org.codehaus.jackson.JsonParseException while deserialising String
0
I have the following string in a resource file and I am trying to deserialise to Map using ObjectMapper
{ 13714974: { get-url: "https://example.com/get", post-url:
"https://example.com/post" }, 13743772: { get-url:
"https://example.com/get", post-url: "https://example.com/post" }
ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
Map<String, Map<String, String>> cmMappings = mapper.readValue(content, Map.class);
When I use codehaus jackson ObjectMapper and try to deserialise it, I get the exception,
Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('1' (code 49)): was expecting either valid name character (for unquoted name) or double-quote (for quoted) to start field name
at [Source: java.io.StringReader@7cdbc5d3; line: 1, column: 3]
at org.codehaus.jackson.impl.JsonParserBase._constructError(JsonParserBase.java:651)
at org.codehaus.jackson.impl.JsonParserBase._reportError(JsonParserBase.java:635)
at org.codehaus.jackson.impl.JsonParserBase._reportUnexpectedChar(JsonParserBase.java:576)
at org.codehaus.jackson.impl.ReaderBasedParser._handleUnusualFieldName(ReaderBasedParser.java:385)
at org.codehaus.jackson.impl.ReaderBasedParser._parseFieldName(ReaderBasedParser.java:268)
at org.codehaus.jackson.impl.ReaderBasedParser.nextToken(ReaderBasedParser.java:118)
and when running the code to deserialise a resource file containing string of this format I get Exception while deserialising because of hyphen in field names.
I tried fasterxml ObjectMapper also but it does not work
So how do I debug the string to the map ?
java deserialization objectmapper fasterxml
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
add a comment |
0
I have the following string in a resource file and I am trying to deserialise to Map using ObjectMapper
{ 13714974: { get-url: "https://example.com/get", post-url:
"https://example.com/post" }, 13743772: { get-url:
"https://example.com/get", post-url: "https://example.com/post" }
ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
Map<String, Map<String, String>> cmMappings = mapper.readValue(content, Map.class);
When I use codehaus jackson ObjectMapper and try to deserialise it, I get the exception,
Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('1' (code 49)): was expecting either valid name character (for unquoted name) or double-quote (for quoted) to start field name
at [Source: java.io.StringReader@7cdbc5d3; line: 1, column: 3]
at org.codehaus.jackson.impl.JsonParserBase._constructError(JsonParserBase.java:651)
at org.codehaus.jackson.impl.JsonParserBase._reportError(JsonParserBase.java:635)
at org.codehaus.jackson.impl.JsonParserBase._reportUnexpectedChar(JsonParserBase.java:576)
at org.codehaus.jackson.impl.ReaderBasedParser._handleUnusualFieldName(ReaderBasedParser.java:385)
at org.codehaus.jackson.impl.ReaderBasedParser._parseFieldName(ReaderBasedParser.java:268)
at org.codehaus.jackson.impl.ReaderBasedParser.nextToken(ReaderBasedParser.java:118)
and when running the code to deserialise a resource file containing string of this format I get Exception while deserialising because of hyphen in field names.
I tried fasterxml ObjectMapper also but it does not work
So how do I debug the string to the map ?
java deserialization objectmapper fasterxml
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54
add a comment |
0
0
0
I have the following string in a resource file and I am trying to deserialise to Map using ObjectMapper
{ 13714974: { get-url: "https://example.com/get", post-url:
"https://example.com/post" }, 13743772: { get-url:
"https://example.com/get", post-url: "https://example.com/post" }
ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
Map<String, Map<String, String>> cmMappings = mapper.readValue(content, Map.class);
When I use codehaus jackson ObjectMapper and try to deserialise it, I get the exception,
Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('1' (code 49)): was expecting either valid name character (for unquoted name) or double-quote (for quoted) to start field name
at [Source: java.io.StringReader@7cdbc5d3; line: 1, column: 3]
at org.codehaus.jackson.impl.JsonParserBase._constructError(JsonParserBase.java:651)
at org.codehaus.jackson.impl.JsonParserBase._reportError(JsonParserBase.java:635)
at org.codehaus.jackson.impl.JsonParserBase._reportUnexpectedChar(JsonParserBase.java:576)
at org.codehaus.jackson.impl.ReaderBasedParser._handleUnusualFieldName(ReaderBasedParser.java:385)
at org.codehaus.jackson.impl.ReaderBasedParser._parseFieldName(ReaderBasedParser.java:268)
at org.codehaus.jackson.impl.ReaderBasedParser.nextToken(ReaderBasedParser.java:118)
and when running the code to deserialise a resource file containing string of this format I get Exception while deserialising because of hyphen in field names.
