Powershell invoke-command $input












1















I have a trouble.. Can someone help me?
Here is my Code :



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

$result = Invoke-Command -ComputerName Machine -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result


Question:
Why the $result doesn't show anything about $MyObject?



It only show $MyObjec (not in the invoke-command) and $env:computername (in the invoke-command)



How can I fix it?



P.S this is really what I want to make,
I want to get into multiple machine which in 6 different AD in the same time, but they should use different username,
and I need $A in the remote machine to deal another thing.



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

#Add
$servers@{'Machine1','Machine2','Machine3'}

Foreach ($servers in $servers) {

Star-Job {

$username = $servers+'account'

$password = $password

$credential = ....($username,$password)

$result = Invoke-Command -ComputerName $servers -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result
}


}



I will try -Argument-List and param{}
Beacase I try Start-Job with -Argument-List and $Using, there have an error.
Thank u for your reply!










share|improve this question




















  • 1





    It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

    – LotPings
    Nov 21 '18 at 8:00











  • Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

    – Max BestWell
    Nov 21 '18 at 11:11













  • today I test that, It can work! Thank you!

    – Max BestWell
    Nov 22 '18 at 8:40


















1















I have a trouble.. Can someone help me?
Here is my Code :



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

$result = Invoke-Command -ComputerName Machine -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result


Question:
Why the $result doesn't show anything about $MyObject?



It only show $MyObjec (not in the invoke-command) and $env:computername (in the invoke-command)



How can I fix it?



P.S this is really what I want to make,
I want to get into multiple machine which in 6 different AD in the same time, but they should use different username,
and I need $A in the remote machine to deal another thing.



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

#Add
$servers@{'Machine1','Machine2','Machine3'}

Foreach ($servers in $servers) {

Star-Job {

$username = $servers+'account'

$password = $password

$credential = ....($username,$password)

$result = Invoke-Command -ComputerName $servers -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result
}


}



I will try -Argument-List and param{}
Beacase I try Start-Job with -Argument-List and $Using, there have an error.
Thank u for your reply!










share|improve this question




















  • 1





    It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

    – LotPings
    Nov 21 '18 at 8:00











  • Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

    – Max BestWell
    Nov 21 '18 at 11:11













  • today I test that, It can work! Thank you!

    – Max BestWell
    Nov 22 '18 at 8:40
















1












1








1








I have a trouble.. Can someone help me?
Here is my Code :



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

$result = Invoke-Command -ComputerName Machine -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result


Question:
Why the $result doesn't show anything about $MyObject?



It only show $MyObjec (not in the invoke-command) and $env:computername (in the invoke-command)



How can I fix it?



P.S this is really what I want to make,
I want to get into multiple machine which in 6 different AD in the same time, but they should use different username,
and I need $A in the remote machine to deal another thing.



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

#Add
$servers@{'Machine1','Machine2','Machine3'}

Foreach ($servers in $servers) {

Star-Job {

$username = $servers+'account'

$password = $password

$credential = ....($username,$password)

$result = Invoke-Command -ComputerName $servers -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result
}


}



I will try -Argument-List and param{}
Beacase I try Start-Job with -Argument-List and $Using, there have an error.
Thank u for your reply!










share|improve this question
















I have a trouble.. Can someone help me?
Here is my Code :



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

$result = Invoke-Command -ComputerName Machine -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result


Question:
Why the $result doesn't show anything about $MyObject?



It only show $MyObjec (not in the invoke-command) and $env:computername (in the invoke-command)



How can I fix it?



P.S this is really what I want to make,
I want to get into multiple machine which in 6 different AD in the same time, but they should use different username,
and I need $A in the remote machine to deal another thing.



$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
servers = $servers
}

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

#Add
$servers@{'Machine1','Machine2','Machine3'}

Foreach ($servers in $servers) {

Star-Job {

$username = $servers+'account'

$password = $password

$credential = ....($username,$password)

$result = Invoke-Command -ComputerName $servers -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result
}


}



I will try -Argument-List and param{}
Beacase I try Start-Job with -Argument-List and $Using, there have an error.
Thank u for your reply!







powershell invoke-command






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 11:33







Max BestWell

















asked Nov 21 '18 at 7:49









Max BestWellMax BestWell

133




133








  • 1





    It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

    – LotPings
    Nov 21 '18 at 8:00











  • Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

    – Max BestWell
    Nov 21 '18 at 11:11













  • today I test that, It can work! Thank you!

    – Max BestWell
    Nov 22 '18 at 8:40
















  • 1





    It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

    – LotPings
    Nov 21 '18 at 8:00











  • Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

    – Max BestWell
    Nov 21 '18 at 11:11













  • today I test that, It can work! Thank you!

    – Max BestWell
    Nov 22 '18 at 8:40










1




1





It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

– LotPings
Nov 21 '18 at 8:00





It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end.

– LotPings
Nov 21 '18 at 8:00













Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

– Max BestWell
Nov 21 '18 at 11:11







Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean!

– Max BestWell
Nov 21 '18 at 11:11















today I test that, It can work! Thank you!

– Max BestWell
Nov 22 '18 at 8:40







today I test that, It can work! Thank you!

– Max BestWell
Nov 22 '18 at 8:40














1 Answer
1






active

oldest

votes


















2














Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).



You can change that by passing the variables to the remote system using the -Argument-List parameter like this:



Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
param($MyObject)

$MyObject.A
}


Or use $using: to get access to the locally defined variables like that:



Invoke-Command -ComputerName Machine -ScriptBlock { 

$using:MyObject.A
}





share|improve this answer























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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).



    You can change that by passing the variables to the remote system using the -Argument-List parameter like this:



    Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
    param($MyObject)

    $MyObject.A
    }


    Or use $using: to get access to the locally defined variables like that:



    Invoke-Command -ComputerName Machine -ScriptBlock { 

    $using:MyObject.A
    }





    share|improve this answer




























      2














      Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).



      You can change that by passing the variables to the remote system using the -Argument-List parameter like this:



      Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
      param($MyObject)

      $MyObject.A
      }


      Or use $using: to get access to the locally defined variables like that:



      Invoke-Command -ComputerName Machine -ScriptBlock { 

      $using:MyObject.A
      }





      share|improve this answer


























        2












        2








        2







        Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).



        You can change that by passing the variables to the remote system using the -Argument-List parameter like this:



        Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
        param($MyObject)

        $MyObject.A
        }


        Or use $using: to get access to the locally defined variables like that:



        Invoke-Command -ComputerName Machine -ScriptBlock { 

        $using:MyObject.A
        }





        share|improve this answer













        Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).



        You can change that by passing the variables to the remote system using the -Argument-List parameter like this:



        Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
        param($MyObject)

        $MyObject.A
        }


        Or use $using: to get access to the locally defined variables like that:



        Invoke-Command -ComputerName Machine -ScriptBlock { 

        $using:MyObject.A
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 8:04









        TobyUTobyU

        2,50421122




        2,50421122
































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