Why does declaring an int array of length INT_MAX create a segmentation fault? [duplicate]
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Segmentation Fault, large arrays
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The following code, when compiled and run, gives me a segmentation fault. Why is this?
#include <stdio.h>
#include <limits.h>
int main(void)
{
int fat_array[INT_MAX];
return 0;
}
c arrays segmentation-fault
asked Nov 10 at 22:20
Uclydde
7011419
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Nov 10 at 22:33
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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This question already has an answer here:
Segmentation Fault, large arrays
1 answer
The following code, when compiled and run, gives me a segmentation fault. Why is this?
#include <stdio.h>
#include <limits.h>
int main(void)
{
int fat_array[INT_MAX];
return 0;
}
c arrays segmentation-fault
asked Nov 10 at 22:20
Uclydde
7011419
marked as duplicate by P.P. c
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Nov 10 at 22:33
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
1
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
2
You'd need 8 GiB of stack space forint fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outsidemain()), or use dynamic memory allocation (malloc()et al).
– Jonathan Leffler
Nov 10 at 22:25
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This question already has an answer here:
Segmentation Fault, large arrays
1 answer
The following code, when compiled and run, gives me a segmentation fault. Why is this?
#include <stdio.h>
#include <limits.h>
int main(void)
{
int fat_array[INT_MAX];
return 0;
}
c arrays segmentation-fault
asked Nov 10 at 22:20
Uclydde
7011419
This question already has an answer here:
Segmentation Fault, large arrays
1 answer
The following code, when compiled and run, gives me a segmentation fault. Why is this?
#include <stdio.h>
#include <limits.h>
int main(void)
{
int fat_array[INT_MAX];
return 0;
}
This question already has an answer here:
Segmentation Fault, large arrays
1 answer
c arrays segmentation-fault
c arrays segmentation-fault
asked Nov 10 at 22:20
Uclydde
7011419
asked Nov 10 at 22:20
Uclydde
7011419
asked Nov 10 at 22:20
Uclydde
7011419
asked Nov 10 at 22:20
Uclydde
7011419
asked Nov 10 at 22:20
Uclydde
7011419
7011419
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Nov 10 at 22:33
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Nov 10 at 22:33
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
1
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
2
You'd need 8 GiB of stack space forint fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outsidemain()), or use dynamic memory allocation (malloc()et al).
– Jonathan Leffler
Nov 10 at 22:25
add a comment |
1
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
1
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
2
You'd need 8 GiB of stack space forint fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outsidemain()), or use dynamic memory allocation (malloc()et al).
– Jonathan Leffler
Nov 10 at 22:25
1
1
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
1
1
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
2
2
You'd need 8 GiB of stack space for
int fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outside main()), or use dynamic memory allocation (malloc() et al).– Jonathan Leffler
Nov 10 at 22:25
You'd need 8 GiB of stack space for
int fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outside main()), or use dynamic memory allocation (malloc() et al).– Jonathan Leffler
Nov 10 at 22:25
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
What you are requesting is to have about 2,147,483,647integer spaces allocated to you. Each integer is usually four bytes so that's 8,589,934,588 bytes which is 8 gigabytes of memory. This is likely above the allowed amount of memory a single process is allowed to reserve, and for good reason, so you get an error.
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
What you are requesting is to have about 2,147,483,647integer spaces allocated to you. Each integer is usually four bytes so that's 8,589,934,588 bytes which is 8 gigabytes of memory. This is likely above the allowed amount of memory a single process is allowed to reserve, and for good reason, so you get an error.
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
add a comment |
up vote
2
down vote
accepted
What you are requesting is to have about 2,147,483,647integer spaces allocated to you. Each integer is usually four bytes so that's 8,589,934,588 bytes which is 8 gigabytes of memory. This is likely above the allowed amount of memory a single process is allowed to reserve, and for good reason, so you get an error.
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
What you are requesting is to have about 2,147,483,647integer spaces allocated to you. Each integer is usually four bytes so that's 8,589,934,588 bytes which is 8 gigabytes of memory. This is likely above the allowed amount of memory a single process is allowed to reserve, and for good reason, so you get an error.
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
What you are requesting is to have about 2,147,483,647integer spaces allocated to you. Each integer is usually four bytes so that's 8,589,934,588 bytes which is 8 gigabytes of memory. This is likely above the allowed amount of memory a single process is allowed to reserve, and for good reason, so you get an error.
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
answered Nov 10 at 22:26
Mitchel Paulin
1,504317
1,504317
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
add a comment |
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
2
2
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
It's slightly misleading to say "above the allowed amount of memory a single process is allowed to reserve". If it were to be heap allocted and the system has enough it's fine to use to reserve/allocate as much and there's no general limit for memory. The specific problem here is that it's "stack" allocated (aka automatic storage).
– P.P.
Nov 10 at 22:45
add a comment |
1
Your system, that time, did not have enough memory for a local array that big. It tried and failed at run time.
– chux
Nov 10 at 22:22
1
stackoverflow without the .com
– PSkocik
Nov 10 at 22:22
2
You'd need 8 GiB of stack space for
int fat_array[INT_MAX]; Unix-like systems are generous and normally give you 8 MiB of stack space; Windows is more conservative and normally only gives you 1 MiB. Either way, it's massively less space than needed. Either allocate the array at file scope (outsidemain()), or use dynamic memory allocation (malloc()et al).– Jonathan Leffler
Nov 10 at 22:25