Variable inside regular expression php





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6















I a stuck with regular expression and i need help.
So basically i want to do somethning like this:



$data = "hi";

$number = 4;



$reg = '/^[a-z"]{1,4}$/';





if(preg_match($reg,$data)) {

    echo 'Match';   

}else {

    echo 'No match';

}


But i want to use variable



$reg = '/^[a-z"]{1, variable here }$/';


I have tried:



$reg = '/^[a-z"]{1, '. $number .'}$/';



$reg = "/^[a-z"]{1, $number}$/";


But not getting right result.



Tnx for help






php regex variables







share|improve this question


















  • 1





    In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

    – Alex W
    Sep 12 '14 at 17:54






  • 3





    @AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

    – Drecker
    Sep 12 '14 at 18:00








  • 1





    @Drecker I was referring to the example above that. Where he put variable here.

    – Alex W
    Sep 12 '14 at 18:01


















6















I a stuck with regular expression and i need help.
So basically i want to do somethning like this:



$data = "hi";

$number = 4;



$reg = '/^[a-z"]{1,4}$/';





if(preg_match($reg,$data)) {

    echo 'Match';   

}else {

    echo 'No match';

}


But i want to use variable



$reg = '/^[a-z"]{1, variable here }$/';


I have tried:



$reg = '/^[a-z"]{1, '. $number .'}$/';



$reg = "/^[a-z"]{1, $number}$/";


But not getting right result.



Tnx for help






php regex variables







share|improve this question


















  • 1





    In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

    – Alex W
    Sep 12 '14 at 17:54






  • 3





    @AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

    – Drecker
    Sep 12 '14 at 18:00








  • 1





    @Drecker I was referring to the example above that. Where he put variable here.

    – Alex W
    Sep 12 '14 at 18:01














6












6








6


2






I a stuck with regular expression and i need help.
So basically i want to do somethning like this:



$data = "hi";

$number = 4;



$reg = '/^[a-z"]{1,4}$/';





if(preg_match($reg,$data)) {

    echo 'Match';   

}else {

    echo 'No match';

}


But i want to use variable



$reg = '/^[a-z"]{1, variable here }$/';


I have tried:



$reg = '/^[a-z"]{1, '. $number .'}$/';



$reg = "/^[a-z"]{1, $number}$/";


But not getting right result.



Tnx for help






php regex variables







share|improve this question














I a stuck with regular expression and i need help.
So basically i want to do somethning like this:



$data = "hi";

$number = 4;



$reg = '/^[a-z"]{1,4}$/';





if(preg_match($reg,$data)) {

    echo 'Match';   

}else {

    echo 'No match';

}


But i want to use variable



$reg = '/^[a-z"]{1, variable here }$/';


I have tried:



$reg = '/^[a-z"]{1, '. $number .'}$/';



$reg = "/^[a-z"]{1, $number}$/";


But not getting right result.



Tnx for help






php regex variables




php regex variables






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Sep 12 '14 at 17:51









EstSiimEstSiim

126129




126129








  • 1





    In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

    – Alex W
    Sep 12 '14 at 17:54






  • 3





    @AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

    – Drecker
    Sep 12 '14 at 18:00








  • 1





    @Drecker I was referring to the example above that. Where he put variable here.

    – Alex W
    Sep 12 '14 at 18:01














  • 1





    In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

    – Alex W
    Sep 12 '14 at 17:54






  • 3





    @AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

    – Drecker
    Sep 12 '14 at 18:00








  • 1





    @Drecker I was referring to the example above that. Where he put variable here.

    – Alex W
    Sep 12 '14 at 18:01








1




1





In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

– Alex W
Sep 12 '14 at 17:54





In the first example, you are using single quotes which prevents PHP from parsing your variable as a variable.

– Alex W
Sep 12 '14 at 17:54




3




3





@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

– Drecker
Sep 12 '14 at 18:00







@AlexW - it doesn't matter which quotes did he use, since he split the string to two parts and add $number via . operator

– Drecker
Sep 12 '14 at 18:00






1




1





@Drecker I was referring to the example above that. Where he put variable here.

