How to find out if a numeric type is signed or unsigned in C#












2














I want to know details about the type of a field by reflection.



I know I can find out that it is a value type with Type.IsValueType. But from there how do I know it is a number? A fixed point number? Signed or unsigned??



Is there anything like Type.IsSigned?










share|improve this question




















  • 2




    What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
    – rory.ap
    Nov 14 '18 at 12:22








  • 1




    You'll have to compare the type with all the CLR's signed types to see if it's one of them.
    – Matthew Watson
    Nov 14 '18 at 12:23








  • 1




    You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
    – ATC
    Nov 14 '18 at 12:23










  • @rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
    – Stefan Bormann
    Nov 14 '18 at 12:36
















2














I want to know details about the type of a field by reflection.



I know I can find out that it is a value type with Type.IsValueType. But from there how do I know it is a number? A fixed point number? Signed or unsigned??



Is there anything like Type.IsSigned?










share|improve this question




















  • 2




    What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
    – rory.ap
    Nov 14 '18 at 12:22








  • 1




    You'll have to compare the type with all the CLR's signed types to see if it's one of them.
    – Matthew Watson
    Nov 14 '18 at 12:23








  • 1




    You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
    – ATC
    Nov 14 '18 at 12:23










  • @rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
    – Stefan Bormann
    Nov 14 '18 at 12:36














2












2








2







I want to know details about the type of a field by reflection.



I know I can find out that it is a value type with Type.IsValueType. But from there how do I know it is a number? A fixed point number? Signed or unsigned??



Is there anything like Type.IsSigned?










share|improve this question















I want to know details about the type of a field by reflection.



I know I can find out that it is a value type with Type.IsValueType. But from there how do I know it is a number? A fixed point number? Signed or unsigned??



Is there anything like Type.IsSigned?







c# reflection






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 12:34

























asked Nov 14 '18 at 12:20









Stefan Bormann

376216




376216








  • 2




    What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
    – rory.ap
    Nov 14 '18 at 12:22








  • 1




    You'll have to compare the type with all the CLR's signed types to see if it's one of them.
    – Matthew Watson
    Nov 14 '18 at 12:23








  • 1




    You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
    – ATC
    Nov 14 '18 at 12:23










  • @rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
    – Stefan Bormann
    Nov 14 '18 at 12:36














  • 2




    What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
    – rory.ap
    Nov 14 '18 at 12:22








  • 1




    You'll have to compare the type with all the CLR's signed types to see if it's one of them.
    – Matthew Watson
    Nov 14 '18 at 12:23








  • 1




    You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
    – ATC
    Nov 14 '18 at 12:23










  • @rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
    – Stefan Bormann
    Nov 14 '18 at 12:36








2




2




What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
– rory.ap
Nov 14 '18 at 12:22






What do you mean by "unknown"? Is it dynamic? Is it an object? Elaborate please.
– rory.ap
Nov 14 '18 at 12:22






1




1




You'll have to compare the type with all the CLR's signed types to see if it's one of them.
– Matthew Watson
Nov 14 '18 at 12:23






You'll have to compare the type with all the CLR's signed types to see if it's one of them.
– Matthew Watson
Nov 14 '18 at 12:23






1




1




You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
– ATC
Nov 14 '18 at 12:23




You probably do something like 1if typeof(myVar) == typeof(int)), or if (myvar is ulong)`...
– ATC
Nov 14 '18 at 12:23












@rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
– Stefan Bormann
Nov 14 '18 at 12:36




@rory.ap: the algorithm does not know which class it will be working on, therefore I must use reflection - I rephrased out that "unknown"
– Stefan Bormann
Nov 14 '18 at 12:36












1 Answer
1






active

oldest

votes


















6














There aren't that many numeric types that are unsigned, so why not compose a list of that:



if (new Type { typeof(ushort), typeof(uint), typeof(ulong), typeof(byte) }.Contains(type))
{
// unsigned.
}


Or if you just want to compare the value (here o):



if (o is ushort || o is uint || o is ulong || o is byte)
{
// unsigned.
}





share|improve this answer























  • Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
    – Stefan Bormann
    Nov 14 '18 at 12:40











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














There aren't that many numeric types that are unsigned, so why not compose a list of that:



if (new Type { typeof(ushort), typeof(uint), typeof(ulong), typeof(byte) }.Contains(type))
{
// unsigned.
}


Or if you just want to compare the value (here o):



if (o is ushort || o is uint || o is ulong || o is byte)
{
// unsigned.
}





share|improve this answer























  • Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
    – Stefan Bormann
    Nov 14 '18 at 12:40
















6














There aren't that many numeric types that are unsigned, so why not compose a list of that:



if (new Type { typeof(ushort), typeof(uint), typeof(ulong), typeof(byte) }.Contains(type))
{
// unsigned.
}


Or if you just want to compare the value (here o):



if (o is ushort || o is uint || o is ulong || o is byte)
{
// unsigned.
}





share|improve this answer























  • Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
    – Stefan Bormann
    Nov 14 '18 at 12:40














6












6








6






There aren't that many numeric types that are unsigned, so why not compose a list of that:



if (new Type { typeof(ushort), typeof(uint), typeof(ulong), typeof(byte) }.Contains(type))
{
// unsigned.
}


Or if you just want to compare the value (here o):



if (o is ushort || o is uint || o is ulong || o is byte)
{
// unsigned.
}





share|improve this answer














There aren't that many numeric types that are unsigned, so why not compose a list of that:



if (new Type { typeof(ushort), typeof(uint), typeof(ulong), typeof(byte) }.Contains(type))
{
// unsigned.
}


Or if you just want to compare the value (here o):



if (o is ushort || o is uint || o is ulong || o is byte)
{
// unsigned.
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 12:24

























answered Nov 14 '18 at 12:23









Patrick Hofman

126k18170224




126k18170224












  • Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
    – Stefan Bormann
    Nov 14 '18 at 12:40


















  • Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
    – Stefan Bormann
    Nov 14 '18 at 12:40
















Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
– Stefan Bormann
Nov 14 '18 at 12:40




Well, thanks. That explicit list of types was my first thought, just hoped there would be a more elegant solution...
– Stefan Bormann
Nov 14 '18 at 12:40


















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