Function receiving and modifying a list without returning it [closed]












-3















There is a question around here with a similar title, however it refers to something different.



Example:



lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]


As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.



Thanks!






python python-2.7 function







share|improve this question













closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 3





    You never called your function.

    – timgeb
    Nov 19 '18 at 17:23











  • Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

    – chepner
    Nov 19 '18 at 17:35


















-3















There is a question around here with a similar title, however it refers to something different.



Example:



lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]


As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.



Thanks!






python python-2.7 function







share|improve this question













closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 3





    You never called your function.

    – timgeb
    Nov 19 '18 at 17:23











  • Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

    – chepner
    Nov 19 '18 at 17:35
















-3












-3








-3








There is a question around here with a similar title, however it refers to something different.



Example:



lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]


As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.



Thanks!






python python-2.7 function







share|improve this question














There is a question around here with a similar title, however it refers to something different.



Example:



lst = [1,2,3,4,2]

def drop_duplicates(lst):

    # Write the rest of the code for question 3a below here.

    lst.pop(0)

print lst





>>> [1, 2, 3, 4, 2]


As you can see my issue is that it is not being modified. I've been told that is possible to accomplish this without adding a return statement or using Global. Would love to have some insight into this.



Thanks!






python python-2.7 function




python python-2.7 function






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 19 '18 at 17:22









Moriel MankevichMoriel Mankevich

1




1




closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by timgeb, jpp, Austin, chepner, pushkin Nov 19 '18 at 17:42


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – timgeb, jpp, Austin, chepner, pushkin

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 3





    You never called your function.

    – timgeb
    Nov 19 '18 at 17:23











  • Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

    – chepner
    Nov 19 '18 at 17:35
















  • 3





    You never called your function.

    – timgeb
    Nov 19 '18 at 17:23











  • Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

    – chepner
    Nov 19 '18 at 17:35










3




3





You never called your function.

– timgeb
Nov 19 '18 at 17:23





You never called your function.

– timgeb
Nov 19 '18 at 17:23













Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

– chepner
Nov 19 '18 at 17:35







Suppose I replaced the def statement with drop_duplicates = operater.methodcaller('pop', 0). Would you still be surprised that lst remained unmodified, given that the definition doesn't mention lst at all.

– chepner
Nov 19 '18 at 17:35














1 Answer
1






active

oldest

votes


















1














You need to call your function



lst = [1,2,3,4,2]

def drop_duplicates(lst):

# Write the rest of the code for question 3a below here.

   lst.pop(0)

drop_duplicates(lst)

print lst



[2, 3, 4, 2]







share|improve this answer






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You need to call your function



    lst = [1,2,3,4,2]
    
def drop_duplicates(lst):
    
# Write the rest of the code for question 3a below here.
    
   lst.pop(0)
    
drop_duplicates(lst)
    
print lst



    [2, 3, 4, 2]







    share|improve this answer




























      1














      You need to call your function



      lst = [1,2,3,4,2]
      
def drop_duplicates(lst):
      
# Write the rest of the code for question 3a below here.
      
   lst.pop(0)
      
drop_duplicates(lst)
      
print lst



      [2, 3, 4, 2]







      share|improve this answer


























        1












        1








        1







        You need to call your function



        lst = [1,2,3,4,2]
        
def drop_duplicates(lst):
        
# Write the rest of the code for question 3a below here.
        
   lst.pop(0)
        
drop_duplicates(lst)
        
print lst



        [2, 3, 4, 2]







        share|improve this answer













        You need to call your function



        lst = [1,2,3,4,2]
        
def drop_duplicates(lst):
        
# Write the rest of the code for question 3a below here.
        
   lst.pop(0)
        
drop_duplicates(lst)
        
print lst



        [2, 3, 4, 2]








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 '18 at 17:26









        Garvita TiwariGarvita Tiwari

        468211




        468211

















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