SensorManager only working on some devices












0















I have the following code to get the x and y angle of my device and it is working fine on my phone, but not my tablet (Samsung galaxy tab e). I was wondering if anyone had any idea as to what could be causing it to work on one device but not another.



I did also ensure that screen rotation was enabled on both. My assumption is that the tablet is lacking a sensor, and what I'm looking for most is a workaround. Any help would be much appreciated. Thanks in advance!



Source code:



double yAngle;
double xAngle;

@Override
protected void onResume() {
super.onResume();
sensorManager.unregisterListener(this);
sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR),RATE);
}

@Override
public void onSensorChanged(SensorEvent event) {
float rotationMatrix;
rotationMatrix = new float[16];
SensorManager.getRotationMatrixFromVector(rotationMatrix, event.values);
determineOrientation(rotationMatrix);
lblY.setText(String.format("%.1f", yAngle));
lblX.setText(String.format("%.1f", xAngle));

}

private void determineOrientation(float rotationMatrix){
//CREATING FLOAT ARRAY OF ORIENTATION VALUES
float orientationValues = new float[3];
SensorManager.getOrientation(rotationMatrix, orientationValues);
yAngle = Math.toDegrees(orientationValues[2]);
xAngle = Math.toDegrees(orientationValues[1]);
}









share|improve this question

























  • sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

    – Umer Farooq
    Nov 17 '18 at 16:03











  • It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

    – Paul Schreckenbach
    Nov 17 '18 at 16:21
















0















I have the following code to get the x and y angle of my device and it is working fine on my phone, but not my tablet (Samsung galaxy tab e). I was wondering if anyone had any idea as to what could be causing it to work on one device but not another.



I did also ensure that screen rotation was enabled on both. My assumption is that the tablet is lacking a sensor, and what I'm looking for most is a workaround. Any help would be much appreciated. Thanks in advance!



Source code:



double yAngle;
double xAngle;

@Override
protected void onResume() {
super.onResume();
sensorManager.unregisterListener(this);
sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR),RATE);
}

@Override
public void onSensorChanged(SensorEvent event) {
float rotationMatrix;
rotationMatrix = new float[16];
SensorManager.getRotationMatrixFromVector(rotationMatrix, event.values);
determineOrientation(rotationMatrix);
lblY.setText(String.format("%.1f", yAngle));
lblX.setText(String.format("%.1f", xAngle));

}

private void determineOrientation(float rotationMatrix){
//CREATING FLOAT ARRAY OF ORIENTATION VALUES
float orientationValues = new float[3];
SensorManager.getOrientation(rotationMatrix, orientationValues);
yAngle = Math.toDegrees(orientationValues[2]);
xAngle = Math.toDegrees(orientationValues[1]);
}









share|improve this question

























  • sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

    – Umer Farooq
    Nov 17 '18 at 16:03











  • It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

    – Paul Schreckenbach
    Nov 17 '18 at 16:21














0












0








0








I have the following code to get the x and y angle of my device and it is working fine on my phone, but not my tablet (Samsung galaxy tab e). I was wondering if anyone had any idea as to what could be causing it to work on one device but not another.



I did also ensure that screen rotation was enabled on both. My assumption is that the tablet is lacking a sensor, and what I'm looking for most is a workaround. Any help would be much appreciated. Thanks in advance!



Source code:



double yAngle;
double xAngle;

@Override
protected void onResume() {
super.onResume();
sensorManager.unregisterListener(this);
sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR),RATE);
}

@Override
public void onSensorChanged(SensorEvent event) {
float rotationMatrix;
rotationMatrix = new float[16];
SensorManager.getRotationMatrixFromVector(rotationMatrix, event.values);
determineOrientation(rotationMatrix);
lblY.setText(String.format("%.1f", yAngle));
lblX.setText(String.format("%.1f", xAngle));

}

private void determineOrientation(float rotationMatrix){
//CREATING FLOAT ARRAY OF ORIENTATION VALUES
float orientationValues = new float[3];
SensorManager.getOrientation(rotationMatrix, orientationValues);
yAngle = Math.toDegrees(orientationValues[2]);
xAngle = Math.toDegrees(orientationValues[1]);
}









share|improve this question
















I have the following code to get the x and y angle of my device and it is working fine on my phone, but not my tablet (Samsung galaxy tab e). I was wondering if anyone had any idea as to what could be causing it to work on one device but not another.



I did also ensure that screen rotation was enabled on both. My assumption is that the tablet is lacking a sensor, and what I'm looking for most is a workaround. Any help would be much appreciated. Thanks in advance!



Source code:



double yAngle;
double xAngle;

@Override
protected void onResume() {
super.onResume();
sensorManager.unregisterListener(this);
sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR),RATE);
}

@Override
public void onSensorChanged(SensorEvent event) {
float rotationMatrix;
rotationMatrix = new float[16];
SensorManager.getRotationMatrixFromVector(rotationMatrix, event.values);
determineOrientation(rotationMatrix);
lblY.setText(String.format("%.1f", yAngle));
lblX.setText(String.format("%.1f", xAngle));

}

private void determineOrientation(float rotationMatrix){
//CREATING FLOAT ARRAY OF ORIENTATION VALUES
float orientationValues = new float[3];
SensorManager.getOrientation(rotationMatrix, orientationValues);
yAngle = Math.toDegrees(orientationValues[2]);
xAngle = Math.toDegrees(orientationValues[1]);
}






java android android-studio android-sensors sensormanager






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share|improve this question













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share|improve this question








edited Nov 17 '18 at 14:53







Paul Schreckenbach

















asked Nov 17 '18 at 14:32









Paul SchreckenbachPaul Schreckenbach

104




104













  • sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

    – Umer Farooq
    Nov 17 '18 at 16:03











  • It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

    – Paul Schreckenbach
    Nov 17 '18 at 16:21



















  • sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

    – Umer Farooq
    Nov 17 '18 at 16:03











  • It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

    – Paul Schreckenbach
    Nov 17 '18 at 16:21

















sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

– Umer Farooq
Nov 17 '18 at 16:03





sensorManager.getDefaultSensor(Sensor.TYPE_ROTATION_VECTOR) returns null when the sensor is not supported by the device. You can log its value to see whether it returns null in the tablet or not ?

– Umer Farooq
Nov 17 '18 at 16:03













It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

– Paul Schreckenbach
Nov 17 '18 at 16:21





It does indeed return null on the tablet. Would you know if there are other sensors that can be used? Thanks

– Paul Schreckenbach
Nov 17 '18 at 16:21












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