SQL Server count records group by 4 weeks in month and location
1
I want to count total rows of 4 weeks in month and group it by location the results should be like:
location week1 week2 week3 week4
Floor A 10 0 3 4
Floor B 5 2 0 0
...
I've tried this to get a week number by given a date.
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
It's gives me this result:
+----+-----------+--------------+------------+
| id | create_by | create_date | WeekNumber |
+----+-----------+--------------+------------+
| 1 | 555001 | '2018-11-01' | 1 |
| 2 | 555002 | '2018-11-05' | 1 |
| 3 | 555004 | '2018-11-06' | 1 |
| 4 | 555001 | '2018-11-10' | 2 |
| 5 | 555003 | '2018-11-17' | 3 |
| 6 | 555002 | '2018-11-17' | 3 |
| 7 | 555001 | '2018-11-18' | 3 |
| 8 | 555003 | '2018-11-20' | 3 |
| 9 | 555001 | '2018-11-22' | 4 |
| 10 | 555001 | '2018-11-25' | 4 |
+----+-----------+--------------+------------+
My tables
tbl_user
+----+----------+----------+
| id | username | location |
+----+----------+----------+
| 1 | 555001 | Floor A |
| 2 | 555002 | Floor B |
| 3 | 555003 | Floor C |
| 4 | 555004 | Floor A |
| 5 | 555005 | Floor C |
+----+----------+----------+
tbl_list
+----+-----------+--------------+
| id | create_by | create_date |
+----+-----------+--------------+
| 1 | 555001 | '2018-11-01' |
| 2 | 555002 | '2018-11-05' |
| 3 | 555004 | '2018-11-06' |
| 4 | 555001 | '2018-11-10' |
| 5 | 555003 | '2018-11-17' |
| 6 | 555002 | '2018-11-17' |
| 7 | 555001 | '2018-11-18' |
| 8 | 555003 | '2018-11-20' |
| 9 | 555001 | '2018-11-22' |
| 10 | 555001 | '2018-11-25' |
+----+-----------+--------------+
sql
sql-server asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
add a comment |
1
I want to count total rows of 4 weeks in month and group it by location the results should be like:
location week1 week2 week3 week4
Floor A 10 0 3 4
Floor B 5 2 0 0
...
I've tried this to get a week number by given a date.
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
It's gives me this result:
+----+-----------+--------------+------------+
| id | create_by | create_date | WeekNumber |
+----+-----------+--------------+------------+
| 1 | 555001 | '2018-11-01' | 1 |
| 2 | 555002 | '2018-11-05' | 1 |
| 3 | 555004 | '2018-11-06' | 1 |
| 4 | 555001 | '2018-11-10' | 2 |
| 5 | 555003 | '2018-11-17' | 3 |
| 6 | 555002 | '2018-11-17' | 3 |
| 7 | 555001 | '2018-11-18' | 3 |
| 8 | 555003 | '2018-11-20' | 3 |
| 9 | 555001 | '2018-11-22' | 4 |
| 10 | 555001 | '2018-11-25' | 4 |
+----+-----------+--------------+------------+
My tables
tbl_user
+----+----------+----------+
| id | username | location |
+----+----------+----------+
| 1 | 555001 | Floor A |
| 2 | 555002 | Floor B |
| 3 | 555003 | Floor C |
| 4 | 555004 | Floor A |
| 5 | 555005 | Floor C |
+----+----------+----------+
tbl_list
+----+-----------+--------------+
| id | create_by | create_date |
+----+-----------+--------------+
| 1 | 555001 | '2018-11-01' |
| 2 | 555002 | '2018-11-05' |
| 3 | 555004 | '2018-11-06' |
| 4 | 555001 | '2018-11-10' |
| 5 | 555003 | '2018-11-17' |
| 6 | 555002 | '2018-11-17' |
| 7 | 555001 | '2018-11-18' |
| 8 | 555003 | '2018-11-20' |
| 9 | 555001 | '2018-11-22' |
| 10 | 555001 | '2018-11-25' |
+----+-----------+--------------+
sql
sql-server asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
add a comment |
1
1
1
I want to count total rows of 4 weeks in month and group it by location the results should be like:
location week1 week2 week3 week4
Floor A 10 0 3 4
Floor B 5 2 0 0
...
I've tried this to get a week number by given a date.
