at 11:36














              What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
              – Floroz
              Nov 12 at 11:43






              What is not clear in "dividing into an array" is: you .split your string morse into an array of single morse word, then iterate over the single word, then I don't understand exactly the next iteration when you .join the value of MORSE_TO_ALPHA.
              – Floroz
              Nov 12 at 11:43














              Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
              – Cary Swoveland
              Nov 13 at 9:19




              Floors, I apologize for not replying to your comments earlier. I somehow missed them. It’s late now so I’ll look into the problems you mention tomorrow.
              – Cary Swoveland
              Nov 13 at 9:19












              Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
              – Floroz
              Nov 13 at 14:12






              Thank you Cary, I have actually managed to get past the issue by inserting the "SOS" in the dictionary manually and added an if statement just to ensure I could pass the test, and incurred in another error using the different versions of your code as it does not encode back the punctuation (".,!?").
              – Floroz
              Nov 13 at 14:12














              Floroz, I've edited my answer.
              – Cary Swoveland
              Nov 15 at 4:34




              Floroz, I've edited my answer.
              – Cary Swoveland
              Nov 15 at 4:34












              up vote
              1
              down vote













              Using Hash#key without replacing the array, rather creating a new one (use map! for replacement):



              array = [1,2,3,4,5]    
              hash = {a: 4, b: 7, c: 3}

              array.map { |el| hash.key(el) }
              # => [nil, nil, :c, :a, nil]


              You may want to think about using Hash#invert and simply referencing the elements by keys for performance reasons as Hash#key is O(n) while Hash# is O(1).



              array = [1,2,3,4,5]
              hash = {a: 4, b: 7, c: 3}
              inverted_hash = hash.invert

              array.map { |el| inverted_hash[el] }
              # => [nil, nil, :c, :a, nil]





              share|improve this answer



























                up vote
                1
                down vote













                Using Hash#key without replacing the array, rather creating a new one (use map! for replacement):



                array = [1,2,3,4,5]    
                hash = {a: 4, b: 7, c: 3}

                array.map { |el| hash.key(el) }
                # => [nil, nil, :c, :a, nil]


                You may want to think about using Hash#invert and simply referencing the elements by keys for performance reasons as Hash#key is O(n) while Hash# is O(1).



                array = [1,2,3,4,5]
                hash = {a: 4, b: 7, c: 3}
                inverted_hash = hash.invert

                array.map { |el| inverted_hash[el] }
                # => [nil, nil, :c, :a, nil]





                share|improve this answer

























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Using Hash#key without replacing the array, rather creating a new one (use map! for replacement):



                  array = [1,2,3,4,5]    
                  hash = {a: 4, b: 7, c: 3}

                  array.map { |el| hash.key(el) }
                  # => [nil, nil, :c, :a, nil]


                  You may want to think about using Hash#invert and simply referencing the elements by keys for performance reasons as Hash#key is O(n) while Hash# is O(1).



                  array = [1,2,3,4,5]
                  hash = {a: 4, b: 7, c: 3}
                  inverted_hash = hash.invert

                  array.map { |el| inverted_hash[el] }
                  # => [nil, nil, :c, :a, nil]





                  share|improve this answer














                  Using Hash#key without replacing the array, rather creating a new one (use map! for replacement):



                  array = [1,2,3,4,5]    
                  hash = {a: 4, b: 7, c: 3}

                  array.map { |el| hash.key(el) }
                  # => [nil, nil, :c, :a, nil]


                  You may want to think about using Hash#invert and simply referencing the elements by keys for performance reasons as Hash#key is O(n) while Hash# is O(1).



                  array = [1,2,3,4,5]
                  hash = {a: 4, b: 7, c: 3}
                  inverted_hash = hash.invert

                  array.map { |el| inverted_hash[el] }
                  # => [nil, nil, :c, :a, nil]






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 11 at 20:06

























                  answered Nov 11 at 19:23









                  Marcin Kołodziej

                  4,067315




                  4,067315






















                      up vote
                      0
                      down vote













                      assuming: arr = 'a b c d', which is not an arr, so please make that morse_string



                      def morse_code(morse_string)
                      new_elements =

                      # iterate over each character in the string,
                      morse_string.split(" ").each do |element|
                      if morse_dict[element]
                      # https://apidock.com/ruby/Array/push
                      new_elements.push( morse_dict[element] )
                      else
                      # whatever you want to do when there is no match
                      end
                      end
                      # re-create the string again, but with braille
                      # https://apidock.com/ruby/Array/join
                      new_elements.join(' ')
                      end

                      morse_string = 'a b c d'
                      morse_code(morse_string)





                      share|improve this answer

























                        up vote
                        0
                        down vote













                        assuming: arr = 'a b c d', which is not an arr, so please make that morse_string



                        def morse_code(morse_string)
                        new_elements =

                        # iterate over each character in the string,
                        morse_string.split(" ").each do |element|
                        if morse_dict[element]
                        # https://apidock.com/ruby/Array/push
                        new_elements.push( morse_dict[element] )
                        else
                        # whatever you want to do when there is no match
                        end
                        end
                        # re-create the string again, but with braille
                        # https://apidock.com/ruby/Array/join
                        new_elements.join(' ')
                        end

                        morse_string = 'a b c d'
                        morse_code(morse_string)





                        share|improve this answer























                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          assuming: arr = 'a b c d', which is not an arr, so please make that morse_string



                          def morse_code(morse_string)
                          new_elements =

                          # iterate over each character in the string,
                          morse_string.split(" ").each do |element|
                          if morse_dict[element]
                          # https://apidock.com/ruby/Array/push
                          new_elements.push( morse_dict[element] )
                          else
                          # whatever you want to do when there is no match
                          end
                          end
                          # re-create the string again, but with braille
                          # https://apidock.com/ruby/Array/join
                          new_elements.join(' ')
                          end

                          morse_string = 'a b c d'
                          morse_code(morse_string)





                          share|improve this answer












                          assuming: arr = 'a b c d', which is not an arr, so please make that morse_string



                          def morse_code(morse_string)
                          new_elements =

                          # iterate over each character in the string,
                          morse_string.split(" ").each do |element|
                          if morse_dict[element]
                          # https://apidock.com/ruby/Array/push
                          new_elements.push( morse_dict[element] )
                          else
                          # whatever you want to do when there is no match
                          end
                          end
                          # re-create the string again, but with braille
                          # https://apidock.com/ruby/Array/join
                          new_elements.join(' ')
                          end

                          morse_string = 'a b c d'
                          morse_code(morse_string)






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 11 at 19:36









                          awsmsce

                          788




                          788






























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                              ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

                              Guess what letter conforming each word