Haskell join function inputs in list in specific order












-6















Exercise



Hello every one!



I have been struggling to get this function working in the specific way they want.



I tried everything and the only output I could make was without the starting and ending point, eg: [((a,b),(b,c))]



Could someone please give me some help? I am stucked...



Update: type Point = (Float, Float)










share|improve this question




















  • 3





    Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

    – DarthFennec
    Nov 21 '18 at 0:31






  • 1





    please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

    – Jere
    Nov 21 '18 at 1:53











  • @Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

    – Kryzek
    Nov 21 '18 at 12:22


















-6















Exercise



Hello every one!



I have been struggling to get this function working in the specific way they want.



I tried everything and the only output I could make was without the starting and ending point, eg: [((a,b),(b,c))]



Could someone please give me some help? I am stucked...



Update: type Point = (Float, Float)










share|improve this question




















  • 3





    Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

    – DarthFennec
    Nov 21 '18 at 0:31






  • 1





    please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

    – Jere
    Nov 21 '18 at 1:53











  • @Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

    – Kryzek
    Nov 21 '18 at 12:22
















-6












-6








-6








Exercise



Hello every one!



I have been struggling to get this function working in the specific way they want.



I tried everything and the only output I could make was without the starting and ending point, eg: [((a,b),(b,c))]



Could someone please give me some help? I am stucked...



Update: type Point = (Float, Float)










share|improve this question
















Exercise



Hello every one!



I have been struggling to get this function working in the specific way they want.



I tried everything and the only output I could make was without the starting and ending point, eg: [((a,b),(b,c))]



Could someone please give me some help? I am stucked...



Update: type Point = (Float, Float)







haskell






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 12:37







Kryzek

















asked Nov 20 '18 at 23:58









KryzekKryzek

14




14








  • 3





    Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

    – DarthFennec
    Nov 21 '18 at 0:31






  • 1





    please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

    – Jere
    Nov 21 '18 at 1:53











  • @Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

    – Kryzek
    Nov 21 '18 at 12:22
















  • 3





    Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

    – DarthFennec
    Nov 21 '18 at 0:31






  • 1





    please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

    – Jere
    Nov 21 '18 at 1:53











  • @Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

    – Kryzek
    Nov 21 '18 at 12:22










3




3





Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

– DarthFennec
Nov 21 '18 at 0:31





Could you show what you've tried? That should give us a better idea of exactly what part you're having trouble with.

– DarthFennec
Nov 21 '18 at 0:31




1




1





please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

– Jere
Nov 21 '18 at 1:53





please narrow down your problem. How far do you get on your own and where exactly do you need help? We are not starting to just randomly solve everyones homework...

– Jere
Nov 21 '18 at 1:53













@Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

– Kryzek
Nov 21 '18 at 12:22







@Jere I got the hint I needed! The only thing missing was joining first and second input to the beginning and ending respectively. Thanks for the interest!

– Kryzek
Nov 21 '18 at 12:22














1 Answer
1






active

oldest

votes


















-1














Well since you got it working without the starting/ending point. An easy way to complete would be use your function but add the starting/ending point in the list in an inner function. So your interface is still same.



Another way using recursion, pattern matching and guards is:



-- assuming the inputs to be int as definition of point not given
solve x z = [(x,z)]

solve x z (y:ys)
| x == 0 = solve y z ys -- x ==0 to be replaced by null/empty condition on x
| null ys && z == 0 = -- z ==0 to be replaced by null/empty condition on z
| null ys = [(y, z)]
| otherwise = (x,y) : solve y z ys


Added a base case when the list is empty or start/end points not valid based on darthfennec comment.






share|improve this answer


























  • That base case doesn't look quite right. I don't think you should be ignoring x.

    – DarthFennec
    Nov 21 '18 at 0:50











  • I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

    – Kryzek
    Nov 21 '18 at 12:17













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1 Answer
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1 Answer
1






active

oldest

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active

oldest

votes









-1














Well since you got it working without the starting/ending point. An easy way to complete would be use your function but add the starting/ending point in the list in an inner function. So your interface is still same.