– Alex W
Sep 12 '14 at 18:01





@Drecker I was referring to the example above that. Where he put variable here.

– Alex W
Sep 12 '14 at 18:01












2 Answers
2






active

oldest

votes


















17














In the first example you have space where you shouldn't have one,



you have:



$reg = '/^[a-z"]{1, '. $number .'}$/';


your should have:



$reg = '/^[a-z"]{1,'. $number .'}$/';


then it works just fine



Update: You have same error in second example - thanks to AbraCadaver






share|improve this answer
























  • @AbraCadaver - thanks, i've edited answer so it will be more visible

    – Drecker
    Sep 12 '14 at 18:03



















1














Another way to use variables in regex is through the use of sprintf.



For example:



$nonWhiteSpace = "^s";

$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);

var_dump($pattern); //gives you /[^s]{1,10}/





share|improve this answer


























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    17














    In the first example you have space where you shouldn't have one,



    you have:



    $reg = '/^[a-z"]{1, '. $number .'}$/';


    your should have:



    $reg = '/^[a-z"]{1,'. $number .'}$/';


    then it works just fine



    Update: You have same error in second example - thanks to AbraCadaver






    share|improve this answer
























    • @AbraCadaver - thanks, i've edited answer so it will be more visible

      – Drecker
      Sep 12 '14 at 18:03
















    17














    In the first example you have space where you shouldn't have one,



    you have:



    $reg = '/^[a-z"]{1, '. $number .'}$/';


    your should have:



    $reg = '/^[a-z"]{1,'. $number .'}$/';


    then it works just fine



    Update: You have same error in second example - thanks to AbraCadaver






    share|improve this answer
























    • @AbraCadaver - thanks, i've edited answer so it will be more visible

      – Drecker
      Sep 12 '14 at 18:03














    17












    17








    17







    In the first example you have space where you shouldn't have one,



    you have:



    $reg = '/^[a-z"]{1, '. $number .'}$/';


    your should have:



    $reg = '/^[a-z"]{1,'. $number .'}$/';


    then it works just fine



    Update: You have same error in second example - thanks to AbraCadaver






    share|improve this answer













    In the first example you have space where you shouldn't have one,



    you have:



    $reg = '/^[a-z"]{1, '. $number .'}$/';


    your should have:



    $reg = '/^[a-z"]{1,'. $number .'}$/';


    then it works just fine



    Update: You have same error in second example - thanks to AbraCadaver







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Sep 12 '14 at 17:57









    DreckerDrecker

    421417




    421417













    • @AbraCadaver - thanks, i've edited answer so it will be more visible

      – Drecker
      Sep 12 '14 at 18:03



















    • @AbraCadaver - thanks, i've edited answer so it will be more visible

      – Drecker
      Sep 12 '14 at 18:03

















    @AbraCadaver - thanks, i've edited answer so it will be more visible

    – Drecker
    Sep 12 '14 at 18:03





    @AbraCadaver - thanks, i've edited answer so it will be more visible

    – Drecker
    Sep 12 '14 at 18:03













    1














    Another way to use variables in regex is through the use of sprintf.



    For example:



    $nonWhiteSpace = "^s";
    
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
    
var_dump($pattern); //gives you /[^s]{1,10}/





    share|improve this answer






























      1














      Another way to use variables in regex is through the use of sprintf.



      For example:



      $nonWhiteSpace = "^s";
      
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
      
var_dump($pattern); //gives you /[^s]{1,10}/





      share|improve this answer




























        1












        1








        1







        Another way to use variables in regex is through the use of sprintf.



        For example:



        $nonWhiteSpace = "^s";
        
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
        
var_dump($pattern); //gives you /[^s]{1,10}/





        share|improve this answer















        Another way to use variables in regex is through the use of sprintf.



        For example:



        $nonWhiteSpace = "^s";
        
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
        
var_dump($pattern); //gives you /[^s]{1,10}/






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Dec 21 '17 at 17:29









        sintakonte

        4,11041430




        4,11041430










        answered Dec 21 '17 at 17:10









        cbernard73cbernard73

        213




        213






























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