Modify the column headers of a pandas data frame

I have this column header:

enter image description here

I put these into a list by x = list(df) and the type of x is a string. I want to put these into another list of strings but converting them into 8/18, 7/18,6/18, etc...

Here is the df.head() output:

enter image description here

Output of print(df.columns)

<class 'str'>

Index(['NDD 8/31', 'Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

       'Jun 2018(P&I Applied)', 'May 2018(P&I Applied)',

       'Apr 2018(P&I Applied)', 'Mar 2018(P&I Applied)',

       'Feb 2018(P&I Expected)', 'Jan 2018(P&I Applied)',

       'Dec 2017(P&I Applied)', 'Nov 2017(P&I Applied)',

       'Oct 2017(P&I Applied)', 'Sep 2017(P&I Applied)',

       'Paystring as of cut off as if 10.31',

       'Paystrings as of

Does anyone know how to achieve this?

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

Can you add the output of print(df.columns) to the question?

– Scott Boston
Nov 15 '18 at 22:31

@ScottBoston Added

– Snorrlaxxx
Nov 15 '18 at 22:36

Do you want to replace Jun 2018 -> 6/18 only, or should the entire column name be 6/18?

– Matthias Ossadnik
Nov 15 '18 at 22:56

@MatthiasOssadnik No I do not need to modify the data frame, I just want to convert Jun 2018 - > 6/18 and put it into a vector or list

– Snorrlaxxx
Nov 15 '18 at 23:04

add a comment |

I have this column header:

enter image description here

I put these into a list by x = list(df) and the type of x is a string. I want to put these into another list of strings but converting them into 8/18, 7/18,6/18, etc...

Here is the df.head() output:

enter image description here

Output of print(df.columns)

<class 'str'>

Index(['NDD 8/31', 'Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

       'Jun 2018(P&I Applied)', 'May 2018(P&I Applied)',

       'Apr 2018(P&I Applied)', 'Mar 2018(P&I Applied)',

       'Feb 2018(P&I Expected)', 'Jan 2018(P&I Applied)',

       'Dec 2017(P&I Applied)', 'Nov 2017(P&I Applied)',

       'Oct 2017(P&I Applied)', 'Sep 2017(P&I Applied)',

       'Paystring as of cut off as if 10.31',

       'Paystrings as of

Does anyone know how to achieve this?

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

Can you add the output of print(df.columns) to the question?

– Scott Boston
Nov 15 '18 at 22:31

@ScottBoston Added

– Snorrlaxxx
Nov 15 '18 at 22:36

Do you want to replace Jun 2018 -> 6/18 only, or should the entire column name be 6/18?

– Matthias Ossadnik
Nov 15 '18 at 22:56

@MatthiasOssadnik No I do not need to modify the data frame, I just want to convert Jun 2018 - > 6/18 and put it into a vector or list

– Snorrlaxxx
Nov 15 '18 at 23:04

add a comment |

I have this column header:

enter image description here

I put these into a list by x = list(df) and the type of x is a string. I want to put these into another list of strings but converting them into 8/18, 7/18,6/18, etc...

Here is the df.head() output:

enter image description here

Output of print(df.columns)

<class 'str'>

Index(['NDD 8/31', 'Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

       'Jun 2018(P&I Applied)', 'May 2018(P&I Applied)',

       'Apr 2018(P&I Applied)', 'Mar 2018(P&I Applied)',

       'Feb 2018(P&I Expected)', 'Jan 2018(P&I Applied)',

       'Dec 2017(P&I Applied)', 'Nov 2017(P&I Applied)',

       'Oct 2017(P&I Applied)', 'Sep 2017(P&I Applied)',

       'Paystring as of cut off as if 10.31',

       'Paystrings as of

Does anyone know how to achieve this?

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

I have this column header:

enter image description here

I put these into a list by x = list(df) and the type of x is a string. I want to put these into another list of strings but converting them into 8/18, 7/18,6/18, etc...

Here is the df.head() output:

enter image description here

Output of print(df.columns)

<class 'str'>

Index(['NDD 8/31', 'Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

       'Jun 2018(P&I Applied)', 'May 2018(P&I Applied)',

       'Apr 2018(P&I Applied)', 'Mar 2018(P&I Applied)',

       'Feb 2018(P&I Expected)', 'Jan 2018(P&I Applied)',

       'Dec 2017(P&I Applied)', 'Nov 2017(P&I Applied)',

       'Oct 2017(P&I Applied)', 'Sep 2017(P&I Applied)',

       'Paystring as of cut off as if 10.31',

       'Paystrings as of

Does anyone know how to achieve this?

python pandas datetime dataframe indexing

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

edited Nov 15 '18 at 23:18

jpp

94.1k2155106

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

asked Nov 15 '18 at 22:24

Snorrlaxxx

14511

Can you add the output of print(df.columns) to the question?

– Scott Boston
Nov 15 '18 at 22:31

@ScottBoston Added

– Snorrlaxxx
Nov 15 '18 at 22:36

Do you want to replace Jun 2018 -> 6/18 only, or should the entire column name be 6/18?

– Matthias Ossadnik
Nov 15 '18 at 22:56

@MatthiasOssadnik No I do not need to modify the data frame, I just want to convert Jun 2018 - > 6/18 and put it into a vector or list

– Snorrlaxxx
Nov 15 '18 at 23:04

add a comment |

Can you add the output of print(df.columns) to the question?

