Regex Match a character which is not followed by another specific character












0















I'm writing a CodeMirror extension for Brackets. To defineSimpleCodeMode I need to do some pattern matching and I'm trying to figure out how to achieve $subject.



e.g.



Match < of all the html tags



<body>


And ignore html tags which are followed by <%



<% if %>


Note: I only want to get the starting < of it



If some can help me out it would be a great help. Please do let me know if you need anymore details.



Thanks!






javascript regex







share|improve this question




















  • 3





    using a regex to parse a template string, can be a very bad idea

    – Daniel A. White
    Aug 10 '16 at 10:57











  • Hi @DanielA.White this is to write an CodeMode extension.

    – Jerad Rutnam
    Aug 10 '16 at 10:58
















0















I'm writing a CodeMirror extension for Brackets. To defineSimpleCodeMode I need to do some pattern matching and I'm trying to figure out how to achieve $subject.



e.g.



Match < of all the html tags



<body>


And ignore html tags which are followed by <%



<% if %>


Note: I only want to get the starting < of it



If some can help me out it would be a great help. Please do let me know if you need anymore details.



Thanks!






javascript regex







share|improve this question




















  • 3





    using a regex to parse a template string, can be a very bad idea

    – Daniel A. White
    Aug 10 '16 at 10:57











  • Hi @DanielA.White this is to write an CodeMode extension.

    – Jerad Rutnam
    Aug 10 '16 at 10:58














0












0








0


1






I'm writing a CodeMirror extension for Brackets. To defineSimpleCodeMode I need to do some pattern matching and I'm trying to figure out how to achieve $subject.



e.g.



Match < of all the html tags



<body>


And ignore html tags which are followed by <%



<% if %>


Note: I only want to get the starting < of it



If some can help me out it would be a great help. Please do let me know if you need anymore details.



Thanks!






javascript regex







share|improve this question
















I'm writing a CodeMirror extension for Brackets. To defineSimpleCodeMode I need to do some pattern matching and I'm trying to figure out how to achieve $subject.



e.g.



Match < of all the html tags



<body>


And ignore html tags which are followed by <%



<% if %>


Note: I only want to get the starting < of it



If some can help me out it would be a great help. Please do let me know if you need anymore details.



Thanks!






javascript regex




javascript regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 13 '18 at 8:40









Wiktor Stribiżew

325k16146226




325k16146226










asked Aug 10 '16 at 10:56









Jerad RutnamJerad Rutnam

1,0961825




1,0961825








  • 3





    using a regex to parse a template string, can be a very bad idea

    – Daniel A. White
    Aug 10 '16 at 10:57











  • Hi @DanielA.White this is to write an CodeMode extension.

    – Jerad Rutnam
    Aug 10 '16 at 10:58














  • 3





    using a regex to parse a template string, can be a very bad idea

    – Daniel A. White
    Aug 10 '16 at 10:57











  • Hi @DanielA.White this is to write an CodeMode extension.

    – Jerad Rutnam
    Aug 10 '16 at 10:58








3




3





using a regex to parse a template string, can be a very bad idea

– Daniel A. White
Aug 10 '16 at 10:57





using a regex to parse a template string, can be a very bad idea

– Daniel A. White
Aug 10 '16 at 10:57













Hi @DanielA.White this is to write an CodeMode extension.

– Jerad Rutnam
Aug 10 '16 at 10:58





Hi @DanielA.White this is to write an CodeMode extension.

– Jerad Rutnam
Aug 10 '16 at 10:58












1 Answer
1






active

oldest

votes


















3














While this seems to be a bad idea, I can see two ways of doing it :



1. Searching for < followed by anything but the % character, then ignoring it



(<)(?:[^%])



The [^] sequence allows you to search for anything but the following character.



The (?:) sequence is for non capturing groups.



2. (Better, if supported) Searching for input not followed by % with a negative lookahead



<(?!%)



The (?!) sequence succeeds if it doesn't match the following character, but is not captured.



If you also want to do it for %>, you can just "reverse" the first option :



(?:[^%])(>)



Or you need a negative lookbehind :



(careful here, the lookahead won't work as you need to go backwards)



(?<!%)>






share|improve this answer


























  • Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

    – Jerad Rutnam
    Aug 10 '16 at 11:03











  • I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

    – Azaghal
    Aug 10 '16 at 11:06











  • Im using regex101.com.

    – Jerad Rutnam
    Aug 10 '16 at 11:11











  • @JeradRutnam what you you mean the second character? It's already ignoring the second %

    – phuclv
    Aug 10 '16 at 11:12











  • Can we add $1 along with the match (<)[^%] somehow?

    – Jerad Rutnam
    Aug 10 '16 at 11:13











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1 Answer
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1 Answer
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active

oldest

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oldest

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active

oldest

votes









3














While this seems to be a bad idea, I can see two ways of doing it :



1. Searching for < followed by anything but the % character, then ignoring it



(<)(?:[^%])



The [^] sequence allows you to search for anything but the following character.



The (?:) sequence is for non capturing groups.



2. (Better, if supported) Searching for input not followed by % with a negative lookahead



<(?!%)



The (?!) sequence succeeds if it doesn't match the following character, but is not captured.