I tried fasterxml ObjectMapper also but it does not work
So how do I debug the string to the map ?
java deserialization objectmapper fasterxml
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
I have the following string in a resource file and I am trying to deserialise to Map using ObjectMapper
{ 13714974: { get-url: "https://example.com/get", post-url:
"https://example.com/post" }, 13743772: { get-url:
"https://example.com/get", post-url: "https://example.com/post" }
ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
Map<String, Map<String, String>> cmMappings = mapper.readValue(content, Map.class);
When I use codehaus jackson ObjectMapper and try to deserialise it, I get the exception,
Exception in thread "main" org.codehaus.jackson.JsonParseException: Unexpected character ('1' (code 49)): was expecting either valid name character (for unquoted name) or double-quote (for quoted) to start field name
at [Source: java.io.StringReader@7cdbc5d3; line: 1, column: 3]
at org.codehaus.jackson.impl.JsonParserBase._constructError(JsonParserBase.java:651)
at org.codehaus.jackson.impl.JsonParserBase._reportError(JsonParserBase.java:635)
at org.codehaus.jackson.impl.JsonParserBase._reportUnexpectedChar(JsonParserBase.java:576)
at org.codehaus.jackson.impl.ReaderBasedParser._handleUnusualFieldName(ReaderBasedParser.java:385)
at org.codehaus.jackson.impl.ReaderBasedParser._parseFieldName(ReaderBasedParser.java:268)
at org.codehaus.jackson.impl.ReaderBasedParser.nextToken(ReaderBasedParser.java:118)
and when running the code to deserialise a resource file containing string of this format I get Exception while deserialising because of hyphen in field names.
I tried fasterxml ObjectMapper also but it does not work
So how do I debug the string to the map ?
java deserialization objectmapper fasterxml
java deserialization objectmapper fasterxml
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
edited Nov 19 '18 at 8:03
Aditya Sharma
4851416
4851416
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
asked Nov 19 '18 at 7:36
Aarish RameshAarish Ramesh
2,15373071
2,15373071
It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54
add a comment |
It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54
It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54
add a comment |
1 Answer
1
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oldest
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This is how we deserialise the above String
try {
ObjectMapper mapper = new ObjectMapper();
ClassPathResource resource = new ClassPathResource("resourceFile");
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
// log error
}
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
This is how we deserialise the above String
try {
ObjectMapper mapper = new ObjectMapper();
ClassPathResource resource = new ClassPathResource("resourceFile");
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
// log error
}
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
add a comment |
0
This is how we deserialise the above String
try {
ObjectMapper mapper = new ObjectMapper();
ClassPathResource resource = new ClassPathResource("resourceFile");
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
// log error
}
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
add a comment |
0
0
0
This is how we deserialise the above String
try {
ObjectMapper mapper = new ObjectMapper();
ClassPathResource resource = new ClassPathResource("resourceFile");
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
// log error
}
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
This is how we deserialise the above String
try {
ObjectMapper mapper = new ObjectMapper();
ClassPathResource resource = new ClassPathResource("resourceFile");
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
TypeReference<HashMap<String, Map<String, String>>> typeRef = new TypeReference<HashMap<String, Map<String, String>>>() {};
cmMappings = mapper.readValue(resource.getInputStream(), typeRef);
} catch (Exception ex) {
// log error
}
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
edited Nov 19 '18 at 9:21
Ashish Kamble
632519
632519
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
answered Nov 19 '18 at 8:17
Aarish RameshAarish Ramesh
2,15373071
2,15373071
add a comment |
add a comment |
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It's not a valid JSON
– user7294900
Nov 19 '18 at 7:39
Yes it is not. readValue is only for deserialising valid json ?
– Aarish Ramesh
Nov 19 '18 at 7:44
So how do I do i deserialise it ?
– Aarish Ramesh
Nov 19 '18 at 7:46
Also fasterxml does not have an ALLOW_UNQUOTED_FIELD_NAMES configuration just like codehaus.json
– Aarish Ramesh
Nov 19 '18 at 7:47
Here is a question on similar problem witht ObjectMapper stackoverflow.com/questions/4815231/…
– Aarish Ramesh
Nov 19 '18 at 7:54