Breadth First Search Counter Example
Statement:
"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."
I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.
I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.
Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.
graph-theory
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Statement:
"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."
I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.
I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.
Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.
graph-theory
Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05
add a comment |
Statement:
"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."
I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.
I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.
Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.
graph-theory
Statement:
"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."
I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.
I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.
Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.
graph-theory
graph-theory
edited Nov 20 '18 at 2:18
John Larkos
asked Nov 20 '18 at 2:01
John LarkosJohn Larkos
167
167
Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05
add a comment |
Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05
Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05
Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05
add a comment |
1 Answer
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Confirm your graph is unweighted and undirected ?
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Confirm your graph is unweighted and undirected ?
add a comment |
Confirm your graph is unweighted and undirected ?
add a comment |
Confirm your graph is unweighted and undirected ?
Confirm your graph is unweighted and undirected ?
answered Nov 22 '18 at 15:37
TheWildHealerTheWildHealer
409217
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Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 '18 at 2:05