showing highest score every time that the user play the game
0
I wrote a python that a user guess a number. If I want to show the highest score every time when the user guessed the number correctly, what should I add to the code?
import random
correct_answer = random.randint(1, 100)
count = 0
while True :
number = int(input("Enter a number: "))
count += 1
if correct_answer == number :
print("Correct.", count, "tries")
one=input("Do you want to play it again?")
if one=='no':
print("Okay")
break
elif one=='yes':
print("okay")
elif correct_answer > number :
print("greater than", number)
else :
print("less than", number)
python
asked Nov 19 '18 at 18:23
LauraLaura
42
add a comment |
0
I wrote a python that a user guess a number. If I want to show the highest score every time when the user guessed the number correctly, what should I add to the code?
import random
correct_answer = random.randint(1, 100)
count = 0
while True :
number = int(input("Enter a number: "))
count += 1
if correct_answer == number :
print("Correct.", count, "tries")
one=input("Do you want to play it again?")
if one=='no':
print("Okay")
break
elif one=='yes':
print("okay")
elif correct_answer > number :
print("greater than", number)
else :
print("less than", number)
python
asked Nov 19 '18 at 18:23
LauraLaura
42
addprint (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must movecorrect_answer = random.randint(1, 100)into while-loop.
– Psytho
Nov 19 '18 at 18:25
add a comment |
0
0
0
I wrote a python that a user guess a number. If I want to show the highest score every time when the user guessed the number correctly, what should I add to the code?
import random
correct_answer = random.randint(1, 100)
count = 0
while True :
number = int(input("Enter a number: "))
count += 1
if correct_answer == number :
print("Correct.", count, "tries")
one=input("Do you want to play it again?")
if one=='no':
print("Okay")
break
elif one=='yes':
print("okay")
elif correct_answer > number :
print("greater than", number)
else :
print("less than", number)
python
asked Nov 19 '18 at 18:23
LauraLaura
42
I wrote a python that a user guess a number. If I want to show the highest score every time when the user guessed the number correctly, what should I add to the code?
import random
correct_answer = random.randint(1, 100)
count = 0
while True :
number = int(input("Enter a number: "))
count += 1
if correct_answer == number :
print("Correct.", count, "tries")
one=input("Do you want to play it again?")
if one=='no':
print("Okay")
break
elif one=='yes':
print("okay")
elif correct_answer > number :
print("greater than", number)
else :
print("less than", number)
python
python
asked Nov 19 '18 at 18:23
LauraLaura
42
asked Nov 19 '18 at 18:23
LauraLaura
42
asked Nov 19 '18 at 18:23
LauraLaura
42
asked Nov 19 '18 at 18:23
LauraLaura
42
asked Nov 19 '18 at 18:23
LauraLaura
42
42
addprint (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must movecorrect_answer = random.randint(1, 100)into while-loop.
– Psytho
Nov 19 '18 at 18:25
add a comment |
addprint (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must movecorrect_answer = random.randint(1, 100)into while-loop.
– Psytho
Nov 19 '18 at 18:25
add
print (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must move correct_answer = random.randint(1, 100) into while-loop.– Psytho
Nov 19 '18 at 18:25
add
print (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must move correct_answer = random.randint(1, 100) into while-loop.– Psytho
Nov 19 '18 at 18:25
add a comment |
0
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add
print (score). But you have to calculate the score which you don't. PS. The secret number is always the same. You must movecorrect_answer = random.randint(1, 100)into while-loop.– Psytho
Nov 19 '18 at 18:25