remove objects with a specific `key: value` from an array
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
];
_.remove(array, function(n) {
return _.includes([ 1,3 ], n.id);
});
lodash
asked Nov 14 '18 at 0:14
farm command
6519
add a comment |
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
];
_.remove(array, function(n) {
return _.includes([ 1,3 ], n.id);
});
lodash
asked Nov 14 '18 at 0:14
farm command
6519
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
];
_.remove(array, function(n) {
return _.includes([ 1,3 ], n.id);
});
lodash
asked Nov 14 '18 at 0:14
farm command
6519
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
{id:1,b:22},
{id:2,b:44},
{id:3,b:56},
{id:4,b:-29}
];
_.remove(array, function(n) {
return _.includes([ 1,3 ], n.id);
});
lodash
lodash
asked Nov 14 '18 at 0:14
farm command
6519
asked Nov 14 '18 at 0:14
farm command
6519
asked Nov 14 '18 at 0:14
farm command
6519
asked Nov 14 '18 at 0:14
farm command
6519
asked Nov 14 '18 at 0:14
farm command
6519
6519
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
1 Answer
1
active
oldest
votes
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
Akrion
9,39211224
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
Akrion
9,39211224
add a comment |
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
Akrion
9,39211224
add a comment |
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
Akrion
9,39211224
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>let data = [{id:1,b:22},{id:2,b:44},{id:3,b:56},{id:4,b:-29}]
const result = _.pullAllBy(data, [{id:1},{id:3}], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)let data = [{ id: 1, b: 22 }, { id: 2, b: 44 }, { id: 3, b: 56 }, { id: 4, b: -29 }]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
Akrion
9,39211224
edited Nov 14 '18 at 17:29
answered Nov 14 '18 at 0:49
Akrion
9,39211224
answered Nov 14 '18 at 0:49
Akrion
9,39211224
answered Nov 14 '18 at 0:49
Akrion
9,39211224
9,39211224
add a comment |
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Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17