Python re.split and re.findall: grouping and capturing
I have strings like "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3" and "00:00 Segment 1 20:0 Segment 2" and want to use re.split() and re.findall() to find all the timestamps and segment names. But I am having problem to achieve optional group without the capturing effect. Here are what I got:
str_1 = "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3"
str_2 = "00:00 Segment 1 20:0 Segment 2"
re.findall(r'dd?:dd?:dd?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
re.split(r'dd?:dd?:dd?', str_1)
=> ['', ' Segment 1 ', ' Segment 2 ', ' Segment 3']
the above works fine but won't be able to handle str_2. If I made the third pair of numbers , it just returns the optional group
re.findall(r'dd?:dd?(:dd?)?', str_1)
=> [':00', ':00', ':00']
re.split(r'dd?:dd?(:dd?)?', str_1)
=> ['', ':00', ' Segment 1 ', ':00', ' Segment 2 ', ':00', ' Segment 3']
re.findall(r'dd?:dd?(:dd?)?', str_2)
=> ['', '']
re.split(r'dd?:dd?(:dd?)?', str_2)
=> ['', None, ' Segment 1 ', None, ' Segment 2']
However, if I made the optional group without capturing, str_2 works fine but results are mixed with str_1
re.findall(r'dd?:dd?(?:dd?)?', str_1)
=> ['00:00', '00:20', '8:00']
re.split(r'dd?:dd?(?:dd?)?', str_1)
=> ['', ':00 Segment 1 ', ':00 Segment 2 ', ':00 Segment 3']
re.findall(r'dd?:dd?(?:dd?)?', str_2)
=> ['00:00', '20:0']
re.split(r'dd?:dd?(?:dd?)?', str_2)
=> ['', ' Segment 1 ', ' Segment 2']
I want to find a regex which works fine on both str_ and str_2, kind of have the optional group but without the capturing effect. Anyway to achieve that?
python regex
asked Nov 14 '18 at 1:16
hanaZ
10019
add a comment |
I have strings like "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3" and "00:00 Segment 1 20:0 Segment 2" and want to use re.split() and re.findall() to find all the timestamps and segment names. But I am having problem to achieve optional group without the capturing effect. Here are what I got:
str_1 = "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3"
str_2 = "00:00 Segment 1 20:0 Segment 2"
re.findall(r'dd?:dd?:dd?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
re.split(r'dd?:dd?:dd?', str_1)
=> ['', ' Segment 1 ', ' Segment 2 ', ' Segment 3']
the above works fine but won't be able to handle str_2. If I made the third pair of numbers , it just returns the optional group
re.findall(r'dd?:dd?(:dd?)?', str_1)
=> [':00', ':00', ':00']
re.split(r'dd?:dd?(:dd?)?', str_1)
=> ['', ':00', ' Segment 1 ', ':00', ' Segment 2 ', ':00', ' Segment 3']
re.findall(r'dd?:dd?(:dd?)?', str_2)
=> ['', '']
re.split(r'dd?:dd?(:dd?)?', str_2)
=> ['', None, ' Segment 1 ', None, ' Segment 2']
However, if I made the optional group without capturing, str_2 works fine but results are mixed with str_1
re.findall(r'dd?:dd?(?:dd?)?', str_1)
=> ['00:00', '00:20', '8:00']
re.split(r'dd?:dd?(?:dd?)?', str_1)
=> ['', ':00 Segment 1 ', ':00 Segment 2 ', ':00 Segment 3']
re.findall(r'dd?:dd?(?:dd?)?', str_2)
=> ['00:00', '20:0']
re.split(r'dd?:dd?(?:dd?)?', str_2)
=> ['', ' Segment 1 ', ' Segment 2']
I want to find a regex which works fine on both str_ and str_2, kind of have the optional group but without the capturing effect. Anyway to achieve that?
