Finding a reversed words in a given string using C program
Actually I have been searching for more than 1 week to find a solution for finding a reversed words in a given string using C. My question is, I have been given a string like this "bakelovekac". Here I have a reversed word of "ake" as "eka" in a string. Now I need to find out this reversed word in a given string and print it. How can it be done? Thanks in advance!
c
asked Nov 15 '18 at 1:36
DhansDhans
1117
|
show 4 more comments
Actually I have been searching for more than 1 week to find a solution for finding a reversed words in a given string using C. My question is, I have been given a string like this "bakelovekac". Here I have a reversed word of "ake" as "eka" in a string. Now I need to find out this reversed word in a given string and print it. How can it be done? Thanks in advance!
c
asked Nov 15 '18 at 1:36
DhansDhans
1117
Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
There is no time limit
– Dhans
Nov 15 '18 at 2:10
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40
|
show 4 more comments
Actually I have been searching for more than 1 week to find a solution for finding a reversed words in a given string using C. My question is, I have been given a string like this "bakelovekac". Here I have a reversed word of "ake" as "eka" in a string. Now I need to find out this reversed word in a given string and print it. How can it be done? Thanks in advance!
c
asked Nov 15 '18 at 1:36
DhansDhans
1117
Actually I have been searching for more than 1 week to find a solution for finding a reversed words in a given string using C. My question is, I have been given a string like this "bakelovekac". Here I have a reversed word of "ake" as "eka" in a string. Now I need to find out this reversed word in a given string and print it. How can it be done? Thanks in advance!
c
c
asked Nov 15 '18 at 1:36
DhansDhans
1117
asked Nov 15 '18 at 1:36
DhansDhans
1117
asked Nov 15 '18 at 1:36
DhansDhans
1117
asked Nov 15 '18 at 1:36
DhansDhans
1117
asked Nov 15 '18 at 1:36
DhansDhans
1117
1117
Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
There is no time limit
– Dhans
Nov 15 '18 at 2:10
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40
|
show 4 more comments
Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
There is no time limit
– Dhans
Nov 15 '18 at 2:10
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40
Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
There is no time limit
– Dhans
Nov 15 '18 at 2:10
There is no time limit
– Dhans
Nov 15 '18 at 2:10
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40
|
show 4 more comments
2 Answers
2
active
oldest
votes
A basic approach would be to iterate over all the characters of the string and for each character check if it is being repeated, if yes then check for the presence of a possible reverse string.
A crude code for above approach would look something like this:
#include <stdio.h>
void checkForRevWord(char *str, char *rev){
int length = 0;
while(1){
if(str >= rev)
break;
if(*str != *rev)
break;
length++;
str++;
rev--;
}
if(length > 1){
while(length--)
printf("%c", *(rev+length+1));
printf("n");
}
return;
}
int main()
{
char *inputStr = "bakelovekac";
char *cur = inputStr;
char *tmp;
while(*cur != ''){
tmp = cur+1;
/* find if current char gets repeated in the input string*/
while(*tmp != ''){
if(*tmp == *cur){
checkForRevWord(cur, tmp);
}
tmp++;
}
cur++;
}
}
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
add a comment |
Go through this program
#include <stdio.h>
#include <string.h>
int main()
{
char text[50]; //this character array to store string
int len,i;
printf("Enter a textn");
scanf("%[^n]s",text);//getting the user input with spaces until the end of the line
len=strlen(text);//getting the length of the array and assigning it the len variable
for(i=len-1;i>=0;i--)
{
printf("%c",text[i]); //printing the text from backwards
}
return 0;
}
thank you.
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
A basic approach would be to iterate over all the characters of the string and for each character check if it is being repeated, if yes then check for the presence of a possible reverse string.
A crude code for above approach would look something like this:
#include <stdio.h>
void checkForRevWord(char *str, char *rev){
int length = 0;
while(1){
if(str >= rev)
break;
if(*str != *rev)
break;
length++;
str++;
rev--;
}
if(length > 1){
while(length--)
printf("%c", *(rev+length+1));
printf("n");
}
return;
}
int main()
{
char *inputStr = "bakelovekac";
char *cur = inputStr;
char *tmp;
while(*cur != ''){
tmp = cur+1;
/* find if current char gets repeated in the input string*/
while(*tmp != ''){
if(*tmp == *cur){
checkForRevWord(cur, tmp);
}
tmp++;
}
cur++;
}
}
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
add a comment |
A basic approach would be to iterate over all the characters of the string and for each character check if it is being repeated, if yes then check for the presence of a possible reverse string.
