*args returns a list containing only those arguments that are even (PYTHON)












3















Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









share|improve this question

























  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

    – Loocid
    Nov 20 '18 at 1:50


















3















Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









share|improve this question

























  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

    – Loocid
    Nov 20 '18 at 1:50
















3












3








3








Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









share|improve this question
















Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)






python python-3.x






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share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 1:53









Austin

10.9k3828




10.9k3828










asked Nov 20 '18 at 1:46









Aarón MásAarón Más

183




183













  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

    – Loocid
    Nov 20 '18 at 1:50





















  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

    – Loocid
    Nov 20 '18 at 1:50



















Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

– Loocid
Nov 20 '18 at 1:50







Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.

– Loocid
Nov 20 '18 at 1:50














2 Answers
2






active

oldest

votes


















0














Do a list-comprehension which picks elements from args that matches our selection criteria:



def myfunc(*args):
return [n for n in args if n%2 == 0]

print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]





share|improve this answer































    0














    This also could be helpful, however, the previous comment looks more advanced:



    def myfunc(*args):
    lista =
    for i in list(args):
    if not i % 2:
    lista.append(i)
    return lista





    share|improve this answer

























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Do a list-comprehension which picks elements from args that matches our selection criteria:



      def myfunc(*args):
      return [n for n in args if n%2 == 0]

      print(myfunc(1,2,3,4,5,6,7,8,9,10))
      # [2, 4, 6, 8, 10]





      share|improve this answer




























        0














        Do a list-comprehension which picks elements from args that matches our selection criteria:



        def myfunc(*args):
        return [n for n in args if n%2 == 0]

        print(myfunc(1,2,3,4,5,6,7,8,9,10))
        # [2, 4, 6, 8, 10]





        share|improve this answer


























          0












          0








          0







          Do a list-comprehension which picks elements from args that matches our selection criteria:



          def myfunc(*args):
          return [n for n in args if n%2 == 0]

          print(myfunc(1,2,3,4,5,6,7,8,9,10))
          # [2, 4, 6, 8, 10]





          share|improve this answer













          Do a list-comprehension which picks elements from args that matches our selection criteria:



          def myfunc(*args):
          return [n for n in args if n%2 == 0]

          print(myfunc(1,2,3,4,5,6,7,8,9,10))
          # [2, 4, 6, 8, 10]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 1:52









          AustinAustin

          10.9k3828




          10.9k3828

























              0














              This also could be helpful, however, the previous comment looks more advanced:



              def myfunc(*args):
              lista =
              for i in list(args):
              if not i % 2:
              lista.append(i)
              return lista





              share|improve this answer






























                0














                This also could be helpful, however, the previous comment looks more advanced:



                def myfunc(*args):
                lista =
                for i in list(args):
                if not i % 2:
                lista.append(i)
                return lista





                share|improve this answer




























                  0












                  0








                  0







                  This also could be helpful, however, the previous comment looks more advanced:



                  def myfunc(*args):
                  lista =
                  for i in list(args):
                  if not i % 2:
                  lista.append(i)
                  return lista





                  share|improve this answer















                  This also could be helpful, however, the previous comment looks more advanced:



                  def myfunc(*args):
                  lista =
                  for i in list(args):
                  if not i % 2:
                  lista.append(i)
                  return lista






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jan 30 at 20:08









                  rickjerrity

                  709713




                  709713










                  answered Jan 30 at 19:40









                  mahyar khatirimahyar khatiri

                  32




                  32






























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