How to initialize a class and pass an object to the constructor in Android?
0
I have the following class:
public class MovieViewModel extends ViewModel {
private String query;
public MovieViewModel() {
MyFactory factory = new MyFactory(); //Pass the query in the constructor
//other stuff
}
}
And in my MainActivity, I'm creating an object of this class like this:
MovieViewModel model = ViewModelProviders.of(this).get(MovieViewModel.class);
How can I create an object of MovieViewModel class and in the same time I initialize the query String so it can be passed to the MyFactory constructor?
java
android asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
add a comment |
0
I have the following class:
public class MovieViewModel extends ViewModel {
private String query;
public MovieViewModel() {
MyFactory factory = new MyFactory(); //Pass the query in the constructor
//other stuff
}
}
And in my MainActivity, I'm creating an object of this class like this:
MovieViewModel model = ViewModelProviders.of(this).get(MovieViewModel.class);
How can I create an object of MovieViewModel class and in the same time I initialize the query String so it can be passed to the MyFactory constructor?
java
android asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
add a comment |
0
0
0
I have the following class:
public class MovieViewModel extends ViewModel {
private String query;
public MovieViewModel() {
MyFactory factory = new MyFactory(); //Pass the query in the constructor
//other stuff
}
}
And in my MainActivity, I'm creating an object of this class like this:
MovieViewModel model = ViewModelProviders.of(this).get(MovieViewModel.class);
How can I create an object of MovieViewModel class and in the same time I initialize the query String so it can be passed to the MyFactory constructor?
java
android asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
I have the following class:
public class MovieViewModel extends ViewModel {
private String query;
public MovieViewModel() {
MyFactory factory = new MyFactory(); //Pass the query in the constructor
//other stuff
}
}
And in my MainActivity, I'm creating an object of this class like this:
MovieViewModel model = ViewModelProviders.of(this).get(MovieViewModel.class);
How can I create an object of MovieViewModel class and in the same time I initialize the query String so it can be passed to the MyFactory constructor?
java
android java
android asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
asked Nov 20 '18 at 11:45
Johans BormmanJohans Bormman
629
629
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
You can create custom Factory.
public class MovieViewModelFactory implements ViewModelProvider.Factory {
private Application mApplication;
private String mParam;
public MovieViewModelFactory(Application application, String param) {
mApplication = application;
mParam = param;
}
@Override
public <T extends ViewModel> T create(Class<T> modelClass) {
return (T) new MovieViewModel(mApplication, mParam);
}
}
Now you can use like this
MovieViewModel movieViewModel = ViewModelProviders.of(this, new MovieViewModelFactory(this.getApplication(), "param")).get(MovieViewModel.class);
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
So you basically say that, in this case there is no need to extendMovieViewModelFactory extend ViewModel?
– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong typeMovieViewModelFactoryinstead ofMovieViewModel?
– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel>is Java Generics which allows only Models extending ViewModel as return type. You will needMovieViewModelextendViewModel.
– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String)andUnchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?
– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor insideMovieViewModelaccepting Application and String.
– Khemraj
Nov 20 '18 at 12:10
|
show 4 more comments
0
You have to provide a factory class :
public class MovieViewModel extends ViewModel {
private String query;
MovieViewModel(String objectToBePassed) {
//other stuff
}
static class MovieViewModelFactory extends ViewModelProvider.NewInstanceFactory {
private String mObject;
public MovieViewModelFactory(String objectToBePassed) {
mObject = objectToePassed;
}
@NonNull
@Override
public <T extends ViewModel> T create(@NonNull Class<T> modelClass) {
return (T) new MovieViewModel(mObject);
}
}
}
and usage
ViewModelProviders.of(context,
new MovieViewModel.MovieViewModelFactory(object))
.get(MovieViewModel.class);
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can create custom Factory.
public class MovieViewModelFactory implements ViewModelProvider.Factory {
private Application mApplication;
private String mParam;
public MovieViewModelFactory(Application application, String param) {
mApplication = application;
mParam = param;
}
@Override
public <T extends ViewModel> T create(Class<T> modelClass) {
return (T) new MovieViewModel(mApplication, mParam);
}
}
Now you can use like this
MovieViewModel movieViewModel = ViewModelProviders.of(this, new MovieViewModelFactory(this.getApplication(), "param")).get(MovieViewModel.class);
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
So you basically say that, in this case there is no need to extendMovieViewModelFactory extend ViewModel?
– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong typeMovieViewModelFactoryinstead ofMovieViewModel?
– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel>is Java Generics which allows only Models extending ViewModel as return type. You will needMovieViewModelextendViewModel.
– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String)andUnchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?
– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor insideMovieViewModelaccepting Application and String.
– Khemraj
Nov 20 '18 at 12:10
|
show 4 more comments
1
You can create custom Factory.
public class MovieViewModelFactory implements ViewModelProvider.Factory {
private Application mApplication;
private String mParam;
public MovieViewModelFactory(Application application, String param) {
mApplication = application;
mParam = param;
}
@Override
public <T extends ViewModel> T create(Class<T> modelClass) {
return (T) new MovieViewModel(mApplication, mParam);
}
}
Now you can use like this
MovieViewModel movieViewModel = ViewModelProviders.of(this, new MovieViewModelFactory(this.getApplication(), "param")).get(MovieViewModel.class);
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
So you basically say that, in this case there is no need to extendMovieViewModelFactory extend ViewModel?
– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong typeMovieViewModelFactoryinstead ofMovieViewModel?
– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel>is Java Generics which allows only Models extending ViewModel as return type. You will needMovieViewModelextendViewModel.
– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String)andUnchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?
– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor insideMovieViewModelaccepting Application and String.
– Khemraj
Nov 20 '18 at 12:10
|
show 4 more comments
1
1
1
You can create custom Factory.
public class MovieViewModelFactory implements ViewModelProvider.Factory {
private Application mApplication;
private String mParam;
public MovieViewModelFactory(Application application, String param) {
mApplication = application;
mParam = param;
}
@Override
public <T extends ViewModel> T create(Class<T> modelClass) {
return (T) new MovieViewModel(mApplication, mParam);
}
}
Now you can use like this
MovieViewModel movieViewModel = ViewModelProviders.of(this, new MovieViewModelFactory(this.getApplication(), "param")).get(MovieViewModel.class);
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
You can create custom Factory.
public class MovieViewModelFactory implements ViewModelProvider.Factory {
private Application mApplication;
private String mParam;
public MovieViewModelFactory(Application application, String param) {
mApplication = application;
mParam = param;
}
@Override
public <T extends ViewModel> T create(Class<T> modelClass) {
return (T) new MovieViewModel(mApplication, mParam);
}
}
Now you can use like this
MovieViewModel movieViewModel = ViewModelProviders.of(this, new MovieViewModelFactory(this.getApplication(), "param")).get(MovieViewModel.class);
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
answered Nov 20 '18 at 11:51
KhemrajKhemraj
14.5k44683
14.5k44683
So you basically say that, in this case there is no need to extendMovieViewModelFactory extend ViewModel?
– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong typeMovieViewModelFactoryinstead ofMovieViewModel?
– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel>is Java Generics which allows only Models extending ViewModel as return type. You will needMovieViewModelextendViewModel.
– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String)andUnchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?
– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor insideMovieViewModelaccepting Application and String.
– Khemraj
Nov 20 '18 at 12:10
|
show 4 more comments
So you basically say that, in this case there is no need to extendMovieViewModelFactory extend ViewModel?
– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong typeMovieViewModelFactoryinstead ofMovieViewModel?
– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel>is Java Generics which allows only Models extending ViewModel as return type. You will needMovieViewModelextendViewModel.
– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String)andUnchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?
– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor insideMovieViewModelaccepting Application and String.
