How to rename in ascending order of files in a folder











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I have a folder named FOLDER and inside, I have files named



file.2.fna
file.5.fna
file.6.fna
file.8.fna
file.12.fna


I want to rename the number part of each file in an ascending order starting with 0.
The desired output is



file.0.fna
file.1.fna
file.2.fna
file.3.fna
file.4.fna


I can do this manually by



mv FOLDER/file.2.fna FOLDER/file.0.fna
rm FOLDER/file.2.fna


But it does not seem appropriate since I have several dozens of files
Is there a for loop to do the job?



The for loop I've tried is



for file in FOLDER/file.*.fna; do n=0; mv file FOLDER/file.${file}.fna      
FOLDER/file.$n.fna; n=$n+1 ; done


This results in only single file with index 0.
I'm not sure how to increase n by 1 here.



Thank you










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  • I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
    – Bishal
    Nov 12 at 6:31










  • Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
    – Sumin Kim
    Nov 12 at 6:37















up vote
0
down vote

favorite












I have a folder named FOLDER and inside, I have files named



file.2.fna
file.5.fna
file.6.fna
file.8.fna
file.12.fna


I want to rename the number part of each file in an ascending order starting with 0.
The desired output is



file.0.fna
file.1.fna
file.2.fna
file.3.fna
file.4.fna


I can do this manually by



mv FOLDER/file.2.fna FOLDER/file.0.fna
rm FOLDER/file.2.fna


But it does not seem appropriate since I have several dozens of files
Is there a for loop to do the job?



The for loop I've tried is



for file in FOLDER/file.*.fna; do n=0; mv file FOLDER/file.${file}.fna      
FOLDER/file.$n.fna; n=$n+1 ; done


This results in only single file with index 0.
I'm not sure how to increase n by 1 here.



Thank you










share|improve this question
























  • I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
    – Bishal
    Nov 12 at 6:31










  • Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
    – Sumin Kim
    Nov 12 at 6:37













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a folder named FOLDER and inside, I have files named



file.2.fna
file.5.fna
file.6.fna
file.8.fna
file.12.fna


I want to rename the number part of each file in an ascending order starting with 0.
The desired output is



file.0.fna
file.1.fna
file.2.fna
file.3.fna
file.4.fna


I can do this manually by



mv FOLDER/file.2.fna FOLDER/file.0.fna
rm FOLDER/file.2.fna


But it does not seem appropriate since I have several dozens of files
Is there a for loop to do the job?



The for loop I've tried is



for file in FOLDER/file.*.fna; do n=0; mv file FOLDER/file.${file}.fna      
FOLDER/file.$n.fna; n=$n+1 ; done


This results in only single file with index 0.
I'm not sure how to increase n by 1 here.



Thank you










share|improve this question















I have a folder named FOLDER and inside, I have files named



file.2.fna
file.5.fna
file.6.fna
file.8.fna
file.12.fna


I want to rename the number part of each file in an ascending order starting with 0.
The desired output is



file.0.fna
file.1.fna
file.2.fna
file.3.fna
file.4.fna


I can do this manually by



mv FOLDER/file.2.fna FOLDER/file.0.fna
rm FOLDER/file.2.fna


But it does not seem appropriate since I have several dozens of files
Is there a for loop to do the job?



The for loop I've tried is



for file in FOLDER/file.*.fna; do n=0; mv file FOLDER/file.${file}.fna      
FOLDER/file.$n.fna; n=$n+1 ; done


This results in only single file with index 0.
I'm not sure how to increase n by 1 here.



Thank you







for-loop rename






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edited Nov 12 at 7:00

























asked Nov 12 at 6:26









Sumin Kim

938




938












  • I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
    – Bishal
    Nov 12 at 6:31










  • Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
    – Sumin Kim
    Nov 12 at 6:37


















  • I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
    – Bishal
    Nov 12 at 6:31










  • Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
    – Sumin Kim
    Nov 12 at 6:37
















I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
– Bishal
Nov 12 at 6:31




I would start by looking at ls -1 which sorts your files alphabetically. You could then write a loop to rename your ordered files as you wish.
– Bishal
Nov 12 at 6:31












Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
– Sumin Kim
Nov 12 at 6:37




Hi @Bishal, I inserted the for loop code I've tried. Still have some problems.Thank you.
– Sumin Kim
Nov 12 at 6:37












1 Answer
1






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up vote
0
down vote













I have got around this by



#!/bin/bash

a=0
echo $a
for i in file_*; do
new=$(printf "file_%d" "$a")
echo $new
mv -i -- "$i" "$new"
let a=a+1
done





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    up vote
    0
    down vote













    I have got around this by



    #!/bin/bash

    a=0
    echo $a
    for i in file_*; do
    new=$(printf "file_%d" "$a")
    echo $new
    mv -i -- "$i" "$new"
    let a=a+1
    done





    share|improve this answer

























      up vote
      0
      down vote













      I have got around this by



      #!/bin/bash

      a=0
      echo $a
      for i in file_*; do
      new=$(printf "file_%d" "$a")
      echo $new
      mv -i -- "$i" "$new"
      let a=a+1
      done





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        I have got around this by



        #!/bin/bash

        a=0
        echo $a
        for i in file_*; do
        new=$(printf "file_%d" "$a")
        echo $new
        mv -i -- "$i" "$new"
        let a=a+1
        done





        share|improve this answer












        I have got around this by



        #!/bin/bash

        a=0
        echo $a
        for i in file_*; do
        new=$(printf "file_%d" "$a")
        echo $new
        mv -i -- "$i" "$new"
        let a=a+1
        done






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 at 7:21









        Sumin Kim

        938




        938






























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