What selector can I use to exclude IDs with a suffix?

I have a bunch of divs on a page (bg_1, bg_5, bg_112 etc.) that I'd like to assign the style 'display:inline-block'.

However, I have other divs called bg_1_log, bg_5_log, bg_112_log etc..) that I do not want to assign this style to.

I have tried:

 $('[id^=bg_]').attr('style','display:inline-block');

This works, but of course that assigns the style to all divs that start with 'bg_', including bg_112_log...

How can I "assign a style to all divs that are just bg_+number?

I'm using jQuery so either that or JS would be fine.

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

1

can you assign a class to them while generating the html?
– Daniel A. White
Nov 13 at 18:35

add a comment |

I have a bunch of divs on a page (bg_1, bg_5, bg_112 etc.) that I'd like to assign the style 'display:inline-block'.

However, I have other divs called bg_1_log, bg_5_log, bg_112_log etc..) that I do not want to assign this style to.

I have tried:

 $('[id^=bg_]').attr('style','display:inline-block');

This works, but of course that assigns the style to all divs that start with 'bg_', including bg_112_log...

How can I "assign a style to all divs that are just bg_+number?

I'm using jQuery so either that or JS would be fine.

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

1

can you assign a class to them while generating the html?
– Daniel A. White
Nov 13 at 18:35

add a comment |

I have a bunch of divs on a page (bg_1, bg_5, bg_112 etc.) that I'd like to assign the style 'display:inline-block'.

However, I have other divs called bg_1_log, bg_5_log, bg_112_log etc..) that I do not want to assign this style to.

I have tried:

 $('[id^=bg_]').attr('style','display:inline-block');

This works, but of course that assigns the style to all divs that start with 'bg_', including bg_112_log...

How can I "assign a style to all divs that are just bg_+number?

I'm using jQuery so either that or JS would be fine.

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

I have a bunch of divs on a page (bg_1, bg_5, bg_112 etc.) that I'd like to assign the style 'display:inline-block'.

However, I have other divs called bg_1_log, bg_5_log, bg_112_log etc..) that I do not want to assign this style to.

I have tried:

 $('[id^=bg_]').attr('style','display:inline-block');

This works, but of course that assigns the style to all divs that start with 'bg_', including bg_112_log...

How can I "assign a style to all divs that are just bg_+number?

I'm using jQuery so either that or JS would be fine.

javascript jquery

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

edited Nov 13 at 18:41

isherwood

36.6k1081111

edited Nov 13 at 18:41

isherwood

36.6k1081111

edited Nov 13 at 18:41

isherwood

36.6k1081111

asked Nov 13 at 18:33

dijon

149617

asked Nov 13 at 18:33

dijon

149617

asked Nov 13 at 18:33

dijon

149617

1

can you assign a class to them while generating the html?
– Daniel A. White
Nov 13 at 18:35

add a comment |

1

can you assign a class to them while generating the html?
– Daniel A. White
Nov 13 at 18:35

can you assign a class to them while generating the html?
– Daniel A. White
Nov 13 at 18:35

add a comment |

3 Answers
3

active

oldest

votes

You could use the selector using not and attribute contains selector like:

$('[id^=bg_]').not('[id*=_log]')

Or, you can also use regex as @zfrisch suggested but here's an improved version (Selector not only limitted to div):

$('*').filter(function() { return this.id.match(/bg_d$/) })

Or, even like:

$('*').attr('id').match(/bg_d$/)

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

add a comment |

You can use JQuery's .filter method

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

Or as another answer pointed out .not

answered Nov 13 at 18:42

zfrisch

4,42311024

add a comment |

If you don't want to select the elements whose id ends with _log then you can use following code:

$('[id^=bg_]').not('[id$=_log]').attr('style','display:inline-block');

answered Nov 13 at 18:44

Gowri Sankar K

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You could use the selector using not and attribute contains selector like:

$('[id^=bg_]').not('[id*=_log]')

Or, you can also use regex as @zfrisch suggested but here's an improved version (Selector not only limitted to div):