– Khemraj
Nov 20 '18 at 12:10
So you basically say that, in this case there is no need to extend
MovieViewModelFactory extend ViewModel?– Johans Bormman
Nov 20 '18 at 12:00
So you basically say that, in this case there is no need to extend
MovieViewModelFactory extend ViewModel?– Johans Bormman
Nov 20 '18 at 12:00
Did you wrong type
MovieViewModelFactory instead of MovieViewModel?– Khemraj
Nov 20 '18 at 12:01
Did you wrong type
MovieViewModelFactory instead of MovieViewModel?– Khemraj
Nov 20 '18 at 12:01
<T extends ViewModel> is Java Generics which allows only Models extending ViewModel as return type. You will need MovieViewModel extend ViewModel.– Khemraj
Nov 20 '18 at 12:07
<T extends ViewModel> is Java Generics which allows only Models extending ViewModel as return type. You will need MovieViewModel extend ViewModel.– Khemraj
Nov 20 '18 at 12:07
My bad. I've created this new class but I have two errors:
MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String) and Unchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?– Johans Bormman
Nov 20 '18 at 12:08
My bad. I've created this new class but I have two errors:
MovieViewModel( ) in MovieViewModel cannot be applied to (android.app.Application, java.lang.String) and Unchecked cast: '***.******.myapp.MovieViewModel' to 'T'. How can change this?– Johans Bormman
Nov 20 '18 at 12:08
You need to make additional constructor inside
MovieViewModel accepting Application and String.– Khemraj
Nov 20 '18 at 12:10
You need to make additional constructor inside
MovieViewModel accepting Application and String.– Khemraj
Nov 20 '18 at 12:10
|
show 4 more comments
0
You have to provide a factory class :
public class MovieViewModel extends ViewModel {
private String query;
MovieViewModel(String objectToBePassed) {
//other stuff
}
static class MovieViewModelFactory extends ViewModelProvider.NewInstanceFactory {
private String mObject;
public MovieViewModelFactory(String objectToBePassed) {
mObject = objectToePassed;
}
@NonNull
@Override
public <T extends ViewModel> T create(@NonNull Class<T> modelClass) {
return (T) new MovieViewModel(mObject);
}
}
}
and usage
ViewModelProviders.of(context,
new MovieViewModel.MovieViewModelFactory(object))
.get(MovieViewModel.class);
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
add a comment |
0
You have to provide a factory class :
public class MovieViewModel extends ViewModel {
private String query;
MovieViewModel(String objectToBePassed) {
//other stuff
}
static class MovieViewModelFactory extends ViewModelProvider.NewInstanceFactory {
private String mObject;
public MovieViewModelFactory(String objectToBePassed) {
mObject = objectToePassed;
}
@NonNull
@Override
public <T extends ViewModel> T create(@NonNull Class<T> modelClass) {
return (T) new MovieViewModel(mObject);
}
}
}
and usage
ViewModelProviders.of(context,
new MovieViewModel.MovieViewModelFactory(object))
.get(MovieViewModel.class);
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
add a comment |
0
0
0
You have to provide a factory class :
public class MovieViewModel extends ViewModel {
private String query;
MovieViewModel(String objectToBePassed) {
//other stuff
}
static class MovieViewModelFactory extends ViewModelProvider.NewInstanceFactory {
private String mObject;
public MovieViewModelFactory(String objectToBePassed) {
mObject = objectToePassed;
}
@NonNull
@Override
public <T extends ViewModel> T create(@NonNull Class<T> modelClass) {
return (T) new MovieViewModel(mObject);
}
}
}
and usage
ViewModelProviders.of(context,
new MovieViewModel.MovieViewModelFactory(object))
.get(MovieViewModel.class);
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
You have to provide a factory class :
public class MovieViewModel extends ViewModel {
private String query;
MovieViewModel(String objectToBePassed) {
//other stuff
}
static class MovieViewModelFactory extends ViewModelProvider.NewInstanceFactory {
private String mObject;
public MovieViewModelFactory(String objectToBePassed) {
mObject = objectToePassed;
}
@NonNull
@Override
public <T extends ViewModel> T create(@NonNull Class<T> modelClass) {
return (T) new MovieViewModel(mObject);
}
}
}
and usage
ViewModelProviders.of(context,
new MovieViewModel.MovieViewModelFactory(object))
.get(MovieViewModel.class);
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
edited Nov 20 '18 at 11:56
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
answered Nov 20 '18 at 11:47
koleanukoleanu
342318
342318
add a comment |
add a comment |
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