How to convert -1x10^200 to IEEE 754 double precision











up vote
-1
down vote

favorite












So like above, I want to find the IEEE 754 representation of -1x10^200.



I know we can get the sign be to be 1, as we have a negative number. However I am unsure of how to find the mantissa/exponent. My initial idea was to convert 10^200 to 2^x. However x is not a whole number. So I figure we need to get a fraction somehow by separating the 10^200 somehow. Theoretically one could use very long devision, but I am looking for a more elegant answer that can be done without a high precision calculator.










share|improve this question


























    up vote
    -1
    down vote

    favorite












    So like above, I want to find the IEEE 754 representation of -1x10^200.



    I know we can get the sign be to be 1, as we have a negative number. However I am unsure of how to find the mantissa/exponent. My initial idea was to convert 10^200 to 2^x. However x is not a whole number. So I figure we need to get a fraction somehow by separating the 10^200 somehow. Theoretically one could use very long devision, but I am looking for a more elegant answer that can be done without a high precision calculator.










    share|improve this question
























      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      So like above, I want to find the IEEE 754 representation of -1x10^200.



      I know we can get the sign be to be 1, as we have a negative number. However I am unsure of how to find the mantissa/exponent. My initial idea was to convert 10^200 to 2^x. However x is not a whole number. So I figure we need to get a fraction somehow by separating the 10^200 somehow. Theoretically one could use very long devision, but I am looking for a more elegant answer that can be done without a high precision calculator.










      share|improve this question













      So like above, I want to find the IEEE 754 representation of -1x10^200.



      I know we can get the sign be to be 1, as we have a negative number. However I am unsure of how to find the mantissa/exponent. My initial idea was to convert 10^200 to 2^x. However x is not a whole number. So I figure we need to get a fraction somehow by separating the 10^200 somehow. Theoretically one could use very long devision, but I am looking for a more elegant answer that can be done without a high precision calculator.







      c++ floating-point binary double ieee-754






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 11 at 1:12









      Philip Bal

      137




      137
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          5
          down vote



          accepted










          −10200 cannot be represented in IEEE-754 basic 64-bit binary format. The closest number that can be represented is -99999999999999996973312221251036165947450327545502362648241750950346848435554075534196338404706251868027512415973882408182135734368278484639385041047239877871023591066789981811181813306167128854888448.



          The encoding of this in the 64-bit format is 0xe974e718d7d7625a. It has a sign of − (encoded as 1 in bit 63), an exponent of 664 (encoded as 1687 or 0x697 in bits 62 to 52), and a significand of 0x1.4e718d7d7625a (encoded as 0x4e718d7d7625a in bits 51 to 0).



          Given that the exponent is 664, you can find the significand by dividing 10200 by 2664, writing the result in binary, and rounding after 52 bits after the radix point. Alternately, after dividing by 2664, multiply by 252 and round to an integer.






          share|improve this answer





















            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244980%2fhow-to-convert-1x10200-to-ieee-754-double-precision%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            5
            down vote



            accepted










            −10200 cannot be represented in IEEE-754 basic 64-bit binary format. The closest number that can be represented is -99999999999999996973312221251036165947450327545502362648241750950346848435554075534196338404706251868027512415973882408182135734368278484639385041047239877871023591066789981811181813306167128854888448.



            The encoding of this in the 64-bit format is 0xe974e718d7d7625a. It has a sign of − (encoded as 1 in bit 63), an exponent of 664 (encoded as 1687 or 0x697 in bits 62 to 52), and a significand of 0x1.4e718d7d7625a (encoded as 0x4e718d7d7625a in bits 51 to 0).



            Given that the exponent is 664, you can find the significand by dividing 10200 by 2664, writing the result in binary, and rounding after 52 bits after the radix point. Alternately, after dividing by 2664, multiply by 252 and round to an integer.






            share|improve this answer

























              up vote
              5
              down vote



              accepted










              −10200 cannot be represented in IEEE-754 basic 64-bit binary format. The closest number that can be represented is -99999999999999996973312221251036165947450327545502362648241750950346848435554075534196338404706251868027512415973882408182135734368278484639385041047239877871023591066789981811181813306167128854888448.



              The encoding of this in the 64-bit format is 0xe974e718d7d7625a. It has a sign of − (encoded as 1 in bit 63), an exponent of 664 (encoded as 1687 or 0x697 in bits 62 to 52), and a significand of 0x1.4e718d7d7625a (encoded as 0x4e718d7d7625a in bits 51 to 0).



              Given that the exponent is 664, you can find the significand by dividing 10200 by 2664, writing the result in binary, and rounding after 52 bits after the radix point. Alternately, after dividing by 2664, multiply by 252 and round to an integer.






              share|improve this answer























                up vote
                5
                down vote



                accepted







                up vote
                5
                down vote



                accepted






                −10200 cannot be represented in IEEE-754 basic 64-bit binary format. The closest number that can be represented is -99999999999999996973312221251036165947450327545502362648241750950346848435554075534196338404706251868027512415973882408182135734368278484639385041047239877871023591066789981811181813306167128854888448.



                The encoding of this in the 64-bit format is 0xe974e718d7d7625a. It has a sign of − (encoded as 1 in bit 63), an exponent of 664 (encoded as 1687 or 0x697 in bits 62 to 52), and a significand of 0x1.4e718d7d7625a (encoded as 0x4e718d7d7625a in bits 51 to 0).



                Given that the exponent is 664, you can find the significand by dividing 10200 by 2664, writing the result in binary, and rounding after 52 bits after the radix point. Alternately, after dividing by 2664, multiply by 252 and round to an integer.






                share|improve this answer












                −10200 cannot be represented in IEEE-754 basic 64-bit binary format. The closest number that can be represented is -99999999999999996973312221251036165947450327545502362648241750950346848435554075534196338404706251868027512415973882408182135734368278484639385041047239877871023591066789981811181813306167128854888448.



                The encoding of this in the 64-bit format is 0xe974e718d7d7625a. It has a sign of − (encoded as 1 in bit 63), an exponent of 664 (encoded as 1687 or 0x697 in bits 62 to 52), and a significand of 0x1.4e718d7d7625a (encoded as 0x4e718d7d7625a in bits 51 to 0).



                Given that the exponent is 664, you can find the significand by dividing 10200 by 2664, writing the result in binary, and rounding after 52 bits after the radix point. Alternately, after dividing by 2664, multiply by 252 and round to an integer.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 at 2:27









                Eric Postpischil

                69.7k874150




                69.7k874150






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.





                    Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                    Please pay close attention to the following guidance:


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53244980%2fhow-to-convert-1x10200-to-ieee-754-double-precision%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    鏡平學校

                    ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

                    Why https connections are so slow when debugging (stepping over) in Java?