Regular expression for length limit 10 digit before decimal till 2 decimal place with Number only?
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(.[0-9]{0,2})?$
javascript regex
|
show 2 more comments
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(.[0-9]{0,2})?$
javascript regex
How did you devise this regex? Your regex doesn't match the-character for sign.
– Dai
Nov 13 at 5:34
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
Do you want to match1.2? or1.22
– vks
Nov 13 at 7:05
@vks both needed
– Deepak Jain
Nov 14 at 6:16
1
@DeepakJain the answer u accepted accepts.as well.1.as well
– vks
Nov 14 at 6:25
|
show 2 more comments
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(.[0-9]{0,2})?$
javascript regex
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(.[0-9]{0,2})?$
javascript regex
javascript regex
edited Nov 14 at 7:11
asked Nov 13 at 5:33
Deepak Jain
2809
2809
How did you devise this regex? Your regex doesn't match the-character for sign.
– Dai
Nov 13 at 5:34
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
Do you want to match1.2? or1.22
– vks
Nov 13 at 7:05
@vks both needed
– Deepak Jain
Nov 14 at 6:16
1
@DeepakJain the answer u accepted accepts.as well.1.as well
– vks
Nov 14 at 6:25
|
show 2 more comments
How did you devise this regex? Your regex doesn't match the-character for sign.
– Dai
Nov 13 at 5:34
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
Do you want to match1.2? or1.22
– vks
Nov 13 at 7:05
@vks both needed
– Deepak Jain
Nov 14 at 6:16
1
@DeepakJain the answer u accepted accepts.as well.1.as well
– vks
Nov 14 at 6:25
How did you devise this regex? Your regex doesn't match the
- character for sign.– Dai
Nov 13 at 5:34
How did you devise this regex? Your regex doesn't match the
- character for sign.– Dai
Nov 13 at 5:34
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
Do you want to match
1.2? or 1.22– vks
Nov 13 at 7:05
Do you want to match
1.2? or 1.22– vks
Nov 13 at 7:05
@vks both needed
– Deepak Jain
Nov 14 at 6:16
@vks both needed
– Deepak Jain
Nov 14 at 6:16
1
1
@DeepakJain the answer u accepted accepts
. as well.1. as well– vks
Nov 14 at 6:25
@DeepakJain the answer u accepted accepts
. as well.1. as well– vks
Nov 14 at 6:25
|
show 2 more comments
2 Answers
2
active
oldest
votes
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)d{0,10}(?:.d{1,2})?$
https://regex101.com/r/Ah8dNu/5
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches.which should not be valid value.regex101.com/r/Ah8dNu/3
– vks
Nov 13 at 7:50
@vks I did notice that, OP had{0,2}in his original code rather than{1, 2}, seemed strange but I thought it was intentional
– CertainPerformance
Nov 13 at 8:20
1
@DeepakJain use^(?!$)d{0,10}(?:.d{1,2})?$. See demo. regex101.com/r/Ah8dNu/4
– vks
Nov 14 at 6:28
|
show 3 more comments
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((.)[0-9]{0,2}){0,1}$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)d{0,10}(?:.d{1,2})?$
https://regex101.com/r/Ah8dNu/5
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches.which should not be valid value.regex101.com/r/Ah8dNu/3
– vks
Nov 13 at 7:50
@vks I did notice that, OP had{0,2}in his original code rather than{1, 2}, seemed strange but I thought it was intentional
– CertainPerformance
Nov 13 at 8:20
1
@DeepakJain use^(?!$)d{0,10}(?:.d{1,2})?$. See demo. regex101.com/r/Ah8dNu/4
– vks
Nov 14 at 6:28
|
show 3 more comments
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)d{0,10}(?:.d{1,2})?$
https://regex101.com/r/Ah8dNu/5
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches.which should not be valid value.regex101.com/r/Ah8dNu/3
– vks
Nov 13 at 7:50
@vks I did notice that, OP had{0,2}in his original code rather than{1, 2}, seemed strange but I thought it was intentional
– CertainPerformance
Nov 13 at 8:20
1
@DeepakJain use^(?!$)d{0,10}(?:.d{1,2})?$. See demo. regex101.com/r/Ah8dNu/4
– vks
Nov 14 at 6:28
|
show 3 more comments
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)d{0,10}(?:.d{1,2})?$
https://regex101.com/r/Ah8dNu/5
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)d{0,10}(?:.d{1,2})?$
https://regex101.com/r/Ah8dNu/5
edited Nov 14 at 7:07
answered Nov 13 at 5:40
CertainPerformance
74.1k143558
74.1k143558
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches.which should not be valid value.regex101.com/r/Ah8dNu/3
– vks
Nov 13 at 7:50
@vks I did notice that, OP had{0,2}in his original code rather than{1, 2}, seemed strange but I thought it was intentional
– CertainPerformance
Nov 13 at 8:20
1
@DeepakJain use^(?!$)d{0,10}(?:.d{1,2})?$. See demo. regex101.com/r/Ah8dNu/4
– vks
Nov 14 at 6:28
|
show 3 more comments
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches.which should not be valid value.regex101.com/r/Ah8dNu/3
– vks
Nov 13 at 7:50
@vks I did notice that, OP had{0,2}in his original code rather than{1, 2}, seemed strange but I thought it was intentional
– CertainPerformance
Nov 13 at 8:20
1
@DeepakJain use^(?!$)d{0,10}(?:.d{1,2})?$. See demo. regex101.com/r/Ah8dNu/4
– vks
Nov 14 at 6:28
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
11111111111 (11 digit are invalid) not working (only 10 digit allowed)
– Deepak Jain
Nov 13 at 5:42
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
10 digit before Decimal
– Deepak Jain
Nov 13 at 5:44
This matches
. which should not be valid value.regex101.com/r/Ah8dNu/3– vks
Nov 13 at 7:50
This matches
. which should not be valid value.regex101.com/r/Ah8dNu/3– vks
Nov 13 at 7:50
@vks I did notice that, OP had
{0,2} in his original code rather than {1, 2}, seemed strange but I thought it was intentional– CertainPerformance
Nov 13 at 8:20
@vks I did notice that, OP had
{0,2} in his original code rather than {1, 2}, seemed strange but I thought it was intentional– CertainPerformance
Nov 13 at 8:20
1
1
@DeepakJain use
^(?!$)d{0,10}(?:.d{1,2})?$ . See demo. regex101.com/r/Ah8dNu/4– vks
Nov 14 at 6:28
@DeepakJain use
^(?!$)d{0,10}(?:.d{1,2})?$ . See demo. regex101.com/r/Ah8dNu/4– vks
Nov 14 at 6:28
|
show 3 more comments
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((.)[0-9]{0,2}){0,1}$
add a comment |
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((.)[0-9]{0,2}){0,1}$
add a comment |
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((.)[0-9]{0,2}){0,1}$
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((.)[0-9]{0,2}){0,1}$
answered Nov 13 at 7:01
Ashish Sapkale
455212
455212
add a comment |
add a comment |
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How did you devise this regex? Your regex doesn't match the
-character for sign.– Dai
Nov 13 at 5:34
@CertainPerformance fixed
– Deepak Jain
Nov 13 at 5:39
Do you want to match
1.2? or1.22– vks
Nov 13 at 7:05
@vks both needed
– Deepak Jain
Nov 14 at 6:16
1
@DeepakJain the answer u accepted accepts
.as well.1.as well– vks
Nov 14 at 6:25