How to make Joi regex() validation fail if the string contains “ ” (whitespace)?
I have the a vehicle registration number being validated by Joi in Node.js and need it to reject any string that contains whitespace (space, tab, etc.)
I tried the following schema, but Joi does let it go through:
const schema = {
regNo: Joi.string()
.regex(/^.*S*.*$/)
.required()
.trim()
}
So, if I submit "JOI 777" the string is considered valid.
What am I doing wrong?
Thanks in advance,
javascript node.js joi
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
add a comment |
I have the a vehicle registration number being validated by Joi in Node.js and need it to reject any string that contains whitespace (space, tab, etc.)
I tried the following schema, but Joi does let it go through:
const schema = {
regNo: Joi.string()
.regex(/^.*S*.*$/)
.required()
.trim()
}
So, if I submit "JOI 777" the string is considered valid.
What am I doing wrong?
Thanks in advance,
javascript node.js joi
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace/^S+$/, IOW: if a whitepace appears it should fail.
– Keith
Nov 20 '18 at 12:03
add a comment |
I have the a vehicle registration number being validated by Joi in Node.js and need it to reject any string that contains whitespace (space, tab, etc.)
I tried the following schema, but Joi does let it go through:
const schema = {
regNo: Joi.string()
.regex(/^.*S*.*$/)
.required()
.trim()
}
So, if I submit "JOI 777" the string is considered valid.
What am I doing wrong?
Thanks in advance,
javascript node.js joi
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
I have the a vehicle registration number being validated by Joi in Node.js and need it to reject any string that contains whitespace (space, tab, etc.)
I tried the following schema, but Joi does let it go through:
const schema = {
regNo: Joi.string()
.regex(/^.*S*.*$/)
.required()
.trim()
}
So, if I submit "JOI 777" the string is considered valid.
What am I doing wrong?
Thanks in advance,
javascript node.js joi
javascript node.js joi
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
asked Nov 20 '18 at 11:47
Nikolay ChekanNikolay Chekan
31
31
Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace/^S+$/, IOW: if a whitepace appears it should fail.
– Keith
Nov 20 '18 at 12:03
add a comment |
Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace/^S+$/, IOW: if a whitepace appears it should fail.
– Keith
Nov 20 '18 at 12:03
Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace
/^S+$/ , IOW: if a whitepace appears it should fail.– Keith
Nov 20 '18 at 12:03
Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace
/^S+$/ , IOW: if a whitepace appears it should fail.– Keith
Nov 20 '18 at 12:03
add a comment |
2 Answers
2
active
oldest
votes
This part of your regex -> /^.* is saying match anything, so the rest of your regEx is pretty much short circuited.
So your RegEx is a bit simpler, /^S+$/
This is then saying, from the start to the end, everything has to be a None whitespace.. Also seen as this checks everything for whitespace, you could also take out your .trim()..
eg.
const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
add a comment |
for skipping whitespace from string just use:
"hello world".replace(/s/g, "");
if you have more than One space use this :
"this string has more than one space".replace(/ /g, '');
for more detail see this link below:
Remove whitespaces inside a string in javascript
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.
– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
This part of your regex -> /^.* is saying match anything, so the rest of your regEx is pretty much short circuited.
So your RegEx is a bit simpler, /^S+$/
This is then saying, from the start to the end, everything has to be a None whitespace.. Also seen as this checks everything for whitespace, you could also take out your .trim()..
eg.
const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
add a comment |
This part of your regex -> /^.* is saying match anything, so the rest of your regEx is pretty much short circuited.
So your RegEx is a bit simpler, /^S+$/
This is then saying, from the start to the end, everything has to be a None whitespace.. Also seen as this checks everything for whitespace, you could also take out your .trim()..
eg.
const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
add a comment |
This part of your regex -> /^.* is saying match anything, so the rest of your regEx is pretty much short circuited.
So your RegEx is a bit simpler, /^S+$/
This is then saying, from the start to the end, everything has to be a None whitespace.. Also seen as this checks everything for whitespace, you could also take out your .trim()..
eg.
const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
This part of your regex -> /^.* is saying match anything, so the rest of your regEx is pretty much short circuited.
So your RegEx is a bit simpler, /^S+$/
This is then saying, from the start to the end, everything has to be a None whitespace.. Also seen as this checks everything for whitespace, you could also take out your .trim()..
eg.
const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});const tests = [
"JOI 777", //space in the middle
"JOI777", //looks good to me
" JOI777", //space at start
"JOI777 ", //space at end
"JOtI77", //tab
"ABC123", //another one that seems ok.
"XYZn111" //newline
];
tests.forEach(t => {
console.log(`${!!t.match(/^S+$/)} "${t}"`);
});answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
answered Nov 20 '18 at 12:13
KeithKeith
8,8301820
8,8301820
add a comment |
add a comment |
for skipping whitespace from string just use:
"hello world".replace(/s/g, "");
if you have more than One space use this :
"this string has more than one space".replace(/ /g, '');
for more detail see this link below:
Remove whitespaces inside a string in javascript
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.
– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
add a comment |
for skipping whitespace from string just use:
"hello world".replace(/s/g, "");
if you have more than One space use this :
"this string has more than one space".replace(/ /g, '');
for more detail see this link below:
Remove whitespaces inside a string in javascript
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.
– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
add a comment |
for skipping whitespace from string just use:
"hello world".replace(/s/g, "");
if you have more than One space use this :
"this string has more than one space".replace(/ /g, '');
for more detail see this link below:
Remove whitespaces inside a string in javascript
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
for skipping whitespace from string just use:
"hello world".replace(/s/g, "");
if you have more than One space use this :
"this string has more than one space".replace(/ /g, '');
for more detail see this link below:
Remove whitespaces inside a string in javascript
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
answered Nov 20 '18 at 12:11
babak abadkheirbabak abadkheir
479311
479311
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.
– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
add a comment |
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.
– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
1
1
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.– Keith
Nov 20 '18 at 12:21
if you have more than One space use this, your first one will remove multiple spaces too,.. Your second one will ONLY remove spaces, not tabs / newline etc.– Keith
Nov 20 '18 at 12:21
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
tnx for the tips I realized now
– babak abadkheir
Nov 20 '18 at 12:25
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
This doesnt really answer the person's question. They are looking to have joi reject a value not modify incomming values.
– unflores
Nov 20 '18 at 13:30
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
Hi all, thanks for the answers. Yes, the answer provided by Keith worked as needed within Joi. Much appreciate everyone's attention!
– Nikolay Chekan
Nov 21 '18 at 9:27
add a comment |
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Your first part of you regex is going to match anything,. I think what you want is a lot simpler, match any none-whitespace
/^S+$/, IOW: if a whitepace appears it should fail.– Keith
Nov 20 '18 at 12:03