Where to initialize a rich edit control on another dialog?











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I have an MFC dialog based application that has 2 Dialogs: Main Dialog CMyDlgand Second dialog CMyDlg2.



On the main Dialog I add a Button "Go dialog 2". So I added a handler for the button so that when clicked it pops up the second dialog. Everything works fine But on the second Dialog I have added a Rich Edit Control from toolbox. I Added for it a variable. I also added a class for the second dialog.



Now If I run the Application I get the dialog one and if I pressed "Go to dialog 2" I got what I want. But I need at some point to change the font of the rich edit control but my program crashes.



So I overrided OnInitDialog and inside it do some changes to the control but program crashes. After debugging I found that the handle of rich edit is null?!



So how and where can I change the color or do some initializations to the control?



(I called AfxInitRichEdit2() in OnInitInstance())



BOOL CMyDlg2::OnInitDialog() {
m_richEdit.SetWindowText("Hello there!"); // program crashes because the handle m_richEdit is null.

return TRUE;
}


And this is the handler of button that creates the Dialog2 and that contains the rich edit control:



void CMyDlg::OnBnClickedButton1(){
CMyDlg2 theDlg;
theDlg.DoModal();
// TODO: Add your control notification handler code here
}



  • If I create the rich edit control programmatically then everything works fine because I create it at OnInitDialog and then it works fine but I need the one that is I added using the wizard toolbox.


*** The thing is that if I write:



    m_richEdit.SetWindowText(""); // program crashes but if I wirte:
GetDlgItem(IDC_RICHEDIT221).SetWindowText(""); it works fine?









share|improve this question




















  • 2




    m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
    – Barmak Shemirani
    Nov 11 at 22:06








  • 2




    To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
    – zett42
    Nov 11 at 22:51






  • 1




    Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
    – zett42
    Nov 11 at 23:04






  • 1




    It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
    – Barmak Shemirani
    Nov 11 at 23:33








  • 1




    Sure, you are welcome.
    – Barmak Shemirani
    Nov 11 at 23:47















up vote
0
down vote

favorite












I have an MFC dialog based application that has 2 Dialogs: Main Dialog CMyDlgand Second dialog CMyDlg2.



On the main Dialog I add a Button "Go dialog 2". So I added a handler for the button so that when clicked it pops up the second dialog. Everything works fine But on the second Dialog I have added a Rich Edit Control from toolbox. I Added for it a variable. I also added a class for the second dialog.



Now If I run the Application I get the dialog one and if I pressed "Go to dialog 2" I got what I want. But I need at some point to change the font of the rich edit control but my program crashes.



So I overrided OnInitDialog and inside it do some changes to the control but program crashes. After debugging I found that the handle of rich edit is null?!



So how and where can I change the color or do some initializations to the control?



(I called AfxInitRichEdit2() in OnInitInstance())



BOOL CMyDlg2::OnInitDialog() {
m_richEdit.SetWindowText("Hello there!"); // program crashes because the handle m_richEdit is null.

return TRUE;
}


And this is the handler of button that creates the Dialog2 and that contains the rich edit control:



void CMyDlg::OnBnClickedButton1(){
CMyDlg2 theDlg;
theDlg.DoModal();
// TODO: Add your control notification handler code here
}



  • If I create the rich edit control programmatically then everything works fine because I create it at OnInitDialog and then it works fine but I need the one that is I added using the wizard toolbox.


*** The thing is that if I write:



    m_richEdit.SetWindowText(""); // program crashes but if I wirte:
GetDlgItem(IDC_RICHEDIT221).SetWindowText(""); it works fine?









share|improve this question




















  • 2




    m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
    – Barmak Shemirani
    Nov 11 at 22:06








  • 2




    To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
    – zett42
    Nov 11 at 22:51






  • 1




    Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
    – zett42
    Nov 11 at 23:04






  • 1




    It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
    – Barmak Shemirani
    Nov 11 at 23:33








  • 1




    Sure, you are welcome.
    – Barmak Shemirani
    Nov 11 at 23:47













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have an MFC dialog based application that has 2 Dialogs: Main Dialog CMyDlgand Second dialog CMyDlg2.



On the main Dialog I add a Button "Go dialog 2". So I added a handler for the button so that when clicked it pops up the second dialog. Everything works fine But on the second Dialog I have added a Rich Edit Control from toolbox. I Added for it a variable. I also added a class for the second dialog.



