When making an and statement, I get an Syntax Error
When making a tax calculator, I seem to continue to be getting an error at the "=" in the following line of code:
elif int(vermogen) >= 30001 and <= 100800:
But I can't see a way to fix this. I've tried removing the integers but that didn't help, I've also tried to change my symbols to > and < instead of <= >= but that also didn't help. I think I made an obvious mistake but I don't seem to find it. When removing the "=" behind the "<" The syntax error moves from the "=" to the "<". I hope to hear from you soon. Here is the code I've been using/ It's in dutch, but that shouldn't affect anything.
vermogen = input('Hoeveelheid vermogen: ')
N_schijf1 = 30000
N_schijf2 = 70800
N_schijf3 = 877200
P_schijf2 = 424.8
P_schijf3 = 11403.6
if int(vermogen) <= 30000:
print("Je betaalt 0 euro aan vermogensbelasting")
elif int(vermogen) >= 30001 and <= 100800:
vermogen_betalen = int(vermogen) - N_schijf1
betalen_vermogen = vermogen_betalen * 0.006
print("Je betaalt",betalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 100801 and <= 978000:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2
betalen_vermogen = vermogen_betalen * 0.013
tebetalen_vermogen = P_schijf2 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 978001:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2 - P_schijf3
betalen_vermogen = vermogen_betalen * 0.0161
tebetalen_vermogen = P_schijf2 + P_schijf3 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
print("Test")
python if-statement syntax-error
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
add a comment |
When making a tax calculator, I seem to continue to be getting an error at the "=" in the following line of code:
elif int(vermogen) >= 30001 and <= 100800:
But I can't see a way to fix this. I've tried removing the integers but that didn't help, I've also tried to change my symbols to > and < instead of <= >= but that also didn't help. I think I made an obvious mistake but I don't seem to find it. When removing the "=" behind the "<" The syntax error moves from the "=" to the "<". I hope to hear from you soon. Here is the code I've been using/ It's in dutch, but that shouldn't affect anything.
vermogen = input('Hoeveelheid vermogen: ')
N_schijf1 = 30000
N_schijf2 = 70800
N_schijf3 = 877200
P_schijf2 = 424.8
P_schijf3 = 11403.6
if int(vermogen) <= 30000:
print("Je betaalt 0 euro aan vermogensbelasting")
elif int(vermogen) >= 30001 and <= 100800:
vermogen_betalen = int(vermogen) - N_schijf1
betalen_vermogen = vermogen_betalen * 0.006
print("Je betaalt",betalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 100801 and <= 978000:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2
betalen_vermogen = vermogen_betalen * 0.013
tebetalen_vermogen = P_schijf2 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 978001:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2 - P_schijf3
betalen_vermogen = vermogen_betalen * 0.0161
tebetalen_vermogen = P_schijf2 + P_schijf3 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
print("Test")
python if-statement syntax-error
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
4
andis used to join complete conditions. Operands don't carry across theand. You can use30001 <= int(vermogen) <= 100800
– khelwood
Nov 19 '18 at 9:30
1
elif int(vermogen) >= 30001 and <= 100800should beelif int(vermogen) >= 30001 and int(vermogen) <= 100800
– JoSSte
Nov 19 '18 at 9:31
add a comment |
When making a tax calculator, I seem to continue to be getting an error at the "=" in the following line of code:
elif int(vermogen) >= 30001 and <= 100800:
But I can't see a way to fix this. I've tried removing the integers but that didn't help, I've also tried to change my symbols to > and < instead of <= >= but that also didn't help. I think I made an obvious mistake but I don't seem to find it. When removing the "=" behind the "<" The syntax error moves from the "=" to the "<". I hope to hear from you soon. Here is the code I've been using/ It's in dutch, but that shouldn't affect anything.
vermogen = input('Hoeveelheid vermogen: ')
N_schijf1 = 30000
N_schijf2 = 70800
N_schijf3 = 877200
P_schijf2 = 424.8
P_schijf3 = 11403.6
if int(vermogen) <= 30000:
print("Je betaalt 0 euro aan vermogensbelasting")
elif int(vermogen) >= 30001 and <= 100800:
vermogen_betalen = int(vermogen) - N_schijf1
betalen_vermogen = vermogen_betalen * 0.006
print("Je betaalt",betalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 100801 and <= 978000:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2
betalen_vermogen = vermogen_betalen * 0.013
tebetalen_vermogen = P_schijf2 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 978001:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2 - P_schijf3
betalen_vermogen = vermogen_betalen * 0.0161
tebetalen_vermogen = P_schijf2 + P_schijf3 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
print("Test")
python if-statement syntax-error
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
When making a tax calculator, I seem to continue to be getting an error at the "=" in the following line of code:
elif int(vermogen) >= 30001 and <= 100800:
But I can't see a way to fix this. I've tried removing the integers but that didn't help, I've also tried to change my symbols to > and < instead of <= >= but that also didn't help. I think I made an obvious mistake but I don't seem to find it. When removing the "=" behind the "<" The syntax error moves from the "=" to the "<". I hope to hear from you soon. Here is the code I've been using/ It's in dutch, but that shouldn't affect anything.