A crude code for above approach would look something like this:
#include <stdio.h>
void checkForRevWord(char *str, char *rev){
int length = 0;
while(1){
if(str >= rev)
break;
if(*str != *rev)
break;
length++;
str++;
rev--;
}
if(length > 1){
while(length--)
printf("%c", *(rev+length+1));
printf("n");
}
return;
}
int main()
{
char *inputStr = "bakelovekac";
char *cur = inputStr;
char *tmp;
while(*cur != ''){
tmp = cur+1;
/* find if current char gets repeated in the input string*/
while(*tmp != ''){
if(*tmp == *cur){
checkForRevWord(cur, tmp);
}
tmp++;
}
cur++;
}
}
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
add a comment |
A basic approach would be to iterate over all the characters of the string and for each character check if it is being repeated, if yes then check for the presence of a possible reverse string.
A crude code for above approach would look something like this:
#include <stdio.h>
void checkForRevWord(char *str, char *rev){
int length = 0;
while(1){
if(str >= rev)
break;
if(*str != *rev)
break;
length++;
str++;
rev--;
}
if(length > 1){
while(length--)
printf("%c", *(rev+length+1));
printf("n");
}
return;
}
int main()
{
char *inputStr = "bakelovekac";
char *cur = inputStr;
char *tmp;
while(*cur != ''){
tmp = cur+1;
/* find if current char gets repeated in the input string*/
while(*tmp != ''){
if(*tmp == *cur){
checkForRevWord(cur, tmp);
}
tmp++;
}
cur++;
}
}
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
A basic approach would be to iterate over all the characters of the string and for each character check if it is being repeated, if yes then check for the presence of a possible reverse string.
A crude code for above approach would look something like this:
#include <stdio.h>
void checkForRevWord(char *str, char *rev){
int length = 0;
while(1){
if(str >= rev)
break;
if(*str != *rev)
break;
length++;
str++;
rev--;
}
if(length > 1){
while(length--)
printf("%c", *(rev+length+1));
printf("n");
}
return;
}
int main()
{
char *inputStr = "bakelovekac";
char *cur = inputStr;
char *tmp;
while(*cur != ''){
tmp = cur+1;
/* find if current char gets repeated in the input string*/
while(*tmp != ''){
if(*tmp == *cur){
checkForRevWord(cur, tmp);
}
tmp++;
}
cur++;
}
}
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
answered Nov 15 '18 at 4:44
SandeepSandeep
647311
647311
add a comment |
add a comment |
Go through this program
#include <stdio.h>
#include <string.h>
int main()
{
char text[50]; //this character array to store string
int len,i;
printf("Enter a textn");
scanf("%[^n]s",text);//getting the user input with spaces until the end of the line
len=strlen(text);//getting the length of the array and assigning it the len variable
for(i=len-1;i>=0;i--)
{
printf("%c",text[i]); //printing the text from backwards
}
return 0;
}
thank you.
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
add a comment |
Go through this program
#include <stdio.h>
#include <string.h>
int main()
{
char text[50]; //this character array to store string
int len,i;
printf("Enter a textn");
scanf("%[^n]s",text);//getting the user input with spaces until the end of the line
len=strlen(text);//getting the length of the array and assigning it the len variable
for(i=len-1;i>=0;i--)
{
printf("%c",text[i]); //printing the text from backwards
}
return 0;
}
thank you.
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
add a comment |
Go through this program
#include <stdio.h>
#include <string.h>
int main()
{
char text[50]; //this character array to store string
int len,i;
printf("Enter a textn");
scanf("%[^n]s",text);//getting the user input with spaces until the end of the line
len=strlen(text);//getting the length of the array and assigning it the len variable
for(i=len-1;i>=0;i--)
{
printf("%c",text[i]); //printing the text from backwards
}
return 0;
}
thank you.
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
Go through this program
#include <stdio.h>
#include <string.h>
int main()
{
char text[50]; //this character array to store string
int len,i;
printf("Enter a textn");
scanf("%[^n]s",text);//getting the user input with spaces until the end of the line
len=strlen(text);//getting the length of the array and assigning it the len variable
for(i=len-1;i>=0;i--)
{
printf("%c",text[i]); //printing the text from backwards
}
return 0;
}
thank you.
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
answered Nov 15 '18 at 4:55
Jayaraj RohanJayaraj Rohan
164
164
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
add a comment |
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
This seems to not address the OPs question about finding a sub string inside the string. I will let him decide though.
– Bwebb
Nov 15 '18 at 20:19
add a comment |
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Seems an ACM or OI problem... What's the range of string length? What's the time limit? If there's no restriction on time, you may just use a stupid brute force; otherwise you need some clever hash trick or dynamic programming I guess.
– Hoblovski
Nov 15 '18 at 1:41
There is no time limit
– Dhans
Nov 15 '18 at 2:10
is ake a word? is it just any series of characters or does it have to be a real word?
– Bwebb
Nov 15 '18 at 2:18
@Bwebb No it doesn't need to be a real word. Just being a series of characters is enough.
– Dhans
Nov 15 '18 at 2:22
any limit on the size of the original word?
– Bwebb
Nov 15 '18 at 2:40