convert separated lines in property to comma separated string in ant
I have property named sound that has string like this and want to convert to string likethis one and again store in same property. I want do do it in ant.please help.
xml string properties ant
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
add a comment |
I have property named sound that has string like this and want to convert to string likethis one and again store in same property. I want do do it in ant.please help.
xml string properties ant
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12
add a comment |
I have property named sound that has string like this and want to convert to string likethis one and again store in same property. I want do do it in ant.please help.
xml string properties ant
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
I have property named sound that has string like this and want to convert to string likethis one and again store in same property. I want do do it in ant.please help.
xml string properties ant
xml string properties ant
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
asked Nov 19 '18 at 16:33
sourabh malavadesourabh malavade
13
13
What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12
add a comment |
What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12
What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12
What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12
add a comment |
1 Answer
1
active
oldest
votes
Use loadresource, f.e. create a new property foobar from your existing foo property:
<project>
<property name="foo" value="hotfix_master_02.sql${line.separator}hotfix_master_07.sql${line.separator}hotfix_metadb_03.sql"/>
<loadresource property="foobar">
<propertyresource name="foo"/>
<filterchain>
<replacestring byline="false" from="${line.separator}" to=","/>
</filterchain>
</loadresource>
<echo>${foobar}</echo>
</project>
output
[echo] ${foobar}} => hotfix_master_02.sql,hotfix_master_07.sql,hotfix_metadb_03.sql
Should also work if property foo is loaded from a file.
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use loadresource, f.e. create a new property foobar from your existing foo property:
<project>
<property name="foo" value="hotfix_master_02.sql${line.separator}hotfix_master_07.sql${line.separator}hotfix_metadb_03.sql"/>
<loadresource property="foobar">
<propertyresource name="foo"/>
<filterchain>
<replacestring byline="false" from="${line.separator}" to=","/>
</filterchain>
</loadresource>
<echo>${foobar}</echo>
</project>
output
[echo] ${foobar}} => hotfix_master_02.sql,hotfix_master_07.sql,hotfix_metadb_03.sql
Should also work if property foo is loaded from a file.
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
add a comment |
Use loadresource, f.e. create a new property foobar from your existing foo property:
<project>
<property name="foo" value="hotfix_master_02.sql${line.separator}hotfix_master_07.sql${line.separator}hotfix_metadb_03.sql"/>
<loadresource property="foobar">
<propertyresource name="foo"/>
<filterchain>
<replacestring byline="false" from="${line.separator}" to=","/>
</filterchain>
</loadresource>
<echo>${foobar}</echo>
</project>
output
[echo] ${foobar}} => hotfix_master_02.sql,hotfix_master_07.sql,hotfix_metadb_03.sql
Should also work if property foo is loaded from a file.
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
add a comment |
Use loadresource, f.e. create a new property foobar from your existing foo property:
<project>
<property name="foo" value="hotfix_master_02.sql${line.separator}hotfix_master_07.sql${line.separator}hotfix_metadb_03.sql"/>
<loadresource property="foobar">
<propertyresource name="foo"/>
<filterchain>
<replacestring byline="false" from="${line.separator}" to=","/>
</filterchain>
</loadresource>
<echo>${foobar}</echo>
</project>
output
[echo] ${foobar}} => hotfix_master_02.sql,hotfix_master_07.sql,hotfix_metadb_03.sql
Should also work if property foo is loaded from a file.
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
Use loadresource, f.e. create a new property foobar from your existing foo property:
<project>
<property name="foo" value="hotfix_master_02.sql${line.separator}hotfix_master_07.sql${line.separator}hotfix_metadb_03.sql"/>
<loadresource property="foobar">
<propertyresource name="foo"/>
<filterchain>
<replacestring byline="false" from="${line.separator}" to=","/>
</filterchain>
</loadresource>
<echo>${foobar}</echo>
</project>
output
[echo] ${foobar}} => hotfix_master_02.sql,hotfix_master_07.sql,hotfix_metadb_03.sql
Should also work if property foo is loaded from a file.
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
answered Nov 26 '18 at 14:40
RebseRebse
9,38822554
9,38822554
add a comment |
add a comment |
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What have you tried so far? Properties in Ant a general not mutable.
– martin clayton
Nov 20 '18 at 7:12