vermogen = input('Hoeveelheid vermogen: ')
N_schijf1 = 30000
N_schijf2 = 70800
N_schijf3 = 877200
P_schijf2 = 424.8
P_schijf3 = 11403.6
if int(vermogen) <= 30000:
print("Je betaalt 0 euro aan vermogensbelasting")
elif int(vermogen) >= 30001 and <= 100800:
vermogen_betalen = int(vermogen) - N_schijf1
betalen_vermogen = vermogen_betalen * 0.006
print("Je betaalt",betalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 100801 and <= 978000:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2
betalen_vermogen = vermogen_betalen * 0.013
tebetalen_vermogen = P_schijf2 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
elif int(vermogen) >= 978001:
vermogen_betalen = int(vermogen) - N_schijf1 - P_schijf2 - P_schijf3
betalen_vermogen = vermogen_betalen * 0.0161
tebetalen_vermogen = P_schijf2 + P_schijf3 + betalen_vermogen
print("Je betaalt",tebetalen_vermogen,"euro aan vermogensbelasting")
print("Test")
python if-statement syntax-error
python if-statement syntax-error
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
asked Nov 19 '18 at 9:29
Martijn MenssenMartijn Menssen
51
51
4
andis used to join complete conditions. Operands don't carry across theand. You can use30001 <= int(vermogen) <= 100800
– khelwood
Nov 19 '18 at 9:30
1
elif int(vermogen) >= 30001 and <= 100800should beelif int(vermogen) >= 30001 and int(vermogen) <= 100800
– JoSSte
Nov 19 '18 at 9:31
add a comment |
4
andis used to join complete conditions. Operands don't carry across theand. You can use30001 <= int(vermogen) <= 100800
– khelwood
Nov 19 '18 at 9:30
1
elif int(vermogen) >= 30001 and <= 100800should beelif int(vermogen) >= 30001 and int(vermogen) <= 100800
– JoSSte
Nov 19 '18 at 9:31
4
4
and is used to join complete conditions. Operands don't carry across the and. You can use 30001 <= int(vermogen) <= 100800– khelwood
Nov 19 '18 at 9:30
and is used to join complete conditions. Operands don't carry across the and. You can use 30001 <= int(vermogen) <= 100800– khelwood
Nov 19 '18 at 9:30
1
1
elif int(vermogen) >= 30001 and <= 100800 should be elif int(vermogen) >= 30001 and int(vermogen) <= 100800– JoSSte
Nov 19 '18 at 9:31
elif int(vermogen) >= 30001 and <= 100800 should be elif int(vermogen) >= 30001 and int(vermogen) <= 100800– JoSSte
Nov 19 '18 at 9:31
add a comment |
2 Answers
2
active
oldest
votes
You must have a complete condition on each side of the and. Operands don't carry across the and into the next condition.
You could write:
int(vermogen) >= 30001 and int(vermogen) <= 100800
Or just:
30001 <= int(vermogen) <= 100800
since Python supports chaining of comparisons
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
add a comment |
you need to change your if from:
elif int(vermogen) >= 100801 and <= 978000:
elif int(vermogen) >= 30001 and <= 100800:
to
elif int(vermogen) >= 100801 and int(vermogen) <= 978000:
elif int(vermogen) >= 30001 and int(vermogen) <= 100800:
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You must have a complete condition on each side of the and. Operands don't carry across the and into the next condition.
You could write:
int(vermogen) >= 30001 and int(vermogen) <= 100800
Or just:
30001 <= int(vermogen) <= 100800
since Python supports chaining of comparisons
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
add a comment |
You must have a complete condition on each side of the and. Operands don't carry across the and into the next condition.
You could write:
int(vermogen) >= 30001 and int(vermogen) <= 100800
Or just:
30001 <= int(vermogen) <= 100800
since Python supports chaining of comparisons
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
add a comment |
You must have a complete condition on each side of the and. Operands don't carry across the and into the next condition.
You could write:
int(vermogen) >= 30001 and int(vermogen) <= 100800
Or just:
30001 <= int(vermogen) <= 100800
since Python supports chaining of comparisons
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
You must have a complete condition on each side of the and. Operands don't carry across the and into the next condition.
You could write:
int(vermogen) >= 30001 and int(vermogen) <= 100800
Or just:
30001 <= int(vermogen) <= 100800
since Python supports chaining of comparisons
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
answered Nov 19 '18 at 9:33
khelwoodkhelwood
31k74363
31k74363
add a comment |
add a comment |
you need to change your if from:
elif int(vermogen) >= 100801 and <= 978000:
elif int(vermogen) >= 30001 and <= 100800:
to
elif int(vermogen) >= 100801 and int(vermogen) <= 978000:
elif int(vermogen) >= 30001 and int(vermogen) <= 100800:
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
add a comment |
you need to change your if from:
elif int(vermogen) >= 100801 and <= 978000:
elif int(vermogen) >= 30001 and <= 100800:
to
elif int(vermogen) >= 100801 and int(vermogen) <= 978000:
elif int(vermogen) >= 30001 and int(vermogen) <= 100800:
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
add a comment |
you need to change your if from:
elif int(vermogen) >= 100801 and <= 978000:
elif int(vermogen) >= 30001 and <= 100800:
to
elif int(vermogen) >= 100801 and int(vermogen) <= 978000:
elif int(vermogen) >= 30001 and int(vermogen) <= 100800:
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
you need to change your if from:
elif int(vermogen) >= 100801 and <= 978000:
elif int(vermogen) >= 30001 and <= 100800:
to
elif int(vermogen) >= 100801 and int(vermogen) <= 978000:
elif int(vermogen) >= 30001 and int(vermogen) <= 100800:
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
answered Nov 19 '18 at 9:32
ddor254ddor254
848519
848519
add a comment |
add a comment |
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4
andis used to join complete conditions. Operands don't carry across theand. You can use30001 <= int(vermogen) <= 100800– khelwood
Nov 19 '18 at 9:30
1
elif int(vermogen) >= 30001 and <= 100800should beelif int(vermogen) >= 30001 and int(vermogen) <= 100800– JoSSte
Nov 19 '18 at 9:31