Allow JSON fragments with Decodable












1














import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}

var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) else{return}

URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}

do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}

override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}


I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))











share|improve this question
























  • Your URL gives 403 FORBIDDEN Error..... check status code....
    – Vishal Patel
    Nov 13 at 6:05










  • Thanks Vishal. The wrong API key was given in the example.
    – Jonathan Jordan
    Nov 13 at 6:20
















1














import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}

var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) else{return}

URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}

do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}

override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}


I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))











share|improve this question
























  • Your URL gives 403 FORBIDDEN Error..... check status code....
    – Vishal Patel
    Nov 13 at 6:05










  • Thanks Vishal. The wrong API key was given in the example.
    – Jonathan Jordan
    Nov 13 at 6:20














1












1








1







import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}

var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) else{return}

URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}

do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}

override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}


I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))











share|improve this question















import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}

var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) else{return}

URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}

do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}

override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}


I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))








json swift






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 at 5:45









rmaddy

238k27309375




238k27309375










asked Nov 13 at 5:30









Jonathan Jordan

12




12












  • Your URL gives 403 FORBIDDEN Error..... check status code....
    – Vishal Patel
    Nov 13 at 6:05










  • Thanks Vishal. The wrong API key was given in the example.
    – Jonathan Jordan
    Nov 13 at 6:20


















  • Your URL gives 403 FORBIDDEN Error..... check status code....
    – Vishal Patel
    Nov 13 at 6:05










  • Thanks Vishal. The wrong API key was given in the example.
    – Jonathan Jordan
    Nov 13 at 6:20
















Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05




Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05












Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20




Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20












2 Answers
2






active

oldest

votes


















0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}


However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
    – Jonathan Jordan
    Nov 13 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self
    – vadian
    Nov 13 at 7:34










  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
    – Jonathan Jordan
    Nov 13 at 7:51










  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
    – vadian
    Nov 13 at 7:54










  • Thank you for your help. I will try this.
    – Jonathan Jordan
    Nov 13 at 7:56



















0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer





















  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
    – Jonathan Jordan
    Nov 13 at 6:43











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274397%2fallow-json-fragments-with-decodable%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}


However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
    – Jonathan Jordan
    Nov 13 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self
    – vadian
    Nov 13 at 7:34










  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
    – Jonathan Jordan
    Nov 13 at 7:51










  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
    – vadian
    Nov 13 at 7:54










  • Thank you for your help. I will try this.
    – Jonathan Jordan
    Nov 13 at 7:56
















0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}


However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
    – Jonathan Jordan
    Nov 13 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self
    – vadian
    Nov 13 at 7:34










  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
    – Jonathan Jordan
    Nov 13 at 7:51










  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
    – vadian
    Nov 13 at 7:54










  • Thank you for your help. I will try this.
    – Jonathan Jordan
    Nov 13 at 7:56














0












0








0






JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}


However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}


However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 at 6:12

























answered Nov 13 at 5:59









vadian

142k13151168




142k13151168












  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
    – Jonathan Jordan
    Nov 13 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self
    – vadian
    Nov 13 at 7:34










  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
    – Jonathan Jordan
    Nov 13 at 7:51










  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
    – vadian
    Nov 13 at 7:54










  • Thank you for your help. I will try this.
    – Jonathan Jordan
    Nov 13 at 7:56


















  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
    – Jonathan Jordan
    Nov 13 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self
    – vadian
    Nov 13 at 7:34










  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
    – Jonathan Jordan
    Nov 13 at 7:51










  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
    – vadian
    Nov 13 at 7:54










  • Thank you for your help. I will try this.
    – Jonathan Jordan
    Nov 13 at 7:56
















Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17






Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17














If the root object is a dictionary you have to decode Recipes.self
– vadian
Nov 13 at 7:34




If the root object is a dictionary you have to decode Recipes.self
– vadian
Nov 13 at 7:34












The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51




The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51












In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54




In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54












Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56




Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56













0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer





















  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
    – Jonathan Jordan
    Nov 13 at 6:43
















0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer





















  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
    – Jonathan Jordan
    Nov 13 at 6:43














0












0








0






You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer












You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 13 at 6:04









rob mayoff

290k41582637




290k41582637












  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
    – Jonathan Jordan
    Nov 13 at 6:43


















  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
    – Jonathan Jordan
    Nov 13 at 6:43
















I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43




I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43


















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274397%2fallow-json-fragments-with-decodable%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

鏡平學校

ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

Why https connections are so slow when debugging (stepping over) in Java?