*args returns a list containing only those arguments that are even (PYTHON)
Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.
My code is wrong i know:
def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)
python python-3.x
add a comment |
Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.
My code is wrong i know:
def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)
python python-3.x
Create a list likeoutput =
then appendn
into it ifn
is even:output.append(n)
. Then returnoutput
at the end ofmyfunc
.
– Loocid
Nov 20 '18 at 1:50
add a comment |
Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.
My code is wrong i know:
def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)
python python-3.x
Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.
My code is wrong i know:
def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)
python python-3.x
python python-3.x
edited Nov 20 '18 at 1:53
Austin
10.9k3828
10.9k3828
asked Nov 20 '18 at 1:46
Aarón MásAarón Más
183
183
Create a list likeoutput =
then appendn
into it ifn
is even:output.append(n)
. Then returnoutput
at the end ofmyfunc
.
– Loocid
Nov 20 '18 at 1:50
add a comment |
Create a list likeoutput =
then appendn
into it ifn
is even:output.append(n)
. Then returnoutput
at the end ofmyfunc
.
– Loocid
Nov 20 '18 at 1:50
Create a list like
output =
then append n
into it if n
is even: output.append(n)
. Then return output
at the end of myfunc
.– Loocid
Nov 20 '18 at 1:50
Create a list like
output =
then append n
into it if n
is even: output.append(n)
. Then return output
at the end of myfunc
.– Loocid
Nov 20 '18 at 1:50
add a comment |
2 Answers
2
active
oldest
votes
Do a list-comprehension which picks elements from args
that matches our selection criteria:
def myfunc(*args):
return [n for n in args if n%2 == 0]
print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]
add a comment |
This also could be helpful, however, the previous comment looks more advanced:
def myfunc(*args):
lista =
for i in list(args):
if not i % 2:
lista.append(i)
return lista
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Do a list-comprehension which picks elements from args
that matches our selection criteria:
def myfunc(*args):
return [n for n in args if n%2 == 0]
print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]
add a comment |
Do a list-comprehension which picks elements from args
that matches our selection criteria:
def myfunc(*args):
return [n for n in args if n%2 == 0]
print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]
add a comment |
Do a list-comprehension which picks elements from args
that matches our selection criteria:
def myfunc(*args):
return [n for n in args if n%2 == 0]
print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]
Do a list-comprehension which picks elements from args
that matches our selection criteria:
def myfunc(*args):
return [n for n in args if n%2 == 0]
print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]
answered Nov 20 '18 at 1:52
AustinAustin
10.9k3828
10.9k3828
add a comment |
add a comment |
This also could be helpful, however, the previous comment looks more advanced:
def myfunc(*args):
lista =
for i in list(args):
if not i % 2:
lista.append(i)
return lista
add a comment |
This also could be helpful, however, the previous comment looks more advanced:
def myfunc(*args):
lista =
for i in list(args):
if not i % 2:
lista.append(i)
return lista
add a comment |
This also could be helpful, however, the previous comment looks more advanced:
def myfunc(*args):
lista =
for i in list(args):
if not i % 2:
lista.append(i)
return lista
This also could be helpful, however, the previous comment looks more advanced:
def myfunc(*args):
lista =
for i in list(args):
if not i % 2:
lista.append(i)
return lista
edited Jan 30 at 20:08
rickjerrity
709713
709713
answered Jan 30 at 19:40
mahyar khatirimahyar khatiri
32
32
add a comment |
add a comment |
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Create a list like
output =
then appendn
into it ifn
is even:output.append(n)
. Then returnoutput
at the end ofmyfunc
.– Loocid
Nov 20 '18 at 1:50