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
It's gives me this result:
+----+-----------+--------------+------------+
| id | create_by | create_date | WeekNumber |
+----+-----------+--------------+------------+
| 1 | 555001 | '2018-11-01' | 1 |
| 2 | 555002 | '2018-11-05' | 1 |
| 3 | 555004 | '2018-11-06' | 1 |
| 4 | 555001 | '2018-11-10' | 2 |
| 5 | 555003 | '2018-11-17' | 3 |
| 6 | 555002 | '2018-11-17' | 3 |
| 7 | 555001 | '2018-11-18' | 3 |
| 8 | 555003 | '2018-11-20' | 3 |
| 9 | 555001 | '2018-11-22' | 4 |
| 10 | 555001 | '2018-11-25' | 4 |
+----+-----------+--------------+------------+
My tables
tbl_user
+----+----------+----------+
| id | username | location |
+----+----------+----------+
| 1 | 555001 | Floor A |
| 2 | 555002 | Floor B |
| 3 | 555003 | Floor C |
| 4 | 555004 | Floor A |
| 5 | 555005 | Floor C |
+----+----------+----------+
tbl_list
+----+-----------+--------------+
| id | create_by | create_date |
+----+-----------+--------------+
| 1 | 555001 | '2018-11-01' |
| 2 | 555002 | '2018-11-05' |
| 3 | 555004 | '2018-11-06' |
| 4 | 555001 | '2018-11-10' |
| 5 | 555003 | '2018-11-17' |
| 6 | 555002 | '2018-11-17' |
| 7 | 555001 | '2018-11-18' |
| 8 | 555003 | '2018-11-20' |
| 9 | 555001 | '2018-11-22' |
| 10 | 555001 | '2018-11-25' |
+----+-----------+--------------+
sql
sql-server asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
I want to count total rows of 4 weeks in month and group it by location the results should be like:
location week1 week2 week3 week4
Floor A 10 0 3 4
Floor B 5 2 0 0
...
I've tried this to get a week number by given a date.
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
It's gives me this result:
+----+-----------+--------------+------------+
| id | create_by | create_date | WeekNumber |
+----+-----------+--------------+------------+
| 1 | 555001 | '2018-11-01' | 1 |
| 2 | 555002 | '2018-11-05' | 1 |
| 3 | 555004 | '2018-11-06' | 1 |
| 4 | 555001 | '2018-11-10' | 2 |
| 5 | 555003 | '2018-11-17' | 3 |
| 6 | 555002 | '2018-11-17' | 3 |
| 7 | 555001 | '2018-11-18' | 3 |
| 8 | 555003 | '2018-11-20' | 3 |
| 9 | 555001 | '2018-11-22' | 4 |
| 10 | 555001 | '2018-11-25' | 4 |
+----+-----------+--------------+------------+
My tables
tbl_user
+----+----------+----------+
| id | username | location |
+----+----------+----------+
| 1 | 555001 | Floor A |
| 2 | 555002 | Floor B |
| 3 | 555003 | Floor C |
| 4 | 555004 | Floor A |
| 5 | 555005 | Floor C |
+----+----------+----------+
tbl_list
+----+-----------+--------------+
| id | create_by | create_date |
+----+-----------+--------------+
| 1 | 555001 | '2018-11-01' |
| 2 | 555002 | '2018-11-05' |
| 3 | 555004 | '2018-11-06' |
| 4 | 555001 | '2018-11-10' |
| 5 | 555003 | '2018-11-17' |
| 6 | 555002 | '2018-11-17' |
| 7 | 555001 | '2018-11-18' |
| 8 | 555003 | '2018-11-20' |
| 9 | 555001 | '2018-11-22' |
| 10 | 555001 | '2018-11-25' |
+----+-----------+--------------+
sql
sql-server sql
sql-server asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
asked Nov 21 '18 at 7:48
Vintage BeefVintage Beef
154112
154112
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
You can try using pivot
with cte as
(
select *,location,
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
from tbl_list a left join tbl_user b on a.create_by=b.username
)
select * from
(select * from cte
pivot
(
count(create_by) for WeekNumber in ([1],[2],[3],[4])
) as pv)A left join
(select location,count(username) countofUser from tbl_user group by location)B on
A.location=B.location
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the... >= ... ANDcan be simply removed
– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
add a comment |
1
I would simply use conditional aggregation:
select u.location,
sum(case when day(l.create_date) >= 1 and day(l.create_date) < 8 then 1 else 0
end) as week1,
sum(case when day(l.create_date) >= 8 and day(l.create_date) < 15 then 1 else 0
end) as week2,
sum(case when day(l.create_date) >= 15 and day(l.create_date) < 22 then 1 else 0
end) as week3,
sum(case when day(l.create_date) >= 22 and day(l.create_date) < 29 then 1 else 0
end) as week4
from tbl_list l join
tbl_user u
on l.create_by = u.username
group by u.location;
This seems much, much simpler than attempting to use pivot. Subqueries are simply not needed for this logic.