Another way using recursion, pattern matching and guards is:



-- assuming the inputs to be int as definition of point not given
solve x z = [(x,z)]

solve x z (y:ys)
| x == 0 = solve y z ys -- x ==0 to be replaced by null/empty condition on x
| null ys && z == 0 = -- z ==0 to be replaced by null/empty condition on z
| null ys = [(y, z)]
| otherwise = (x,y) : solve y z ys


Added a base case when the list is empty or start/end points not valid based on darthfennec comment.






share|improve this answer


























  • That base case doesn't look quite right. I don't think you should be ignoring x.

    – DarthFennec
    Nov 21 '18 at 0:50











  • I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

    – Kryzek
    Nov 21 '18 at 12:17


















-1














Well since you got it working without the starting/ending point. An easy way to complete would be use your function but add the starting/ending point in the list in an inner function. So your interface is still same.



Another way using recursion, pattern matching and guards is:



-- assuming the inputs to be int as definition of point not given
solve x z = [(x,z)]

solve x z (y:ys)
| x == 0 = solve y z ys -- x ==0 to be replaced by null/empty condition on x
| null ys && z == 0 = -- z ==0 to be replaced by null/empty condition on z
| null ys = [(y, z)]
| otherwise = (x,y) : solve y z ys


Added a base case when the list is empty or start/end points not valid based on darthfennec comment.






share|improve this answer


























  • That base case doesn't look quite right. I don't think you should be ignoring x.

    – DarthFennec
    Nov 21 '18 at 0:50











  • I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

    – Kryzek
    Nov 21 '18 at 12:17
















-1












-1








-1







Well since you got it working without the starting/ending point. An easy way to complete would be use your function but add the starting/ending point in the list in an inner function. So your interface is still same.



Another way using recursion, pattern matching and guards is:



-- assuming the inputs to be int as definition of point not given
solve x z = [(x,z)]

solve x z (y:ys)
| x == 0 = solve y z ys -- x ==0 to be replaced by null/empty condition on x
| null ys && z == 0 = -- z ==0 to be replaced by null/empty condition on z
| null ys = [(y, z)]
| otherwise = (x,y) : solve y z ys


Added a base case when the list is empty or start/end points not valid based on darthfennec comment.






share|improve this answer















Well since you got it working without the starting/ending point. An easy way to complete would be use your function but add the starting/ending point in the list in an inner function. So your interface is still same.



Another way using recursion, pattern matching and guards is:



-- assuming the inputs to be int as definition of point not given
solve x z = [(x,z)]

solve x z (y:ys)
| x == 0 = solve y z ys -- x ==0 to be replaced by null/empty condition on x
| null ys && z == 0 = -- z ==0 to be replaced by null/empty condition on z
| null ys = [(y, z)]
| otherwise = (x,y) : solve y z ys


Added a base case when the list is empty or start/end points not valid based on darthfennec comment.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 1:06

























answered Nov 21 '18 at 0:42









peeyush singhpeeyush singh

509313




509313













  • That base case doesn't look quite right. I don't think you should be ignoring x.

    – DarthFennec
    Nov 21 '18 at 0:50











  • I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

    – Kryzek
    Nov 21 '18 at 12:17





















  • That base case doesn't look quite right. I don't think you should be ignoring x.

    – DarthFennec
    Nov 21 '18 at 0:50











  • I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

    – Kryzek
    Nov 21 '18 at 12:17



















That base case doesn't look quite right. I don't think you should be ignoring x.

– DarthFennec
Nov 21 '18 at 0:50





That base case doesn't look quite right. I don't think you should be ignoring x.

– DarthFennec
Nov 21 '18 at 0:50













I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

– Kryzek
Nov 21 '18 at 12:17







I forgot to include, the Point is: type Point = (Float, Float) I am trying now your solutions and thank you for a quick reply!!

– Kryzek
Nov 21 '18 at 12:17






















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