Now If I run the Application I get the dialog one and if I pressed "Go to dialog 2" I got what I want. But I need at some point to change the font of the rich edit control but my program crashes.



So I overrided OnInitDialog and inside it do some changes to the control but program crashes. After debugging I found that the handle of rich edit is null?!



So how and where can I change the color or do some initializations to the control?



(I called AfxInitRichEdit2() in OnInitInstance())



BOOL CMyDlg2::OnInitDialog() {
m_richEdit.SetWindowText("Hello there!"); // program crashes because the handle m_richEdit is null.

return TRUE;
}


And this is the handler of button that creates the Dialog2 and that contains the rich edit control:



void CMyDlg::OnBnClickedButton1(){
CMyDlg2 theDlg;
theDlg.DoModal();
// TODO: Add your control notification handler code here
}



  • If I create the rich edit control programmatically then everything works fine because I create it at OnInitDialog and then it works fine but I need the one that is I added using the wizard toolbox.


*** The thing is that if I write:



    m_richEdit.SetWindowText(""); // program crashes but if I wirte:
GetDlgItem(IDC_RICHEDIT221).SetWindowText(""); it works fine?









share|improve this question















I have an MFC dialog based application that has 2 Dialogs: Main Dialog CMyDlgand Second dialog CMyDlg2.



On the main Dialog I add a Button "Go dialog 2". So I added a handler for the button so that when clicked it pops up the second dialog. Everything works fine But on the second Dialog I have added a Rich Edit Control from toolbox. I Added for it a variable. I also added a class for the second dialog.



Now If I run the Application I get the dialog one and if I pressed "Go to dialog 2" I got what I want. But I need at some point to change the font of the rich edit control but my program crashes.



So I overrided OnInitDialog and inside it do some changes to the control but program crashes. After debugging I found that the handle of rich edit is null?!



So how and where can I change the color or do some initializations to the control?



(I called AfxInitRichEdit2() in OnInitInstance())



BOOL CMyDlg2::OnInitDialog() {
m_richEdit.SetWindowText("Hello there!"); // program crashes because the handle m_richEdit is null.

return TRUE;
}


And this is the handler of button that creates the Dialog2 and that contains the rich edit control:



void CMyDlg::OnBnClickedButton1(){
CMyDlg2 theDlg;
theDlg.DoModal();
// TODO: Add your control notification handler code here
}



  • If I create the rich edit control programmatically then everything works fine because I create it at OnInitDialog and then it works fine but I need the one that is I added using the wizard toolbox.


*** The thing is that if I write:



    m_richEdit.SetWindowText(""); // program crashes but if I wirte:
GetDlgItem(IDC_RICHEDIT221).SetWindowText(""); it works fine?






c++ mfc






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 0:02

























asked Nov 11 at 21:45









Maestro

7410




7410








  • 2




    m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
    – Barmak Shemirani
    Nov 11 at 22:06








  • 2




    To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
    – zett42
    Nov 11 at 22:51






  • 1




    Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
    – zett42
    Nov 11 at 23:04






  • 1




    It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
    – Barmak Shemirani
    Nov 11 at 23:33








  • 1




    Sure, you are welcome.
    – Barmak Shemirani
    Nov 11 at 23:47














  • 2




    m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
    – Barmak Shemirani
    Nov 11 at 22:06








  • 2




    To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
    – zett42
    Nov 11 at 22:51






  • 1




    Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
    – zett42
    Nov 11 at 23:04






  • 1




    It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
    – Barmak Shemirani
    Nov 11 at 23:33








  • 1




    Sure, you are welcome.
    – Barmak Shemirani
    Nov 11 at 23:47








2




2




m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
– Barmak Shemirani
Nov 11 at 22:06






m_richEdit won't be NULL, but it's window handle will be NULL because it's not created as a window yet. You have to call the default method first. Change to: BOOL CMyDlg2::OnInitDialog(){__super::OnInitDialog();m_richEdit.SetWindowText("Hello there!");return TRUE;}
– Barmak Shemirani
Nov 11 at 22:06






2




2




To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
– zett42
Nov 11 at 22:51




To be precise, the richedit window has already been created in CMyDlg2::OnInitDialog(), but it won't be associated with the m_richEdit variable, unless the base class's OnInitDialog() method is called.
– zett42
Nov 11 at 22:51




1




1




Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
– zett42
Nov 11 at 23:04




Basically like Barmak wrote, but __super is Microsoft-specific, I would write CDialog::OnInitDialog() instead, which is standard C++.
– zett42
Nov 11 at 23:04




1




1




It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
– Barmak Shemirani
Nov 11 at 23:33






It looks like you are calling the base class method now CMyDlg2::OnInitDialog(){CDialog::OnInitDialog(); ...} that should work.
– Barmak Shemirani
Nov 11 at 23:33






1




1




Sure, you are welcome.
– Barmak Shemirani
Nov 11 at 23:47




Sure, you are welcome.
– Barmak Shemirani
Nov 11 at 23:47












1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










You probably have the following code inserted by wizard:



void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}


This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.



