Get distinct records values
Is there a way to query for objects with not same values on some field? For example I have Records:
{ id : 1, name : "my_name", salary : 1200 }
{ id : 2, name : "my_name", salary : 800 }
{ id : 3, name : "john", salary : 500 }
Query : find all with NOT_THE_SAME(name)
I just want records with id 1 and 3 because I specified that I don't want records with same value in field name or 2 and 3, it does not matter in this situation.
mongodb
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
add a comment |
Is there a way to query for objects with not same values on some field? For example I have Records:
{ id : 1, name : "my_name", salary : 1200 }
{ id : 2, name : "my_name", salary : 800 }
{ id : 3, name : "john", salary : 500 }
Query : find all with NOT_THE_SAME(name)
I just want records with id 1 and 3 because I specified that I don't want records with same value in field name or 2 and 3, it does not matter in this situation.
mongodb
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
add a comment |
Is there a way to query for objects with not same values on some field? For example I have Records:
{ id : 1, name : "my_name", salary : 1200 }
{ id : 2, name : "my_name", salary : 800 }
{ id : 3, name : "john", salary : 500 }
Query : find all with NOT_THE_SAME(name)
I just want records with id 1 and 3 because I specified that I don't want records with same value in field name or 2 and 3, it does not matter in this situation.
mongodb
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
Is there a way to query for objects with not same values on some field? For example I have Records:
{ id : 1, name : "my_name", salary : 1200 }
{ id : 2, name : "my_name", salary : 800 }
{ id : 3, name : "john", salary : 500 }
Query : find all with NOT_THE_SAME(name)
I just want records with id 1 and 3 because I specified that I don't want records with same value in field name or 2 and 3, it does not matter in this situation.
mongodb
mongodb
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
edited Dec 18 '13 at 10:32
Chris Seymour
62.9k20125162
62.9k20125162
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
asked Dec 18 '13 at 10:24
GelidusGelidus
5451719
5451719
add a comment |
add a comment |
5 Answers
5
active
oldest
votes
You can use db.collection.distinct to get back an array of unique values:
> db.test.distinct("name")
[ "my_name", "john" ]
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
add a comment |
You can also use a distinct sentence with filtered collection. For example, you can get distinct values of names from salaries over 800 with the following query:
db.test.distinct("name", { "salary": { $gt: 800 } })
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
add a comment |
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
should list all names with their salaries.
$max returns the highest salary per element. You could also choose $first etc, see https://docs.mongodb.com/manual/reference/operator/aggregation/group/#accumulator-operator.
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
add a comment |
Mongo DB version > 3.4
db.test.distinct("name")
Mongo DB version < 3.4
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
add a comment |
db.runCommand ( {
distinct: "CollectionName",
key: "key",
query: { "createdDate": {
$gte:new ISODate("2017-04-04T23:59:59Z"),
$lte:new ISODate("2017-04-25T23:59:59Z")}} } )
this query helps find data in collection , will fetch value of key from all documents which satisfy condition of between date
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use db.collection.distinct to get back an array of unique values:
> db.test.distinct("name")
[ "my_name", "john" ]
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
add a comment |
You can use db.collection.distinct to get back an array of unique values:
> db.test.distinct("name")
[ "my_name", "john" ]
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
add a comment |
You can use db.collection.distinct to get back an array of unique values:
> db.test.distinct("name")
[ "my_name", "john" ]
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
You can use db.collection.distinct to get back an array of unique values:
> db.test.distinct("name")
[ "my_name", "john" ]
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
answered Dec 18 '13 at 10:30
Chris SeymourChris Seymour
62.9k20125162
62.9k20125162
add a comment |
add a comment |
You can also use a distinct sentence with filtered collection. For example, you can get distinct values of names from salaries over 800 with the following query:
db.test.distinct("name", { "salary": { $gt: 800 } })
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
add a comment |
You can also use a distinct sentence with filtered collection. For example, you can get distinct values of names from salaries over 800 with the following query:
db.test.distinct("name", { "salary": { $gt: 800 } })
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
add a comment |
You can also use a distinct sentence with filtered collection. For example, you can get distinct values of names from salaries over 800 with the following query:
db.test.distinct("name", { "salary": { $gt: 800 } })
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
You can also use a distinct sentence with filtered collection. For example, you can get distinct values of names from salaries over 800 with the following query:
db.test.distinct("name", { "salary": { $gt: 800 } })
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
answered Sep 7 '16 at 21:38
J.C. GrasJ.C. Gras
1,6031519
1,6031519
add a comment |
add a comment |
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
should list all names with their salaries.