If you also want to do it for %>, you can just "reverse" the first option :



(?:[^%])(>)



Or you need a negative lookbehind :



(careful here, the lookahead won't work as you need to go backwards)



(?<!%)>






share|improve this answer


























  • Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

    – Jerad Rutnam
    Aug 10 '16 at 11:03











  • I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

    – Azaghal
    Aug 10 '16 at 11:06











  • Im using regex101.com.

    – Jerad Rutnam
    Aug 10 '16 at 11:11











  • @JeradRutnam what you you mean the second character? It's already ignoring the second %

    – phuclv
    Aug 10 '16 at 11:12











  • Can we add $1 along with the match (<)[^%] somehow?

    – Jerad Rutnam
    Aug 10 '16 at 11:13
















3














While this seems to be a bad idea, I can see two ways of doing it :



1. Searching for < followed by anything but the % character, then ignoring it



(<)(?:[^%])



The [^] sequence allows you to search for anything but the following character.



The (?:) sequence is for non capturing groups.



2. (Better, if supported) Searching for input not followed by % with a negative lookahead



<(?!%)



The (?!) sequence succeeds if it doesn't match the following character, but is not captured.



If you also want to do it for %>, you can just "reverse" the first option :



(?:[^%])(>)



Or you need a negative lookbehind :



(careful here, the lookahead won't work as you need to go backwards)



(?<!%)>






share|improve this answer


























  • Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

    – Jerad Rutnam
    Aug 10 '16 at 11:03











  • I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

    – Azaghal
    Aug 10 '16 at 11:06











  • Im using regex101.com.

    – Jerad Rutnam
    Aug 10 '16 at 11:11











  • @JeradRutnam what you you mean the second character? It's already ignoring the second %

    – phuclv
    Aug 10 '16 at 11:12











  • Can we add $1 along with the match (<)[^%] somehow?

    – Jerad Rutnam
    Aug 10 '16 at 11:13














3












3








3







While this seems to be a bad idea, I can see two ways of doing it :



1. Searching for < followed by anything but the % character, then ignoring it



(<)(?:[^%])



The [^] sequence allows you to search for anything but the following character.



The (?:) sequence is for non capturing groups.



2. (Better, if supported) Searching for input not followed by % with a negative lookahead



<(?!%)



The (?!) sequence succeeds if it doesn't match the following character, but is not captured.



If you also want to do it for %>, you can just "reverse" the first option :



(?:[^%])(>)



Or you need a negative lookbehind :



(careful here, the lookahead won't work as you need to go backwards)



(?<!%)>






share|improve this answer















While this seems to be a bad idea, I can see two ways of doing it :



1. Searching for < followed by anything but the % character, then ignoring it



(<)(?:[^%])



The [^] sequence allows you to search for anything but the following character.



The (?:) sequence is for non capturing groups.



2. (Better, if supported) Searching for input not followed by % with a negative lookahead



<(?!%)



The (?!) sequence succeeds if it doesn't match the following character, but is not captured.



If you also want to do it for %>, you can just "reverse" the first option :



(?:[^%])(>)



Or you need a negative lookbehind :



(careful here, the lookahead won't work as you need to go backwards)



(?<!%)>







share|improve this answer














share|improve this answer



share|improve this answer








edited Aug 10 '16 at 12:27

























answered Aug 10 '16 at 11:01









AzaghalAzaghal

245110




245110













  • Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

    – Jerad Rutnam
    Aug 10 '16 at 11:03











  • I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

    – Azaghal
    Aug 10 '16 at 11:06











  • Im using regex101.com.

    – Jerad Rutnam
    Aug 10 '16 at 11:11











  • @JeradRutnam what you you mean the second character? It's already ignoring the second %

    – phuclv
    Aug 10 '16 at 11:12











  • Can we add $1 along with the match (<)[^%] somehow?

    – Jerad Rutnam
    Aug 10 '16 at 11:13



















  • Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

    – Jerad Rutnam
    Aug 10 '16 at 11:03











  • I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

    – Azaghal
    Aug 10 '16 at 11:06











  • Im using regex101.com.

    – Jerad Rutnam
    Aug 10 '16 at 11:11











  • @JeradRutnam what you you mean the second character? It's already ignoring the second %

    – phuclv
    Aug 10 '16 at 11:12











  • Can we add $1 along with the match (<)[^%] somehow?

    – Jerad Rutnam
    Aug 10 '16 at 11:13

















Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

– Jerad Rutnam
Aug 10 '16 at 11:03





Hi @Baptiste, Thanks for the answer. It almost do what I wanted.How is it possible to ignore the second charater which is after < ?

– Jerad Rutnam
Aug 10 '16 at 11:03













I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

– Azaghal
Aug 10 '16 at 11:06





I don't know what tool you are working with, but you could just replace what you get with the $1 variable with most of them.

– Azaghal
Aug 10 '16 at 11:06













Im using regex101.com.

– Jerad Rutnam
Aug 10 '16 at 11:11





Im using regex101.com.

– Jerad Rutnam
Aug 10 '16 at 11:11













@JeradRutnam what you you mean the second character? It's already ignoring the second %

– phuclv
Aug 10 '16 at 11:12





@JeradRutnam what you you mean the second character? It's already ignoring the second %

– phuclv
Aug 10 '16 at 11:12













Can we add $1 along with the match (<)[^%] somehow?

– Jerad Rutnam
Aug 10 '16 at 11:13





Can we add $1 along with the match (<)[^%] somehow?

– Jerad Rutnam
Aug 10 '16 at 11:13




















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