jasper server problem to pass request parameter
I have a problem with jasper server/ jasper report 6.6.0
I'll explain to you briefly:
I have configured a user on jasper report. For example XXXXXXX.
This user can access the reports through two links.
The difference between these two links is a parameter in request (code)
For example:
1st link https://<host>:<port>/<context path>?cf=XXXXXXX&code=A
2nd link https://<host>:<port>/<context path>?cf=XXXXXXX&code=B
This link redirects to
https://<host>:<port>/<context path>/j_spring_security_check?j_username=XXXXXXX&j_password=MYPASS
If login success access to report :
https://<host>:<port>/<context path>/flow.html?_flowId=searchFlow
I would like to be passed on the report the parameter (code) that the user chose (A or B) .
This parameter will be passed into the report query as a where clause.
I tried to set the Attribute for the user (LoggedInUserAttribute_code
) and I set to the report Parameter $P{LoggedInUserAttribute_code}
but this parameter is fixed. I can set A or B and it isn't the user's choice.
Can anyone tell me how to pass the parameter (code) from the request to the report?
Should I pass the parameter to spring when I call j_spring_security_check
and put the parameter in session?
I hope you understand the question.
Thank you so much
spring spring-security jasperserver j-security-check
add a comment |
I have a problem with jasper server/ jasper report 6.6.0
I'll explain to you briefly:
I have configured a user on jasper report. For example XXXXXXX.
This user can access the reports through two links.
The difference between these two links is a parameter in request (code)
For example:
1st link https://<host>:<port>/<context path>?cf=XXXXXXX&code=A
2nd link https://<host>:<port>/<context path>?cf=XXXXXXX&code=B
This link redirects to
https://<host>:<port>/<context path>/j_spring_security_check?j_username=XXXXXXX&j_password=MYPASS
If login success access to report :
https://<host>:<port>/<context path>/flow.html?_flowId=searchFlow
I would like to be passed on the report the parameter (code) that the user chose (A or B) .
This parameter will be passed into the report query as a where clause.
I tried to set the Attribute for the user (LoggedInUserAttribute_code
) and I set to the report Parameter $P{LoggedInUserAttribute_code}
but this parameter is fixed. I can set A or B and it isn't the user's choice.
Can anyone tell me how to pass the parameter (code) from the request to the report?
Should I pass the parameter to spring when I call j_spring_security_check
and put the parameter in session?
I hope you understand the question.
Thank you so much
spring spring-security jasperserver j-security-check
add a comment |
I have a problem with jasper server/ jasper report 6.6.0
I'll explain to you briefly:
I have configured a user on jasper report. For example XXXXXXX.
This user can access the reports through two links.
The difference between these two links is a parameter in request (code)
For example:
1st link https://<host>:<port>/<context path>?cf=XXXXXXX&code=A
2nd link https://<host>:<port>/<context path>?cf=XXXXXXX&code=B
This link redirects to
https://<host>:<port>/<context path>/j_spring_security_check?j_username=XXXXXXX&j_password=MYPASS
If login success access to report :
https://<host>:<port>/<context path>/flow.html?_flowId=searchFlow
I would like to be passed on the report the parameter (code) that the user chose (A or B) .
This parameter will be passed into the report query as a where clause.
I tried to set the Attribute for the user (LoggedInUserAttribute_code
) and I set to the report Parameter $P{LoggedInUserAttribute_code}
but this parameter is fixed. I can set A or B and it isn't the user's choice.
Can anyone tell me how to pass the parameter (code) from the request to the report?
Should I pass the parameter to spring when I call j_spring_security_check
and put the parameter in session?
I hope you understand the question.
Thank you so much
spring spring-security jasperserver j-security-check
I have a problem with jasper server/ jasper report 6.6.0
I'll explain to you briefly:
I have configured a user on jasper report. For example XXXXXXX.
This user can access the reports through two links.
The difference between these two links is a parameter in request (code)
For example:
1st link https://<host>:<port>/<context path>?cf=XXXXXXX&code=A
2nd link https://<host>:<port>/<context path>?cf=XXXXXXX&code=B
This link redirects to
https://<host>:<port>/<context path>/j_spring_security_check?j_username=XXXXXXX&j_password=MYPASS
If login success access to report :
https://<host>:<port>/<context path>/flow.html?_flowId=searchFlow
I would like to be passed on the report the parameter (code) that the user chose (A or B) .
This parameter will be passed into the report query as a where clause.
I tried to set the Attribute for the user (LoggedInUserAttribute_code
) and I set to the report Parameter $P{LoggedInUserAttribute_code}
but this parameter is fixed. I can set A or B and it isn't the user's choice.
Can anyone tell me how to pass the parameter (code) from the request to the report?
Should I pass the parameter to spring when I call j_spring_security_check
and put the parameter in session?
I hope you understand the question.
Thank you so much
spring spring-security jasperserver j-security-check
spring spring-security jasperserver j-security-check
edited Nov 21 '18 at 17:27
Alex K
18.6k1481166
18.6k1481166
asked Nov 21 '18 at 7:44
user10684316user10684316
11
11
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