$max returns the highest salary per element. You could also choose $first etc, see https://docs.mongodb.com/manual/reference/operator/aggregation/group/#accumulator-operator.
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
add a comment |
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
should list all names with their salaries.
$max returns the highest salary per element. You could also choose $first etc, see https://docs.mongodb.com/manual/reference/operator/aggregation/group/#accumulator-operator.
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
add a comment |
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
should list all names with their salaries.
$max returns the highest salary per element. You could also choose $first etc, see https://docs.mongodb.com/manual/reference/operator/aggregation/group/#accumulator-operator.
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
should list all names with their salaries.
$max returns the highest salary per element. You could also choose $first etc, see https://docs.mongodb.com/manual/reference/operator/aggregation/group/#accumulator-operator.
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
answered Jul 3 '17 at 14:00
serv-incserv-inc
15.2k57289
15.2k57289
add a comment |
add a comment |
Mongo DB version > 3.4
db.test.distinct("name")
Mongo DB version < 3.4
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
add a comment |
Mongo DB version > 3.4
db.test.distinct("name")
Mongo DB version < 3.4
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
add a comment |
Mongo DB version > 3.4
db.test.distinct("name")
Mongo DB version < 3.4
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
Mongo DB version > 3.4
db.test.distinct("name")
Mongo DB version < 3.4
db.test.aggregate([{$group: {_id: "$name", salary: {$max: "$salary"}}}])
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
edited Nov 18 '18 at 0:32
Stephen Rauch
30k153758
30k153758
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
answered Nov 18 '18 at 0:09
Ramesh SeeraRamesh Seera
413
413
add a comment |
add a comment |
db.runCommand ( {
distinct: "CollectionName",
key: "key",
query: { "createdDate": {
$gte:new ISODate("2017-04-04T23:59:59Z"),
$lte:new ISODate("2017-04-25T23:59:59Z")}} } )
this query helps find data in collection , will fetch value of key from all documents which satisfy condition of between date
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
add a comment |
db.runCommand ( {
distinct: "CollectionName",
key: "key",
query: { "createdDate": {
$gte:new ISODate("2017-04-04T23:59:59Z"),
$lte:new ISODate("2017-04-25T23:59:59Z")}} } )
this query helps find data in collection , will fetch value of key from all documents which satisfy condition of between date
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
add a comment |
db.runCommand ( {
distinct: "CollectionName",
key: "key",
query: { "createdDate": {
$gte:new ISODate("2017-04-04T23:59:59Z"),
$lte:new ISODate("2017-04-25T23:59:59Z")}} } )
this query helps find data in collection , will fetch value of key from all documents which satisfy condition of between date
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
db.runCommand ( {
distinct: "CollectionName",
key: "key",
query: { "createdDate": {
$gte:new ISODate("2017-04-04T23:59:59Z"),
$lte:new ISODate("2017-04-25T23:59:59Z")}} } )
this query helps find data in collection , will fetch value of key from all documents which satisfy condition of between date
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
edited Jul 3 '17 at 13:50
serv-inc
15.2k57289
15.2k57289
answered Apr 26 '17 at 14:58
GSKGSK
25337
answered Apr 26 '17 at 14:58
GSKGSK
25337
answered Apr 26 '17 at 14:58
GSKGSK
25337
25337
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
add a comment |
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, this reduces the readability of both the code and the explanations!
– Martin Tournoij
Apr 26 '17 at 23:37
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
@Carpetsmoker - added comments ,hope this helps
– GSK
Apr 28 '17 at 9:07
add a comment |
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