Hex Byte calculation from Java to Javascript
Getting a mismatch when trying to convert the Java code below to JavaScript, the output is every so slightly different.
Java
byte ex = new byte[26];
bits = 304;
for (int loop=0; loop<8; ++loop) {
ex[ex.length-1-loop] = (byte)(0xFF&(bits>>(loop*8)));
System.out.println("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
Ex value: 48
Ex value: 1
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
JavaScript
var ex = new Int8Array(26);
var bits = 304;
for (var loop = 0; loop < 8; ++loop) {
ex[ex.length - 1 - loop] = (0xFF & (bits >> (loop * 8)));
console.log("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
You can see the errant 48 and 1 in the JavaScript. The Java is working as expected, I need the JS to match it.
For the errant calculations loop is 4 (for 48) and 5 (for 1). Both need to be zero.
That being said I tried the Java again without assigning the value to the array and got the SAME as JavaScript. I can't figure out why assigning it to the byte array makes a difference:
byte c = (byte)(0xFF&(304>>(4*8)));
int d = (byte)(0xFF&(304>>(5*8)));
System.out.println("c: " + c);
System.out.println("d: " + d);
Output:
c: 48
d: 1
Being under time pressures doesn't allow me the luxury of spending hours diving into it further so I'm hoping this great community can shed some light on it!
Thanks
EDIT
I dove down a bit more and found what appears to be occurring, see Java hex calculation. When a solution is found I'll delete one of these questions.
javascript java arrays
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
add a comment |
Getting a mismatch when trying to convert the Java code below to JavaScript, the output is every so slightly different.
Java
byte ex = new byte[26];
bits = 304;
for (int loop=0; loop<8; ++loop) {
ex[ex.length-1-loop] = (byte)(0xFF&(bits>>(loop*8)));
System.out.println("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
Ex value: 48
Ex value: 1
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
JavaScript
var ex = new Int8Array(26);
var bits = 304;
for (var loop = 0; loop < 8; ++loop) {
ex[ex.length - 1 - loop] = (0xFF & (bits >> (loop * 8)));
console.log("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
You can see the errant 48 and 1 in the JavaScript. The Java is working as expected, I need the JS to match it.
For the errant calculations loop is 4 (for 48) and 5 (for 1). Both need to be zero.
That being said I tried the Java again without assigning the value to the array and got the SAME as JavaScript. I can't figure out why assigning it to the byte array makes a difference:
byte c = (byte)(0xFF&(304>>(4*8)));
int d = (byte)(0xFF&(304>>(5*8)));
System.out.println("c: " + c);
System.out.println("d: " + d);
Output:
c: 48
d: 1
Being under time pressures doesn't allow me the luxury of spending hours diving into it further so I'm hoping this great community can shed some light on it!
Thanks
EDIT
I dove down a bit more and found what appears to be occurring, see Java hex calculation. When a solution is found I'll delete one of these questions.
javascript java arrays
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
add a comment |
Getting a mismatch when trying to convert the Java code below to JavaScript, the output is every so slightly different.
Java
byte ex = new byte[26];
bits = 304;
for (int loop=0; loop<8; ++loop) {
ex[ex.length-1-loop] = (byte)(0xFF&(bits>>(loop*8)));
System.out.println("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
Ex value: 48
Ex value: 1
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
JavaScript
var ex = new Int8Array(26);
var bits = 304;
for (var loop = 0; loop < 8; ++loop) {
ex[ex.length - 1 - loop] = (0xFF & (bits >> (loop * 8)));
console.log("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
You can see the errant 48 and 1 in the JavaScript. The Java is working as expected, I need the JS to match it.
For the errant calculations loop is 4 (for 48) and 5 (for 1). Both need to be zero.
That being said I tried the Java again without assigning the value to the array and got the SAME as JavaScript. I can't figure out why assigning it to the byte array makes a difference:
byte c = (byte)(0xFF&(304>>(4*8)));
int d = (byte)(0xFF&(304>>(5*8)));
System.out.println("c: " + c);
System.out.println("d: " + d);
Output:
c: 48
d: 1
Being under time pressures doesn't allow me the luxury of spending hours diving into it further so I'm hoping this great community can shed some light on it!
Thanks
EDIT
I dove down a bit more and found what appears to be occurring, see Java hex calculation. When a solution is found I'll delete one of these questions.
javascript java arrays
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
Getting a mismatch when trying to convert the Java code below to JavaScript, the output is every so slightly different.
Java
byte ex = new byte[26];
bits = 304;
for (int loop=0; loop<8; ++loop) {
ex[ex.length-1-loop] = (byte)(0xFF&(bits>>(loop*8)));
System.out.println("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
Ex value: 48
Ex value: 1
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
Ex value: 0
JavaScript
var ex = new Int8Array(26);
var bits = 304;
for (var loop = 0; loop < 8; ++loop) {
ex[ex.length - 1 - loop] = (0xFF & (bits >> (loop * 8)));
console.log("Ex value: " + ex[ex.length-1-loop]);
}
Console output:
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
> "Ex value: 48"
> "Ex value: 1"
> "Ex value: 0"
> "Ex value: 0"
You can see the errant 48 and 1 in the JavaScript. The Java is working as expected, I need the JS to match it.
For the errant calculations loop is 4 (for 48) and 5 (for 1). Both need to be zero.
That being said I tried the Java again without assigning the value to the array and got the SAME as JavaScript. I can't figure out why assigning it to the byte array makes a difference:
byte c = (byte)(0xFF&(304>>(4*8)));
int d = (byte)(0xFF&(304>>(5*8)));
System.out.println("c: " + c);
System.out.println("d: " + d);
Output:
c: 48
d: 1
Being under time pressures doesn't allow me the luxury of spending hours diving into it further so I'm hoping this great community can shed some light on it!
Thanks
EDIT
I dove down a bit more and found what appears to be occurring, see Java hex calculation. When a solution is found I'll delete one of these questions.
javascript java arrays
javascript java arrays
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
edited Nov 14 '18 at 1:17
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
asked Nov 13 '18 at 23:51
Dan James Palmer
93552050
93552050
add a comment |
add a comment |
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