BOOL CMyDlg2::OnInitDialog() 
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");

//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL

//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();

//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}


It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.



GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:



HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");


There is no additional initialization needed.



But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.



Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText






share|improve this answer























  • Yes I have that code inserted by the wizard.
    – Maestro
    Nov 12 at 0:03










  • Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
    – Maestro
    Nov 12 at 0:06












  • I added more clarification in Edit.
    – Barmak Shemirani
    Nov 12 at 0:21










  • Understood now! thank you for your help and efforts and time.
    – Maestro
    Nov 12 at 0:24











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










You probably have the following code inserted by wizard:



void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}


This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.



BOOL CMyDlg2::OnInitDialog() 
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");

//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL

//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();

//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}


It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.



GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:



HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");


There is no additional initialization needed.



But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.



Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText






share|improve this answer























  • Yes I have that code inserted by the wizard.
    – Maestro
    Nov 12 at 0:03










  • Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
    – Maestro
    Nov 12 at 0:06












  • I added more clarification in Edit.
    – Barmak Shemirani
    Nov 12 at 0:21










  • Understood now! thank you for your help and efforts and time.
    – Maestro
    Nov 12 at 0:24















up vote
2
down vote



accepted










You probably have the following code inserted by wizard:



void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}


This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.



BOOL CMyDlg2::OnInitDialog() 
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");

//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL

//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();

//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}


It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.



GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:



HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");


There is no additional initialization needed.



But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.



Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText






share|improve this answer























  • Yes I have that code inserted by the wizard.
    – Maestro
    Nov 12 at 0:03










  • Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
    – Maestro
    Nov 12 at 0:06












  • I added more clarification in Edit.
    – Barmak Shemirani
    Nov 12 at 0:21










  • Understood now! thank you for your help and efforts and time.
    – Maestro
    Nov 12 at 0:24













up vote
2
down vote



accepted







up vote
2
down vote



accepted






You probably have the following code inserted by wizard:



void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}


This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.



BOOL CMyDlg2::OnInitDialog() 
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");

//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL

//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();

//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}


It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.



GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:



HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");


There is no additional initialization needed.



But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.



Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText






share|improve this answer














You probably have the following code inserted by wizard:



void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}


This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.



BOOL CMyDlg2::OnInitDialog() 
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");

//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL

//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();

//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}


It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.



GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:



HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");


There is no additional initialization needed.



But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.



Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 12 at 3:26

























answered Nov 12 at 0:02









Barmak Shemirani

20.5k42044




20.5k42044












  • Yes I have that code inserted by the wizard.
    – Maestro
    Nov 12 at 0:03










  • Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
    – Maestro
    Nov 12 at 0:06












  • I added more clarification in Edit.
    – Barmak Shemirani
    Nov 12 at 0:21










  • Understood now! thank you for your help and efforts and time.
    – Maestro
    Nov 12 at 0:24


















  • Yes I have that code inserted by the wizard.
    – Maestro
    Nov 12 at 0:03










  • Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
    – Maestro
    Nov 12 at 0:06












  • I added more clarification in Edit.
    – Barmak Shemirani
    Nov 12 at 0:21










  • Understood now! thank you for your help and efforts and time.
    – Maestro
    Nov 12 at 0:24
















Yes I have that code inserted by the wizard.
– Maestro
Nov 12 at 0:03




Yes I have that code inserted by the wizard.
– Maestro
Nov 12 at 0:03












Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
– Maestro
Nov 12 at 0:06






Would you mind to explain why GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello"); works?
– Maestro
Nov 12 at 0:06














I added more clarification in Edit.
– Barmak Shemirani
Nov 12 at 0:21




I added more clarification in Edit.
– Barmak Shemirani
Nov 12 at 0:21












Understood now! thank you for your help and efforts and time.
– Maestro
Nov 12 at 0:24




Understood now! thank you for your help and efforts and time.
– Maestro
Nov 12 at 0:24


















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