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can try using pivot
with cte as
(
select *,location,
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
from tbl_list a left join tbl_user b on a.create_by=b.username
)
select * from
(select * from cte
pivot
(
count(create_by) for WeekNumber in ([1],[2],[3],[4])
) as pv)A left join
(select location,count(username) countofUser from tbl_user group by location)B on
A.location=B.location
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the... >= ... ANDcan be simply removed
– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
add a comment |
1
You can try using pivot
with cte as
(
select *,location,
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
from tbl_list a left join tbl_user b on a.create_by=b.username
)
select * from
(select * from cte
pivot
(
count(create_by) for WeekNumber in ([1],[2],[3],[4])
) as pv)A left join
(select location,count(username) countofUser from tbl_user group by location)B on
A.location=B.location
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the... >= ... ANDcan be simply removed
– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
add a comment |
1
1
1
You can try using pivot
with cte as
(
select *,location,
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
from tbl_list a left join tbl_user b on a.create_by=b.username
)
select * from
(select * from cte
pivot
(
count(create_by) for WeekNumber in ([1],[2],[3],[4])
) as pv)A left join
(select location,count(username) countofUser from tbl_user group by location)B on
A.location=B.location
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
You can try using pivot
with cte as
(
select *,location,
CASE WHEN DAY(create_date) >= 1 AND DAY(create_date) < 8 THEN 1
WHEN DAY(create_date) >= 8 AND DAY(create_date) < 15 THEN 2
WHEN DAY(create_date) >= 15 AND DAY(create_date) < 22 THEN 3
ELSE 4 END AS WeekNumber
from tbl_list a left join tbl_user b on a.create_by=b.username
)
select * from
(select * from cte
pivot
(
count(create_by) for WeekNumber in ([1],[2],[3],[4])
) as pv)A left join
(select location,count(username) countofUser from tbl_user group by location)B on
A.location=B.location
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
edited Nov 21 '18 at 8:35
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
answered Nov 21 '18 at 7:54
fa06fa06
17k21018
17k21018
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the... >= ... ANDcan be simply removed
– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
add a comment |
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the... >= ... ANDcan be simply removed
– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
I got this error msg "Incorrect syntax near '1'"
– Vintage Beef
Nov 21 '18 at 8:11
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the
... >= ... AND can be simply removed– dnoeth
Nov 21 '18 at 8:22
As a CASE stops when the first TRUE condition is met (and there's no day 0), all the
... >= ... AND can be simply removed– dnoeth
Nov 21 '18 at 8:22
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
Thank you so much. One more question How do I count numbers of user like Floor A has 2 users that created list data Floor B 1 user and Floor C 1
– Vintage Beef
Nov 21 '18 at 8:29
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
@VintageBeef, updated the answer for count user location wise - you can check
– fa06
Nov 21 '18 at 8:36
add a comment |
1
I would simply use conditional aggregation:
select u.location,
sum(case when day(l.create_date) >= 1 and day(l.create_date) < 8 then 1 else 0
end) as week1,
sum(case when day(l.create_date) >= 8 and day(l.create_date) < 15 then 1 else 0
end) as week2,
sum(case when day(l.create_date) >= 15 and day(l.create_date) < 22 then 1 else 0
end) as week3,
sum(case when day(l.create_date) >= 22 and day(l.create_date) < 29 then 1 else 0
end) as week4
from tbl_list l join
tbl_user u
on l.create_by = u.username
group by u.location;
This seems much, much simpler than attempting to use pivot. Subqueries are simply not needed for this logic.
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
add a comment |
1
I would simply use conditional aggregation:
select u.location,
sum(case when day(l.create_date) >= 1 and day(l.create_date) < 8 then 1 else 0
end) as week1,
sum(case when day(l.create_date) >= 8 and day(l.create_date) < 15 then 1 else 0
end) as week2,
sum(case when day(l.create_date) >= 15 and day(l.create_date) < 22 then 1 else 0
end) as week3,
sum(case when day(l.create_date) >= 22 and day(l.create_date) < 29 then 1 else 0
end) as week4
from tbl_list l join
tbl_user u
on l.create_by = u.username
group by u.location;
This seems much, much simpler than attempting to use pivot. Subqueries are simply not needed for this logic.
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
add a comment |
1
1
1
I would simply use conditional aggregation:
select u.location,
sum(case when day(l.create_date) >= 1 and day(l.create_date) < 8 then 1 else 0
end) as week1,
sum(case when day(l.create_date) >= 8 and day(l.create_date) < 15 then 1 else 0
end) as week2,
sum(case when day(l.create_date) >= 15 and day(l.create_date) < 22 then 1 else 0
end) as week3,
sum(case when day(l.create_date) >= 22 and day(l.create_date) < 29 then 1 else 0
end) as week4
from tbl_list l join
tbl_user u
on l.create_by = u.username
group by u.location;
This seems much, much simpler than attempting to use pivot. Subqueries are simply not needed for this logic.
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
I would simply use conditional aggregation:
select u.location,
sum(case when day(l.create_date) >= 1 and day(l.create_date) < 8 then 1 else 0
end) as week1,
sum(case when day(l.create_date) >= 8 and day(l.create_date) < 15 then 1 else 0
end) as week2,
sum(case when day(l.create_date) >= 15 and day(l.create_date) < 22 then 1 else 0
end) as week3,
sum(case when day(l.create_date) >= 22 and day(l.create_date) < 29 then 1 else 0
end) as week4
from tbl_list l join
tbl_user u
on l.create_by = u.username
group by u.location;
This seems much, much simpler than attempting to use pivot. Subqueries are simply not needed for this logic.
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
answered Nov 21 '18 at 12:24
Gordon LinoffGordon Linoff
788k35312417
788k35312417
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
add a comment |
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
Thank you so much. I found the same as your by myself too.
– Vintage Beef
Nov 29 '18 at 11:15
add a comment |
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