– Scott Boston
Nov 15 '18 at 22:31

@ScottBoston Added

– Snorrlaxxx
Nov 15 '18 at 22:36

Do you want to replace Jun 2018 -> 6/18 only, or should the entire column name be 6/18?

– Matthias Ossadnik
Nov 15 '18 at 22:56

@MatthiasOssadnik No I do not need to modify the data frame, I just want to convert Jun 2018 - > 6/18 and put it into a vector or list

– Snorrlaxxx
Nov 15 '18 at 23:04

Can you add the output of print(df.columns) to the question?

– Scott Boston
Nov 15 '18 at 22:31

@ScottBoston Added

– Snorrlaxxx
Nov 15 '18 at 22:36

Do you want to replace Jun 2018 -> 6/18 only, or should the entire column name be 6/18?

– Matthias Ossadnik
Nov 15 '18 at 22:56

@MatthiasOssadnik No I do not need to modify the data frame, I just want to convert Jun 2018 - > 6/18 and put it into a vector or list

– Snorrlaxxx
Nov 15 '18 at 23:04

add a comment |

1 Answer
1

active

oldest

votes

You can convert to datetime and then use strftime. The below logic also ensures non-date columns remain unchanged.

df = pd.DataFrame(columns=['Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

                           'Jun 2018(P&I Applied)', 'Paystring as of cut off as if 10.31'])



dates = pd.Series(pd.to_datetime(df.columns.str[:8], errors='coerce'))



df.columns = dates.dt.strftime('%m/%y').mask(dates.isnull(), pd.Series(df.columns))



print(df.columns)



# Index(['08/18', '07/18', '06/18', 'Paystring as of cut off as if 10.31'], dtype='object')



print(dates.dt.month)



# 0    8.0

# 1    7.0

# 2    6.0

# 3    NaN

# dtype: float64

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

|
show 3 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You can convert to datetime and then use strftime. The below logic also ensures non-date columns remain unchanged.

df = pd.DataFrame(columns=['Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

                           'Jun 2018(P&I Applied)', 'Paystring as of cut off as if 10.31'])



dates = pd.Series(pd.to_datetime(df.columns.str[:8], errors='coerce'))



df.columns = dates.dt.strftime('%m/%y').mask(dates.isnull(), pd.Series(df.columns))



print(df.columns)



# Index(['08/18', '07/18', '06/18', 'Paystring as of cut off as if 10.31'], dtype='object')



print(dates.dt.month)



# 0    8.0

# 1    7.0

# 2    6.0

# 3    NaN

# dtype: float64

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

|
show 3 more comments

You can convert to datetime and then use strftime. The below logic also ensures non-date columns remain unchanged.

df = pd.DataFrame(columns=['Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

                           'Jun 2018(P&I Applied)', 'Paystring as of cut off as if 10.31'])



dates = pd.Series(pd.to_datetime(df.columns.str[:8], errors='coerce'))



df.columns = dates.dt.strftime('%m/%y').mask(dates.isnull(), pd.Series(df.columns))



print(df.columns)



# Index(['08/18', '07/18', '06/18', 'Paystring as of cut off as if 10.31'], dtype='object')



print(dates.dt.month)



# 0    8.0

# 1    7.0

# 2    6.0

# 3    NaN

# dtype: float64

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

|
show 3 more comments

You can convert to datetime and then use strftime. The below logic also ensures non-date columns remain unchanged.

df = pd.DataFrame(columns=['Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

                           'Jun 2018(P&I Applied)', 'Paystring as of cut off as if 10.31'])



dates = pd.Series(pd.to_datetime(df.columns.str[:8], errors='coerce'))



df.columns = dates.dt.strftime('%m/%y').mask(dates.isnull(), pd.Series(df.columns))



print(df.columns)



# Index(['08/18', '07/18', '06/18', 'Paystring as of cut off as if 10.31'], dtype='object')



print(dates.dt.month)



# 0    8.0

# 1    7.0

# 2    6.0

# 3    NaN

# dtype: float64

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

You can convert to datetime and then use strftime. The below logic also ensures non-date columns remain unchanged.

df = pd.DataFrame(columns=['Aug 2018(P&I Applied)', 'Jul 2018(P&I Applied)',

                           'Jun 2018(P&I Applied)', 'Paystring as of cut off as if 10.31'])



dates = pd.Series(pd.to_datetime(df.columns.str[:8], errors='coerce'))



df.columns = dates.dt.strftime('%m/%y').mask(dates.isnull(), pd.Series(df.columns))



print(df.columns)



# Index(['08/18', '07/18', '06/18', 'Paystring as of cut off as if 10.31'], dtype='object')



print(dates.dt.month)



# 0    8.0

# 1    7.0

# 2    6.0

# 3    NaN

# dtype: float64

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

edited Nov 15 '18 at 23:45

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

answered Nov 15 '18 at 22:32

jpp

94.1k2155106

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

|
show 3 more comments

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

Could you re-edit your answer to include the data frame I have?

– Snorrlaxxx
Nov 15 '18 at 23:21

@Snorrlaxxx, No I can't, because your question doesn't have a complete dataframe.

– jpp
Nov 15 '18 at 23:23

Okay, how would I convert the series into a string?

– Snorrlaxxx
Nov 15 '18 at 23:25

@Snorrlaxxx, I don't understand your question, maybe str(my_series) ?

– jpp
Nov 15 '18 at 23:25

Quick question how do I just get the months from dates list?

– Snorrlaxxx
Nov 15 '18 at 23:35

|
show 3 more comments

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