react ref value is empty

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}

I have a react component with an uncontrolled input element like below:

class TestComponent {



onAddTypeClicked = el => {

    console.log(el);

    console.log(el.value);

};





render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            />   

        </div>

    );

}

Now when I type some value in input field and click button, the input is getting printed correctly but it's value is empty. It works fine if I use document.getElementById approach though. Can anyone point if I'm doing anything wrong, please?

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

Would you try to pass .current? so this.onAddTypeClicked(this.assetTypesAdd.current);

– Sung M. Kim
Nov 22 '18 at 4:40

current is valid if we create ref using React.createRef() but in my case I'm using callback pattern.

– geekprogrammer
Nov 22 '18 at 5:14

add a comment |

I have a react component with an uncontrolled input element like below:

class TestComponent {



onAddTypeClicked = el => {

    console.log(el);

    console.log(el.value);

};





render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            />   

        </div>

    );

}

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

Would you try to pass .current? so this.onAddTypeClicked(this.assetTypesAdd.current);

– Sung M. Kim
Nov 22 '18 at 4:40

current is valid if we create ref using React.createRef() but in my case I'm using callback pattern.

– geekprogrammer
Nov 22 '18 at 5:14

add a comment |

I have a react component with an uncontrolled input element like below:

class TestComponent {



onAddTypeClicked = el => {

    console.log(el);

    console.log(el.value);

};





render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            />   

        </div>

    );

}

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

I have a react component with an uncontrolled input element like below:

class TestComponent {



onAddTypeClicked = el => {

    console.log(el);

    console.log(el.value);

};





render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            />   

        </div>

    );

}

javascript reactjs

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

edited Nov 22 '18 at 4:55

Matthew Herbst

11.4k134890

asked Nov 22 '18 at 4:31

geekprogrammer

509525

asked Nov 22 '18 at 4:31

geekprogrammer

509525

asked Nov 22 '18 at 4:31

geekprogrammer

509525

Would you try to pass .current? so this.onAddTypeClicked(this.assetTypesAdd.current);

– Sung M. Kim
Nov 22 '18 at 4:40

current is valid if we create ref using React.createRef() but in my case I'm using callback pattern.

– geekprogrammer
Nov 22 '18 at 5:14

add a comment |

Would you try to pass .current? so this.onAddTypeClicked(this.assetTypesAdd.current);

– Sung M. Kim
Nov 22 '18 at 4:40

current is valid if we create ref using React.createRef() but in my case I'm using callback pattern.

– geekprogrammer
Nov 22 '18 at 5:14

Would you try to pass .current? so this.onAddTypeClicked(this.assetTypesAdd.current);

– Sung M. Kim
Nov 22 '18 at 4:40

current is valid if we create ref using React.createRef() but in my case I'm using callback pattern.

– geekprogrammer
Nov 22 '18 at 5:14

add a comment |

1 Answer
1

active

oldest

votes

I believe your code is working correctly and the value of accessible in this.assetTypesAdd.value and its printed value is the same. I'm not sure where you are getting an empty value for the input.

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

I believe your code is working correctly and the value of accessible in this.assetTypesAdd.value and its printed value is the same. I'm not sure where you are getting an empty value for the input.

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

add a comment |

I believe your code is working correctly and the value of accessible in this.assetTypesAdd.value and its printed value is the same. I'm not sure where you are getting an empty value for the input.

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

add a comment |

I believe your code is working correctly and the value of accessible in this.assetTypesAdd.value and its printed value is the same. I'm not sure where you are getting an empty value for the input.

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

I believe your code is working correctly and the value of accessible in this.assetTypesAdd.value and its printed value is the same. I'm not sure where you are getting an empty value for the input.

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

// Example class component

class MyComponent extends React.Component {



  onAddTypeClicked = el => {

      console.log(el.value);

      this.forceUpdate();

  };



  render() {

    return (

        <div>

            <input

                name="asset_types"

                ref={el => this.assetTypesAdd = el}

            />

            <button

                type="button"

                onClick={e => this.onAddTypeClicked(this.assetTypesAdd)}

            >

                Click me

            </button>

            {this.assetTypesAdd && 

                <div>Value of input: {this.assetTypesAdd.value}</div>}

            

        </div>

    );

  }

}



// Render it

ReactDOM.render(

  <MyComponent/>,

  document.getElementById("react")

);

button {

    width: 100px;

    height: 20px;

    display: block;

    margin: 10px 0;

}

<div id="react"></div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

answered Nov 22 '18 at 5:13

Shawn Andrews

965719

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

add a comment |

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

Thanks for your answer. I just realized that there was a mistake in my code.

– geekprogrammer
Nov 22 '18 at 5:23

add a comment |

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