$('*').filter(function() { return this.id.match(/bg_d$/) })

Or, even like:

$('*').attr('id').match(/bg_d$/)

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

add a comment |

You could use the selector using not and attribute contains selector like:

$('[id^=bg_]').not('[id*=_log]')

Or, you can also use regex as @zfrisch suggested but here's an improved version (Selector not only limitted to div):

$('*').filter(function() { return this.id.match(/bg_d$/) })

Or, even like:

$('*').attr('id').match(/bg_d$/)

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

add a comment |

You could use the selector using not and attribute contains selector like:

$('[id^=bg_]').not('[id*=_log]')

Or, you can also use regex as @zfrisch suggested but here's an improved version (Selector not only limitted to div):

$('*').filter(function() { return this.id.match(/bg_d$/) })

Or, even like:

$('*').attr('id').match(/bg_d$/)

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

You could use the selector using not and attribute contains selector like:

$('[id^=bg_]').not('[id*=_log]')

Or, you can also use regex as @zfrisch suggested but here's an improved version (Selector not only limitted to div):

$('*').filter(function() { return this.id.match(/bg_d$/) })

Or, even like:

$('*').attr('id').match(/bg_d$/)

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

edited Nov 13 at 18:55

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

answered Nov 13 at 18:36

Bhojendra Rauniyar

50.7k2079124

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

add a comment |

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

Perfect, I didn't know I could use the .not in conjunction with the contains selector.
– dijon
Nov 13 at 21:23

add a comment |

You can use JQuery's .filter method

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

Or as another answer pointed out .not

answered Nov 13 at 18:42

zfrisch

4,42311024

add a comment |

You can use JQuery's .filter method

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

Or as another answer pointed out .not

answered Nov 13 at 18:42

zfrisch

4,42311024

add a comment |

You can use JQuery's .filter method

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

Or as another answer pointed out .not

answered Nov 13 at 18:42

zfrisch

4,42311024

You can use JQuery's .filter method

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

Or as another answer pointed out .not

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

$('div')

    .filter(function() {

        return this.id.match(/bg_d$/);

    })

    .css("backgroundColor", "green");

div:after {

  content: "test";

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id="bg_1"></div>

<div id="bg_2"></div>

<div id="bg_3"></div>

<div id="bg_4"></div>

<div id="bg_5"></div>

<div id="bg_6"></div>

<div id="bg_1_log"></div>

<div id="bg_2_log"></div>

<div id="bg_3_log"></div>

<div id="bg_4_log"></div>

<div id="bg_5_log"></div>

<div id="bg_6_log"></div>

answered Nov 13 at 18:42

zfrisch

4,42311024

answered Nov 13 at 18:42

zfrisch

4,42311024

answered Nov 13 at 18:42

zfrisch

4,42311024

answered Nov 13 at 18:42

zfrisch

4,42311024

add a comment |

If you don't want to select the elements whose id ends with _log then you can use following code:

$('[id^=bg_]').not('[id$=_log]').attr('style','display:inline-block');

answered Nov 13 at 18:44

Gowri Sankar K

add a comment |

If you don't want to select the elements whose id ends with _log then you can use following code:

$('[id^=bg_]').not('[id$=_log]').attr('style','display:inline-block');

answered Nov 13 at 18:44

Gowri Sankar K

add a comment |

If you don't want to select the elements whose id ends with _log then you can use following code:

$('[id^=bg_]').not('[id$=_log]').attr('style','display:inline-block');

answered Nov 13 at 18:44

Gowri Sankar K

If you don't want to select the elements whose id ends with _log then you can use following code:

$('[id^=bg_]').not('[id$=_log]').attr('style','display:inline-block');

answered Nov 13 at 18:44

Gowri Sankar K

answered Nov 13 at 18:44

Gowri Sankar K

answered Nov 13 at 18:44

Gowri Sankar K

answered Nov 13 at 18:44

Gowri Sankar K

add a comment |

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