React measure, get width of widest of two sibling elements?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I have two absolutely positioned sibling elements. I want to use react-measure to set the parent container to the width of the widest absolute element. I'm having a bit of trouble getting my head around how to do that.
You can't re-use the measureRef it seems, and if you nested two Measure components the props would collide? Nest them and rename the props in-between? Is there a less ugly way?
javascript reactjs
edited Nov 22 '18 at 4:29
kiranvj
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
add a comment |
I have two absolutely positioned sibling elements. I want to use react-measure to set the parent container to the width of the widest absolute element. I'm having a bit of trouble getting my head around how to do that.
You can't re-use the measureRef it seems, and if you nested two Measure components the props would collide? Nest them and rename the props in-between? Is there a less ugly way?
javascript reactjs
edited Nov 22 '18 at 4:29
kiranvj
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
add a comment |
I have two absolutely positioned sibling elements. I want to use react-measure to set the parent container to the width of the widest absolute element. I'm having a bit of trouble getting my head around how to do that.
You can't re-use the measureRef it seems, and if you nested two Measure components the props would collide? Nest them and rename the props in-between? Is there a less ugly way?
javascript reactjs
edited Nov 22 '18 at 4:29
kiranvj
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
I have two absolutely positioned sibling elements. I want to use react-measure to set the parent container to the width of the widest absolute element. I'm having a bit of trouble getting my head around how to do that.
You can't re-use the measureRef it seems, and if you nested two Measure components the props would collide? Nest them and rename the props in-between? Is there a less ugly way?
javascript reactjs
javascript reactjs
edited Nov 22 '18 at 4:29
kiranvj
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
edited Nov 22 '18 at 4:29
kiranvj
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
edited Nov 22 '18 at 4:29
kiranvj
13k23653
edited Nov 22 '18 at 4:29
kiranvj
13k23653
edited Nov 22 '18 at 4:29
kiranvj
13k23653
13k23653
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
asked Nov 22 '18 at 4:16
EloffEloff
10.3k106489
10.3k106489
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think I figured this out, if you use the HOC withContentRect it's a little clearer:
const enhance = compose(
withContentRect('bounds'),
renameProp('contentRect', 'rect1'),
renameProp('measureRef', 'ref1'),
withContentRect('bounds'),
renameProp('contentRect', 'rect2'),
renameProp('measureRef', 'ref2'),
);
const Component = enhance(({ rect1, rect2, ref1, ref2 }) => {
const width = Math.max(rect1.bounds.width || 0, rect2.bounds.width || 0) + 32;
return (
<div style={{position: relative, width }}>
<div ref={ref1} style={{position: absolute}}>Foo</div>
<div ref={ref2} style={{position: absolute}}>Bar</div>
</div>
);
}
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53423822%2freact-measure-get-width-of-widest-of-two-sibling-elements%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think I figured this out, if you use the HOC withContentRect it's a little clearer:
const enhance = compose(
withContentRect('bounds'),
renameProp('contentRect', 'rect1'),
renameProp('measureRef', 'ref1'),
withContentRect('bounds'),
renameProp('contentRect', 'rect2'),
renameProp('measureRef', 'ref2'),
);
const Component = enhance(({ rect1, rect2, ref1, ref2 }) => {
const width = Math.max(rect1.bounds.width || 0, rect2.bounds.width || 0) + 32;
return (
<div style={{position: relative, width }}>
<div ref={ref1} style={{position: absolute}}>Foo</div>
<div ref={ref2} style={{position: absolute}}>Bar</div>
</div>
);
}
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
add a comment |
I think I figured this out, if you use the HOC withContentRect it's a little clearer:
const enhance = compose(
withContentRect('bounds'),
renameProp('contentRect', 'rect1'),
renameProp('measureRef', 'ref1'),
withContentRect('bounds'),
renameProp('contentRect', 'rect2'),
renameProp('measureRef', 'ref2'),
);
const Component = enhance(({ rect1, rect2, ref1, ref2 }) => {
const width = Math.max(rect1.bounds.width || 0, rect2.bounds.width || 0) + 32;
return (
<div style={{position: relative, width }}>
<div ref={ref1} style={{position: absolute}}>Foo</div>
<div ref={ref2} style={{position: absolute}}>Bar</div>
</div>
);
}
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
add a comment |
I think I figured this out, if you use the HOC withContentRect it's a little clearer:
const enhance = compose(
withContentRect('bounds'),
renameProp('contentRect', 'rect1'),
renameProp('measureRef', 'ref1'),
withContentRect('bounds'),
renameProp('contentRect', 'rect2'),
renameProp('measureRef', 'ref2'),
);
const Component = enhance(({ rect1, rect2, ref1, ref2 }) => {
const width = Math.max(rect1.bounds.width || 0, rect2.bounds.width || 0) + 32;
return (
<div style={{position: relative, width }}>
<div ref={ref1} style={{position: absolute}}>Foo</div>
<div ref={ref2} style={{position: absolute}}>Bar</div>
</div>
);
}
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
I think I figured this out, if you use the HOC withContentRect it's a little clearer:
const enhance = compose(
withContentRect('bounds'),
renameProp('contentRect', 'rect1'),
renameProp('measureRef', 'ref1'),
withContentRect('bounds'),
renameProp('contentRect', 'rect2'),
renameProp('measureRef', 'ref2'),
);
const Component = enhance(({ rect1, rect2, ref1, ref2 }) => {
const width = Math.max(rect1.bounds.width || 0, rect2.bounds.width || 0) + 32;
return (
<div style={{position: relative, width }}>
<div ref={ref1} style={{position: absolute}}>Foo</div>
<div ref={ref2} style={{position: absolute}}>Bar</div>
</div>
);
}
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
edited Nov 25 '18 at 18:47
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
answered Nov 22 '18 at 20:19
EloffEloff
10.3k106489
10.3k106489
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53423822%2freact-measure-get-width-of-widest-of-two-sibling-elements%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
