Concatenate columns based on separator in order
0
I have 2 columns that I would like to concatenate into a single column. Each column has separators ">" and each row either has the same number of separators or none at all.
col1 <- c('A > B > C > B > B > A > B > A > C',
'A > B',
'A > C > B',
'A',
'A > B > B > C')
col2 <- c('D > E > E > E > F > F > D > F > E',
'D > F',
'F > F > E',
'E',
'E > F > D > D')
df <- data.frame(col1, col2)
I would like to end up with a data frame like this:
col1
A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E
A|D > B|F
A|F > C|F > B|E
A|E
A|E > B|F > B|D > C|D
r
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
add a comment |
0
I have 2 columns that I would like to concatenate into a single column. Each column has separators ">" and each row either has the same number of separators or none at all.
col1 <- c('A > B > C > B > B > A > B > A > C',
'A > B',
'A > C > B',
'A',
'A > B > B > C')
col2 <- c('D > E > E > E > F > F > D > F > E',
'D > F',
'F > F > E',
'E',
'E > F > D > D')
df <- data.frame(col1, col2)
I would like to end up with a data frame like this:
col1
A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E
A|D > B|F
A|F > C|F > B|E
A|E
A|E > B|F > B|D > C|D
r
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
1
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27
add a comment |
0
0
0
I have 2 columns that I would like to concatenate into a single column. Each column has separators ">" and each row either has the same number of separators or none at all.
col1 <- c('A > B > C > B > B > A > B > A > C',
'A > B',
'A > C > B',
'A',
'A > B > B > C')
col2 <- c('D > E > E > E > F > F > D > F > E',
'D > F',
'F > F > E',
'E',
'E > F > D > D')
df <- data.frame(col1, col2)
I would like to end up with a data frame like this:
col1
A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E
A|D > B|F
A|F > C|F > B|E
A|E
A|E > B|F > B|D > C|D
r
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
I have 2 columns that I would like to concatenate into a single column. Each column has separators ">" and each row either has the same number of separators or none at all.
col1 <- c('A > B > C > B > B > A > B > A > C',
'A > B',
'A > C > B',
'A',
'A > B > B > C')
col2 <- c('D > E > E > E > F > F > D > F > E',
'D > F',
'F > F > E',
'E',
'E > F > D > D')
df <- data.frame(col1, col2)
I would like to end up with a data frame like this:
col1
A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E
A|D > B|F
A|F > C|F > B|E
A|E
A|E > B|F > B|D > C|D
r
r
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
asked Nov 19 '18 at 18:09
ericbrownaustinericbrownaustin
309316
309316
1
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27
add a comment |
1
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27
1
1
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27
add a comment |
1 Answer
1
active
oldest
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You are looking for:
mapply(paste,strsplit(col1,' > '),strsplit(col2,' > '),sep='|',collapse=' > ')
[1] "A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E"
[2] "A|D > B|F"
[3] "A|F > C|F > B|E"
[4] "A|E"
[5] "A|E > B|F > B|D > C|D"
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You are looking for:
mapply(paste,strsplit(col1,' > '),strsplit(col2,' > '),sep='|',collapse=' > ')
[1] "A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E"
[2] "A|D > B|F"
[3] "A|F > C|F > B|E"
[4] "A|E"
[5] "A|E > B|F > B|D > C|D"
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
add a comment |
1
You are looking for:
mapply(paste,strsplit(col1,' > '),strsplit(col2,' > '),sep='|',collapse=' > ')
[1] "A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E"
[2] "A|D > B|F"
[3] "A|F > C|F > B|E"
[4] "A|E"
[5] "A|E > B|F > B|D > C|D"
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
add a comment |
1
1
1
You are looking for:
mapply(paste,strsplit(col1,' > '),strsplit(col2,' > '),sep='|',collapse=' > ')
[1] "A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E"
[2] "A|D > B|F"
[3] "A|F > C|F > B|E"
[4] "A|E"
[5] "A|E > B|F > B|D > C|D"
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
You are looking for:
mapply(paste,strsplit(col1,' > '),strsplit(col2,' > '),sep='|',collapse=' > ')
[1] "A|D > B|E > C|E > B|E > B|F > A|F > B|D > A|F > C|E"
[2] "A|D > B|F"
[3] "A|F > C|F > B|E"
[4] "A|E"
[5] "A|E > B|F > B|D > C|D"
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
answered Nov 19 '18 at 18:19
OnyambuOnyambu
15.8k1521
15.8k1521
add a comment |
add a comment |
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1
My original try comprised of calculating the max number of separators and using that in a split function. df$pathlength <- stringr::str_count(df$col1, ">") + 1 stringr::str_split_fixed(df$col1,">",max(df$pathlength)) stringr::str_split_fixed(df$col2,">",max(df$pathlength)) This gives 2 data frames with equal number of columns, however, I am not sure how to join the 2 to keep the relationship between each original combination.
– ericbrownaustin
Nov 19 '18 at 18:27