python regex
asked Nov 14 '18 at 1:16
hanaZ
10019
add a comment |
I have strings like "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3" and "00:00 Segment 1 20:0 Segment 2" and want to use re.split() and re.findall() to find all the timestamps and segment names. But I am having problem to achieve optional group without the capturing effect. Here are what I got:
str_1 = "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3"
str_2 = "00:00 Segment 1 20:0 Segment 2"
re.findall(r'dd?:dd?:dd?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
re.split(r'dd?:dd?:dd?', str_1)
=> ['', ' Segment 1 ', ' Segment 2 ', ' Segment 3']
the above works fine but won't be able to handle str_2. If I made the third pair of numbers , it just returns the optional group
re.findall(r'dd?:dd?(:dd?)?', str_1)
=> [':00', ':00', ':00']
re.split(r'dd?:dd?(:dd?)?', str_1)
=> ['', ':00', ' Segment 1 ', ':00', ' Segment 2 ', ':00', ' Segment 3']
re.findall(r'dd?:dd?(:dd?)?', str_2)
=> ['', '']
re.split(r'dd?:dd?(:dd?)?', str_2)
=> ['', None, ' Segment 1 ', None, ' Segment 2']
However, if I made the optional group without capturing, str_2 works fine but results are mixed with str_1
re.findall(r'dd?:dd?(?:dd?)?', str_1)
=> ['00:00', '00:20', '8:00']
re.split(r'dd?:dd?(?:dd?)?', str_1)
=> ['', ':00 Segment 1 ', ':00 Segment 2 ', ':00 Segment 3']
re.findall(r'dd?:dd?(?:dd?)?', str_2)
=> ['00:00', '20:0']
re.split(r'dd?:dd?(?:dd?)?', str_2)
=> ['', ' Segment 1 ', ' Segment 2']
I want to find a regex which works fine on both str_ and str_2, kind of have the optional group but without the capturing effect. Anyway to achieve that?
python regex
asked Nov 14 '18 at 1:16
hanaZ
10019
I have strings like "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3" and "00:00 Segment 1 20:0 Segment 2" and want to use re.split() and re.findall() to find all the timestamps and segment names. But I am having problem to achieve optional group without the capturing effect. Here are what I got:
str_1 = "00:00:00 Segment 1 00:20:00 Segment 2 8:00:00 Segment 3"
str_2 = "00:00 Segment 1 20:0 Segment 2"
re.findall(r'dd?:dd?:dd?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
re.split(r'dd?:dd?:dd?', str_1)
=> ['', ' Segment 1 ', ' Segment 2 ', ' Segment 3']
the above works fine but won't be able to handle str_2. If I made the third pair of numbers , it just returns the optional group
re.findall(r'dd?:dd?(:dd?)?', str_1)
=> [':00', ':00', ':00']
re.split(r'dd?:dd?(:dd?)?', str_1)
=> ['', ':00', ' Segment 1 ', ':00', ' Segment 2 ', ':00', ' Segment 3']
re.findall(r'dd?:dd?(:dd?)?', str_2)
=> ['', '']
re.split(r'dd?:dd?(:dd?)?', str_2)
=> ['', None, ' Segment 1 ', None, ' Segment 2']
However, if I made the optional group without capturing, str_2 works fine but results are mixed with str_1
re.findall(r'dd?:dd?(?:dd?)?', str_1)
=> ['00:00', '00:20', '8:00']
re.split(r'dd?:dd?(?:dd?)?', str_1)
=> ['', ':00 Segment 1 ', ':00 Segment 2 ', ':00 Segment 3']
re.findall(r'dd?:dd?(?:dd?)?', str_2)
=> ['00:00', '20:0']
re.split(r'dd?:dd?(?:dd?)?', str_2)
=> ['', ' Segment 1 ', ' Segment 2']
I want to find a regex which works fine on both str_ and str_2, kind of have the optional group but without the capturing effect. Anyway to achieve that?
python regex
python regex
asked Nov 14 '18 at 1:16
hanaZ
10019
asked Nov 14 '18 at 1:16
hanaZ
10019
asked Nov 14 '18 at 1:16
hanaZ
10019
asked Nov 14 '18 at 1:16
hanaZ
10019
asked Nov 14 '18 at 1:16
hanaZ
10019
10019
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
It looks like you're missing the : in your pattern; you need two, one for the ?: and one for your literal :, ala:
re.findall(r'dd?:dd?(?::dd?)?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
answered Nov 14 '18 at 1:27
B. Morris
1667
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It looks like you're missing the : in your pattern; you need two, one for the ?: and one for your literal :, ala:
re.findall(r'dd?:dd?(?::dd?)?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
answered Nov 14 '18 at 1:27
B. Morris
1667
add a comment |
It looks like you're missing the : in your pattern; you need two, one for the ?: and one for your literal :, ala:
re.findall(r'dd?:dd?(?::dd?)?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
answered Nov 14 '18 at 1:27
B. Morris
1667
add a comment |
It looks like you're missing the : in your pattern; you need two, one for the ?: and one for your literal :, ala:
re.findall(r'dd?:dd?(?::dd?)?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
answered Nov 14 '18 at 1:27
B. Morris
1667
It looks like you're missing the : in your pattern; you need two, one for the ?: and one for your literal :, ala:
re.findall(r'dd?:dd?(?::dd?)?', str_1)
=> ['00:00:00', '00:20:00', '8:00:00']
answered Nov 14 '18 at 1:27
B. Morris
1667
answered Nov 14 '18 at 1:27
B. Morris
1667
answered Nov 14 '18 at 1:27
B. Morris
1667
answered Nov 14 '18 at 1:27
B. Morris
1667
1667
add a comment |
add a comment |
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